BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com IBPS CLERK PRELIMS 2016 – ALL INDIA MOCK TEST – 2 Solution Key QUANTITATIVE APTITUDE 1). 120×(70 / 100) = 84 , 70×(60/100) = 42, 110×(60/100) = 66 40×(55/100) = 22, 160×(60/100) = 96 Total number of boys in College A = 84 + 42 + 66 + 22 + 96 = 310 (116/100) ×50 = 58, (72/100) ×50 = 36, (100/100)×(100-51) = 49, (60/100) ×(100-65) = 21, (116/100)×50 = 58 Total number of girls in College B = 58 + 36 + 49 + 21 + 58 = 222 Difference between number of boys in College A and number of girls in College B = (310 – 222) = 88 Answer: d) 2). 110×(60/100) = 66, 100×(51/100) = 51, 96×(50/100) = 48 100×(57/100) = 57, 116×(50/100) = 58 Average number of boys studying in Electronics stream in all five colleges = (66 + 51 + 48 + 57 + 58) / 5 = 280 / 5 = 56 Answer: e) 3). Number of girls in Telecom stream of College D = (50/100)×(100-56) = 22 It's total students = 50 (22/50)×100 = 44 Answer: c) 4). 80×(65 / 100) : 65×(60/100) 80 : 60 = 4 : 3 Answer: c) 5). Number of boys of Civil stream of College A = 160×(60/100) = 96 Number of girls in Electronics stream of College C = (96/100) ×50 = 48 [(96 – 48) / 48] × 100 = 100 6). The series is 232, 292, 312, 372, …. Answer: e) 7). The series is +32, +52, +72, +112, +132,…. Answer: a) 8). The series is +120, +128, +136, +…. +160, …. Answer: c)

9). The series is ×1 + 2, ×2 + 4, ×3 + 6, ×4 + 8, ×5 + 10, ×6 + 12,……. Answer: b) 10). The series is -3, -9, -27 ,-81 -243, …. Answer: e) 11). ? = (4800 – 120) × 2.532 = 4680 × 2.532 = 11849.76; Approx = 11850 Answer: a) 12). ? = [(1.5129 + 5.4756) / 1.11] × 10 = (6.9885 / 1.11) × 10 = 6.2959 × 10 = 62.959; Approx = 63 Answer: b) 13). ? = [(17 / 100) × 760] + [(57 / 100) × 79] + 77.77 = 129.2 + 45.03 + 77.77 = 251.82; Approx = 252 Answer: d) 14). 36 √? + 32√? = (68 / 11) × (?) If ? = 121, then √? = 11 36 × 11 + 32 × 11 = (68 / 11) × 121 748 = 68 × 11 ? = 121 Answer: d) 15). ?=(3.2)2 + (9.8)2 + (8.13)2 + (4.24)2 = ? ? = 10.24 + 96.04 + 66.0969 + 17.9776 = 190.354; Approx = 190 16) C)10.2 4.6+(9.8*2)-14 = 10.2 17) D)31 256 + 729 – 24 = 961 = 312 18) B)1179 3(46-16) + (36-3)3 = 90 + 332 90+ 1089 = 1179 19) A)30256 22×248×122 = 665632 665632/22 = 30256 20) B)1311 399.99 + 1000.9 – 89.999 = 1310.89 = 1311 Short 400+1000-90 = 1310

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BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com 21) E) If X = Y or relation cannot be established 6x2 – x – 2 = 0 6x2 + 3x – 4x – 2 = 0 Gives x = -1/2, 2/3 5y2 – 18y + 9 = 0 5y2 – 15y – 3y + 9 = 0 Gives y = 3/5, 3 Put on number line -1/2 3/5 2/3 3 22) A) If X > Y 3x2 – 4x – 4 = 0 3x2 + 2x – 6x – 4 = 0 Gives x = -2/3 , 2 4y2 + 23y + 15 = 0 4y2 + 20y + 3y + 15 = 0 Gives y = -5, -3/4 Put on number line -5 -3/4 -2/3 2 23) C) If X ≥ Y 3x2 – 4x – 4 = 0 3x2 – 6x + 2x – 4 = 0 Gives x = -2/3, 2 3y2 + 14y + 8 = 0 3y2 + 12y + 2y + 8 = 0 Gives y = -4, -2/3 Put on number line -4 -2/3 2 24) B) If X < Y 2x2 + 17x + 30 = 0 2x2 + 12x + 5x + 30 = 0 Gives x = -6, -5/2 6y2 – 5y – 6 = 0 6y2 – 9y + 4y – 6 = 0 Gives y = -2/3, 3/2 Put on number line -6 -5/2 -2/3 3/2 25) E) If X = Y or relation cannot be established 3x2 – 7x – 6 = 0 3x2 – 9x + 2x – 6 = 0 Gives x = -2/3, 3 4y2 – 11y + 6 = 0 4y2 – 8y – 3y + 6 = 0 Gives y= 3/4 2 Put on number line -2/3 3/4 2 3 26). Let the breath be x meters. Then, length=x+6 meters Now, (x) (x+6) – 5(x+6) =242 or, x2+ 6x-5x-30=242 or, x2+x-272=0

Or, x2+17x-16x-272=0 or, x(x+17) -16(x+17) =0 Or, (x-16) (x+17) =0 X=16, (neglect negative value.) ∴Length=16+6=22m ∴Area of rectangular plot=16×22=352 sq m Answer: b) 27). Let the present age of Sonalika be 5x and that of Manav be 9x. Then, (5x+8) / (9x+8) =7/11 or,55x+88=63x+56 or, 8x=32 ∴x=4 years ∴Sonalika’s age = (5x-3)=5×4-3=17 years Manav’s age =9×4-3=33 years ∴ Sum =33+17=50 years Answer: d) 28). Anamika’s monthly income= (11×43700×2) / 19=Rs.50600 Suman’s monthly income= (50600×60) / 100=Rs.30360 Answer: d) 29). Aggregate marks to pass= [(160+220+240) /100] ×54= (620×55) /100=341 Total marks he scores in the first and second paper=118+84=202 ∴marks required in the third paper to pass the exam=341-202=139 Answer: c) 30). Let the sum invested be Rs. x. And the rate of interest be r. Then, (x×4(r+6)/100) – (x×4×r/100) =3600 or, 4xr+24x-4xr=3600×100 Or, 24x=3600×100 ∴x=Rs.15000 Answer: c) 31). Boat’s upstream speed=7.8×60/18=26 kmph Boat’s downstream speed=15.2×60/24=38 kmph ∴speed of boat in still water=26+38/2=32kmph Answer: d) 32). Total number of balls=3+4+2=9 In (S) =9C2=(8×9/2)=36 Now, for the drawn balls not to be red 2 balls can be selected from (4+3) =7 balls In 7C2ways=(7×6/2)=21 ∴Reqd probability=(21/36)=(7/12) Answer: b) 33). Pipe A should be closed after [1-24/48] ×32=1/2×32=16 minutes Answer: d)

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BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com 34). Number of ways=7! /2! =2520 (∵ R appears twice) Answer: d) 35). Let the original rate be Rs. X. Then, new rate=20% of x=x/5 Now, 300/ (x/5) –(300/x)=5 or, (1500-300)/x=5 or, x=(1200/5)=Rs.240 ∴ Reduced price=(240/5)=Rs.48 Answer: e) REASONING ABILITY

First conclusion directly follows and E>=C doesn’t follow) 49) Answer – 1. Only conclusion 1 follow A=C=D>=E (B = E doesn’t follow always and A>B doesn’t follow) 50)Answer – 1. Only conclusion 1 follow P>=Q=RQ directly follows and P>=T doesn’t follow) 51) Answer – 2 C1A78EU3T2BVZ0SW4GP 52) Answer – 1.$ 17th from the left end – Z and 6th to the left of Z is $

Direction (36-40):

53) Answer – 2 –Z + 0 54) Answer – 3.three 3T$, 0S-, 4G% 55) Answer – 3.@V& In forward direction +3 then +2 (Direction 56-60): 36) Answer-3 37) Answer – 2 38) Answer -4 39) Answer -5) 40) Answer -1) (Direction 41-45):

41) Answer – C 42) Answer – A 43) Answer – A 44) Answer – C 45) Answer – D 46) Answer – 2. only conclusion 2nd follow A>=BE (we cannot say anything about A and E but C>E directly follows.) 47) Answer – 3. Either 1 or 2 follow. (A = B >=C < D = E) 48) Answer – 1. Only conclusion 1 follow A>B=C>D<=E

56) Answer – c) Y 57) Answer – b) P 58) Answer – b) two 59) Answer – a) PQZ P and Q are brothers and Z is the brother of R 60) Answer – b) Brother in law Questions (61-65): In the rearrangements, the words starting with consonants are arranged in alphabetical order from left to right, and the words starting with vowels and followed by a number are arranged in alphabetical order from right to left along with the number in each step. Input: power turn copper every 22 order 34 flower kite inter 29 aptitude 41 hope Step I: copper power turn every 22 order 34 flower kite inter 29 hope aptitude 41 Step II: copper flower power turn order 34 kite inter 29 aptitude 41 every 22

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BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com Step III: copper flower hope power turn order 34 kite aptitude 41 every 22 inter 29 Step IV: copper flower hope kite power turn aptitude 41 every 22 inter 29 order 34 61. Answer: a) 62. Answer: b) 63. Answer: c) 64. Answer: d) 65. Answer: e) 66. Answer: b) 67. Answer: b) 68. Answer: a)

Answer : c) 70). According to the question, the direction diagram will be as follows

Clearly, Radhika’s house is towards South-West from the final position D. Answer : d) ENGLISH LANGUAGE 71. B 72. D 73. E 74. C 75. B 76. D 77. C 78. A 79. B 80. C

69) According to the question, the direction diagram is as follows

81. A 82. A 83. A 84. B 85. C 86. C 87. A 88. B 89. D 90. E 91. E 92. B 93. C 94. D 95. A 96. A 97. C 98. E 99. C 100. E

Clearly, temple is towards South-East respect to Raman’s house.

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