Modeling of failure in cement based angle ply laminates Barzin Mobasher Department of Civil and Environmental Engineering Arizona State University Tempe, Arizona, 85287-5306 The American Ceramic Society 101st Annual Meeting April 25-28, 1999 - Indianapolis, IN.

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Outline of presentation  

  

Introduction Development and mechanical properties of angle ply laminates Mechanical properties of angle ply and sandwich laminates Failure characteristics Micro-mechanical modeling  



Fracture mechanics composite materials laminate theory

Conclusions

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Toughening Due to Fiber Bridging Determination of Bend over point  



  

Modeling steps and requirements: Fiber debonding and pullout response Closing Pressure formulation for a single isolated crack Crack face stiffness Stress Intensity reduction toughening and strength of lamina enhancements

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BOP, distributed cracking, and CDS state BOP Distributed Cracking leading to Characteristic damage state Determination of Bend Over point using Fracture Mechanics approach Determination of lamina failure using composite mechanics approach

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Cracking in Tensile Specimens-1

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Cracking in Tensile Specimens-2

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Delamination and shear failure criteria are needed Shear failure mechanism in a unidirectional specimen

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Lightweight concrete sandwich laminates 25

 Pumice

concrete,  unreinforced core

Specimen 1 Specimen 2

Stress(N/mm^2)

20

Specimen 3

15

10

5

0

0

2

4

Deflection (mm)

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6

Coupled problem of matrix and interface crack growth   

Fiber Pullout Closing Pressure Formulation Toughening of Matrix

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Failure Criteria for Lamina Cracking 

Bridging effect of fibers s

m

K Ic = K I - K I

L* (x)

f x a

CODc = CODm - COD f

KI

f

ac



 =  P * (U) g(1, ) d a a 0

2 COD f = E'

a

a

  a0 a f

P * (U) K IP

Fiber debonding in the wake region

 K IF d d F

F P* (U,x)

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 g =K I (x)

FEM model for uniaxial Tension Specimen

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Toughening of the Matrix in terms of KI required for crack growth 100

E = 210 GPa f

due to applied load

E = 30 GPa m

1/2

80

 = 0.3

I

K , MPa-mm

f

 = 0.18 m

60

K = 35.66 MPa mm Ic

40

CTOD = 0.02 mm

composite

c

L = 15 mm f

20

due to fibers 0

r = 0.1 mm

FEM R-Curve Model

f

V = 5% f

20

22

24

26

Crack Length, mm

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1/2

Effect of interfacial shear strength E = 200 GPa

25

f

E = 28 GPa f

L = 20 mm r = 0.15 mm V = 5%

Crack Length, mm

24 23

f

a = 19.05 mm 0

22 21 No Fiber

20

q = 5.5 N/mm y

q = 2.5 N/mm y

0.000

0.001

0.002 0.003 COD/2, mm

0.004

0.005

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Effect of fiber volume fraction K = 35.66 MPa mm

25

1/2

Ic

CTOD = 0.012 mm c

f

24

E = 28 GPa m

L = 20 mm f

r = 0.15 mm

23

Steel Fiber

f

v = 12%

q = 2.5 N/mm y

a = 19.05 mm

22

0

21 V = 0%

20

f

Initial crack tip

V = 5% f

V = 15% f

0.000

0.001

0.002

0.003

COD/2, mm

0.004

0.005

Applied Load/Thickness, N/mm

Crack Length, mm

E = 200 GPa

f

60

v = 10% f

v = 5% f

40 K = 35.66 MPa mm

1/2

Ic

CTOD = 0.012 mm c

E = 200000 MPa

20

f

E = 28000 MPa m

q = 5.5 N/mm v = 0% f

y

L = 20 mm r = 0.15 mm

0 0.00

0.05

0.10

Deflection, mm You created this PDF from an application that is not licensed to print to novaPDF printer (http://www.novapdf.com)

0.15

0.20

Modeling of SFRC 200 due to applied load

160 E = 210 GPa f

1/2

E = 30 GPa f

120

 = 0.18 m

K = 35.66 MPa mm

1/2

Ic

CTOD = 0.02 mm

composite

80

c

L = 15 mm

I

K , MPa-mm

m

 = 0.3

f

r = 0.1 mm f

V = 5%

due to fibers

40

f

FEM R-Curve Model

0

20

30

40

Crack Length, mm You created this PDF from an application that is not licensed to print to novaPDF printer (http://www.novapdf.com)

50

Incremental Approach Piecewise linear approach:  ΔN    ΔM

   



A   B 

B  

D 

 0  Δε     Δκ   

N or M

For uniaxial loads only in a symmetric lamina (B=0) :    ΔN   A   Δε 0             

For Bending only in a symmetric lamina (B=0) :  ΔM   D   Δ       You created this PDF from an application that is not licensed to print to novaPDF printer (http://www.novapdf.com)

e or d

Computations Within a load step Compute overall stiffness Calculate the strains, stresses, curvature, and elongation

Check for the failure in the components of the lamina using th e fracture Mechanics approach. update the lamina properties

Initialize all the geometrical and historical parameters for each lamina. Then, update the stresses with imposed forces added in this increment

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Check for the failure of the entire lamina using Tsai-Wu Theory update the structure

Tsai-Wu Failure Criterion R  F11  F2  2  F111 2  F22  2 2  2F12 1 2  F66  6 2  F44  4 2  F55  5 2

If R<1 safe if R  1, failure of the lamina

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Material Property to Yield surface Parameters (in MPa)

 t1 := 50

F1 :=

 t2 := 10  c1 := 15  c2 := 15

 12 := 5  13 := 5

 23 := 8

F2 := F12 :=

-7 150 1

30 -1

225000

F11 := F22 :=

1 750 1 150

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F66 := F55 :=

1 64 1

25 1 F44 := 25

Failure Surface 7

1

1

1 1 2 2 R :=            150 1 30 2 750 1 150 2 112500 1 2

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Cross Ply Laminates 30

ply failure in 0 lamina

Stress, MPa

20

First ply failure in 90 lamina

first ply failure in 0 lamina

10 matrix cracking in 0 lamina matrix cracking in 90 lamina 0 0.000

0.004

0/90/0 0.008 Strain, mm/mm

0.012

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0.016

Flexural Prediction 40

Flexural Sress(MPa)

cracking of zero lamina

30 Theoretical Result

0/90/90/0

20 Matrix cracking in 90 ply

10

0 0.0

Matrix cracking in Zero ply

2.0 4.0 Deflection (mm)

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