SET - I

SUMMATIVE ASSESSMENT - II - 2016 - 2017 MATHEMATICS (English Medium) Class : VII

1.

(Max. Marks : 80)

PART - A SECTION - I Sum of an acute angles in a right angles = 900 Ratio of an acute angles = 4:5 Sum of their ratios = 9

(1m)

4 9 5 9

(1m)

First angle

0 = 90

0 Second angle = 90

2.

4x2=8

400 (½ m)

500

(½ m)

4 ( 2) 5 4 ( 2) 5 8 5 4 ( 10) 40

(1m)

40

This is Associative property under multiplication of integers 3.

4.

(1m)

1 meter = 100cm 2704 meters = 27.4x100cm = 2740.0cm 27.4 meters = 2740cm

(1m) (1m)

(i) Opposite sides of a Black Board (ii) Ironbars of window Note:- Any two examples like above

(1m) (1m)

SECTION - II 5.

Principle = P = Rs. 6500 Time = T = 4 years Rate of interest = R = 9% Interest =

I=

PTR 100

I=

6500x4x9 100

I = 65x36 I = Rs.2340 Amount = A = P + I Amount = A = Rs.6500+2340 Amount = A = Rs.8840

5x4 = 20

(1/2 m)

(1/2m) (1m)

06.

Sum of the observations Number of observations

Average

(1m)

246 238 212 248 256 216 (2m) 6

Average

1416 6

Average = 236 (attendance of the school) 07.

(1m)

S

P

m 4c

5cm m 4c

O

5cm

R

Q

In POQ and ROS PO = OR = 5cm(side) POQ ROS (Angle) (Vertically opposite angles) QO = OS = 4cm (side) (2m) By S.A.S Property POQ ROS (2m) 08.

09.

According to sides (i) Equilateral triangle (ii) Isosceles triangle (iii) Scalane triangle According to angles: (i) Acute angle triangle (ii) Right angle triangle (iii) Obtuse angle triangle Cost of 5kgs tomatoes = 65.00 Cost of 1kg tomatoes = 65/5 = 13 Cost of 8kgs tomatoes = 13x8 Cost of 8kgs tomatoes = 104 Ramana will pay for 8kgs tomatoes = 104

SECTION - III 10-A Let the breadth of the Rectangle = x m Twide the breadth = 2x m Its length = (2x-8) m Perimeter of the rectangle = 2(l+b) Perimeter of the Rectangle = 2(2x-8+x) m = 2(3x-8) m = (6x-16) m By problem, the perimeter of the rectangle = 56 m 6x-16 = 56

(2m)

(2m) (2m)

(2m)

(1m) (1m)

(2m)

6x = 56+16 x= 72/6 x = 12 Breadth of the rectangle = x 12 m Length of the rectangle = 2x-8 = 2x12-8 Length of the rectangle = 24-8=16m 10-B (i)

5

1 2 4 3 3

=

28 22 4 5 5

=

50 5

= 10 (ii)

(iii)

(iv)

(2m)

3

1 2 2 3 3

=

10 3

=

10 8 3

=

7 3

4

5 2 3 7 3

8 3

2

1 3

=

33 11 7 3

=

3311 11 7 3

=

121 2 17 7 7

5

6 3 2 8 4

=

(2m)

(2m)

(2m)

46 11 8 4

46 23 4 = 8 11 2

=

23 11

2

1 11

11-A S.P of each cycle = `.3000 Grain% on first cycle - 20% Loss % on second cyle = 20%

(2m)

(2m)

For first cycle If C.P is 100, then profit is 20 then SP = 120 If S.P is `.120 then C.P = 100 If S.P is `.1 then C.P =

100 120

If S.P is `.3000 then C.P =

100 3000 120

= `.2500 For second cycle If C.P is `.100 then the loss is 20 then S.P = 80 If S.P is `.80 then C.P = 100 If S.P is `.1 then CP =

100 80

If SP is `.3000 then CP =

100 3000 80

`.3750 Total C.P = `.2500+`.3750 = `.6250 Total S.P = `.3000+`.3750 = `.6000 Loss = C.P - S.P Loss = 6250-6000 Loss = `.250 Loss% =

loss 100 CP

Loss% =

250 100 4% 6250

11-B Ratio of Engineers and doctors = 3:4 (i) No. of Engineers =18 Let, No.of Doctors = x 3:4 = 18:x Product of the Means = Product of extremities 3 x = 4 18 x

=

= 24 Number of Engineers x = 24 No. of doctors = 56 Let, no. of doctors = y 3:4 = y:56 4 y = 3 56 y y

(2m) (1m)

(1m)

(1m)

(2m)

4 186 3

x

(ii)

(2m)

(2m)

(2m)

3 5614 = 4

= 42 Number of Doctors y = 42

(2m)

: The sum of the angles of a triangle is 1800

To prone

:

A

B

(

: A triangle ABC

5 1 4

C 180 0

B

(

Given

A

P

2

Q

(

12-A Statement

3

C

Construction : Though ‘A’ draw a line PQ parallel to BC Proof: From the figure, 2 5 (alternate interior angles) 3 4 (alternate interior angles) 2 3 5 4 (adding(1) and (2) Adding 1 on both sides 1 2 3 1 5 4 0 (Angles forming a straight line) 1 2 3 180 A

B

C 1800

4cm

4cm

The sum of the angles of a triangle is 1800 R C 12-B (i)

3cm

1200 B P

(

(

1200 A

3cm

Q

In ABC and PQR AB = PQ = 3cm (side) B Q 120 0 (angle) BC = QR = 4cm (side) By S.A.S Congruency criterion ABC

(2m)

(2m)

PQR A (

(ii)

B

D

C

In ABD and ACD AB = AC (given) BAD CAD (given) AD = AD (common) By S.A.S congruency criterion ABD ACD

(2m) (2m) [ P.T.O ]

Class

No.of Students

VI VII VIII IX X

(ii)

110

84 72 96 105 98

Scale: On x-axis, 1cm = 1class On y-axis, 1cm = 10units

100

NO. OF STUDENTS

13-A (i)

(1m)

90 80 70 60 50 40 30 20 10 vi

vii viii

ix

x

CLASS . For each correct rectangle one mark (5x1 = 5m) . For Axis and marking numbers and classes (2m)

Time Spent for

Time Spent

Angle of sector

Sleep

8hrs

8 3600 24

120 0

School

6hrs

6 360 0 24

90 0

Play

2hrs

2 360 0 24

30 0

Others

8hrs

8 3600 24

120 0

Total

24hrs

3600

For preparation of table (4m)

for drawn diagram

(4m) Sleep 900 300

(

1200

(

School

(

(ii)

PIE Diagram

Pla y

13-B (i)

1200

Others

PART - B SECTION - IV 14 (C)

15(B)

16(D)

17(B)

18(A)

19(C)

20(B)

21(A)

22(C)

23(D)

24(B)

25(C)

26(C)

27(A)

28(B)

29(C)

30(C)

31(C)

32(A)

33(A)