arXiv:0707.3052v1 [math.MG] 20 Jul 2007

EXTREMAL PROBLEMS IN MINKOWSKI SPACE RELATED TO MINIMAL NETWORKS K. J. SWANEPOEL Abstract. We solve the following problem of Z. F¨ uredi, J. C. Lagarias and F. Morgan [FLM]: Is there an upper bound polynomial in n for the largest cardinality of a set S of unit vectors in an n-dimensional Minkowski space (or Banach space) such that the sum of any subset has norm less than 1? We prove that |S| ≤ 2n and that equality holds iff the space is linearly isometric to ℓn ∞ , the space with an n-cube as unit ball. We also remark on similar questions raised in [FLM] that arose out of the study of singularities in length-minimizing networks in Minkowski spaces.

1. Introduction In [LM] Lawlor and Morgan derived a geometrical description for the singularities (Steiner points) of a length-minimizing network connecting a finite set of points in a smooth Minkowski space (finite dimensional Banach space). In Euclidean space the geometrical description is equivalent to the classical result that at a singularity three line segments meet at 120◦ angles. See also [BG], [M] and [CR] for a discussion of length-minimizing networks and their history. The geometrical description of Lawlor and Morgan leads to extremal problems of a combinatorial type in strictly convex Minkowski spaces. Such problems are considered in [FLM]. In this note we briefly remark on some of these problems and solve one of the open problems stated in [FLM] (see theorem 3). 2. Preliminaries We denote the real numbers by R and the real vector space of n-tuples of real numbers by Rn . The coordinates of a vector x ∈ Rn will be denoted by x = (x(1), x(2), . . . , x(n)). The standard basis e1 , e2 , . . . , en will be used, where ei is the vector for which ei (i) = 1 and ei (j) = 0 for i 6= j. A Minkowski space (or finite-dimensional Banach space) (Rn , Φ) is Rn endowed with a norm Φ. A Minkowski space is strictly convex if Φ(x) = Φ(y) = 1, x 6= y implies Φ(x + y) < 2. 1991 Mathematics Subject Classification. 52A40 (Primary) 52A21, 49Q10 (Secondary). Key words and phrases. Minimal networks, Minkowski spaces, Finite-dimensional Banach spaces, Sums of unit vectors problem. 1

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K. J. SWANEPOEL

We denote by ℓnp the n-dimensional Minkowski space with norm !1/p n X p |x(i)| Φp (x) = i=1

for p ≥ 1, and by ℓn∞ the space with norm

Φ∞ (x) = max |x(i)|. 1≤i≤n

We now state Auerbach’s lemma which relates the spaces ℓn1 and ℓn∞ to an arbitrary Minkowski space in n dimensions. A proof may be found in [Pi, page 29]. Auerbach’s Lemma. For any Minkowski space (Rn , Φ) there exists a linear isomorphism T : Rn → Rn such that Φ∞ (x) ≤ Φ(T x) ≤ Φ1 (x), i.e. (1)

max |x(i)| ≤ Φ(T x) ≤

1≤i≤n

n X

|x(i)|.

i=1

We denote the n-dimensional Lebesgue measure (or volume) of measurable V ⊆ Rn by vol(V ). If U, V ⊆ Rn , then we define U + V = {u + v | u ∈ U, v ∈ V }. The Brunn-Minkowski inequality relates the volumes of compact U and V to that of U + V . A proof may be found in [BZ]. Brunn-Minkowski inequality. If U, V ⊆ Rn are compact, then (vol(U + V ))1/n ≥ (vol(U ))1/n + (vol(V ))1/n . 3. Extremal Problems From now on S will denote a finite set of unit vectors in a Minkowski space. In [FLM] the following type of extremal problems is considered: Find the largest cardinality of S satisfying a selection of the following conditions: P (A) Φ( x∈J x) ≤ 1 for all J ⊆ S (the strong collapsing condition) ′ (A ) Φ(x + y) ≤ 1 for all x, y ∈ S, x 6= y (the weak collapsing condition) P (B) (the strong balancing condition) x∈S x = 0 0 is in the relative interior (B ′ ) (the weak balancing condition) of the convex hull of S See [LM] and [FLM] for the connection between these conditions and minimal networks. In [FLM] it is proved that (A′ ) and (B ′ ) together give an upper bound |S| ≤ 2n for an arbitrary Minkowski space, and |S| ≤ n + 1 for strictly convex Minkowski spaces. In [LM] it is proved that there exist a strictly convex norm on Rn and a subset S of n+1 unit vectors satisfying (A) and (B). |S| = 2n is attained in for example ℓn∞ with S = {±ei | 1 ≤ i ≤ n}, in which case even the strong conditions (A) and (B) hold. However, there are other Minkowski spaces where equality is also attained (see theorem 1).

EXTREMAL PROBLEMS IN MINKOWSKI SPACE

3

This is to be contrasted with theorem 3 where we show that the extreme case for S satisfying (A) and (B) can only be attained for ℓn∞ . Theorem 1. For infinitely many n ≥ 1 there exists a set of unit vectors S = {x1 , . . . , x2n } ⊆ ℓn1 satisfying (A′ ) and the strong balancing condition (B). In particular, such a set exists if a Hadamard matrix of order n exists. Proof. We recall that an n × n Hadamard matrix H consists of (±1)-entries such that HH t = nI, and such matrices exist for infinitely many n (see [vLW, chapter 18]). We let v1 , . . . , vn be the column vectors of H, and set xi = n1 vi for i = 1, . . . , n. Then S := {±xi | 1 ≤ i ≤ n} is a set of 2n unit vectors. Since the column vectors of H are orthogonal, hvi , vj i = 0 for i 6= j, implying that Φ1 (xi + xj ) = 1 and Φ1 (xi − xj ) = 1 for all i 6= j. It follows that S satisfies (A′ ) and (B).  The question now is what happens if there is no balancing condition present. In [FLM] an upper bound of |S| < 3n is derived from the weak collapsing condition (A′ ) alone using a volume argument. Using the BrunnMinkowski inequality we obtain a sharper bound (theorem 2). In [FLM] a strictly convex norm and a set S of unit vectors with |S| ≥ (1.02)n satisfying (A′ ) are constructed for all sufficiently large n. It would be interesting to find the greatest lower bound of the α’s for which |S| ≤ αn for any set S of unit vectors in an arbitrary Minkowski space satisfying (A′ ), and sufficiently large n. Theorem 2. If a set S of unit vectors in Rn satisfy (A′ ), then |S| < 2n+1 . Proof. We denote the closed unit ball with centre x and radius r by B(x, r) = {y ∈ Rn | Φ(x − y) ≤ r}, and the volume of a ball of unit radius by β. For distinct x, y ∈ S we obtain from the triangle inequality that Φ(x − y) ≥ 1. Let k = |S|. We partition S into two sets S S1 and S21 of sizes ⌊k/2⌋ 1 and ⌈k/2⌉, respectively. Let Vi = B(0, 2 ) ∪ x∈Si B(x, 2 ) for i = 1, 2. Clearly, each Vi consists of closed balls with disjoint interiors, and therefore, vol(V1 ) = β(⌊k/2⌋ + 1)2−n and vol(V2 ) = β(⌈k/2⌉ + 1)2−n . Using (A′ ) we obtain V1 + V2 ⊆ B(0, 2), and vol(V1 + V2 ) ≤ 2n β. By the Brunn-Minkowski inequality we now have 2β 1/n ≥ 21 β 1/n (⌊k/2⌋ + 1)1/n + 12 β 1/n (⌈k/2⌉ + 1)1/n > β 1/n (k/2)1/n , and |S| < 2n+1 .



From the above proof we actually find that if Φ(x) = Φ(y) = 1 and Φ(x + y) ≤ 1 imply Φ(x − y) ≥ r > 1, then |S| ≤ 2(1 + 1/r)n + 1 for S satisfying (A′ ). Such is the case for ℓnp : It follows from the Clarkson inequality [C] for p ≥ 2, and the Hanner inequality [H] for 1 < p < 2, that r may be taken to be 31/p for p ≥ 2, and (2p − 1)1/p for 1 < p < 2. For ℓn1 an upper bound |S| ≤ 2n holds: If the coordinates of two unit vectors x and y have the same sequence of signs, i.e. sgn(x(i)) = sgn(y(i)) for all i = 1, . . . , n, then Φ1 (x + y) = 2, contradicting (A′ ). In the Euclidean

4

K. J. SWANEPOEL

case ℓn2 we of course have |S| ≤ 3, independent of n. For ℓn∞ the sharp upper bound |S| ≤ 2n holds: If |S| ≥ 2n + 1, then by the pigeon-hole principle there are three vectors x, y, z ∈ S and an i ∈ {1, . . . , n} such that |x(i)| = |y(i)| = |z(i)| = 1. Some two of these vectors will have the same sign in the ith coordinate, and their sum will then have a norm of 2. In [FLM, problem 3.7] the question is asked whether the strong collapsing condition (A) on its own gives an upper bound for |S| that is polynomial in n. A linear upper bound may be derived by the same technique as in theorem 2. We partition the elements of S except for at most 2 into subsets S1 , . . . , Sk of size 3, where k = ⌊|S|/3⌋. For i = 1, . . . , k let [ [ B(x + y, 12 ). Vi = B(x, 21 ) ∪ x,y∈Si ,x6=y

x∈Si

From (A) it follows that each Vi consists of 6 balls with disjoint interiors, and V1 + · · · + Vk ⊆ B(0, 12 k + 1). By the Brunn-Minkowski inequality we obtain 1 1 1/n k, and k ≤ 2/(61/n − 1). Therefore, |S| ≤ 6/(61/n − 1) + 2 < 2k + 1 ≥ 26 (6/ ln 6)n, after some calculus. This bound is not sharp, however. In the following theorem we derive the sharp upper bound |S| ≤ 2n. Theorem 3. Let S be a finite set of unit vectors in a Minkowski space (Rn , Φ) satisfying the collapsing condition (A). Then |S| ≤ 2n, and equality holds iff (Rn , Φ) is linearly isometric to ℓn∞ , with S corresponding to the set {±ei | 1 ≤ i ≤ n} under any isometry. Proof. By Auerbach’s lemma we may assume (after applying a linear isomorphism of Rn ) that for any vector x ∈ Rn the inequalities (1) hold, with T now the identity. Choose m distinct vectors x1 , . . . , xm from S. By (1) we have n X |xj (i)| ≥ 1 for all j = 1, . . . m. (2) i=1

Suppose that for some coordinate i ∈ {1, . . . , n} we have n X

xj (i) > 1.

j=1 xj (i)≥0

Then Φ(

m X

xj ) ≥

j=1 xj (i)≥0

m X

xj (i)

j=1 xj (i)≥0

by (1), contradicting (A). Therefore, (3)

m X

xj (i) ≤ 1 for all i = 1, . . . n,

j=1xj (i)≥0

EXTREMAL PROBLEMS IN MINKOWSKI SPACE

5

and similarly, m X

(4)

−xj (i) ≤ 1 for all i = 1, . . . , n.

j=1 xj (i)≤0

From (3) and (4) it follows that from (2) we have m≤

(5)

Pm

j=1 |xj (i)|

n m X X

≤ 2 for all i = 1, . . . , n, and

|xj (i)| ≤ 2n,

j=1 i=1

and |S| ≤ 2n. If |S| = 2n for some set of unit vectors S = {x1 , . . . , x2n } satisfying P (A), then equality must hold in (5), (3) and (4). Therefore, 2n j=1 xj = 0, showing that in the extreme case the strong balancing condition (B) must be satisfied. We now show that conditions (A) and (B) together with the assumption |S| = 2n imply that (Rn , Φ) is linearly isometric to ℓn∞ , and S corresponds to {±ei | 1 ≤ i ≤ n}, as claimed in [FLM]. We recall theorem 3.1 of [FLM]: If (Rn , Φ) is a Minkowski space and S is a set of unit vectors satisfying (A′ ) and (B ′ ), then |S| ≤ 2n, and if equality holds, then S corresponds to {±ei | 1 ≤ i ≤ n} under some linear isomorphism. We therefore have S = {±xi | 1 ≤ i ≤ n} where the xi ’s are linearly independent. We first show that if (Rn , Φ) = ℓn∞ then S = {±ei | 1 ≤ i ≤ n} must hold. For i = 1, . . . , n choose ji ∈ {1, . . . , n} such that |xi (ji )| = 1. After renaming, we may assume xi (ji ) = 1. The ji ’s must be distinct, otherwise (A) is contradicted. We may therefore rename the xi ’s to obtain xi (i) = 1 for i = 1, . . . , n. If we have xi (j) 6= 0 for some i 6= j, then either Φ∞ (xi + xj ) > 1 or Φ∞ (−xi + xj ) > 1, contradicting (A). Therefore, xi (j) = 0 for all i 6= j, and we have S = {±ei | i = 1, . . . , n}. To show that in fact (Rn , Φ) is linearly isometric to ℓn∞ , we use the following theorem of Petty [Pe] (see also [FLM, theorem 2.1]): If T is a subset of a Minkowski space (Rn , Φ) such that Φ(x− y) = 1 for all x, y ∈ T, x 6= y, then |T | ≤ 2n , with equality iff (Rn , Φ) is linearly isometric to ℓn∞ . P We will apply this theorem to the set T = { i∈A xi | A ⊆ {1, . . . , n}}. Obviously |T | = 2n . We now show that X X (6) Φ( xi − xi ) = 1 for all A, B ⊆ {1, . . . , n}, A 6= B, i∈A

i∈B

thus completing the proof. Firstly, we have X X X X Φ( xi − xi ) = Φ( xi + −xi ) ≤ 1 i∈A

i∈B

i∈A\B

i∈B\A

6

K. J. SWANEPOEL

by (A). Secondly, A \ B 6= ∅ or B \ A 6= ∅, since A 6= B. We assume without loss that A \ B 6= ∅ and choose j ∈ A \ B. Then X X X X 2 = Φ(2xj ) ≤ Φ( xi − xi ) + Φ( xi − xi ) i∈A

i∈B

X X ≤ Φ( xi − xi ) + 1, i∈A

i∈B∪{j}

i∈A\{j}

i∈B

showing that (6) holds.



For strictly convex norms the bound in the above theorem should perhaps be |S| ≤ n + 1, but this seems to require a new idea. References [BG] [BZ] [C] [CR] [FLM]

[H] [LM]

[M] [Pe] [Pi] [vLW]

M. W. Bern and R. L. Graham, The shortest-network problem, Scientific American (January 1989), 66–71. Yu. D. Burago and V. A. Zalgaller, Geometric inequalities, Springer-Verlag, Berlin, Heidelberg, New York, 1988. J. A. Clarkson, Uniformly convex spaces, Trans. Amer. Math. Soc. 40 (1936), 296–414. R. Courant and H. Robbins, What is Mathematics?, Oxford Univ. Press, Oxford, 1941. Z. F¨ uredi, J. C. Lagarias and F. Morgan, Singularities of minimal surfaces and networks and related extremal problems in Minkowski space, Discrete and Computational Geometry (New Brunswick, NJ, 1989/1990), DIMACS Ser. Discrete Math. Theoret. Comput. Sci. 6, (J. E. Goodman, R. Pollack and W. Steiger, eds.), Amer. Math. Soc., Providence, RI, 1991, pp. 95–109. O. Hanner, On the uniform convexity of Lp and ℓp , Ark. Mat. 3 (1956), 239–244. G. R. Lawlor and F. Morgan, Paired calibrations applied to soap films, immiscible fluids, and surfaces and networks minimizing other norms, Pacific J. Math. 166 (1994), 55–83. F. Morgan, Crystals, networks, and undergraduate research, Math. Intelligencer 14 (1992), 37–44. C. M. Petty, Equilateral sets in Minkowski spaces, Proc. Amer. Math. Soc. 29 (1971), 369–374. A. Pietsch, Operator Ideals, North-Holland, Amsterdam, 1980. J. H. van Lint and R. M. Wilson, A Course in Combinatorics, Cambridge Univ. Press, Cambridge, 1992.

Department of Mathematics and Applied Mathematics, University of Pretoria, Pretoria 0002, South Africa E-mail address: [email protected]

arXiv:0707.3052v1 [math.MG] 20 Jul 2007

We prove that |S| ≤ 2n and that equality holds iff the space is linearly isometric to ℓn. ∞, the space with an n-cube as unit ball. We also remark on similar questions raised in [FLM] that arose out of the study of singularities in length-minimizing networks in Minkowski spaces. 1. Introduction. In [LM] Lawlor and Morgan derived ...

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