RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / BIOLOGY

Medical - UG Time : 3 Hrs. Marks : 720

AIPMT : 2015 CODE - G

Date : 03-05-2015

BIOLOGY Q.1

In Opuntia leaves become modified into spines to reduce the rate of transpiration.

Q.2

Horizontal distribution of different species occupying different levels in a biotic community is known as zonation.

Q.3

Transpiration cause water to rise in plants by pulling through xylem components Root pressure causes water to rise in plants by pushing water in xylem elements

Q.4

Regulation of lac operon by repressor is referred to as negative regulation.

Q.5

High value of BOD  water is highly polluted. Because of presence of high amount of organic matter number of organisams increases which increase demand for oxygen.

Q.6

Agaricus is saprophytic fungus (Not parasitic) Phytophthora belong to Phycomycetes Mucor belong to Phycomycetes.

Q.7

Prolactin has no role in parturition, it helps in lactation process, (lactogenic hormone), development of mammary glands (mammotropin) & maintainance of corpus luteum (leutotropin).

Q.8

Epinephrine / Adrenaline is a hormone - a chemical signal that has both endocrine and neural roles.

Q.9

Vaccines for the following diseases are prepared with following :(a) Tuberculosis - harmones (attenuated) bacteria - mycobacterium Tuberculae (b) Whooping cough - killed bacteria - bordetella partusis bacteria (c) Diphtheria - Inactivated toxin (d) Polio - Harmless virus.

Q.10 Rough endoplasmic reticulum produces nuclear envelope in telophase. Q.11 Glyphosate is a herbicide and crops are engineered for glyphosate are resistant/tolerant to herbicides (By which main plants can be kept safe while using glyphosate as weedicide in fields). Q.12 Since cambium is absent, Vascular bundles are closed and secondary growth is not seen. Q.13 Selaginella is heterosporous producing micro & megaspores. Coralloid roots in Cycas have Anabaena .

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / BIOLOGY

Q.14 Anabaena is prokaryotic blue green alga, showing no true nucleus (nucleoid). Q.15 Honey is made by bees by nectar (regurgitation & evaporation). Q.16 Removal of proximal convoluted tubule from the nephron results in lack of reabsorption of high threshhold substances from renal tubules, and obligatory reabsorption of water is also affected leading to more diluted urine. Q.17 Vestibular apparatus (otolith organs ie. utricle & sacculus & semicircular canal) help in maintaining body posture, equilibrium & balancing the body. Thus it will help gymnast to balance its body upside down even in total darkness. Q.18 The hilum is a scar on the seed where funicle was attached. In many of the seeds like mungbean, pigeon pea it is very district. Q.19 A fluid connective tissue, constituents of which are blood is plasma plus blood cells ie. RBC, WBC & platelets. (ie. plasma plus blood corpuscles) (55% plasma & 45% corpuscles) Q.20 Methanogens in cow & buffalo guts are helpful for partial digestion of cellulose (which is a major constituent of grass) Q.21 In Geitonogamy pollen grains are transferred between two different flowers on the same plant. Eg Maize. Q.22 Chargaff’s rule A = T, G = C

C = 17% So G = 17%

A+G =1 T+C

A + G + C + T = 100

Since A = y So A = 33%, T = 33%

 A + 17 + 17 + T = 100  A + T = 100 – 34 = 66

Q.23 Capacitation refers to process occurring in uterus in which changes occur in sperms which helps to enable them to fertilize - ovum. These include Dilution of inhibiting factors in semen. Removal of cholesterol layer (galea) on acrosome. Q.24

Q.25

Q.26 Q.27 Q.28

Increase in permeability of membrane to Ca 2 Homo habilis has the smallest brain capacity of 650-800cc. Homo erectus has capacity of 900 cc Homo sapiens has capacity of 1350 cc Homo Neaderthalis has capacity of 1400 cc. Chikungunga virus is transmitted through aedes aegypti mosquito and does not get transmitted through semen. Human immunodeficiency virus, hepatitis B virus & Ebola virus are sexually transmitted disease, thus are transmitted through semen. Monocot stem has open and scattered vascular bundles. Roots in monocots have radial vascular bundles. Blood pressure in the mammalian aorta is maximum during systole of the left ventricle, because blood is pumped into aorta under high pressure. The Bt-toxin is an inactive protoxin which is activated due to alkaline pH in the insect gut.

Q.29 The rate of production of organic matter during photosynthesis is gross primary productivity. 22

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / BIOLOGY

Q.30 In a ring girdled plant, since phloem is removed, translocation of food does not take towards roots, so root dies first. Q.31 Erythropoiesis starts in liver in foetus. Q.32 Keel is a petal in vexillary aestivation which is a characteristic of family Fabacae Tomato-Solanaceae.Tulip and Aloe-Lilliacea. Q.33 Bryophytes and pteridophytes have an independant gametophyte. In spermatophytes gametophyte is reduced and dependant on sporophyte Q.34 Flattened membranous sacs  Thylakoids Stack of thylakoids  Grana Q.35 Renin does not favour for the formation of large quantities of dilute urine as it activates RAAS ( Renin angiotensin activating system) so it causes reabsorption of sodium which leads to formation of concentrated urine. Q.36 Ribosomes  60 to 65% rRNA 30 to 40% Protein Q.37 Nectar & pollen are floral rewards to the animal pollinators which are used by animals like bees as food. Q.38 In aves skin is non glandular, in mammals pinnae is absent in whale, cyclostamata paired appendages are absent. Q.39 Alleles or Allelomorphs are the two (or more) alternative forms of a gene (factors), controlling same characters occuping identical loci (positions) or homologous chromosomes these terms were coined by Bateson. Q.40 Hysteroctomy is removal of uterus (Hystera means uterus) Q.41 The United Nation Climate Change Conference was held in Durban South Africa from 28 November to 11 December 2011 to establish a new treaty to limit carbon emissions. Q.42 HIV that causes AIDS, first starts destroying helper T - cells. Q.43 Mannitol is stored food in Phaeophyceae (Brown Algae) Rhodophyceae members store food in the form of Floridean starch. Q.44 In cryopreservation, genes/gene pools are stored at -196oC under liquid nitrogen which is an advance exsitu conservation of bio diversity. Q.45 Rough ER - Production of proteins. Whereas smooth ER is the site for synthesis of lipids & glycogen. Q.46 Newly cooled lava, Bare rock & newly created pond  Primary succession. Q.47 Encephalitis is not a sexually transmitted disease. Q.48 Translocation is reciprocol of chromosomal segment between non-homologous chromosome. Movement of gene from one linkage group to another is called crossing over. Inversion : - When a piece of chromosome is removal & rejoined in reverse order, its known as inversion. Duplication : In this mutation deleted chromosomal segment is attached to its normal homologus chromosome. Here a gene or many genes are repeated twice or more times in the same chromosome. Q.49 Because of more success for food, population of B shows increase in no. of individuals Q.50 Sigmoid curve shows 3 major phases like initial lag phase, exponential log phase & steady or stationary phase Q.51 Levitt (1954) proposed Active Potassium Transport theory in which stomatal movements (opening & closing) is because of influx & efflux of K+. Q.52 Cytochromes which are Iron containing electron acceptors are present on cristae of mitochondria, helpful in ETS. SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / BIOLOGY

Q.53 Silent spring  Pesticide pollution. The book documented the detrimental effects on the environmentparticularly on birds of the indiscriminate use of pesticides. Q.54 Language comprehension is the function of wernicke’s area of parietal lobe of cerebrum. Q.55 Exoskeleton is responsible for diversification of insects on land. Q.56 During muscle contraction actin filament slides over myosin filament, where none of them shorten in length. Q.57 Polysomes are Polyribosomes, attached to mRNA. Q.58 The mass of living material at a trophic level at a particular time is standing crop. The inorganic substances present at a trophic level at a particular time is called as standing state Q.59 Option (3) suggest correct match. Q.60 Multiple alleles are present on the same locus of the chromosome Q.61 Due to depletion of stratospheric ozone, there is increased risk of skin cancer, damage to cornea, conjunctiva etc. as well as reduces our immune system. Q.62 Recombination (crossing over) is the most common mechanism of genetic variation in the population of a sexually reproducing organism Q.63 Zinc, Cu, Manganese, selenium & boron are micromolecules. Q.64 Transmission tissue is characteristic feature of solid style which helps in directing pollen tube. Woman B

Q.65 Man A [ I AI A / I AI O ]

[ I BI B / I I O ]

Progeny I A I O I B I O

I AI O I O I O

A

B

AB

O

Q.66 Brunner’s glands are present in the submucosa of duodenum and secrete mucous. Q.67 Guava & Cucumber - epigynous china rose - Hypogynous Q.68 Formation of abnormal ova i.e., 22 + XX in the mother will lead to birth of human baby with ‘XXX’ genotype. Q.69 Because of greater elongation of cells on shaded side, it makes the plant bend towards light source. Q.70 The chromosomes in which centromere is situated close to one end are Acrocentric, if it is at the centre metacentric, near to the centre - sub - meta centric, at one end - Telocentric Q.71 A technique of micropropagation is somatic embryogenesis (which forms clones Of ex-plant in the form of embryo) Q.72 After S phase, amount of DNA gets doubled but number of chromosomes remain same

Chromosome number Amount of DNA

Gamete (n) Single

Cell (after S phase) (2n) Four times

Q.73 Gastric juice of infants contains Pepsinogen, Lipase, rennin Q.74 Platypus is an egg laying mammal. Q.75 Floral formula is of Solanaceae family hence is of Petunia, Brassica is from Brassicacene family whereas Allium belong to Liliaceac & Sesbania belong to Fabaceae Q.76 Tissue culture, seed bank & cryopreservation are ex- situ conservation Sacred groves, National park, wildlife sanctuary is in-situ conservation. Q.77 Genetic engineering approval committee regulates GM research & safety of introducing GM organisms for 44

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / BIOLOGY

public services. Q.78 Trichinella spiralis is viviparous roundworm. Q.79 Arthroidal membrane joins terga , sterna and pleura of cockroach body. Q.80 Tropical rain forest shows striated vegetation because of which most animals are tree dwellers Q.81 Polyethylene glycol & sodium nitrate increases fusion of protoplasts & hence can be used as fusogen in somatic hybridization or protoplast fusion. Q.82 Glenoid canty of scapula articulate with head of humerus. Q.83 A population will not exist in Hardy - weinberg equilibrium if individuals mate selectively as mutation , nonrandom mating and genetic driff affects equilibrium. Q.84 Sprirogyra shows morphological isogamy, physiological anisogamy where male gamete is motile but not having flagella Polysiphonia belong to Rhodophyte which is characterised by non-motile male gametes (non-flagellated) Q.85 Rise in CO2 concentration stimulates chemoreceptors present in aorta and carotid artery which stimulates respiratory centre. Q.86 Spermatogonia i.e. sperm mother cell is diploid whereas spermatids, first polar body and second polar body are Haploid. Q.87 Runners - in Cynadon Offsets - in Eicchornia & Pistia Bulbils - in Dioscorea Q.88 The competitive inhibitor increases the Km of the enzyme for the substrate. Q.89 Active form of Entamoeba histolytica feeds upon erythrocytes , mucosa and submucos of colon. Q.90 Seven pairs of contrasting characters in pea plants , were studied by mendel is his experiments.

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

PHYSICS 91.

E  h 

hc 

 h E Pi    C   h  E Pr    C    2 E  P light  Pr  Pi  C  2E Momentum transfered to the surface    P light  C

92.

N

From Figure sin 45o 

PS OS W VA = 10 km/h

1 PS  2 100 PS 

45°

100 km

P

100 100 2   50 2 2 2

VB = 10 km/h S

relative velocity between A and B is

PS – shortest distance

VBA  VA2  VB2  10 2

t

O

50 2 10 2

t  5h

93. M A  4 kg , M B  2 kg , M C  1 kg M  M A  MB  MC F  M .a. F  (4  2  1) a 14  7 a a2

66

E

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

F  F   4a 14  F   4  2 14  8  F F  6 N

94.

E  Ar E  Aa E  Aa

1 q  Aa 4 0 a 2

q  4 0 Aa 3

95.

1 1 1   R RB RC

X

A RA = R

RB = 1.5 R B Q

P

C RC = 3 R

1 1 1   R 1.5 R 3R V

1 2 1  R 3R R  R

VXP  VA  iR VPQ  VB  VC  iR

VA  VB  VC

96.

d 1 mm  1  103 m D 1m

  500  109 m

a width of central maxima = width of 10 maxima

2 a

s

2  D   10   a  d  a

2d 10 D SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

2  10 3 a 10  1 a  2  104 m a  0.2 mm

97.

U  nCv dT  5R   n   TB  TA   2  

5nR  PBVB PAVA     2  nR nR 

 5/ 2  PBVB  PAVA   5 / 2  2  103  5  103  4   5 / 2  8  10 3 

 20kJ 98.

d-x B

A x N1

W

N2

force balance

N1  N2  W _________(1) Torque balance about C.O.M. of rod

N1x  N2  d  x  Putting value of N2 from equation (1)

N1x  W  N1  d  x 

 N1x  Wd  Wx  N1d  N1x  N1d  W  d  x   N1 

99.

W  d  x d

GMm mv 2  Centripetal force r2 r

v2 

GM ____________(1) r

88

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

T

2 r v

T2 

4 2r 2 v2

Putting value of v2 from (1)

T2 

T2 

4 2 r 2  GM     r  4 2 r 3 __________(2) GM

T 2  kr 3 ____________(3) from (2) and (3)

4 2  k  GMK  4 2 GM

5v 100.

101.

As it is forward - bias takes + ve value From conservation energy initial total energy 1 1 m1u12  m2u22 2 2

Total final energy 1 1 m2v22  m1v12   2 2 1 1 1 1 m1u12  m2u22  m1v12  m2 v22   2 2 2 2

102.



1 1 1 1 m1u12  m2u22    m1v12  m2 v22 2 2 2 2



h p

p  h

like  yx  c   3 Ahyperbola

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

103.

Pressure at the bottom P   gd  103  10  2700 P  27  106 Pa  Fractional compression = compressibility x pressure

 45.4 1011 Pa1  27 106 Pa

104.

105.

 1.2 102 In both cases the temperature difference between the ends of the rool is 100C  rate of heat flow is also 4J/s in the second case.

a

d d dv d    dt dx dt dx d   2 n x 2 n  1 dx a    2n  x 2 n  1     x 2 n 

a   2 n 2 x  4 n  1

106.

 A  sin  2     A sin   2  A  sin   A  2  cot  2  A sin   2  A  A  cos   sin   2  2   A  A sin   sin   2 2  A A  sin     sin    2 2  2 2

     107.

V12   2  a 2  x12  _____(1) V22   2  a 2  x22  _____(2)

(1) ––– (2) V12  V22   2  x22  x12 

1100

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

V12  V22 x22  x12



T  2

108.

x22  x12 V12  V22

K P  KQ

In 1st case : elongation (X) is same. 1 1 K P X 2 , WQ  K Q X 2 2 2

 WP 

 WP  WQ

In 2nd case : Force of elongation is same.  X1 

F F , X2  KP KQ

WP 

1 1 F2 K1 X 12  2 2 KP

W2 

1 1 F2 K 2 X 22  2 2 KQ

 WP  WQ

109.

Energy of electron in He  3rd orbit = 13.6  E3   13.6    13.6 

Z2 eV n2

4 eV 9 4  1.6  1019 J 9

In Bohr’s model : E3   K .E3  9.7  10 19 J 

 

110.

BI 

1 me  2 2

2  9.7  1019  1.46  106 m / sec 31 9.1  10

0 i (k ) 4 R BIII 

0 i (  k ) 4 R

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

0 i  (i ) 4R

BII 

B  BI  BII  BIII B

0 i ( 2k   i ) 4 R

B

111.

0i  (2k   i ) 4 R

FV = constant = k m

dv V k dt k

 Vdv   m dt v2 k  t 2 m 

2k t m

V 

F m

dv dt

2 k 1 1 2 t m 2

m

 112.

mk 12 t 2

Closed organ pipe nc 

V 4l

Open organ pipe n0 

V 2l '

IInd overtone of open organ pipe n  3n0 n 

3V 2l 

nc  n V 3V  4l 2l 

1122

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

l   6l l  6  20 l   120 cm

r

113.

e i

X

B i

e T

i

e e  2 n  e    ne 2  2 /   2

B

Q.114

0i 0 ne  2R 2R 1 1  (1.5  1)   f R 1 f lens



1 f concave

1 f concave

0.5 R

 1 1  (1.7  1)   R R 



0.7  2 1.4  R R

1 0.5 1.4 0.5 0.4 0.4      f eq R R R R 20 f eq   50cm

115.

Wein’s Displacement Law

mT  Constant P  violet max m Q  Red max m R  Green max m

r  g  v Tr  Tg  Tv TP  TR  TQ SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

116.

Surface tension 

force MLT 2  length L

 Surfacetension  MT 2  Energy   ML2T 2 Velocity   LT 1 S  k Ea V b T c

 RHS    LHS  a

b

c

MT 2   ML2T 2   LT 1  T  M L0T 2  M a L2 a b T 2 a bc M a 1 L  2a  b  0  b   2

T   2a  b  c  2  2  2  c  2

C  2

 S   k E 'V 2 T 2 117.

T2

2

W 1 low temp

T1

Q1  w  Q2

  1

T1 T2

1 T  1 1 10 T2

T1 1 9  1  T2 10 10 Q2 T2  Q1 T1 Q1  w T2  Q1 T1

1144

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

Q1  10 10  Q1 9

9Q1  90  10Q1 90  Q1

118.

By COAM R  mv0 R0  mv '  0   2 

 v '  2v0 1 1 2 So final K .E .  mv '2  m  2v  2 2  2mv 2

119.



a

sin  

2D/a

 a

y   D a y

D a

width of centeral maxima is 120.

2 D a

By Bernoullis theorem 1 1 P1   v12  P2   v22 2   2  (Assuming is root width is very small)  inside

outside

Pressure difference P1  P2 

1   v22  v12  2

P1  P2 

1  1.2  40 2  0 2  2



1 0.6  1.2 1600 2

 960 N / m 2 SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

15 1 5 15

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Force acting on the roof is f = 960 x 250  960 

1000 4

 24  104  2.4 105 N upwords

121.

Cv 

n R 2 n RR 2

C p  Cv  R 

n  C p    1 R 2 

n  1 R C p  2  n2    Cv n / 2R n

  1 122.

2 n

Radius of the nucleus R = R0 A 1/3 1/ 3

RAl  A1    RTe  A2 

1/ 3

 27     125 

1

RAl  33  3     3/ 5 RTe  53  RTe 

123.

5 RAl 3

As initial and final points are same so U ABC  U AC

A  B is isochoric process dWAB  0 dQAB  dU AB  400 J

B  C is isobaric process dQBC  dU BC  dWBC 100 J  dU BC  6  10 4  2 103 

100 J  dU BC  12 10

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dU BC  100  120  20 J So, U ABC  U AC U AB  U C  dQAC  dWAC 1   400  20  dQAC   2  10 4  2  10 3   2  10 3  4  10 4  2  

380 J  dQAC   40  40  dQAC  380  80  460 J 124.

Work done by force  K .E  K .E f  K .Ei W .D  K .Ei  K .E f 30

1

 0.1xdx  2 10 10

2

 K .E f

20

0.1 

x2 2

30 20

500  K .E f

0.1  900  400   500  K .E f 2

0.1

500  500  K .E f 2

25  500  K .E f  475

x A

125.

i

C

BX V

V B

D

P.d. across the AB is

VA  VB  B1  a V 

0i aV 2  x  a / 2 

P.d. across the CD is

VC  VD  B2  a V 

 0i aV 2  x  a / 2 

Net P.d. in the loop is SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

17 1 7 17

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 VA  VB   VC  VD  

0iaV  1 1     2  x  a / 2 x  a / 2 



0iaV 2

 126.

  2a     x  a / 2  x  a / 2  

1

 2 x  a  2 x  a 

I  I1  I 2  I 3

2 2 5mr 2 2 I 2  I3  mr  mr  3 3 I1 

2 2 mr 3

I  2  5

 127.

128.

mr 2 2 2  mr 3 3

12mr 2  4mr 2 3

A 0 0 1 1

B 0 1 0 1

Y1 1 1 0 0

Y2 1 0 1 0

Y 0 0 0 1

m2 g  T  m2a T   m1 g  m1a m1 m 2 g  m1T  m1 m 2 a Tm2  m1 gm2  m1m2a m1mg 1     T  m1  m2   0 T

129.

m1m2 g 1    m1  m2

hc  hv    eV0 ______(1)  hc    e V0  ________(2) 2 hc  2  2eV0 ________(3) 

1188

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 3  1  O    V0   V0e   

hc T

T 

hc 

hc  4eV0 

 4 130.

y1  a sin t  y2  b sin  t   / 2 

y R  y1  y2  a 2  b 2 sin t    131.

SHM with complitude (4) L=4 , 800

1cm  1mv 100cm  100mv 400cm  400mv  0.4V V  0.4  8 R 

2 8 8 R

16 160   40 0.4 4

R = 32 132.

R

5m 2R 2R

M R

4R 12R

M x  5 M  9R  x 

X  45R  5x 6 x  45R 2 x  15 R x  7.5 R

133. N P0  Vrms irms

Vrms  irms R

Vrms Vrms R R

Vrms  irms R



SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

19 1 9 19

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Physics

P0 

2 Vrms 2  Vrms  P0 R R

L

R

N

P  Vrms irms cos  2  Vrms

R z2

 P0 R 

134.

R z2

R2 P  P0 2 z The area cross section of conductor is non uniform so current density will be different but the numbers of flow of electron will be same so current will be constant. C1=C C2 q'=q

135.

disconnected

V

q  CV  V  q / c

C2  CK q2 U1  2c q2 U2  2CK

q2  1  U   1 2C  k  1 1  U  CV 2   1 2 k 

C2  CK V '

q CK

V'

V K

2200

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Chemistry

CHEMISTRY H





Q.136

+

 O + CH 3 Li  + –

Li O  CH 4

Q.137 The enolic form of ethyl acetoacetate has 16 single bonds (= 16 sigma bonds) and 2 double bonds ( equal to 2 sigma and 2 pi bonds) Q.138 It is an alternating polyamide copolymer of glycine  H 2 N  CH 2  COOH  and amino caproic acid  H 2 N  CH 2 5 COOH  and is biodegradable

O

O

O

H 2 N  CH 2  C  OH  HN CH 2 5 COOH   H 2 N  CH 2  C  NH  CH 2 5 C 

n

H Nylon -2-nylon-6 Q.139. There is no   H in the structure I and II Q.140 CH 2  CN  2 H N  C C C  N

 6  4 

H O

 4  1 

O=C O-H O Xe O

 4  4  O

O

N  C C  N

 3  4 

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

21 2 1 21

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Q.141 Order of bond order O2   1s 2 *1s 2 2 s 2 * 2 s 2 2 p z2  2 p x2   2 p 2y 



*

2 p x2   * 2 p1y 

no.of electronsin BMO-no of electrons in ABMo 2

Bond order = 

10  7 3   1.5 2 2

O2   1s 2 *1s 2 2 s 2 * 2s 2 2 pz2  2 px2   2 p 2y 



*

2 p1x   * 2 p 0y 

Bond order =

10  5 5   2.5 2 2

O22    1s 2 *1s 2 2 s 2 * 2 s 2 2 pz2  2 p x2   2 p 2y 



*

2 px0   * 2 p y0 

Bond order 

10  4 6  3 2 2

Order ofbond order : O22  O2  O2 Q.142 Sodium pump used for conduction of signals from brain to organ and vice versa. In which Na+ and K+ are exchanged. Q.143 Co  CN  6 

3

Co3   Ar  3d 6 eg orbital t2g orbital

CN– is using strong field ligand so zero unpaired electrons are present. Q.144 By Arrhenius equation k  Ae  Ea / RT

ln k  ln A 

Ea RT

on plotting ln k vs

1 T

2222

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Chemistry

lnA lnk

slope = -Ea/R

1/T  By knowing slope activation energy can be determined. Q.145. Its nucleophilic substitution reaction. It follows SN2 mechanism.

Q.146 For ideal solution Pobs  PRaoult

P  0

H mix  0

S mix   ve

Vmix  0 Q.147 Metal nitrates are usualy not found as nitrates in their ores because they are highly soluble in water. Q.148. For the Idoform test there must be a terminal CH 3 group, similarly for the Tollen’s test CHO group is required. Hence, as per question the structure would be O CH 3  CH 2  C  CH 2  CH 3 3

Q.149 1) Co  NH 3 6  Cl3  Co  NH 3 6   3Cl  2) Co  NH 3 3 Cl3   Co  NH 3 3 Cl3  1

3) Co  NH 3 4 Cl2  Cl  Co  NH 3 4 Cl2   Cl  2

4) Co  NH 3 5 Cl  Cl2  Co  NH 3 5 Cl   2Cl  so Co  NH 3 3 Cl3  does not ionize so doesn’t give test for chloride ions. Q.150 Let the masses of H2 and O2 be x g and 4x g

nH 2 x/2 4    Molar ratio  nO2 4 x / 32 1 Q.151 Allylic and benzylic halides show high reactivity towards SN1 reaction.

H + + H 3C  C  CH  CH 2  Cl  CH 3  CH  CH  CH 2  H 3C  CH  CH  CH 2  Cl 

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

23 2 3 23

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Chemistry

Q.152 Under weakly acidic conditions Nitro benzene on electrolytic reduction gives aniline but under strongly acetic condition we get p - aminophenol. NO2

NHOH -

4e + 4H

NH2 -

2e + 2H weakly +

H (strongly) NH2

OH

Q.153 NaHSO3 is used as food preservative as it produces SO2 on decomposition which checks the oxidation of food. Q.154 we know G  G 0  2.303RT log Q but at equilibrium

G  0 , Q  k G 0  2.303RT log K Q.155 S

Cl O

O

O

O

O

O O

O N

O=C O

O

O

 2  ClO3 & SO3 are isoelectronic and are pyramidal

Q.156 Angular momentum of electron in ‘d’ orbital  l  l  1

h 2

 2  2  1

h      2  

 6

2244

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Chemistry

Q.157 Order of bond order O2   1s 2 *1s 2 2 s 2 * 2 s 2 2 p z2  2 p x2   2 p 2y 



*

2 p x2   * 2 p1y 

Bond order  

no.of electrons in BMO-no of electrons ABMo 2

10  7 3   1.5 2 2

O2   1s 2 *1s 2 2 s 2 * 2s 2 2 p z2   2 p x2   2 p 2y 



*

2 p1x   * 2 p 0y 

Bond order =

10  5 5   2.5 2 2

O2   1s 2 *1s 2 2s 2 * 2s 2 2 pz2  2 px2   2 p 2y 



*

2 p1x   * 2 p1y 

Bond order 

10  6 4  2 2 2

Order ofbond order : O2  O2  O2 Q.158 Magnetic moment =

n  n  2  B.M.

where n = number of unpaired electrons  2.84  n  n  2  B.M.

 2.84 

2

 n  n  2

8  n 2  2n On solving n = 2

only Ni 2   Ar  3d 8 4s 0 has 2 unpaired electrons. Q.159 The enthalpy of hydrogenation is inversely proportional to stability of alkene III  II  I

Q.160 CH 3 O3   CH 3  Zn , H 2O

OHC CH 2

CH 3

CH 3

C

C

H

CH 2

O

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

25 2 5 25

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Chemistry

Q.161 There are 4 bond’s, hence total  -electrons are 8. K sp

Solubility

Ag 2CrO4

1.1 1012

S

AgCl

1.8  1010

S  K sp  1.34 10 5

AbBr

5  10 13

S  K sp  0.71 10 6

AgI

8.3  1017

S  K sp  0.9  10 8

Q.162 Salt

3

K sp 4

 0.65  104

 solubility of Ag 2CrO4 is highest it will precipitate last.

Q.163 for ‘n’ order reaction t1/ 2  C01 n

where C0 is initial concentration of reactant. for first order reaction n = 1, half life is independent of intial concentration (O )

Q.164 1.

( III )

Fe  H 2O   Fe2O3  H 2 Steam (O )

( III )

2.

Moisture Fe  O2   Fe2O3. x H 2O

3.

CuSO4  Fe   FeSO4  Cu

4.

Fe  5 CO   Fe CO 5

(O )

(O )

( II )

(O )

 During formation of Fe  CO 5 oxidation number of Fe doesn’t change. Q.165 Bithional functions as antiseptic. Q.166 CH 3

CH 3 CH 3  C  Cl

  CH 3  C   Cl 

CH 3

(more stable due to 9 hyper conjugation structures & 3 +I groups)

CH 3

Q.167 Edge length a = 361 pm, effective number in unit cell = 4 (given)

 It is a FCC structure  face diagonal = 4r

 

2 a  4r r

2  361  127 pm 4

2266

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Chemistry

Q.168 Molality of solution of x = molality of solution of y = 0.2 mol/kg by elevation in boiling point relation Tb  iK b m or Tb  i  Tb of solution of ‘x’ > Tb of solution of ‘y’

 ‘i’ of solution of x > i of solution of ‘y’  solute ‘x’ undergoing dissociation

Q.169 PN 2  Ptotal  PH 2O  725  25  700mm WN2 

PVM 700  40  28  RT 760 1000  300  0.0821

 0.042 g

% of Nitrogen 

0.042  100 0.25

 16.573%

Q.170 Ar, K & Ca belong to the same period. Being Nobel gas radii of Ar is heighest. We also know for isoelectronic species size decreases with increase in positive charge of the ion. Q.171 due to lanthanoid contraction Zr (Zirconium)and Hf (Hafnium) have almost same atomic radii. Q.172 Electronic configuration of Fe 2 is  Ar  3d 6 4s 0  Number of ‘d’ electrons = 6

Ne – 1s 2 2 s 2 2 p 6  6  p electrons  Mg – 1s 2 2s 2 2 p 6 3s 2  6  s electrons  Cl – 1s 2 2 s 2 2 p 6 3s 2 3 p 5 11  p electrons 

 Ar  3d 6 4s 2  6  d electrons  Q.173 In keto - enol tautomerism the keto form should have   hydrogen (I & II) H3C

CH3

H3C

CH3



I)

OH

O

CH3 CH3 

II)

O

CH3 CH3 OH SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

27 2 7 27

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : G / Chemistry

In IIIrd ketone

H  H  III) 

CH3 CH3

CH3 CH3

O

OH

here  H participates in tautomerism Q.174 Al2  SO4 3  2 Al 3  3SO42  Volume of Vant Hoff’s factor i = 5

K 4  Fe  CN 6   4 K    Fe  CN 6 

4

i  5

K 2 SO4  2 K   SO42  i  3 K 3  Fe  CN 6   3K    Fe  CN  6 

3

i  4

Al  NO3 3  Al 3  3 NO3  i  4  NO3

NO2

NO2

NO2

Hybridisation

sp 2

sp 2

sp 2

sp (linear)

Bond angle

1200

 1200  1200 1800

Q.175 Species

so NO2 has maximum bond angle. Q.176. Electrophilic addition takes place via more stable carbo cation. HBr C6 H 5  CH  CH  CH 3  

C6 H 5  CH  CH 2  CH 3 Br

Q.177 Tyndall effect is the scattering of light by sol particles. which can’t be affected by charge on them Q.178 Down the group solubility of sulphate of alkaline earth metal decreases because of increase in lattice enrergy gradually. Q.179 In Fuel cell energy of combustion is converted into electrical energy. Q.180 R  P

K

 P eq  R eq

 1.6 1012 

 P eq  R eq

  P eq   R eq

so mostly the products will be present in the equilibrium mixture. 2288

AIPMT-2015-Solutions-Code-G.pdf

Q.8 Epinephrine / Adrenaline is a hormone - a chemical signal that has both endocrine and neural roles. Q.9 Vaccines for the following diseases are prepared ...

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