3017
111111111111111111111111111111
March 2013
(for Scheme I Candidates only) Second Year Higher Secondary Examination Part- Ill
BIOLOGY Maximum : 60 Scores Time : 2 Hours Cool off time : 20 Minutes Preparatory Time : 5 Minutes Genera/Instructions to Candidates : • There is a 'cool off time' of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further there is '5 minutes' 'Preparatory Time' at the end of the Botany Examination and before the commencement of Zoology Examination. • You are not allowed to write your answers nor to discuss anything with others during the 'cool off time' and 'Preparatory Time'. • Use the 'cool off time' to get familiar with questions and to plan your answers. • Read questions carefully before answering. • All questions are compulsory and only internal choice is allowed. • When you select a question, all the sub-questions must be answered from the same question itself. • Calculations, figures and graphs should be shown in the answer sheet itself. • Malayalam version of the questions is also provided. • Give equations wherever necessary. • Electronic devices except non programmable calculators are not allowed in the Examination Hall. m1m<8~006Ul3ci3
•
• • • • • • •
:
mlrocjlnS:ls crumcwcnm1m o.J606lm (]612J:J§6YT5l~),o cru6C8ru:J§Wd76)J,o 10 m1ml8 oJ'lcmo 'cf3-:,Jcf6 63:Jn.Ov 6)6)So' ~6ml:Jco51Cll1c£}6)J,o. ci3-:,~S:J6)(15) (]612J:J§6ffi1 o.JCllldhS:1~ (](l()n91o
:J 6ffiv. g;Q"' (] ru §c!3-:,gl am (]..2J :J Bj 6l5B cJ6cfr6) ~ M'm Cllo 04) \f'J, (15):JC] ffi:J, ffi 86§§ClJ CllJ,ffi:Jco5J Clr@CIClW oJlmlmcwo mscnm:JC8m:J o.J:JSl~. ~cnmro6"15BcJ6 04)\f'J,m>J,nnm>lm ffi6mJ C8..2J:JBjb15BcJ6 ®BD:Jo.JJffi<]do ru:Jco5Jc!76)6ffio. 04) ~:J (]..2J :J Bj 6"15B cfbc£}6)6o ~Mm (Q o 04) \f'6(15)6ffi o . 63ro6 (]..2J :JBjmcru ro ~cnmro6l m\jl6m:Jon 6)(1l)(l)6)611l'Tm s 6cnm6 cf3-:, I:?J6Ylml):Jam ~o.J (]..2J:JBj6l5B~o ffi)l)(]® C8..2J:JBj mcruro1am mlrrn m>6lnn 6l®ro6l611l'TmSJ,C]c£}6)6Tr5cm:J6YT)'. cf3-:,6ffic£}6)v c!3-:,J§e.!J,c!3-:,cf6, .!l.f1Lm>6mcJ6, l(f):Jn.OJ,c!3-:,cJ6, o.mrrn1ru ~cnmro C8o.J<;tj01am ®6lrrn ~ 6ml:Jm51 rol c£}6)6ffio. (]..2J:JBj6mcJ6 ffie.JW:J§Mmle.JJ,o mamc!3-:,lm513J,G'f@. Clr@ClJ CICljffi6§§ ffiill eJ coro) cru mru :Jcf3-:,j6l5B cJ6 6)cf3-:,:JS6c£}6)6ffio. C8Lo.J:JL(I):Jffi6cf3-:,cJ6 6lill
1
111111111111111 T 1111111
PART- A
Maximum Score : 30 Time: 1 Hour Cool off Time: 10 l·Ainutes
BOTA~JY
o.ffi o Lm.Jl <8 w o cru odWJ1 m7> , cru1 oVt1
1. After syngamy and triple fusion
m1c6il!Jp LS1c;t:j1u7> n..O~o.9::lffiJp
in embryosac embryo will be
<8UO(b ·o
~6f@Jcfu6(ffi l!5~6IDO ()JJ1
diploid and endosperm will be (Score: 1)
(Score: 1)
2. In honey bees and some lizards female gamete undergoes development to form new
n..Oi 6) mw1 m7>
organisms without fertilization.
n...J6 ®1 w ~i oJl cfu ci7> ~ 6115 ocfu6 em
This phenomenon is called
Ln...J lcfu1CQ)6)CQ) - - - - - o.B)ITnu
C0 o mt=fl
(Score: 1)
0t m1 on6 o
(Score: 1)
3. Final community that is in near
3 ~&OO~~~mm7>~caJeJl
equilibrium with environment in
L6QJ1 w (1)(6)1 m s6C6YID 6 m1 m7> dW! 6on
ecological succession 's called
rm 00)1 mcfutii1lJ?,6ID1RJ6)(Q) _ _ __ n..g1 err) oJ1~~on6.
(Score: 1)
(Score : 1)
4. Morphologically and genetically simila r individuals are called (Score: 1) (Score : 1) 3017
-2-
111111111111111111111111111111
5. Natural interlinked food chains are called
(Score: 1)
5. o.J (()
mro.J (() 0
6Y2J mJJ 6) <;8 3u cfu1 s cOO6ffi)
ffi'@ynf)J(()CJ0006lJ~ cfu6)~
----
ntj)CTTl oJl~~Jo.
6 MOET is a programme for herd improvement. Expand MOET.
6. MOET
(Score: 1)
ffi0(f)615B6)~ @ill~@<;tjS6(0®6
ruJcfO ~~~ o.JBD®1COJJ6IT).
MOET
ntj) 6) (ll)) (ffiu oJl CJO B ill J cOO6 cfu .
(Score: 1) 7. A novel strategy to prevent nematode infestation is based on
(Score: 1) 7. @ffiillC8RJCW6cfu~@S ffi©lcfuill6m@(O® @_QJ06cOOJm6~~ m4cmm oJlBj
RNA
gQ ~ (0 n.O 0 cfO ffi)u mm s1 cru..o J mill J cOOl
'RNA interference'.
COJJ6ffi.
a) Explain RNA interference.
a) RNA gQ ~& n.o o cfO emu ntD 6) ml) ffi'Ju ru1uoBillJc006cfu.
b) Can you suggest, how it can be used for producing nematode resistant plant.
(Scores: 2)
b) gQ'D Lo.JLcfulCOJ@COJ @ffiillC8RJCW6cfu@~ 6)_QJ06c006ffi'J 6)_QJSJce:,cm ~®uJBlc;dl cOOJcfO ntj)615B@ffi ~o.JC8COJJCJ5lcOOJ @ill("TT) [email protected]@<;tjSJ
?
(Scores: 2) 8. Read the statements below and 8. ®J@\j) @cfuJS6(0®1co1c006ffi'J Lo.JCQ?Jrum
identify the mode of interaction
cfu em
(lJ J
COJ1 ~u'
emi crl1i ffi) 6cfu ~ 6) s
between the species.
o.J(()ffi)uo.J(() 6Y2JmDo ®1(()1~o1COJ6cfu.
a) Tiger eating deer
a) cfuS6ru mJm1@m e5cfhl51c006ffi'J6,
b) Butterfly feeding pollen
b) o.JJ@
c) 63-9Jlarn cfuJ6m@<;tjS6ffi'J Human c) Human liver fluke feed on snail d) Lice on humans
3017
liver fluke. d) mm6n.91jco1arn cfuJ6ffi6)ilis6(T() cso.Jcm.
llllllllllllllllllllllllllllll e) ~dh9::l(OI0)1am ill§.ffiJ,on 638&G001cu.r
e) Orchid attached to a tree
f) 6) ..!2J s1 cfu ~ 6) s cg (lJ ffi1 am cfu 8 6TT)
f) Mycorrhizal association of fungi
@ 6) 6) 0 cru am ffim(g(fU8
and roots of higher plants
cru1 (g(Q)n9:l cfO.
g) Sparrow eating seed
g) oJl wm) cs cfu91l G006on cfuJ, ffiJ, oJl.
h) ce:,on6cfu8eJlcfucg§8S cg..!2Jfficr-n' cfu::>6TD
h) Egrets foraging close to cattle
6>cfu881 ce:,cJb.
(Scores: 2)
(Scores: 2)
9. acru::>o....01 ADA deficiency offion 9. Sophie was born with a genetic ~ m1 ® cfu
6) 6) (lJ cfu eJ j cg (010) 8 6) s (Q) 8 6TT)u
disorder- ADA deficiency. n.J1oon®.
a) What is ADA deficiency ?
a) offimn86ffi ADA deficiency ?
b) Can you suggest methods to
b) ADA deficiency
treat this ADA deficiency ?
G008m6§§ ru~ce:,cib m1fficgC3(/(n
(Scores: 2)
(Scores: 2)
10. A list of organisms are given. Place
.!211ce:,1arru1
10.
sl1o.Jlce:,~6)S
63ffi6 cruJ.!2..f1ce:, ®86)~
~ cfu8SJ,(010)1 roJ G006 on6. @2ClJ @(Q)
them in different trophic levels. Grass, Man, Fishes, Birds, Lion,
:ilS 8 o....01 cfuu eJ (lJ e.JJ, cfu §.1 eJ 8 (Q)1
(Scores: 2)
@ ffi 0
."511 m1 GOO6ce:,.
"....J6 §[,
Grasshopper, Zooplankton, Trees.·
oJl oJl W
mm6 n91j cfO, mi cfO, n.J cfu91l ce:,cib,
~.:'\ 0 o.Do' n.JJ, am~ 8Sl ' cruJ g.d ::>cfu"sG'riO' :--_ :thl16m3 cJb.
(Scores: 2) 3017
111111111111111111111111111111
11. In summer we use air conditioners and in winter we use heaters. Here
11. (]OJffiffi'Oc008e.J((5)'TI)u ffi80 %)CWC0cfu6l1Si citlffi02,cfu~o, ffi6W®2,clb8e.J~ nDiR06 cfu§?,o ~nJ<8CW8W1c006Cffi6. ®8nJm1e.J
homeostasis is accomplished by m1cwtcrn1c008rro m8o cfu~l®1m m8ffic&
artificial means. Explain four ways 60136>~
by which other living organisms gt6i
cope with the situation.
CU'©@CW1c006<8mJ8cm
o..n cfb em
~ cm1 m8
mn
ffi86
~nJ (] w 8w1
c002, em m8e.J6 OJ<#lce:,cm oJl OJ co1 c002,ce:,.
(Scores :2)
(Scores :2)
12. (J)(]OJnS16m ffil08nJm6013g1lco'O 12. Plant breeding programmes are
~®jG..go
lcfbffi8ffi6~®G..gffi8Wl
carried out in a systematic way in
(] lnJ 8l(j) J ffi6 cfb cfO ms
research organizations. Explain
gJJ~ tm1lru5l6151'3 OJ~ 63C06 n.J6®lcm ~mo
main steps in breeding to produce a new genetic variety.
(Scores: 2)
~@nJ:JB1~ cfu60l..gJ' oJlcroBJce:,ffilcOO:J<8m8
?
(Scores: 2)
13. Environmentalists usually says:
13. 6)6)gt60J6>6>0JoJlwjo
m~6>cJ:jS:Jcm
nJe.J cfb:)(06ffi6013~6)6l1S(l"T') nJC01
'There are many causes for OJ8B1 cfucm rrumffi®D1 c0080661"@. 6>6>gt60J
biodiversity losses'. Illustrate four major causes of biodiversity loss. (Scores: 2) 3017
6>6>0JoJlWjo mnS:!S6>cJ:jS:Jffi6~~ ffi:Je.Ju cfb:JC06m6m3 cfO oJl croBi ce:,co1 c006cfb.
(Scores: 2)
111111111111111111111111111111
14. Jaya read in a Biotechnology book
14. nJ60
that alien DNA can be introduced
(010)1 am 6) 6) m(g Lcmo ~em~ cfu9:j em OJ~ cw6o 6YlJ(gCW8e.llmcfu'm5' OJ ~CW6o LnJ(gOJCf01
into host cell by micro injection and
c£}£)86)Q:l(l"f) ~CW 63ffi6 6YlJ(gCQJ861Scfu(gffi0 ~
biolistics. Explain these methods.
w nJ6cw em (010)1 am
OJ ornfl c£}£)6em cw6
61158CW1. ~'TI lnJ lcfu1CW cmcJD om 6)(10)('1'1)
(Scores: 2}
(Scores : 2)
OJ1croB"1cmr6lc£}£)6cfu.
15. Species diversity decrease from
15. C5~a:lWj<8ffi6lJ<8CWc£}£)8cJ0 LWJ,OJ6013~1aft
equator towards poles. Ecologists
6161~0J616IOJOJ1Wjo cfuJ,OOJ8m51 cfu86ffi
61 ~ SJ, em6. ~
proposed various hypothesis.
o_J1 CfO Bl cfu ro1 c£}£) 8 em
nJ ro1
Suggest two hypothesis for this phenomenon.
mr
LnJ ®1 rs::>(ll)o o11 CfO~cfur6lc£}£)oem ro61'1i
(Scores: 2}
cn5l B.l):)(YQ)60BcJD ml ffi
16. Genetic Engineering include
16. ~m18lcfu' om6@2.]lffilcwc5160Y3lam, 610m5'LSl
creation of recombinant DNA with
cfu9:j
em om em 6) 6) \fl.) m6cfu§6 6) s \fl.) o..o o CQ)
(g(OY0)861S c51
the help of restriction enzymes.
DNA ~61150
c£}£)6(ffi6·
a) Explain recombinant DNA
,.
a) o1
nmcmoam nm ('115)' ?
technology.
b) 6) o (ll)VLs1 cfu9:j em om em 6) 6) \fl.) o b) What are restriction enzymes?
ng)(ffi8aTh ng)(YQ)u ? 63ffiJ, 6)0\fl.)ulSl
Name a restriction enzyme.
cfu9:j
(Scores : 2} .
3017
-6-
em
o.tD em 6) 6) \fl.) m161 ~ (g nJ rou
o.tl)l96®6cfu.
(Scores : 2)
111111111111111111111111111111
17. i) nJ6~® CTUCTUj0613~am nJ(()0(f)6ID
17. i) Flowering plants evolved an
(010)1mow1 nJe.Jruw ®Om6cfu~e.Jm
array of adaptations to achieve
0613 ~ 6'f"'@.
pollination. a) nJ(()O(f)6IDo O{j)6Jml)m) OJ1C!OB"l
a) Explain pollination.
cfu(()1 c006 cfu.
b) cfuls0613cfD OJ(jSJW6o cfuOA OJ(jS]w6
b) Point out adaptations found
ffi6§§ nJ(()O(f)6ID(010)1m6
in flowers for insect pollination
cru cruj 6m3~ am cfu o6ID 6)
and wind pollination.
®0 ffi6 cfu~e.J m
0613 cfD o.ffi6l ml)(ffiv
ffi)~_!l]~c006cfu.
c) Illustrate pollination in
c) OJ 0 ell ffi)v<8 m o1 (Q) w1 am cfu 0 6ID
Vallisnaria~
6l
OR
cfu(()1 c006cfu.
OR
ii) Artificial hybridization is one of
ii) c9Jl®lm6fl1lg16 cruefue.Jmo OJ1§ OJffiBD
the major approa:hes for crop
mo.nmoW6§§ 63(()6 LnJWom (()J®1
improvement programme. In
wo6ff)'. ~ro LnJLc.fulwCQ)]am ®OmOOJC!Oj
such crosses it is important to
o.J~ 6l ffiJ os1 cfu6l § 63 (jSJ OJ o
avoid unwanted pollen.
OJ§6l(() ®0®jOOJC/0jffiOGffi a) mBCJ)'Q)6J(Q) ®OffiOOJC!Oj ~6lffiJOSl
a) Explain how can we protect
cfu~am mlrrn6o Offi06136lm CTUo(()~
stigma from unwanted pollen c0006)Q)m) o.J1C!OBlcfuc6lc000<8Q)0 ?
b) How artificial pollination can be performed?
3017
b) cB:v)L®1m6J21lg16m>Cfue.Jmo ms(010)6
(Scores : 4)
cm6l®6m36lm ?
-7-
(Scores : 4)
llllllllllllllllllllllllllllll Maximum Score : 30 Time: 1 Hour Cool off Time : 10 Minutes
PART -8
ZOOLOGY 1. g16ffi1(Q)cfu
1. The flow of genetic information is shown below.
oJlOJm(0'®16)~
LnJOJ8o.D(f)@1
wo6lD ..2J2,0J6)s c&86ml8Jlm1~rrn®.
a, b,
Name the processes a, b, c
C,
d o.g)mli
LnJ®1!58(fl)6N3~6)S
(]nJ6)(0192,@2,cfu.
and d.
(Scores : 4xY2=2)
(Scores : 4x%=2)
2. ~'Dg16ffi1ffi)1ffi)16)mw6o 6)cma)(1l(]R8g16m
2. The
following
compares
(11)1 ffi)16)ffiCQJ2, o (0)8 (0 @ffijo 6) ..2J qffi rrn
statements
the
process
LnJ CW80Jmc&gl am (f()a)l w ~8(0'®®'
of
oogenesis and spermatogenesis.
om®?
Which one is not true ?
a) ®0<26inD8amnJoBmo 63ffi2, m1®11® LnJow®0)1 am ml e.1 ~rrn6 . CJ.ffirrn8am
a) Production of ovum ceases at certain
age,
but
(f()2,<2~8amnJ8Bmo LnJ8Wmow o.J6ffi6
sperm
citlffi1e.J2,o ®2,Sffi2,ml2,.
production continues even in old men
b)
LIS~ 6m8 OJ ffilO cWl
am
but
6) rrn (0)6s 6N36rrn6. 6) em &m(] 8 8 g16 m1 (11)1 m) ffi'© 61i0c&63l wro <:11 m8
spermatogenesis starts at the
OJ ffiill cWl6) eJ (0'®2, <2 cru 8 cJ0 m8 L(Q) <2m
onset of puberty
®2,56N36~·
b) Oogenesis begins in the embryonic
3017
~'D g16 m1 (11)1 m)
stages,
((5)
-8-
111111111111111111111111111111
c) Meiotic arrest occurs both in Oogenesis and spermatogenesis d)
d) Polar bodies are formed in oogenesis.
gyo~rr51m5lcru1ro'O
cB:JcJ6 §2ro'OnJ oc31
(Score: 1)
(Score: 1)
3. @nJcu5lLu51.LLJoffi§
3. Identify the traits from the pedigree
®1ml..gJo1mu 63J
chart. Give one example each.
(Scores : 1 + 1 = 2)
3017
§2BOn.Dffi6TDo o.1l ®o Clfj) ':96 ®6cfrJ. (Scores : 1 + 1 = 2)
-9-
111111111111111111111111111111
4. _QJ2/lJ6JS
4. Arrange the following examples
6TD60l36J~
under two heads viz-homologous
6)cfu8SJ,~1ro1~rrn ~B8o..Offi
homologous organs
nffirrDJ,o analogous organs nffirrDJ,o
organs and analogous organs.
ro 6nSJ,l(!)~ CJ:JOW1 lce:,mi ce:,ro1 ~ce:,.
(Scores: 2)
(Scores: 2)
Forelimb of whale and bat,·kWings of butterfly and bat,>'.\ Heart of man and cheetah, Eyes of octopus and mammals.
5.
5. ''Nature does a lot of service for
loJ~®1, CTD8mJ~1cfuQ)~eJj<8ill8 oJleJ
which an economic value or price
cru~..nJl cfu
tag can be put". Substantiate giving
woroo~o
examples.
o..0 ro6TD 60Bcf0 mco'Oce:,1 cruo w~ ce:, ffi1 ~ ce:,.
(Scores: 2)
6J...QJ~rrDJ,. ~88
(Scores: 2) 6. A poultry farm manager was cursing
6. ®6JcVl oJ'DcfOLS1n.Oom1co'O,
his hens for producing lion share
oJ~OJcf0<8cfu81§lcfucfO ~61@80J8cf0 cfu8(()6ffi
of cocks in its progeny. Hearing
mo CQJ16J d%)8 6n51 ro1 d%)2, rrn ® ~~
this, Kumar- farm attender starts
n.08o ®ORcfOM08CQJ cfuJ,illOfO, ®J,SfO~
to blame his wife for delivering
CQJ :_) CQJ1 6) oJ Ei'fffi cfuJ, §1 cfu cJ0 d%)v
consecutive girl children. Analyze
~ cfO Q) 0
m co'Oce:,1 CQ! ® 6J cVl cs oroJ6JCQ! cfuJ, 86J'J:j SJ,
the situations scientifically and state
~6rrDJ,. gQ'D ®OOJ
whether you agree with Kumar.
m o CQJ1 ru1 CRJ ce:, eJ m o
6J ...QJ
<:ill6 ce:, .
cBJJ,moc516J~ ®O@lloJOCQJ
(Scores: 3)
3017
cs~ro1cs8Cf)0JJ,o
-1o-
?
(Scores : 3)
7. .DJl 21
Some bioactive molecules, their source
and
their
6ill cg(Q)o
((J©ceJ oJ em cro mol®cfucfO,
®0QJ(Q)6 6)S Cl@O®C&\f, ®OQJ (Q)66)S
medical
6)6)QJ BjC!OOl~o.J (() ffiO(Q) lo.JOW:)ffi jo
importance are given in the table
ntj) rrn1 OJ CQ>06ffi' _Q_J6 OJ 6)S CQ)6§§ o.J §1 cfu
below. Fill up the missing parts.
CQ>1am 6)cfuOs6((l!O)lro1~rrn®. ru1§6Clo.JOCQ>
csowo o.J~ro1c,B1~cfu.
(Scores: 2)
Bioactive Molecule
a
Source
Medical Importance
Streptococcus
Removes clots from blood vessels
Cyclosporin-A
b
(Scores : 2)
c I
Monascus Purpureus
d
Blood Cholesterol lowering agent
8t'Most often HIV infection occur due to conscious behaviour patterns. Do you agree with this statement ? Substantiate your answer.
m1e>m§66)S ~(OfO)(()o
(Scores : 2)
(Scores : 2)
3017
-11-
llllllllllllllllllllllllllllll 9. Lactose
9. Given below is the figure showing
6)~ croocm1BJJj®m1m'n
lac
functioning of lac operon in
operon @~ LoJruro®mmo cfuJOOc006cm
presence of lactose. Redraw the
.£LJ1L®o o..TI61r56o rum..gJ 1 ffi6®m'O 6 ClJ@ffi
figure and label the parts numbered
am> cOO 6m ~ 31 m1 c006 em
(Scores : 3)
1 to 6.
(ELL®TfTOl
?f
i
am>SCQK)~@<;tjS6®m6ce,·
·1 i
@
J(f) 615l3 cJD
(Scores : 3)
I o- :I
~
~
l l
10. loJ~@l CQ)l affi
10. Nature has as many varieties of
()1) ()1)
plants which give drugs for abuse,
63"0<1.91 W615BcfD
maffice,6(ffi
J 6m ~@. ~ (l5)6~ oJ J 6) eJ
(l5)
6) (ffi '
as th~re are medicinal plants which
Q:lCWc006 Q:lffi6(ffi6cfu~JCQ)l B6ffi6oJ~CW0Cf)o
give medicines. Substantiate with
6) .!2..l ~ oClJ6 em
two examples.
ru CW6 cOO cJD
® ffi6 em
6).!2JSJce,~o WOffiO~ffi66f@. mGr@ ~BO
(Scores: 2)
nDffi6ffi6mciD mamcfbl
(Scores: 2) 3017
-12-
111111111111111111111111111111
11. ®06)\j> nJ0
11. Suggest the ART which may be successful
OJ1~WlnJBmoa:wceuJo~cm ART
in the following
ml&a:<3cr6lc6UJ6c£b. conditions.
a) 63ffi6 a) A female cannot produce ovum,
l
ro'0<86ffiDOMo.JOBffio
cruou5lceuJ6m~.
nmcmom'O
mTI~
cru an eJ mcom1 m6 o cru1 cfr(Q) o6ffiD
but can provide suitable
(0)'())16)~ oJ1 cm"l S6§.§.
OJ §.&-3::1 ~ o
environment for fertilization and (G'@ OJ~J mow
cru oon ...!lJ ro-' 60B em
further development.
cruowJlll061D. b) Male partner is unable to
b) o.Jc!,ffi6crl1o.Jano§l~ sperm count
inseminate the female or has
OJ §. 6) (() cfu6 0 OJ 06nf rom 6) ~ ab1am l
very low sperm count.
(On))OcTO c) Fusion of gametes and zygote
ffi) ab eJ
m0 m s
ffi'©OJ6tm1~.
c) l
ffi) abe.J
formation does not occur within
mOJ6 o m5l cf7®o6ffiD(l}fl5)l6)~ ~amo.Jo
the body of the female.
Bm OJ6 o l
(Scores : Y2 + Y2 + 2 = 3)
(Scores : 1f2 + Y2 + 2 = 3)
3017
-13-
1111111 111111111111111 11111111
12. ~m1emc& OJCW6 o.{f)rrn m1eJc:illlro1> RNA
12. RNA is not an ideal molecule as
63(()6
genetic material because
Q)Jem~c&JnJ(()Q)JCQ) emcfDmOLemCW~.
nti)C'®66lc&O 6)6f@ffiJOmTl, a) 6l6l0<86DJOCTU16l~ 2'0H l(J)4<~:f
a) 2'0H group of ribose is reactive
(0J®1(0JOJ~<8e.Jffi6x;:8S6ffiJCID6
and make it labile
m4e.Jo RNA -CW66lS ne.~sm~ moRo cmocso.Jl~rrn6.
b) It is catalytic and hence reactive
b) RNA 63ro6 roocmemJroc&mocmem1mom1>
LnJ®ILnJruro®mm®"051<8eJro6l<;i:ls6rrn6.
c) Both (a) and (b)
c) (a) cm6o (b) cm6o d) None of the above
(Score: 1)
d) <8Q)roTlnJ06m'I'IDOJ 63\ffi60
®()~.
(Score: 1)
13.
13. The diagram represents a process
(J)Offi<88o~m1cm1m}l6Jm
6l _!2_] ~em of gametogenesis. Closely observe
LnJem1ffi1womo
~ Lem o em4~ mocill1
m1 rol
dhl:ll . g,l em J 6l ~ 6l c& os 6®m1 ro1 c£MJ6rm
it and answer the following.
(g_!l_]JBj60Bc.iDcOO' ~®mroo mm1>c&6c&.
a) Is it spermatogenesis or Oogenesis?
W0<86ffi0 CTU4~
b) <8 o.91 cmvcu.) 6l _!2_] ~ 6l _!2_] o1 em
b) What does the smaller shaded
6<5Bcm nti)C'®16lm
circle represent ?
7
-14-
OJ~ MID
cm4~c;J~rrn6?
111111111111111111111111111111
c) <&cd1cQrcwu
c) Write down two significance of
@_QJ~ 6)_QJ01w Cl.J00115)
6m3 cJO ffi) ~..2Sl ~~em cs J (f) 6<5T3 cJD
production of the same.
~6TYSJClJ6rffi®16)~ 2 lnJJWJffij
(Scores : % + % + (%x2) = 2)
OOBcfO o.ffiljl6®6cfu.
(Scores : % + Y2 + (Y2x2) = 2)
14.
14. cm1wo1 63Jru:l o.ffi6YlJ<&WJ~m1
Theory of chemical evolution is a
63ffiJ lo.JcfuJffi<&C5G!IlJ6T'ri' ®1W01 63Jo..Ou
version of theory of abiogenesis.
6) cfu m1 cOO afn
Analyze the statement.
o.ffi (lJ eJ ~ cd1 em . g}2 'U
lnJCWJrum
(Scores :2)
ms0115)Jcfu. 15.
"Conservation of biodiversity is a
15. "6)6)~(lJ6)6)ClJoJlWj ffi)offidhl::16mo C1{j)~J
collective responsibility of all
ffiJld!161lB§S@S(Q)J,O cfuJaJW ~0115)ffiOJJGl
Nations". Write a slogan stressing
0115) mJ orr)'." 6) 6) ~OJ 6) 6) OJ oJl WJo ffi)offi
the significance of biodiversity
cB:Mi <&~6TY5®16)~
conservation.
~'Drmcin mcincfu1 63ffi6 11l6lBJOJJcfujo
(Score : 1)
o.ffi\j)6®6cfu.
3017
(Scores : 2)
-15-
ln.JJWJm jC0'®1 mu
(Score : 1)
