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Sciencia Acta Xaveriana An International Science Journal ISSN. 0976-1152

Volume 2 No. 2 pp. 29-59 Sep 2011

The Pebbling Number of 4-star Graph A. Lourdusamy1, A. Punitha Tharani2, 1

Department of Mathematics, St. Xavier’s College, Palayamkottai, India. E-mail Address: [email protected] 2

Department of Mathematics, St. Mary’s College, Tuticorin, India. E-mail Address: [email protected] Abstract : A pebbling move on a graph G consists of taking two pebbles off one vertex and placing one pebble to an adjacent vertex. The pebbling number of a connected graph G, f(G), is the least n such that any distribution of n pebbles on G allows one pebble to be moved to any specified but arbitrary vertex by a sequence of pebbling moves. In this paper we will determine the pebbling number of 4-star graph.

1.Introduction One recent development in graph theory, suggested by Lagarias and Saks, called pebbling has been the subject of much research and substantive generalizations. It was first introduced into the literature by Chung [1], and has been developed by many others including Hulbert, who published a survey of pebbling results in [5]. Given a connected graph G, distribute k pebbles on its vertices in some configuration, C. Specifically, a configuration on a graph G is a function from V (G) to N U {0} representing an arrangement of pebbles on G. We call the total

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The Pebbling Number of 4-star Graph

number of pebbles, k, the size of the configuration. A pebbling move is defined as the simultaneous removal of two pebbles from some vertex and addition of one pebble on an adjacent vertex. Chung [1] defined thepebbling number of a connected graph, which we denote f(G), as follows : f(G) is the minimum number of pebbles such that from any configuration of f(G) pebbles on the vertices of G, any designated vertex can receive one pebble after a finite number of pebbling moves. There are many known results in [5] regarding f(G). If one pebble is placed at each other vertex than the target vertex, v, then no pebble can be moved to v. Also, if w is at distance of d from v and 2d -1 pebbles are placed at w, then no pebble can be moved to v. Thus, we have f(G) > max {n(G), 2diam(G)}, where n(G) denotes the number of vertices in G. and diam(G) denotes the diameter of G. Graphs G that satisfy f(G) = n(G) are calledClass 0 graphs and graphs G that satisfy f(G) = n(G)+1 are calledClass 1 graphs[2]. Class 0 graphs include the complete graph Kn, n-cube Qn [1,9], complete bipartite graphs Km,n [10], the product graph C5 × C5 [4] and many others. We find an elegant characterization about Class 1 graphs in [5]. The path Pn [10], n-cube Qn [1,9], even cycle [9,10] are examples of graphs G that satisfy f(G) = 2diam(G), whereas the odd cycle [9,10] is an example of a graph not satisfying either lower bounds. Another interesting result is the pebbling number of a tree, which is beautifully worked out in [8]. Hulbert [5] has written an excellent survey article on graph pebbling. Note that pebbling number does not exist for a disconnected graph. Throughout this paper, G will denote a simple connected graph. We now proceed to find the pebbling number of the 4-star graph. 2. n-star graph A formal group theoretic model called the Cayley Graph has been introduced in the literature for designing and analyzing symmetric interconnection networks. The two important members of this class are the star graph and the hypercube. An n-dimensional hypercube or n-cube, consists of 2n vertices labeled by (0,1)-tuples of length n. Two vertices are adjacent if their labels are different in exactly one entry. Chung [1] proved that the n-cube satisfies f(Qn) = 2n. This paper explores the pebbling number of 4-star graph. We were particularly intrigued by n-star graph since it has fewer interconnecting edges. Definition : 2.1 [6] An n-star graph, denoted by Sn, is an undirected graph consisting of n! vertices labeled with the n! permutations on n-symbols (we use symbols 1,2,…, n) and such

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that there is an edge between any two vertices if and only if, their labels differ only in the first (left most) and in any (one) other position. Recursive Construction 2.2 [6]. Sn can be recursively constructed from n copies of Sn-1 as follows : We first construct n copies, G1,G2, …., Gn, of Sn-1 and label each Gi using all symbols 1 through n except symbol i ; then for each label in Gi we add symbol i as the last symbol (rightmost) in that label (or in any other fixed position); finally, we connect by an edge every pair of vertices u and v such that label of v is obtained from that of u by exchanging the first and last symbols of u. Partitioning 2.3 [6] The n-star can be partitioned in n-1 different ways into n copies of (n-1) stars. The different ways correspond to different symbol positions in the labels. For each symbol position i other than the first position (left most position) we can partition Sn into n copies of (n-1)-star denoted 1i, 2i, … , ni. Each ki contains all the vertices of Sn with symbol k in the i-th position of their labels. If however we try to partition along the first position, we obtain n collections of (n-1) ! isolated vertices, Figure 2.1.1 illustrates the partitioning of a 4star into four 3-stars (each 3-star is an hexagon) along the fourth position (rightmost). The four 3-stars are denoted 14, 24, 34 and 44

Figure 2.1.1. : The 4-star viewed as four interconnected 3 -stars

The Pebbling Number of 4-star Graph

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Theorem 2.4 . The pebbling number of 3-star is f(S3) = 8. Proof. Clearly 3-star is the cycle with six vertices i.e. C6. Therefore f(S3) = 8 [7]. Theorem 2.5 [7]. The t-pebbling number of the cycle C2k is ft (C2k) = 2kt. Definition 2.6. We say that two vertices of S3 are opposite to each other if they are at a distance of three from each other. Clearly there are three pairs of opposite vertices in S3. We include some facts here, most of which are quite straightforward and can be easily verified. Let n be the number of pebbles distributed on the vertices of S3 and let (u, v) be a pair of opposite vertices in S3. FACTS 1.

If n = 7 then either u or v can be 2-pebbled

2.

If n = 10 and if u cannot be 2-pebbled then v be can be 4-pebbled.

3.

If n = 11 and if u cannot be 2-pebbled then v can be 8-pebbled.

4.

If n = 12 and if u cannot be 2-pebbled then v can be 10-pebbled.

5.

If n = 13 then either u or v can be 4-pebbled.

6.

If n = 14 and if u cannot be 2-pebbled then v can be 12-pebbled.

7.

If n = 15 and if u cannot be 4-pebbled then v can be 6-pebbled.

8.

If n = 18 and if u cannot be 4-peebled then v can be 8-pebbled.

9.

If n = 8 and if u cannot be 2-pebbled and v can be 2-pebbled but cannot be 4-pebbled, then either u1 can be 2-pebbled or v1 can be 4-pebbled where (u1, v1) is a pair of oppo site vertices such that u1 is adjacent to u and v1 is adjacent to v.

Next, we find the pebbling number of S4. 3.The pebbling number of S4 For our convenience, we represent S4 as in Figure 3.1.1.

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Figure 3.1.1 : S 4

In Figure 3.1.1 the four copies of S3 are represented by Gi, i = 1,2,3,4 and the vertices of S4 are represented by xij, i = 1,2,3,4 ; j = 1,2,….,6. Definition 3.1 [3]. Given a pebbling of G, a transmitting subgraph of G is a path x0, x1,…, xk such that there are at least two pebbles on x0 and at least one pebble on each of the other vertices in the path except possibly xk. In this case, we can transmit a pebble from x0 to xk. Theorem 3.2. The pebbling number of S4 is f (S4) = 4 ! + 2. Proof : Let the target vertex be x31 of G3. First, we prove f (S4) > 26. We consider the distribution of twenty five pebbles on the vertices of S4 as follows: We place fifteen pebbles on x44 and one pebble each on every vertex of G2 except x16 and one pebble each on every vertex of G2 other than x23 and we place zero pebbles on the rest of the vertices of S4. In this distribution we cannot move a pebble to x31.

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,

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{x35, x36, x31} .

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Step 2 . Let

3

= 1.

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BIBLIOGRAPHY 1. F.R.K. Chung, Pebbling in hypercubes, SIAM J. Disc. Math.2 (4) (1989) 467-472. 2. T.A. Clarke, R.A. Hochberg and G.H. Hurlbert, Pebbling in diameter two graphs and products of paths, J. Graph Jh. 25 (1997), 119-128. 3. D.S. Herscovici, Graham’s pebbling conjecture on products of cycles, J Graph Theory, 42, No.2, (2003), 141-154.

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4. D.S. Herscovici and A.W. Higgins, The Pebbling Number of C5 × C5, Disc. Math., 187 (1998), No. 1–3, 123–135. 5. G. Hurlbert, Recent progress in graph pebbling, graph Theory Notes of New York, XLIX (2005), 25 – 34. 6. Khaled Day, Anand Tripathi, A comparative study of Topological Properties of Hypercubes and Star Graphs (preprint). 7. A. Lourdusamy and S.Somasundaram, The t-pebbling number of graphs, South East Asian Bulletin of Mathematics 30 (2006), 907-914. 8. D. Moews, Pebbling Graphs, J. Combin, Theory Series B,55 (1992), 244-252. 9. L. Pachter, H.S. Snevily and B. Vopxman, On pebbling graphs, Congressus Numerantium 107 (1995), 65 – 80. 10. C. Xavier and A. Lourdusamy, Pebbling numbers in Graphs, Pure Appl.Math.Sci., 43 (1996), No. 1-2, 73-79.

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