RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
Medical - UG Time : 3 Hrs. Marks : 720
AIPMT : 2015 CODE - F
Date : 03-05-2015
CHEMISTRY Q.1
Electrophilic addition takes place via more stable carbo cation. HBr C6 H 5 CH CH CH 3
C6 H 5 CH CH 2 CH 3 Br
Q.2
WN2
PVM 700 40 28 RT 760 1000 300 0.0821
0.042 g
% of Nitrogen
0.042 100 0.25
16.573%
Q.3
Salt
K sp
Solubility
Ag 2CrO4
1.1 1012
S
AgCl
1.8 1010
S K sp 1.34 10 5
AbBr
5 10 13
S K sp 0.71 10 6
AgI
8.3 1017
S K sp 0.9 10 8
3
K sp 4
0.65 104
solubility of Ag 2CrO4 is highest it will precipitate last.
Q.4
Bithional functions as antiseptic.
Q.5
Metal nitrates are usualy not found as nitrates in their ores because they are highly soluble in water.
Q.6
Order of bond order O2 1s 2 *1s 2 2 s 2 * 2 s 2 2 p z2 2 p x2 2 p 2y SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
*
2 p x2 * 2 p1y
no.of electronsin BMO-no of electrons in ABMo 2
Bond order =
10 7 3 1.5 2 2
O2 1s 2 *1s 2 2 s 2 * 2s 2 2 p z2 2 p x2 2 p 2y
*
2 p1x * 2 p 0y
Bond order =
10 5 5 2.5 2 2
O22 1s 2 *1s 2 2 s 2 * 2 s 2 2 pz2 2 p x2 2 p 2y
*
2 px0 * 2 p y0
Bond order
10 4 6 3 2 2
Order ofbond order : O22 O2 O2 Q.7
Ar, K & Ca belong to the same period. Being Nobel gas radii of Ar is heighest. We also know for isoelectronic species size decreases with increase in positive charge of the ion.
Q.8
By Arrhenius equation k Ae Ea / RT
ln k ln A
Ea RT
on plotting ln k vs
1 T
lnA lnk
slope = -Ea/R
1/T By knowing slope activation energy can be determined.
Q.9 S
Cl O O
O
O
O O
22
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
O
O N
O=C O
O
O
2 ClO3 & SO3 are isoelectronic and are pyramidal
Q.10
For the Idoform test there must be a terminal CH 3 group, similarly for the Tollen’s test CHO group is required. Hence, as per question the structure would be O CH 3 CH 2 C CH 2 CH 3
Q.11 Order of bond order O2 1s 2 *1s 2 2 s 2 * 2 s 2 2 pz2 2 px2 2 p 2y
*
2 p x2 * 2 p1y
Bond order
no.of electrons in BMO-no of electrons ABMo 2
10 7 3 1.5 2 2
O2 1s 2 *1s 2 2 s 2 * 2s 2 2 p z2 2 p x2 2 p 2y
*
2 p1x * 2 p 0y
Bond order =
10 5 5 2.5 2 2
O2 1s 2 *1s 2 2s 2 * 2s 2 2 p z2 2 p x2 2 p 2y
*
2 p1x * 2 p1y
Bond order
10 6 4 2 2 2
Order of bond order : O2 O2 O2 H
–
Q.12
+
O + CH 3 Li + –
Li O CH 4
Q.13
Under weakly acidic conditions Nitro benzene on electrolytic reduction gives aniline but under strongly acetic condition we get p - aminophenol. SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
NO2
NHOH -
4e + 4H
NH2 -
2e + 2H weakly +
H (strongly) NH2
OH
Q.14 Magnetic moment =
n n 2 B.M.
where n = number of unpaired electrons 2.84 n n 2 B.M.
2.84
2
n n 2
8 n 2 2n On solving n = 2
only Ni 2 Ar 3d 8 4s 0 has 2 unpaired electrons. Q.15
Edge length a = 361 pm, effective number in unit cell = 4 (given)
It is a FCC structure face diagonal = 4r
2 a 4r
r
2 361 127 pm 4
Q.16 Allylic and benzylic halides show high reactivity towards SN1 reaction.
H + + H 3C C CH CH 2 Cl CH 3 CH CH CH 2 H 3C CH CH CH 2 Cl Q.17 Al2 SO4 3 2 Al 3 3SO42 Volume of Vant Hoff’s factor i = 5
K 4 Fe CN 6 4 K Fe CN 6
4
i 5
K 2 SO4 2 K SO42 i 3
44
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
K 3 Fe CN 6 3K Fe CN 6
3
i 4
Al NO3 3 Al 3 3 NO3 i 4 Q.18 NaHSO3 is used as food preservative as it produces SO2 on decomposition which checks the oxidation of food. There are 4 bond’s, hence total -electrons are 8. Q.20 Down the group solubility of sulphate of alkaline earth metal decreases because of increase in lattice enrergy gradually. Q.19
NO3
NO2
NO2
NO2
Hybridisation
sp 2
sp 2
sp 2
sp (linear)
Bond angle
1200
1200 1200 1800
Q.21 Species
so NO2 has maximum bond angle. Q.22 R P
K
P eq R eq
1.6 1012
P eq R eq
P eq R eq
so mostly the products will be present in the equilibrium mixture. Q.23 Electronic configuration of Fe 2 is Ar 3d 6 4s 0 Number of ‘d’ electrons = 6
Ne – 1s 2 2 s 2 2 p 6 6 p electrons Mg – 1s 2 2s 2 2 p 6 3s 2 6 s electrons Cl – 1s 2 2 s 2 2 p 6 3s 2 3 p 5 11 p electrons
Ar 3d 6 4s 2 6 d electrons Q.24 CH 3 CH 3 C Cl CH 3
CH 3 CH 3 C Cl
(more stable due to 9 hyper conjugation structures & 3 +I
CH 3
groups) Q.25 In Fuel cell energy of combustion is converted into electrical energy. Q.26
There is no H in the structure I and II SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
Q.27
Its nucleophilic substitution reaction. It follows SN2 mechanism. 3
Q.28 1) Co NH 3 6 Cl3 Co NH 3 6 3Cl 2) Co NH 3 3 Cl3 Co NH 3 3 Cl3 1
3) Co NH 3 4 Cl2 Cl Co NH 3 4 Cl2 Cl 2
4) Co NH 3 5 Cl Cl2 Co NH 3 5 Cl 2Cl so Co NH 3 3 Cl3 does not ionize so doesn’t give test for chloride ions. Q.29 Let the masses of H2 and O2 be x g and 4x g
nH 2 x/2 4 Molar ratio n 4 x / 32 1 O2 (O )
Q.30
1.
( III )
Fe H 2O Fe2O3 H 2 Steam (O )
( III )
2.
Moisture Fe O2 Fe2O3. x H 2O
3.
CuSO4 Fe FeSO4 Cu
4.
Fe 5 CO Fe CO 5
(O )
(O )
( II )
(O )
During formation of Fe CO 5 oxidation number of Fe doesn’t change. Q.31 due to lanthanoid contraction Zr (Zirconium)and Hf (Hafnium) have almost same atomic radii. Q.32 We know G G 0 2.303RT log Q but at equilibrium
G 0 , Q k G 0 2.303RT log K Q.33 Angular momentum of electron in ‘d’ orbital l l 1
h 2
2 2 1
h 2
6 Q.34 Molality of solution of x = molality of solution of y = 0.2 mol/kg by elevation in boiling point relation Tb iK b m
66
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
or Tb i Tb of solution of ‘x’ > Tb of solution of ‘y’ ‘i’ of solution of x > i of solution of ‘y’ solute ‘x’ undergoing dissociation
Q.35 Sodium pump used for conduction of signals from brain to organ and vice versa. In which Na+ and K+ are exchanged. Q.36
The enthalpy of hydrogenation is inversely proportional to stability of alkene
Q.37
III II I The enolic form of ethyl acetoacetate has 16 single bonds (= 16 sigma bonds) and 2 double bonds ( equal to 2 sigma and 2 pi bonds)
Q.38 It is an alternating polyamide copolymer of glycine H 2 N CH 2 COOH and amino caproic acid H 2 N CH 2 5 COOH and is biodegradable
O
O
O
H 2 N CH 2 C OH HN CH 2 5 COOH H 2 N CH 2 C NH CH 2 5 C
n
H Nylon -2-nylon-6 Q.39 CH 2 CN 2 H N C C C N
6 4
H O
4 1
O=C O-H O Xe O
4 4 O
O
N C C N Q.40 Co CN 6
3 4
3
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Chemistry
Co3 Ar 3d 6 eg orbital t2g orbital
CN– is using strong field ligand so zero unpaired electrons are present. Q.41 For ideal solution Pobs PRaoult
P 0
H mix 0
S mix ve
Vmix 0 Q.42 Tyndall effect is the scattering of light by sol particles. which can’t be affected by charge on them. Q.43 In keto - enol tautomerism the keto form should have hydrogen (I & II) H3C
H3C
CH3
CH3
I)
OH
O
CH3 CH3
II)
O
CH3 CH3 OH
In IIIrd ketone
H H III)
CH3 CH3 O
CH3 CH3 OH
here H participates in tautomerism Q.44 for ‘n’ order reaction t1/ 2 C01 n
where C0 is initial concentration of reactant. for first order reaction n = 1, half life is independent of intial concentration Q.45 CH 3 O3 CH 3 Zn , H 2O
OHC CH 2
CH 3
CH 3
C
C
H 88
CH 2
O
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / BIOLOGY
BIOLOGY Q.46 Trichinella spiralis is viviparous roundworm. Q.47 In cryopreservation, genes/gene pools are stored at -196oC under liquid nitrogen which is an advance ex-situ conservation of bio diversity. Q.48 Agaricus is saprophytic fungus (Not parasitic) Phytophthora belong to Phycomycetes Mucor belong to Phycomycetes. Q.49 Zinc, Cu, Manganese, selenium & boron are micromolecules. Q.50 Polyethylene glycol & sodium nitrate increases fusion of protoplasts & hence can be used as fusogen in somatic hybridization or protoplast fusion. Q.51 Prolactin has no role in parturition, it helps in lactation process, (lactogenic hormone), development of mammary glands (mammotropin) & maintainance of corpus luteum (leutotropin). Q.52 Bryophytes and pteridophytes have an independant gametophyte. In spermatophytes gametophyte is reduced and dependant on sporophyte Q.53 Encephalitis is not a sexually transmitted disease. Q.54 In Opuntia leaves become modified into spines to reduce the rate of transpiration. Q.55 Levitt (1954) proposed Active Potassium Transport theory in which stomatal movements (opening & closing) is because of influx & efflux of K+. Q.56 Homo habilis has the smallest brain capacity of 650-800cc. Homo erectus has capacity of 900 cc Homo sapiens has capacity of 1350 cc Homo Neaderthalis has capacity of 1400 cc. Q.57 High value of BOD water is highly polluted. Because of presence of high amount of organic matter number of organisams increases which increase demand for oxygen. Q.58 During muscle contraction actin filament slides over myosin filament, where none of them shorten in length. Q.59 Vestibular apparatus (otolith organs ie. utricle & sacculus & semicircular canal) help in maintaining body posture, equilibrium & balancing the body. Thus it will help gymnast to balance its body upside down even in total darkness. Woman B
Q.60 Man A [ I AI A / I AI O ]
[ I BI B / I I O ]
Progeny I A I O I B I O
I AI O I O I O
A
B
AB
O
Q.61 Sigmoid curve shows 3 major phases like initial lag phase, exponential log phase & steady or stationary phase Q.62 The United Nation Climate Change Conference was held in Durban South Africa from 28 November to 11 December 2011 to establish a new treaty to limit carbon emissions. SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
9 99
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / BIOLOGY
Q.63 A technique of micropropagation is somatic embryogenesis (which forms clones Of ex-plant in the form of embryo) Q.64 Seven pairs of contrasting characters in pea plants , were studied by mendel is his experiments. Q.65 Floral formula is of Solanaceae family hence is of Petunia, Brassica is from Brassicacene family whereas Allium belong to Liliaceac & Sesbania belong to Fabaceae Q.66 Glyphosate is a herbicide and crops are engineered for glyphosate are resistant/tolerant to herbicides (By which main plants can be kept safe while using glyphosate as weedicide in fields). Q.67 Brunner’s glands are present in the submucosa of duodenum and secrete mucous. Q.68 Chargaff’s rule A = T, G = C
C = 17% So G = 17%
A+G =1 T+C
A + G + C + T = 100 A + 17 + 17 + T = 100
Since A = y
A + T = 100 – 34 So A = 33%, T = 33% = 66
Q.69 The Bt-toxin is an inactive protoxin which is activated due to alkaline pH in the insect gut. Q.70 Cytochromes which are Iron containing electron acceptors are present on cristae of mitochondria, helpful in ETS. Q.71 Selaginella is heterosporous producing micro & megaspores. Coralloid roots in Cycas have Anabaena . Q.72 A fluid connective tissue, constituents of which are blood is plasma plus blood cells ie. RBC, WBC & platelets. (ie. plasma plus blood corpuscles) (55% plasma & 45% corpuscles) Q.73 Translocation is reciprocol of chromosomal segment between non-homologous chromosome. Movement of gene from one linkage group to another is called crossing over. Inversion : - When a piece of chromosome is removal & rejoined in reverse order, its known as inversion. Duplication : In this mutation deleted chromosomal segment is attached to its normal homologus chromosome. Here a gene or many genes are repeated twice or more times in the same chromosome. Q.74 Genetic engineering approval committee regulates GM research & safety of introducing GM organisms for public services. Q.75 Silent spring Pesticide pollution. The book documented the detrimental effects on the environment-particularly on birds of the indiscriminate use of pesticides. Q.76 Gastric juice of infants contains Pepsinogen, Lipase, rennin Q.77 Due to depletion of stratospheric ozone, there is increased risk of skin cancer, damage to cornea, conjunctiva etc. as well as reduces our immune system. Q.78 Capacitation refers to process occurring in uterus in which changes occur in sperms which helps to enable them to fertilize - ovum. These include Dilution of inhibiting factors in semen. Removal of cholesterol layer (galea) on acrosome. Increase in permeability of membrane to Ca 2 110 0
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / BIOLOGY
Q.79 Tropical rain forest shows striated vegetation because of which most animals are tree dwellers Q.80 Anabaena is prokaryotic blue green alga, showing no true nucleus (nucleoid). Q.81 Glenoid canty of scapula articulate with head of humerus. Q.82 Transmission tissue is characteristic feature of solid style which helps in directing pollen tube. Q.83 Ribosomes 60 to 65% rRNA 30 to 40% Protein Q.84 Regulation of lac operon by repressor is referred to as negative regulation. Q.85 Renin does not favour for the formation of large quantities of dilute urine as it activates RAAS ( Renin angiotensin activating system) so it causes reabsorption of sodium which leads to formation of concentrated urine. Q.86 Because of greater elongation of cells on shaded side, it makes the plant bend towards light source. Q.87 Rough endoplasmic reticulum produces nuclear envelope in telophase. Q.88 Option (3) suggest correct match. Q.89 Keel is a petal in vexillary aestivation which is a characteristic of family Fabacae Tomato-Solanaceae.Tulip and Aloe-Lilliacea. Q.90 Guava & Cucumber - epigynous china rose - Hypogynous Q.91 Epinephrine / Adrenaline is a hormone - a chemical signal that has both endocrine and neural roles. Q.92 Tissue culture, seed bank & cryopreservation are ex- situ conservation Sacred groves, National park, wildlife sanctuary is in-situ conservation. Q.93 HIV that causes AIDS, first starts destroying helper T - cells. Q.94 Hysteroctomy is removal of uterus (Hystera means uterus) Q.95 Removal of proximal convoluted tubule from the nephron results in lack of reabsorption of high threshhold substances from renal tubules, and obligatory reabsorption of water is also affected leading to more diluted urine. Q.96 Monocot stem has open and scattered vascular bundles. Roots in monocots have radial vascular bundles. Q.97 Exoskeleton is responsible for diversification of insects on land. Q.98 Spermatogonia i.e. sperm mother cell is diploid whereas spermatids, first polar body and second polar body are Haploid. Q.99 Flattened membranous sacs Thylakoids Stack of thylakoids Grana Q.100 The chromosomes in which centromere is situated close to one end are Acrocentric, if it is at the centre - metacentric, near to the centre - sub - meta centric, at one end - Telocentric Q.101 In a ring girdled plant, since phloem is removed, translocation of food does not take towards roots, so root dies first. Q.102 Horizontal distribution of different species occupying different levels in a biotic community is known as zonation. Q.103 Multiple alleles are present on the same locus of the chromosome Q.104 The mass of living material at a trophic level at a particular time is standing crop. The inorganic substances present at a trophic level at a particular time is called as standing state SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
11 1 1 11
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / BIOLOGY
Q.105 Platypus is an egg laying mammal. Q.106 The rate of production of organic matter during photosynthesis is gross primary productivity. Q.107 Erythropoiesis starts in liver in foetus. Q.108 Recombination (crossing over) is the most common mechanism of genetic variation in the population of a sexually reproducing organism Q.109 Blood pressure in the mammalian aorta is maximum during systole of the left ventricle, because blood is pumped into aorta under high pressure. Q.110 Rise in CO2 concentration stimulates chemoreceptors present in aorta and carotid artery which stimulates respiratory centre. Q.111 Since cambium is absent, Vascular bundles are closed and secondary growth is not seen. Q.112 Sprirogyra shows morphological isogamy, physiological anisogamy where male gamete is motile but not having flagella Polysiphonia belong to Rhodophyte which is characterised by non-motile male gametes (non-flagellated) Q.113 In Geitonogamy pollen grains are transferred between two different flowers on the same plant. Eg Maize. Q.114 Runners - in Cynadon Offsets - in Eicchornia & Pistia Bulbils - in Dioscorea Q.115 Polysomes are Polyribosomes, attached to mRNA. Q.116 After S phase, amount of DNA gets doubled but number of chromosomes remain same Chromosome number Amount of DNA
Ga mete (n) Single
Cell (after S phase) (2n) Four times
Q.117 Alleles or Allelomorphs are the two (or more) alternative forms of a gene (factors), controlling same characters occuping identical loci (positions) or homologous chromosomes these terms were coined by Bateson. Q.118 Rough ER - Production of proteins. Whereas smooth ER is the site for synthesis of lipids & glycogen. Q.119 Arthroidal membrane joins terga , sterna and pleura of cockroach body. Q.120 In aves skin is non glandular, in mammals pinnae is absent in whale, cyclostamata paired appendages are absent. Q.121 The competitive inhibitor increases the Km of the enzyme for the substrate. Q.122 Language comprehension is the function of wernicke’s area of parietal lobe of cerebrum. Q.123 Honey is made by bees by nectar (regurgitation & evaporation). Q.124 Active form of Entamoeba histolytica feeds upon erythrocytes , mucosa and submucos of colon. Q.125 Chikungunga virus is transmitted through aedes aegypti mosquito and does not get transmitted through semen. Human immunodeficiency virus, hepatitis B virus & Ebola virus are sexually transmitted disease, thus are transmitted through semen. Q.126 A population will not exist in Hardy - weinberg equilibrium if individuals mate selectively as mutation , nonrandom mating and genetic driff affects equilibrium. 112 2
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / BIOLOGY
Q.127 Methanogens in cow & buffalo guts are helpful for partial digestion of cellulose (which is a major constituent of grass) Q.128 The hilum is a scar on the seed where funicle was attached. In many of the seeds like mungbean, pigeon pea it is very district. Q.129 Newly cooled lava, Bare rock & newly created pond Primary succession. Q.130 Mannitol is stored food in Phaeophyceae (Brown Algae) Rhodophyceae members store food in the form of Floridean starch. Q.131 Because of more success for food, population of B shows increase in no. of individuals Q.132 Vaccines for the following diseases are prepared with following :(a) Tuberculosis - harmones (attenuated) bacteria - mycobacterium Tuberculae (b) Whooping cough - killed bacteria - bordetella partusis bacteria (c) Diphtheria - Inactivated toxin (d) Polio - Harmless virus. Q.133 Nectar & pollen are floral rewards to the animal pollinators which are used by animals like bees as food. Q.134 Formation of abnormal ova i.e., 22 + XX in the mother will lead to birth of human baby with ‘XXX’ genotype. Q.135 Transpiration cause water to rise in plants by pulling through xylem components Root pressure causes water to rise in plants by pushing water in xylem elements
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR |
13 SION| THANE| LOKPURAM(THANE) | D1 OM 3BIVLI | KALYAN| PANVEL| KAMOTHE| NERUL| SANPADA| KHARGHAR| 13
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
PHYSICS r
136.
X
B i
e T
i
e e 2 n e ne 2 2 / 2
B
137.
e i
0i 0 ne 2R 2R
U nCv dT 5R n TB TA 2
5nR PBVB PAVA 2 nR nR
5/ 2 PBVB PAVA 5 / 2 2 103 5 103 4 5 / 2 8 10 3
20kJ 138.
y1 a sin t y2 b sin t / 2 y R y1 y2 a 2 b 2 sin t SHM with complitude (4)
139.
a
d d dv d dt dx dt dx d 2 n x 2 n 1 dx a 2n x 2 n 1 x 2 n
a 2 n 2 x 4 n 1 140.
Radius of the nucleus R = R0 A 1/3 114 4
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics 1/ 3
RAl A1 RTe A2 3
1/ 3
27 125
1 3
RAl 3 3/ 5 RTe 53 RTe
5 RAl 3
d 1 mm 1 103 m
141.
D 1m
500 109 m
a width of central maxima = width of 10 maxima
2 a
s
2 D 10 a d a
2d 10 D
a
2 10 3 10 1
a 2 104 m a 0.2 mm
142.
a
sin
2D/a
a
y D a y
D a
2 D a The area cross section of conductor is non uniform so current density will be different but the numbers of flow of electron will be same so current will be constant. Wein’s Displacement Law
width of centeral maxima is 143. 144.
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
15 1 5 15
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
mT Constant P violet max m Q Red max m R Green max m
r g v Tr Tg Tv TP TR TQ
145.
L=4 , 800
1cm 1mv 100cm 100mv 400cm 400mv 0.4V V 0.4 8 R
2 8 8 R
16 160 40 0.4 4
R = 32 146.
Energy of electron in He 3 orbit = 13.6 E3 13.6 13.6
rd
Z2 eV n2
4 eV 9 4 1.6 1019 J 9
In Bohr’s model : E3 K .E3 9.7 10 19 J
147.
BI
1 me 2 2
2 9.7 1019 1.46 106 m / sec 31 9.1 10
0 i (k ) 4 R BIII
0 i ( k ) 4 R
BII
0 i (i ) 4R
B BI BII BIII 116 6
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
B
0 i ( 2k i ) 4 R
B
148.
0i (2k i ) 4 R
h p
p h
like yx c 3 Ahyperbola C1=C C2 q'=q
149.
disconnected
V
q CV V q / c
C2 CK q2 U1 2c q2 2CK
U2
U
q2 1 1 2C k
1 1 U CV 2 1 2 k
C2 CK q CK
V '
V K Closed organ pipe V'
150.
V 4l Open organ pipe nc
n0
V 2l '
IInd overtone of open organ pipe SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
17 1 7 17
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
n 3n0 3V 2l
n
nc n V 3V 4l 2l l 6l l 6 20 l 120 cm
151.
A sin 2 A sin 2 A sin A 2 cot 2 A sin 2 A A cos sin 2 2 A A sin sin 2 2 A A sin sin 2 2 2 2
152.
153.
A 0 0 1 1
T2
B 0 1 0 1
Y1 1 1 0 0
Y2 1 0 1 0
Y 0 0 0 1
2
W 1 low temp
T1 118 8
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
Q1 w Q2
1
T1 T2
1 T 1 1 10 T2
T1 1 9 1 T2 10 10 Q2 T2 Q1 T1 Q1 w T2 Q1 T1 Q1 10 10 Q1 9
9Q1 90 10Q1 90 Q1
154.
hc hv eV0 ______(1) hc e V0 ________(2) 2 hc 2 2eV0 ________(3)
3 1 O V0 V0e
hc T
T
hc
hc 4eV0
4 155.
E h
hc
h E Pi C
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
19 1 9 19
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
h E Pr C 2 E P light Pr Pi C 2E Momentum transfered to the surface P light C
156.
By COAM R mv0 R0 mv ' 0 2
v ' 2v0 1 1 2 So final K .E . mv '2 m 2v 2 2 2mv 2
1 1 (1.5 1) f R
157.
1 f lens
1 f concave
1 f concave
0.5 R
1 1 (1.7 1) R R
0.7 2 1.4 R R
1 0.5 1.4 0.5 0.4 0.4 f eq R R R R 20 f eq 50cm
158.
m2 g T m2a T m1 g m1a m1 m 2 g m1T m1 m 2 a Tm2 m1 gm2 m1m2a m1mg 1 T m1 m2 0 T
m1m2 g 1 m1 m2
220 0
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
159.
V12 2 a 2 x12 _____(1) V22 2 a 2 x22 _____(2)
(1) ––– (2) V12 V22 2 x22 x12
V12 V22 x22 x12 T 2
x22 x12 V12 V22 N
160.
From Figure sin 45o
PS OS
W VA = 10 km/h
1 PS 2 100 PS
O 45°
100 km
P
100 100 2 50 2 2 2
relative velocity between A and B is
E
VB = 10 km/h S
PS – shortest distance
VBA VA2 VB2 10 2
t
50 2 10 2
t 5h
161.
d-x B
A x N1
W
N2
force balance
N1 N2 W _________(1) Torque balance about C.O.M. of rod
N1x N2 d x Putting value of N2 from equation (1)
N1x W N1 d x
N1x Wd Wx N1d N1x
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
21 2 1 21
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
N1d W d x N1
162.
W d x d
Pressure at the bottom P gd 103 10 2700 P 27 106 Pa Fractional compression = compressibility x pressure
45.4 1011 Pa1 27 106 Pa
163.
1.2 102 From conservation energy initial total energy
1 1 m1u12 m2u22 2 2
Total final energy 1 1 m2v22 m1v12 2 2 1 1 1 1 m1u12 m2u22 m1v12 m2 v22 2 2 2 2
164.
1 1 1 1 m1u12 m2u22 m1v12 m2 v22 2 2 2 2
GMm mv 2 Centripetal force r2 r v2
T
GM ____________(1) r
2 r v
T2
4 2r 2 v2
Putting value of v2 from (1)
T2
T2
4 2 r 2 GM r 4 2 r 3 __________(2) GM
T 2 kr 3 ____________(3)
222 2
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
from (2) and (3)
4 2 k GMK 4 2 GM 165.
Work done by force K .E K .E f K .Ei W .D K .Ei K .E f 30
1
0.1xdx 2 10 10
2
K .E f
20
x2 0.1 2
30 20
500 K .E f
0.1 900 400 500 K .E f 2
0.1
500 500 K .E f 2
25 500 K .E f 475
166.
By Bernoullis theorem 1 1 P1 v12 P2 v22 2 2 (Assuming is root width is very small) inside
outside
Pressure difference P1 P2
1 v22 v12 2
P1 P2
1 1.2 40 2 0 2 2
1 0.6 1.2 1600 2
960 N / m 2 Force acting on the roof is f = 960 x 250 960
1000 4
24 104 2.4 105 N upwords
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
23 2 3 23
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
167.
R
5m 2R 2R
M R
4R 12R
M x 5 M 9R x
X 45R 5x 6 x 45R 2 x 15R x 7.5 R
168. N P0 Vrms irms
Vrms irms R
Vrms Vrms R R
Vrms irms R
P0
2 Vrms 2 Vrms P0 R R
L
R
N
P Vrms irms cos 2 Vrms
R z2
P0 R
P P0 169.
Cv
R z2
R2 z2
n R 2
C p Cv R
n RR 2
n C p 1 R 2
n 1 R C p 2 n2 Cv n / 2R n
224 4
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
1 170.
2 n
As initial and final points are same so U ABC U AC
A B is isochoric process dWAB 0 dQAB dU AB 400 J
B C is isobaric process dQBC dU BC dWBC 100 J dU BC 6 10 4 2 103
100 J dU BC 12 10 dU BC 100 120 20 J So, U ABC U AC U AB U C dQAC dWAC 1 400 20 dQAC 2 10 4 2 10 3 2 10 3 4 10 4 2
380 J dQAC 40 40 dQAC 380 80 460 J 171.
Surface tension
force MLT 2 length L
Surfacetension MT 2 Energy ML2T 2 Velocity LT 1 S k Ea V b T c
RHS LHS a
b
c
MT 2 ML2T 2 LT 1 T M L0T 2 M a L2 a b T 2 a bc M a 1 L 2a b 0 b 2
T 2a b c 2 2 2 c 2 SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
25 2 5 25
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
C 2
S k E 'V 2 T 2 5v 172. As it is forward - bias takes + ve value 173. M A 4 kg , M B 2 kg , M C 1 kg M M A MB MC F M .a. F (4 2 1) a 14 7 a
a2
F F 4a 14 F 4 2 14 8 F F 6 N
174.
1 1 1 R RB RC
X
A RA = R
RB = 1.5 R B Q
P
C RC = 3 R
1 1 1 R 1.5 R 3R V
1 2 1 R 3R R R
VXP VA iR VPQ VB VC iR
VA VB VC 175.
I I1 I 2 I 3
226 6
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
2 5mr 2 I 2 I3 mr 2 mr 2 3 3 I1
2 2 mr 3
I 2 5
176.
mr 2 2 2 mr 3 3
12mr 2 4mr 2 3
E Ar E Aa E Aa
1 q Aa 4 0 a 2
q 4 0 Aa 3 177.
In both cases the temperature difference between the ends of the rool is 100C rate of heat flow is also 4J/s in the second case.
178.
K P KQ
In 1st case : elongation (X) is same. WP
1 1 K P X 2 , WQ K Q X 2 2 2
WP WQ
In 2nd case : Force of elongation is same. X1
F F , X2 KP KQ
1 1 F2 2 WP K1 X 1 2 2 KP W2
1 1 F2 K 2 X 22 2 2 KQ
WP WQ
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
27 2 7 27
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
x A
179.
i
C
BX V
V B
D
P.d. across the AB is
VA VB B1 a V
0i aV 2 x a / 2
P.d. across the CD is
VC VD B2 a V
0i aV 2 x a / 2
Net P.d. in the loop is
VA VB VC VD
0iaV 1 1 2 x a / 2 x a / 2
0iaV 2
180.
2a x a / 2 x a / 2
1
2 x a 2 x a
FV = constant = k m
dv V k dt k
Vdv m dt v2 k t 2 m
2k t m
V
F m
dv dt
228 8
RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : F / Physics
m
2 k 1 1 2 t m 2 mk 12 t 2
SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |
29 2 9 29
