RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

Medical - UG Time : 3 Hrs. Marks : 720

AIPMT : 2015 CODE - H

Date : 03-05-2015

PHYSICS 1. M A  4 kg , M B  2 kg , M C  1 kg M  M A  MB  MC F  M .a. F  (4  2  1) a 14  7 a a2

F  F   4a 14  F   4  2 14  8  F F  6 N

2.

Radius of the nucleus R = R0 A 1/3 1/ 3

RAl  A1    RTe  A2 

1/ 3

 27     125 

1

RAl  33  3     3/ 5 RTe  53  RTe 

5 RAl 3 SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

3.



h p

p  h

like  yx  c   3 Ahyperbola 4.

In both cases the temperature difference between the ends of the rool is 100C  rate of heat flow is also 4J/s in the second case.

5.

a



sin  

2D/a

 a

y   D a y

D a

width of centeral maxima is 6.

7.

A 0 0 1 1

B 0 1 0 1

Y1 1 1 0 0

Y2 1 0 1 0

2 D a

Y 0 0 0 1

V12   2  a 2  x12  _____(1) V22   2  a 2  x22  _____(2)

(1) ––– (2) V12  V22   2  x22  x12 



V12  V22 x22  x12

T  2

x22  x12 V12  V22

22

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

1 1  (1.5  1)   f R

8.

1 f lens



1 f concave

1 f concave

0.5 R

 1 1  (1.7  1)   R R 



0.7  2 1.4  R R

1 0.5 1.4 0.5 0.4 0.4      f eq R R R R 20 f eq   50cm

r

9.

X

B

10.

e i

i

e T

i

e e  2 n  e    ne 2  2 /   2

B

0i 0 ne  2R 2R

a

d d dv d    dt dx dt dx d   2 n x 2 n  1 dx a    2n  x 2 n  1     x 2 n 

a   2 n 2 x  4 n  1 11.

E  Ar E  Aa E  Aa

1 q  Aa 4 0 a 2

q  4 0 Aa 3 SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

3 33

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

12.

E  h 

hc 

 h E Pi    C   h  E Pr    C    2 E  P light  Pr  Pi  C  2E Momentum transfered to the surface    P light  C

13.

1 1 1   R RB RC

X

A RA = R

RB = 1.5 R B Q

P

C RC = 3 R

1 1 1   R 1.5 R 3R V

1 2 1  R 3R R  R

VXP  VA  iR VPQ  VB  VC  iR

VA  VB  VC 14.

d-x B

A x N1

W

N2

force balance

N1  N2  W _________(1) Torque balance about C.O.M. of rod

N1x  N2  d  x  Putting value of N2 from equation (1)

N1x  W  N1  d  x 

 N1x  Wd  Wx  N1d  N1x  N1d  W  d  x   N1 

W  d  x d

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

15.

BI 

0 i (k ) 4 R BIII 

0 i (  k ) 4 R

BII 

0 i  (i ) 4R

B  BI  BII  BIII

0 i ( 2k   i ) 4 R

B

0i  (2k   i ) 4 R By Bernoullis theorem B

16.

1 1 P1   v12  P2   v22 2   2  (Assuming is root width is very small)  inside

outside

Pressure difference P1  P2 

1   v22  v12  2

P1  P2 

1  1.2  40 2  0 2  2



1 0.6  1.2 1600 2

 960 N / m 2 Force acting on the roof is f = 960 x 250  960 

1000 4

 24  104  2.4 105 N upwords

17.

d 1 mm  1  103 m D 1m

a

9

  500  10 m

width of central maxima = width of 10 maxima

2 a

s

2  D   10   a  d 

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

a

2d 10 D

a

2  10 3 10  1

a  2  104 m a  0.2 mm

18.

By COAM R  mv0 R0  mv '  0   2 

 v '  2v0 1 1 2 So final K .E .  mv '2  m  2v  2 2  2mv 2

19.

GMm mv 2  Centripetal force r2 r v2 

T

GM ____________(1) r

2 r v

T2 

4 2r 2 v2

Putting value of v2 from (1)

T2 

T2 

4 2 r 2  GM     r  4 2 r 3 __________(2) GM

T 2  kr 3 ____________(3) from (2) and (3)

4 2  k  GMK  4 2 GM

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

20.

I  I1  I 2  I 3

2 5mr 2 I 2  I3  mr 2  mr 2  3 3 2 2 mr 3

I1 

mr 2 2 2 I  2  5  mr 3 3  21.

12mr 2  4mr 2 3 N

From Figure PS OS

sin 45o 

W VA = 10 km/h

1 PS  2 100

O 45°

100 km

P

100 100 2 PS    50 2 2 2

E

VB = 10 km/h S

relative velocity between A and B is

PS – shortest distance

VBA  VA2  VB2  10 2

t

50 2 10 2

t  5h

22.

Cv 

n R 2

C p  Cv  R 

n RR 2

n  C p    1 R 2 

n    1 R n  2 2     Cv n / 2R n Cp

  1

2 n

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

5v 23. As it is forward - bias takes + ve value 24.

hc  hv    eV0 ______(1)  hc    e V0  ________(2) 2 hc  2  2eV0 ________(3) 

 3  1  O    V0   V0e   

hc T

T 

hc 

hc  4eV0 

 4 C1=C C2 q'=q

25.

disconnected

V

q  CV  V  q / c

C2  CK U1 

q2 2c

U2 

q2 2CK

U

q2  1    1 2C  k 

1 1  U  CV 2   1 2 k 

C2  CK V '

q CK

V'

V K 88

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

26.

FV = constant = k dv V k dt

m

k

 Vdv   m dt v2 k  t 2 m

F m

m



27.

T2

2k t m

V 



dv dt

2 k 1 1 2 t m 2 mk 12 t 2

2

W 1 low temp

T1

Q1  w  Q2

  1

T1 T2

1 T  1 1 10 T2

T1 1 9  1  T2 10 10 Q2 T2  Q1 T1 Q1  w T2  Q1 T1

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

9 99

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

Q1  10 10  Q1 9

9Q1  90  10Q1 90  Q1

28.

U  nCv dT  5R   n   TB  TA   2  

5nR  PBVB PAVA     2  nR nR 

 5/ 2  PBVB  PAVA   5 / 2  2  103  5  103  4 

 5 / 2  8  103 

 20kJ 29.

Work done by force  K .E  K .E f  K .Ei W .D  K .Ei  K .E f 30

1

 0.1xdx  2 10 10

2

 K .E f

20

0.1 

x2 2

30 20

500  K .E f

0.1  900  400   500  K .E f 2

0.1

500  500  K .E f 2

25  500  K .E f  475

30.

Energy of electron in He  3rd orbit = 13.6  E3   13.6    13.6 

Z2 eV n2

4 eV 9 4  1.6  1019 J 9

In Bohr’s model : E3   K .E3

1100

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

 9.7  10 19 J 

 

1 me  2 2

2  9.7  1019  1.46  106 m / sec 31 9.1  10

31. N P0  Vrms irms

Vrms  irms R

Vrms Vrms R R

Vrms  irms R



P0 

2 Vrms 2  Vrms  P0 R R

L

R

N

P  Vrms irms cos  2  Vrms

R z2

 P0 R 

P  P0 32.

R z2

R2 z2

m2 g  T  m2a T   m1 g  m1a m1 m 2 g  m1T  m1 m 2 a Tm2  m1 gm2  m1m2a m1mg 1     T  m1  m2   0 T

m1m2 g 1    m1  m2

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

11 1 1 11

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

33.

 A  sin    2    A sin   2  A  sin   A  2  cot  2  A sin   2  A  A  cos   sin   2  2   A  A sin   sin   2 2  A A  sin     sin    2 2  2 2

     34.

Wein’s Displacement Law

mT  Constant P  violet max m Q  Red max m R  Green max m

r  g  v Tr  Tg  Tv TP  TR  TQ

x A

35.

i

C

BX V B

V D

P.d. across the AB is

VA  VB  B1  a V 

0i aV 2  x  a / 2 

P.d. across the CD is 1122

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

VC  VD  B2  a V

 0i aV 2  x  a / 2 



Net P.d. in the loop is

 VA  VB   VC  VD  

0iaV 2

1   1     xa/2 xa/2



0iaV 2

  2a     x  a / 2  x  a / 2  

 36.

1

 2 x  a  2 x  a  R

5m 2R 2R

M R

4R 12R

M x  5 M  9R  x 

X  45R  5x 6 x  45R 2 x  15R x  7.5 R

37.

K P  KQ

In 1st case : elongation (X) is same.  WP 

1 1 K P X 2 , WQ  K Q X 2 2 2

 WP  WQ

In 2nd case : Force of elongation is same.  X1 

F F , X2  KP KQ

1 1 F2 2 WP  K1 X 1  2 2 KP W2 

1 1 F2 K 2 X 22  2 2 KQ

 WP  WQ SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

13 1 3 13

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

38.

From conservation energy initial total energy 1 1 m1u12  m2u22 2 2

Total final energy 1 1 m2v22  m1v12   2 2 1 1 1 1 m1u12  m2u22  m1v12  m2 v22   2 2 2 2

 39.

1 1 1 1 m1u12  m2u22    m1v12  m2 v22 2 2 2 2

Pressure at the bottom P   gd  103  10  2700 P  27  106 Pa  Fractional compression = compressibility x pressure

 45.4 1011 Pa1  27 106 Pa

40.

 1.2 102 As initial and final points are same so

U ABC  U AC

A  B is isochoric process dWAB  0 dQAB  dU AB  400 J

B  C is isobaric process dQBC  dU BC  dWBC 100 J  dU BC  6  10 4  2 103 

100 J  dU BC  12 10 dU BC  100  120  20 J So, U ABC  U AC U AB  U C  dQAC  dWAC 1   400  20  dQAC   2  10 4  2  10 3   2  10 3  4  10 4  2  

380 J  dQAC   40  40  dQAC  380  80  460 J

1144

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

41.

Closed organ pipe nc 

V 4l

Open organ pipe n0 

V 2l '

IInd overtone of open organ pipe n  3n0 n 

3V 2l 

nc  n V 3V  4l 2l  l   6l l  6  20 l   120 cm

42.

y1  a sin t  y2  b sin  t   / 2  y R  y1  y2  a 2  b 2 sin t    SHM with complitude (4)

43.

Surface tension 

force MLT 2  length L

 Surfacetension  MT 2  Energy   ML2T 2 Velocity   LT 1 S  k Ea V b T c

 RHS    LHS  a

b

c

MT 2   ML2T 2   LT 1  T  M L0T 2  M a L2 a b T 2 a bc M a 1 L  2a  b  0  b   2

T   2a  b  c  2  2  2  c  2 SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

15 1 5 15

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Physics

C  2

 S   k E 'V 2 T 2 44. 45.

The area cross section of conductor is non uniform so current density will be different but the numbers of flow of electron will be same so current will be constant.

L=4 , 800

1cm  1mv 100cm  100mv 400cm  400mv  0.4V V  0.4  8 R 

2 8 8 R

16 160   40 0.4 4

R = 32

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / BIOLOGY

BIOLOGY Q.46 Floral formula is of Solanaceae family hence is of Petunia, Brassica is from Brassicacene family whereas Allium belong to Liliaceac & Sesbania belong to Fabaceae Q.47 The Bt-toxin is an inactive protoxin which is activated due to alkaline pH in the insect gut. Q.48 Vaccines for the following diseases are prepared with following :(a) Tuberculosis - harmones (attenuated) bacteria - mycobacterium Tuberculae (b) Whooping cough - killed bacteria - bordetella partusis bacteria (c) Diphtheria - Inactivated toxin (d) Polio - Harmless virus. Q.49 Trichinella spiralis is viviparous roundworm. Q.50 Genetic engineering approval committee regulates GM research & safety of introducing GM organisms for public services. Q.51 Mannitol is stored food in Phaeophyceae (Brown Algae) Rhodophyceae members store food in the form of Floridean starch. Q.52 Anabaena is prokaryotic blue green alga, showing no true nucleus (nucleoid). Q.53 The mass of living material at a trophic level at a particular time is standing crop. The inorganic substances present at a trophic level at a particular time is called as standing state Q.54 Monocot stem has open and scattered vascular bundles. Roots in monocots have radial vascular bundles. Q.55 Vestibular apparatus (otolith organs ie. utricle & sacculus & semicircular canal) help in maintaining body posture, equilibrium & balancing the body. Thus it will help gymnast to balance its body upside down even in total darkness. Q.56 Runners - in Cynadon Offsets - in Eicchornia & Pistia Bulbils - in Dioscorea Q.57 In a ring girdled plant, since phloem is removed, translocation of food does not take towards roots, so root dies first. Q.58 Horizontal distribution of different species occupying different levels in a biotic community is known as zonation. Q.59 Newly cooled lava, Bare rock & newly created pond  Primary succession. Q.60 Spermatogonia i.e. sperm mother cell is diploid whereas spermatids, first polar body and second polar body are Haploid. Q.61 Formation of abnormal ova i.e., 22 + XX in the mother will lead to birth of human baby with ‘XXX’ genotype. Q.62 Nectar & pollen are floral rewards to the animal pollinators which are used by animals like bees as food. Q.63 Gastric juice of infants contains Pepsinogen, Lipase, rennin Q.64 Active form of Entamoeba histolytica feeds upon erythrocytes , mucosa and submucos of colon. Q.65 Ribosomes  60 to 65% rRNA 30 to 40% Protein SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / BIOLOGY

Q.66 Tropical rain forest shows striated vegetation because of which most animals are tree dwellers Q.67 Zinc, Cu, Manganese, selenium & boron are micromolecules. Q.68 Erythropoiesis starts in liver in foetus. Q.69 The competitive inhibitor increases the Km of the enzyme for the substrate. Q.70 Capacitation refers to process occurring in uterus in which changes occur in sperms which helps to enable them to fertilize - ovum. These include Dilution of inhibiting factors in semen. Removal of cholesterol layer (galea) on acrosome. Increase in permeability of membrane to Ca 2 Q.71 Methanogens in cow & buffalo guts are helpful for partial digestion of cellulose (which is a major constituent of grass) Q.72 Guava & Cucumber - epigynous china rose - Hypogynous Q.73 Regulation of lac operon by repressor is referred to as negative regulation. Q.74 In aves skin is non glandular, in mammals pinnae is absent in whale, cyclostamata paired appendages are absent. Q.75 Alleles or Allelomorphs are the two (or more) alternative forms of a gene (factors), controlling same characters occuping identical loci (positions) or homologous chromosomes these terms were coined by Bateson. Q.76 Cytochromes which are Iron containing electron acceptors are present on cristae of mitochondria, helpful in ETS. Q.77 Agaricus is saprophytic fungus (Not parasitic) Phytophthora belong to Phycomycetes Mucor belong to Phycomycetes. Q.78 Because of more success for food, population of B shows increase in no. of individuals Q.79 The United Nation Climate Change Conference was held in Durban South Africa from 28 November to 11 December 2011 to establish a new treaty to limit carbon emissions. Q.80 Rise in CO2 concentration stimulates chemoreceptors present in aorta and carotid artery which stimulates respiratory centre. Q.81 Brunner’s glands are present in the submucosa of duodenum and secrete mucous. Q.82 Epinephrine / Adrenaline is a hormone - a chemical signal that has both endocrine and neural roles. Q.83 A fluid connective tissue, constituents of which are blood is plasma plus blood cells ie. RBC, WBC & platelets. (ie. plasma plus blood corpuscles) (55% plasma & 45% corpuscles) Q.84 During muscle contraction actin filament slides over myosin filament, where none of them shorten in length. Q.85 Tissue culture, seed bank & cryopreservation are ex- situ conservation Sacred groves, National park, wildlife sanctuary is in-situ conservation. Q.86 Transpiration cause water to rise in plants by pulling through xylem components Root pressure causes water to rise in plants by pushing water in xylem elements Q.87 Platypus is an egg laying mammal. 118 8

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / BIOLOGY

Q.88 A technique of micropropagation is somatic embryogenesis (which forms clones Of ex-plant in the form of embryo) Q.89 Rough endoplasmic reticulum produces nuclear envelope in telophase. Q.90 Blood pressure in the mammalian aorta is maximum during systole of the left ventricle, because blood is pumped into aorta under high pressure. Q.91 Hysteroctomy is removal of uterus (Hystera means uterus) Q.92 Prolactin has no role in parturition, it helps in lactation process, (lactogenic hormone), development of mammary glands (mammotropin) & maintainance of corpus luteum (leutotropin). Q.93 A population will not exist in Hardy - weinberg equilibrium if individuals mate selectively as mutation , non-random mating and genetic driff affects equilibrium. Q.94 Glenoid canty of scapula articulate with head of humerus. Q.95 Translocation is reciprocol of chromosomal segment between non-homologous chromosome. Movement of gene from one linkage group to another is called crossing over. Inversion : - When a piece of chromosome is removal & rejoined in reverse order, its known as inversion. Duplication : In this mutation deleted chromosomal segment is attached to its normal homologus chromosome. Here a gene or many genes are repeated twice or more times in the same chromosome. Q.96 Flattened membranous sacs  Thylakoids Stack of thylakoids  Grana Q.97 In Geitonogamy pollen grains are transferred between two different flowers on the same plant. Eg Maize. Q.98 Encephalitis is not a sexually transmitted disease. Q.99 Sigmoid curve shows 3 major phases like initial lag phase, exponential log phase & steady or stationary phase Q.100 Because of greater elongation of cells on shaded side, it makes the plant bend towards light source. Q.101 Polyethylene glycol & sodium nitrate increases fusion of protoplasts & hence can be used as fusogen in somatic hybridization or protoplast fusion. Q.102 Rough ER - Production of proteins. Whereas smooth ER is the site for synthesis of lipids & glycogen. Q.103 Recombination (crossing over) is the most common mechanism of genetic variation in the population of a sexually reproducing organism. Q.104 Bryophytes and pteridophytes have an independant gametophyte. In spermatophytes gametophyte is reduced and dependant on sporophyte Q.105 Honey is made by bees by nectar (regurgitation & evaporation). Q.106 The chromosomes in which centromere is situated close to one end are Acrocentric, if it is at the centre - metacentric, near to the centre - sub - meta centric, at one end - Telocentric Q.107 Selaginella is heterosporous producing micro & megaspores. Coralloid roots in Cycas have Anabaena . Q.108 Polysomes are Polyribosomes, attached to mRNA. Q.109 Levitt (1954) proposed Active Potassium Transport theory in which stomatal movements (opening & closing) is because of influx & efflux of K+. SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | 19 SION | THANE | LOKPURAM (THANE) | DOMBIVLI 1 9 | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR | 19

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / BIOLOGY

Q.110 Arthroidal membrane joins terga , sterna and pleura of cockroach body. Q.111 Homo habilis has the smallest brain capacity of 650-800cc. Homo erectus has capacity of 900 cc Homo sapiens has capacity of 1350 cc Homo Neaderthalis has capacity of 1400 cc. Q.112 Since cambium is absent, Vascular bundles are closed and secondary growth is not seen. Q.113 After S phase, amount of DNA gets doubled but number of chromosomes remain same Ga mete (n) Single

Chromosome number Amount of DNA

Cell (after S phase) (2n) Four times

Q.114 In cryopreservation, genes/gene pools are stored at -196oC under liquid nitrogen which is an advance ex-situ conservation of bio diversity. Q.115 The hilum is a scar on the seed where funicle was attached. In many of the seeds like mungbean, pigeon pea it is very district. Q.116 Chargaff’s rule A = T, G = C

C = 17% So G = 17%

A+G =1 T+C

A + G + C + T = 100  A + 17 + 17 + T = 100  A + T = 100 – 34

Since A = y

So A = 33%, T = 33% = 66 Q.117 Multiple alleles are present on the same locus of the chromosome Woman B

Q.118 Man A [ I AI A / I AI O ]

[ I BI B / I I O ]

Progeny I A I O I B I O

I AI O I O I O

A

B

AB

O

Q.119 HIV that causes AIDS, first starts destroying helper T - cells. Q.120 Transmission tissue is characteristic feature of solid style which helps in directing pollen tube. Q.121 The rate of production of organic matter during photosynthesis is gross primary productivity. Q.122 Chikungunga virus is transmitted through aedes aegypti mosquito and does not get transmitted through semen. Human immunodeficiency virus, hepatitis B virus & Ebola virus are sexually transmitted disease, thus are transmitted through semen. Q.123 Exoskeleton is responsible for diversification of insects on land. Q.124 Keel is a petal in vexillary aestivation which is a characteristic of family Fabacae Tomato-Solanaceae.Tulip and Aloe-Lilliacea. Q.125 Seven pairs of contrasting characters in pea plants , were studied by mendel is his experiments.

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / BIOLOGY

Q.126 Renin does not favour for the formation of large quantities of dilute urine as it activates RAAS ( Renin angiotensin activating system) so it causes reabsorption of sodium which leads to formation of concentrated urine. Q.127 Language comprehension is the function of wernicke’s area of parietal lobe of cerebrum. Q.128 Due to depletion of stratospheric ozone, there is increased risk of skin cancer, damage to cornea, conjunctiva etc. as well as reduces our immune system. Q.129 Glyphosate is a herbicide and crops are engineered for glyphosate are resistant/tolerant to herbicides (By which main plants can be kept safe while using glyphosate as weedicide in fields). Q.130 Removal of proximal convoluted tubule from the nephron results in lack of reabsorption of high threshhold substances from renal tubules, and obligatory reabsorption of water is also affected leading to more diluted urine. Q.131 High value of BOD  water is highly polluted. Because of presence of high amount of organic matter number of organisams increases which increase demand for oxygen. Q.132 Option (3) suggest correct match. Q.133 In Opuntia leaves become modified into spines to reduce the rate of transpiration. Q.134 Silent spring  Pesticide pollution. The book documented the detrimental effects on the environment-particularly on birds of the indiscriminate use of pesticides. Q.135 Sprirogyra shows morphological isogamy, physiological anisogamy where male gamete is motile but not having flagella Polysiphonia belong to Rhodophyte which is characterised by non-motile male gametes (non-flagellated)

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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CHEMISTRY Q.136 S

Cl O

O

O

O

O

O

O

O N

O=C O

O

O

 2  ClO3 & SO3 are isoelectronic and are pyramidal

Q.137 Its nucleophilic substitution reaction. It follows SN2 mechanism. Q.138 Molality of solution of x = molality of solution of y = 0.2 mol/kg by elevation in boiling point relation Tb  iK b m or Tb  i  Tb of solution of ‘x’ > Tb of solution of ‘y’  ‘i’ of solution of x > i of solution of ‘y’  solute ‘x’ undergoing dissociation

Q.139 By Arrhenius equation k  Ae  Ea / RT

ln k  ln A 

Ea RT

on plotting ln k vs

1 T

lnA lnk

slope = -Ea/R

1/T  By knowing slope activation energy can be determined.

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Chemistry

Q.140 It is an alternating polyamide copolymer of glycine  H 2 N  CH 2  COOH  and amino caproic acid  H 2 N  CH 2 5 COOH  and is biodegradable

O

O

O

H 2 N  CH 2  C  OH  HN CH 2 5 COOH   H 2 N  CH 2  C  NH  CH 2 5 C 

n

H Nylon -2-nylon-6 Q.141 CH 3 O3   CH 3  Zn , H 2O

OHC CH 2

CH 3

CH 3

C

C

H

O

CH 2

K sp

Solubility

Ag 2CrO4

1.1 1012

S

AgCl

1.8  1010

S  K sp  1.34 10 5

AbBr

5  10 13

S  K sp  0.71 10 6

AgI

8.3  1017

S  K sp  0.9  10 8

Q.142 Salt

3

K sp 4

 0.65  104

 solubility of Ag 2CrO4 is highest it will precipitate last.

Q.143 Order of bond order O2   1s 2 *1s 2 2 s 2 * 2 s 2 2 p z2  2 p x2   2 p 2y 



*

2 p x2   * 2 p1y 

Bond order =



no.of electronsin BMO-no of electrons in ABMo 2

10  7 3   1.5 2 2

O2   1s 2 *1s 2 2 s 2 * 2s 2 2 p z2   2 p x2   2 p 2y 



*

2 p1x   * 2 p 0y 

Bond order =

10  5 5   2.5 2 2 SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Chemistry

O22    1s 2 *1s 2 2 s 2 * 2 s 2 2 pz2  2 p x2   2 p 2y 



*

2 px0   * 2 p y0 

Bond order 

10  4 6  3 2 2

Order ofbond order : O22  O2  O2 Q.144 Magnetic moment =

n  n  2  B.M.

where n = number of unpaired electrons  2.84  n  n  2  B.M.

 2.84 

2

 n  n  2

8  n 2  2n On solving n = 2

only Ni 2   Ar  3d 8 4s 0 has 2 unpaired electrons. Q.145 Electronic configuration of Fe 2 is  Ar  3d 6 4s 0  Number of ‘d’ electrons = 6

Ne – 1s 2 2 s 2 2 p 6  6  p electrons  Mg – 1s 2 2s 2 2 p 6 3s 2  6  s electrons  Cl – 1s 2 2 s 2 2 p 6 3s 2 3 p 5 11  p electrons 

 Ar  3d 6 4s 2  6  d electrons  Q.146 Order of bond order O2   1s 2 *1s 2 2 s 2 * 2s 2 2 p z2  2 p x2   2 p 2y 



*

2 p x2   * 2 p1y 

Bond order 



no.of electrons in BMO-no of electrons ABMo 2

10  7 3   1.5 2 2

O2   1s 2 *1s 2 2 s 2 * 2s 2 2 p z2   2 p x2   2 p 2y 



*

2 p1x   * 2 p 0y 

Bond order =

10  5 5   2.5 2 2

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Chemistry

O2   1s 2 *1s 2 2s 2 * 2s 2 2 p z2  2 p x2   2 p 2y 



*

2 p1x   * 2 p1y 

Bond order 

10  6 4  2 2 2

Order ofbond order : O2  O2  O2 Q.147 Al2  SO4 3  2 Al 3  3SO42  Volume of Vant Hoff’s factor i = 5

K 4  Fe  CN 6   4 K    Fe  CN 6 

4

i  5

K 2 SO4  2 K   SO42  i  3 K 3  Fe  CN 6   3K    Fe  CN  6 

3

i  4

Al  NO3 3  Al 3  3 NO3  i  4  Q.148 Metal nitrates are usualy not found as nitrates in their ores because they are highly soluble in water. H



–

Q.149

+

 O + CH 3 Li  + –

Li O  CH 4

Q.150 Sodium pump used for conduction of signals from brain to organ and vice versa. In which Na+ and K+ are exchanged. Q.151 There are 4 bond’s, hence total  -electrons are 8. Q.152 for ‘n’ order reaction t1/ 2  C01 n

where C0 is initial concentration of reactant. for first order reaction n = 1, half life is independent of intial concentration Q.153 Edge length a = 361 pm, effective number in unit cell = 4 (given)

 It is a FCC structure  face diagonal = 4r

 

2 a  4r r

2  361  127 pm 4 SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Chemistry

Q.154 We know G  G 0  2.303RT log Q but at equilibrium

G  0 , Q  k G 0  2.303RT log K Q.155 Let the masses of H2 and O2 be x g and 4x g

nH 2 x/2 4    Molar ratio  nO2 4 x / 32 1 3

Q.156 1) Co  NH 3 6  Cl3  Co  NH 3 6   3Cl  2) Co  NH 3 3 Cl3   Co  NH 3 3 Cl3  1

3) Co  NH 3 4 Cl2  Cl  Co  NH 3 4 Cl2   Cl  2

4) Co  NH 3 5 Cl  Cl2  Co  NH 3 5 Cl   2Cl  so Co  NH 3 3 Cl3  does not ionize so doesn’t give test for chloride ions. Q.157 R  P

K

 P eq  R eq

 1.6 1012 

 P eq  R eq

  P eq   R eq

so mostly the products will be present in the equilibrium mixture. Q.158 CH 2  CN  2 H N  C C C  N

 6  4 

H O

 4  1 

O=C O-H

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O Xe

 4  4 

O

O O

 3  4 

N  C C  N Q.159 Co  CN  6 

3

Co3   Ar  3d 6 eg orbital t2g orbital CN– is using strong field ligand so zero unpaired electrons are present. Q.160 For the Idoform test there must be a terminal CH 3 group, similarly for the Tollen’s test CHO group is required. Hence, as per question the structure would be O CH 3  CH 2  C  CH 2  CH 3 Q.161 In keto - enol tautomerism the keto form should have   hydrogen (I & II) H3C

CH3

H3C

CH3



I)

OH

O

CH3 CH3 

II)

CH3 CH3

O

OH

In IIIrd ketone

H  H  III) 

CH3 CH3 O

CH3 CH3 OH

here  H participates in tautomerism SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Chemistry

Q.162 Bithional functions as antiseptic. Q.163 The enthalpy of hydrogenation is inversely proportional to stability of alkene III  II  I Q.164 Allylic and benzylic halides show high reactivity towards SN1 reaction.

H + + H 3C  C  CH  CH 2  Cl  CH 3  CH  CH  CH 2  H 3C  CH  CH  CH 2  Cl  Q.165 Down the group solubility of sulphate of alkaline earth metal decreases because of increase in lattice enrergy gradually. NO3

NO2

NO2

NO2

Hybridisation

sp 2

sp 2

sp 2

sp (linear)

Bond angle

1200

 1200  1200 1800

Q.166 Species

so NO2 has maximum bond angle. Q.167 PN 2  Ptotal  PH 2O  725  25  700mm WN2 

PVM 700  40  28  RT 760 1000  300  0.0821

 0.042 g

% of Nitrogen 

0.042  100 0.25

 16.573%

Q.168 NaHSO3 is used as food preservative as it produces SO2 on decomposition which checks the oxidation of food. Q.169. Electrophilic addition takes place via more stable carbo cation. HBr C6 H 5  CH  CH  CH 3  

C6 H 5  CH  CH 2  CH 3 Br (O )

Q.170 1.

( III )

Fe  H 2O   Fe2O3  H 2 Steam (O )

( III )

2.

Moisture Fe  O2   Fe2O3. x H 2O

3.

CuSO4  Fe   FeSO4  Cu

4.

Fe  5 CO   Fe CO 5

(O )

(O )

( II )

(O )

 During formation of Fe  CO 5 oxidation number of Fe doesn’t change. 228 8

RAO IIT ACADEMY / Medical - UG / AIPMT - 2015 / Solutions / Code : H / Chemistry

Q.171 For ideal solution Pobs  PRaoult

P  0

H mix  0

S mix   ve

Vmix  0 Q.172 due to lanthanoid contraction Zr (Zirconium)and Hf (Hafnium) have almost same atomic radii. Q.173 Tyndall effect is the scattering of light by sol particles. which can’t be affected by charge on them Q.174 Under weakly acidic conditions Nitro benzene on electrolytic reduction gives aniline but under strongly acetic condition we get p - aminophenol. NO2 NHOH NH 2

-

4e 4H+

-

2e 2H+ weakly H+ (strongly) NH2

OH Q.175 There is no   H in the structure I and II Q.176 The enolic form of ethyl acetoacetate has 16 single bonds (= 16 sigma bonds) and 2 double bonds (equal to 2 sigma and 2 pi bonds) Q.177 Ar, K & Ca belong to the same period. Being Nobel gas radii of Ar is heighest. We also know for isoelectronic species size decreases with increase in positive charge of the ion. Q.178 Angular momentum of electron in ‘d’ orbital  l  l  1

h 2

 2  2  1

h      2  

 6 Q.179 In Fuel cell energy of combustion is converted into electrical energy. Q.180 CH 3 CH 3  C  Cl CH 3

CH 3   CH 3  C   Cl 

(more stable due to 9 hyper conjugation structures & 3 +I

CH 3

groups)

SANTACRUZ | ANDHERI | GOREGAON | KANDIVALI (E) | KANDIWALI (W) | BORIVALI | BHAYANDER | VASAI | POWAI | DADAR | SION | THANE | LOKPURAM (THANE) | DOMBIVLI | KALYAN | PANVEL | KAMOTHE | NERUL | SANPADA | KHARGHAR |

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