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NATIONAL ACADEMY DHARMAPURI
TRB MATHEMATICS
FUNTIONAL ANALYSIS
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CLASS -I Holderβs inequality 1
1
π
π
π π=1
If p> 1and + = 1,then π π=1
π π=1
π₯π π¦π β€ [
π₯π
π₯π π¦π β€ [ π π=1
] [
π π=1
π¦π
1
π₯π
π π ]
π π=1
[
1
π¦π
π π ]
OR
]
Holderβs inequality For intgrable function π π
π π₯ π(π₯) dxβ€ [
π π
1
1
π π
π(π₯) π ππ₯]π [
π(π₯) π ππ₯]π
ππ’π‘ π = π = 2 ,then, π π=1 π π=1
[
π₯π π¦π β€ [
π π=1
2
π₯π π¦π ] β€ [
1
π π=1
π₯π 2 ]2 [ π π=1
π₯π 2 ] [
1
π¦π 2 ]2 or π π=1
π¦π 2 ]
ππππ ππ ππππ€π ππ πππ’πππ¦ β² s inequality Minkowskβs inequality
www.asiriyar.com ο If pβ₯1,then
[
π π=1
1
π₯π + π¦π
π π ]
β€ [
π π=1
1
π₯π
π π ]
π π=1
+[
1
π¦π
π π ]
ο If f and g are real or complex valued integrable function defined on [a,b], Then
[
π π
π
π π₯ + π π₯ dx] ππ₯ β€ [
π π
π π₯
π
1 π
ππ₯] + [
π π
π
1 π
π(π₯) ππ₯] where pβ₯ 1
Metric space Let X be a non-empty set. A metric on X is a real valued function XΓ π satisfying the following Three conditions, For every x,y β π πππ π₯ β π¦ 1. d(x,y)β₯0 and d(x,y) = 0 if and only if x =y 2. d(x,y) = d(y,x) for every x,yβ π 3. d(x, y) β€d(x, z) + d(z,y) for any x,y,z β π d(x,y) is called the distance between x and y ,it is finite non-negative real number. π΅πππππ
ππππππ ππππππ Let N be a complex or real linear space a norm on N is a function such that (
:π β π
)
i.
π₯ β₯ 0 and π₯ = 0 βΊ x = 0 www.tnmanavan.blogspot.in
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π₯+π¦ β€ π₯ + π¦ ππ₯ = π π₯ for all x,yππ and aππ ππ π
ii. iii.
N is called a normed linear space. Definition Let N be a normed linear space, a sequence {xn} in N is said to converge to an element x in N if given π > 0,there exists a positive integer n0 such that π₯π β π₯ < π for all nβ₯n0 πΌπ‘ ππ πππππ‘ππ ππ¦ limπ₯ββ π₯π = π₯ xnβ π₯ πππ π₯π β π₯ β 0 as nβ β Theorems ο A normed linear space N is a matric space with respect to the metric d defined by D(x,y) = π₯ β π¦
for all x,y ππ
ο If N is a normed linear space,Then ο· π₯ + π¦ β€ π₯ + π¦
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π₯ β π¦
β€ π₯βπ¦
ο If N is a normed linear space,Then the norm : π β π
is continuous on N. ο The operation of addition and scalar multiplication in N are jointly continuous. If xn βx, yn β π¦ and anβ π ,Then xn+ynβ x+y, anxnβax
ο Let N be a normed linear space and M be a subspace of N, then the closure π of M is also a subspace of N ο A subset M in a normed linear space N is bounded if and only if there is a positive constant C such that π₯ β€ πΆ for all x ππ Cauchy sequence A sequence {xn} in N is called a Cauchy sequence in N ,If given π β₯ 0there exists a positive integer n0 such that π₯π β π₯π < π for all m,nβ₯n0 If {xn} is a Cauchy sequence in N,Then π₯π β π₯π β 0 ππ m,nβ β
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Properties of a Cauchy sequence i.
If N is normed linear space ,then every convergent sequence is a Cauchy sequence. Itβs converse is not true
ii.
Every Cauchy sequence in a normed linear space is bounded.
Complete A normed linear space N is said to be complete if every Cauchy sequence in N converges to an element of N. β If π₯π β π₯π β 0 ππ ,nβ β, then there exists x ππ such that π₯π β π₯
β 0 ππ ,nβ β,
π©πππππ πππππ A complete normed linear space is called a Banach space. ο Every complete subspace M of a normed linear space is closed
www.asiriyar.com Convergent of series
A series β π=1 π₯π , xn ππ is said to be convergent to x ππ, If the sequence of partial sums {sn} converges to x in N. A series
β π=1 π₯π
β π=1
is said to be absolutely convergent if
π₯π is convergent.
Theorem A normed linear space N is complete if and only if every absolutely convergent series is convergent. Example of Banach spaces. 1. The real linear space R and the complex linear space C are normed linear space under the norm π₯ = π₯ for all xππ
ππ πΆ R and C are complete β R and C are Banach spaces. 2. The linear space Rn or Cn are Banach space with Norm, π₯ = [ 3. (i) Rn or Cn are Banach space with Norm, π₯ = [ Which is denited by lpn (ii) π₯ = Max { π₯1 , π₯2 , π₯3 , β¦
π π=1
π π=1
1
π₯π π ]π ,1β€ π β€ β
π , π₯π } , which is denoted by πβ
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1
π₯π 2 ]2
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4. The linear space C of all convergent sequence x = {xn} with the Norm. π₯ = sup1β€π β€β π₯π is a Banach space denoted by C 5. The linear space πβ of all bounded sequence x = {xn} with the Norm. π₯ = sup1β€π β€β π₯π is a Banach space. 6. The linear space ππ , p> 1 of all sequences [ π₯ =[ 7.
π π=1
β π=1
π₯π π ] < β with norm
1
π₯π π ]π is a Banach space, It is denoted by
π
If [a,b] is a bounded and closed interval, The linear space C[a,b] of all continuous functions defined on [a,b] is a Banach space with the norm, π = Sup{ π(π₯) / xπ[a.b]}
8. Let C(x) be the set of all continuous real valued function on a compact metric space X, then C(X) is a Banach space with the norm π = Sup{ π(π₯) / xπX]
www.asiriyar.com πΊππππππππ
A normed linear space N is said to be separable if it has a countable dense subset.
ie., There is a countable subset D in N such that π· = π
Example 1. Every subset of a separable normal linear space is separable 2. The normed linear space ππ , 1β€ π β€ β are separable 3. The space πβ is not separable Quatient space Let N be a normed linear space and M be a subspace of N, Then called Quotient space. It is denoted by Q(x) Q(x) is called canonical( Natural ) mapping of L onto
π π
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π π
= {π₯ + π/π₯πN} is
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Theorem: If M is a closed linear subspace of a normed linear space N, Then quotian space
π π
is a
normed linear space with norm of each cosert x+M defined as π₯ + π = inf{ π₯ + π /mπM }. If N is Banach space, then the quotient space
π π
is also a Banach space with above norm
Direct sum of subspace Let M and N are subspace of Banach space B, If every element z on B is represented uniquely in the form z = x+y ,xπM,yπN,Then B is said to be direct sum of N,M It is denoted by B = MβN Theorem Let a Banach Space B = MβN and zπB be z =x+y uniquely with xπM,yπN ,then π§
1
= π₯ + π¦ is a normal on direct sum B = MβN
www.asiriyar.com If B1 is the direct sum space with this new norm, then B1 is a Banach space if M and N are closed. Continuous linear Transformation
T:NβN1 is continuous if and only if xnβx in N implies T(xn) βT(x) in N1 1. Zero Transformation is denoted by 0 2.Identity Transformation is denoted by I
Theorem If T is continuous at the origin, Then it is continuous everywhere and the continutity is uniform. Bounded linear transformation A linear transformation T:NβN1 is said to be bounded linear transformation if there exists a positive constant M such that π(π₯) β€M π₯ for all xπN. Theorem 1. T:NβN1 is bounded if and only if T is continuous. 2. Let T:NβN1 be a linear transformation ,Then T is bounded if and only if T maps bounded sets in N into bounded set in N1 www.tnmanavan.blogspot.in
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Bound of T Let T be a bounded linear transformation of N into N1, Then the norm , π(π₯) = inf{M/ π(π₯) β€M π₯ for all xπN} is called the bound of T (OR) π = sup{
π(π₯) π₯
/ xπN and xβ 0 }
Theorem If N and N1 are normed linear space and T:NβN1, Then the following are equivalent (a) π
= sup{
π(π₯) π₯
/ xπN and xβ 0 }
(b) π = sup{ π(π₯) / xπN and π β€ 1 } (c) π = sup{ π(π₯) / xπN and π = 1} B(N,N1) The set of all bounded linear transformation of normed space N into N1 is denoted by B(N,N1)
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ο B(N,N1) is a normed linear space with linear operation (i) (T1+T2)(x) = T1(x)+T2(x), (ii) (aT)x = aT(x) and norm defined by π = sup{
π(π₯) π₯
/ xπN and xβ 0 }
If N1 is a Banach space ,then B(N,N1) is also Banach space. 1. If T1,T2 π B(N,N1), the π1 π2 β€ π1
π2
2. If TnβT and Tn1βT1, Then TnTn1βTT1 as nβ β which implies that the multiplication is jointly continuous. Theorem ο Let M be a closed subspace of a normed linear space and T be the natural mapping of N onto the quotient space
π π
defined by T(x) =x+M,Then T is bounded linear
transformation with π β€ 1 ο Let N and N1 be normed linear space and let T:NβN1 be a bounded linear transformation of N into N1,If M is the kernel of T, then i) M is closed subspace of N ii) T induces a natural transformation T1 of N/M onto N1 such that π 1 = π www.tnmanavan.blogspot.in
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Definition Let N and N1 be normed linear space ,an isometric isomorphism of N into N1 is a oneone linear transformation T of N into N1 such that π(π₯) = π₯ for all xβ π For any x,y β π β π π₯ β π(π¦) = π(π₯ β π¦) = π₯ β π¦ Definition Topologically isomorphic Two normed linear space N and N1 are said to be topologically isomorphic, if (i) There exists a linear operator T:NβN1 having the inverse T-1 (ii) T establishes the isomorphism of N and N1 (iii) T and T-1 are continuous in their respective domains. Theorem Let N and N1 be normed linear space and Let T be linear transformation of N into N1. If T(N) is the range of T, Then the inverse T-1 exists and is bounded (continuous) in its domain of definition if and only if there exists a constan m>0 such that m π β€ π»(π) for all xβ π
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Let N and N1 be normed linear space. The N and N1 are topologically isomorphic if and only if there exist a linear operator T on N onto N1 and positive constants m and M such that m π β€ π»(π) β€ π π for all xβ π΅
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NATIONAL ACADEMY TRB MATHS COACHING CENTRE β DHARMAPURI FUNCTIONAL ANALYSIS TEST β 1
1. If f and g are real or complex valued integrable function defined on [a,b], Then Minkowskβs inequality is (a) [
π π
(b) [
π π
(c) [
π π
(d) [
π π
π π₯ + π π₯ dx]π ππ₯ β€ [ π π₯ + π π₯ dx]π ππ₯ β€ [
π π π π
π π₯ + π π₯ dx] ππ₯ β€ [
π π
π π₯ + π π₯ dx]π ππ₯ > [
π π
π
π π₯ π π₯
1
1
ππ₯]π + [
π π
π(π₯) π ππ₯]π where p< 1
ππ₯] + [
π π
π(π₯)
π
1 π
π π₯
π
ππ₯] + [
π π₯
π
ππ₯]π + [
1
ππ₯] wherepβ₯ 1 1 π
π π
π(π₯) ππ₯] where pβ₯ 1
π π
π(π₯) π ππ₯]π where pβ₯ 1
π
1
2. If N be a complex or real linear space a norm on N is a function ,Then www.tnmanavan.blogspot.in
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(a)
π₯+π¦ β€ π₯ + π¦
(b) π₯ + π¦ > π₯ + π¦
(c) π₯ + π¦ + π¦
(d) π₯ + π¦ β€ π₯
3. Let N be a normed linear space, For every x,y β π (a) π₯ β π¦
β€ π₯βπ¦
(b)
(c) π₯ β π¦ = π₯ β π¦
(d)
π₯ β π¦ π₯ β π¦
> π₯ β π¦ =0
4. If every Cauchy sequence in N converges to an element of a normed linear space N, then N is (a) Banach space
(b) complete
(c) Hilbert space
5. ππ π is (a) Not Banach space (b) Linear space (c) Banach space 6. In a Banach space xnβ x, ynβ y implies that xn+yn β π₯ (a) x+y (b) (c) x-y π¦
(d)Metric space
(d) None of these (d) xy
7. If N be a Normed linear space and π₯ = 0 ππ πππ ππππ¦ ππ (a) x= 0
(c) xβ 0
(b) x is a real
(d) x>0
8. Every Cauchy sequence in a normed linear space is (a) not converges
(b) absolutely convergent
www.asiriyar.com (c) bounded.
(d)neither convergent nor divergent
9. A normed linear space N is complete if and only if every absolutely convergent series is, (a) not converges
(b) convergent
(c) divergent
(d)neither convergent nor divergent
10. A subspace M of a Banach space B is complete if and only if M is (a) bounded (b) Unbounded (c) Closed in B 11. If M is a closed linear subspace of a normed linear space N, Then quotian space
π π
(d) Open in B
is a normed linear space with norm
(a) π₯ + π = sup{ π₯ + π /mπM }
(b) π₯ + π = inf{ π₯ /xπN }.
(c) π₯ + π = inf{ π₯ + π /mπM }
(d) π₯ + π = inf{ π /mπM }.
12. Let M be a closed subspace of a normed linear space N, For each xπN, let π₯ + π = inf{ π₯ + π /mπM } then resfective to this norm (a) N+M is a normed linear space (c)
π π
(b)NM is a normed linear space
is a normed linear space
(d) N - M is a normed linear space
13. A complete normed linear space is (a) Hilbert space (b) Banach space
(c) Vector space
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(d) None of these
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14. M is a closed linear subspace of the a normed linear space N. If N is a Banach space then the following is also a Banach space. (a) NM
(b) N+M 1
1
π
π
(c) N-M
(d)
π π
15. If p> 1 and q is defined by + = 1 and for f and g two complex valued measurable function such that fβ πΏπ π₯ , π β πΏπ π₯ , then the Holderβs inequality is (a) (c)
ππ dxβ€ π
π₯
π₯
π
ππ dx β₯ π
π π
π
π
π
(b)
π₯
ππππ₯ β€ π
π
π
π
(d)
π₯
ππππ₯ β₯ π
π
π
π
16. Let M be a subspace of a normed linear space N. The set of all cosets {x+M/ xβ π } is a normed space in the quotient form if (a) M is an open subspace of N (b) M = N (c) M is a closed subspace of N
(d) M is finite subspace os N
17. Let ( π₯1 , π₯2 , π₯3 , β¦ β¦ , π₯π ) β π
π . π₯ = ( (a) P = 100
(b) p = π π=1
18. Holderβs inequality (a)
π π=1 3
p> 1and π + π = 1
π₯π π¦π β€ [
π π=1
1
π₯π π )π does not define a norm when (c) p= 1
2 1 π π
π₯π ] [
π π=1
1 π π
π¦π ]
(d) p =
1 2
for p,q such that , 1
1
(b) p> 1and β = 1
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1
π
π
(c) p> 1and + = 0
π 1
π 1
π
π
(d) p> 1and + = 1
19. If 1β€P1
π π=1
1
π₯π π ]π
(d)
None of these
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