Proof Without Words: The Golden Ratio Roger B. Nelsen ([email protected]), Lewis & Clark College, Portland, OR Theorem. If x > 0 and x = 1 + 1/x, then x = ϕ = (1 +

√ 5)/2.

Proof. 1/x

x 1/x

1 x

1 1 1

1/x

x

1 x

2x – 1

1/x

√ 1+ 5 . (2x − 1) = 5 =⇒ x = ϕ = 2 2

Exercise. Show that ϕ 2 + (1/ϕ)2 = 3. (Hint: In the figure, create a square with area 3 by drawing a diagonal in each of the four rectangles.) Summary. We employ a square with area 5 to determine the golden ratio (without using the quadratic formula). http://dx.doi.org/10.4169/college.math.j.47.2.108 MSC: 97G40

108

© THE MATHEMATICAL ASSOCIATION OF AMERICA

Proof Without Words: The Golden Ratio 108

Proof Without Words: The Golden Ratio. Roger B. Nelsen ([email protected]), Lewis & Clark College, Portland, OR. Theorem. If x > 0 and x = 1 + 1/x, then x = ϕ ...

53KB Sizes 0 Downloads 217 Views

Recommend Documents

Proof Without Words: A Trigonometric Proof of the Arithmetic Mean ...
We prove wordlessly the arithmetic mean-geometric mean inequality for two positive numbers by an equivalent trigonometric inequality. Reference. 1. L. Tan, Proof without words: Eisenstein's duplication formula, Math. Mag. 71 (1998) 207, http:// · dx.

Proof Without Words: Nested Square Roots 204
a + bx, squaring to obtain x2 = a + bx, and solving for the positive root. An alternative method begins by dividing the quadratic by x to obtain x = b + a/x. Theorem.

Proof Without Words: Every Octagonal Number Is the ...
2. M. Benito and J. L. Varona, Advances in aliquot sequences, Math. Comp. 68 (1999), 389–393. ... (2002), Art. 52, 9pp. [http://jipam.vu.edu.au/v3n4/043 02.html].

Proof Without Words: A Triangular Identity
Proof Without Words: A Triangular Identity. 2 + 3 + 4 = 9 = 32 − 02. 5 + 6 + 7 + 8 + 9 = 35 = 62 − 12. 10 + 11 + 12 + 13 + 14 + 15 + 16 = 91 = 102 − 32 ... tn = 1 + 2 ...

Proof Without Words: A Surprising Integer Result 94
Proof Without Words: A Surprising Integer Result. Roger B. Nelsen ([email protected]), Lewis & Clark College, Portland, OR. Theorem. 48 = 47. Proof. Corollary ...

Proof Without Words: Inequalities for Two Numbers ... - Claudi Alsina
CLAUDI ALSINA. Universitat Politècnica de Catalunya. ROGER B. NELSEN. Lewis & Clark College p,q ÷ 0, p ' q = 1 ÷. 1 p. ' 1 q. ' 4 and p +. 1 p. È. ·fl. ‹ ÷'. 2.

Proof Without Words: A Right Triangle Identity 355
Roger B. Nelsen ([email protected]), Lewis & Clark College, Portland, OR. Theorem. Let s,r, R denote that semiperimeter, inradius, and circumradius,.

Proof Without Words: Square Triangular Numbers and ...
Proof Without Words: Square Triangular Numbers and Almost. Isosceles Pythagorean Triples. Roger B. Nelsen ([email protected]), Lewis & Clark College, ...

Proof Without Words: Perfect Numbers and Triangular ...
Every even perfect number, Np = 2p−1(2p − 1) with p ≥ 3 prime, ... T. T p= = 2 –1. 3 +1 p n. T. T. 3 +1 n. = 1 + 9 n. Note that for p odd, 2p − 2 ≡ (−1)p + 1 ≡ 0 ...

Proof Without Words: Perfect Numbers Modulo 7 17
Theorem ([1]). Every even perfect number Np = 2p−1(2p − 1) for prime p = 3 is congruent to 1 or 6 modulo 7. In particular, p ≡ 1 mod 3 =⇒ Np ≡ 1 mod 7 and p ...

Proof Without Words: Perfect Numbers and Sums of ...
Theorem. Every even perfect number Np = 2p−1(2p − 1) with p ≥ 3 prime is the sum of the first n odd cubes for n = 2(p−1)/2, i.e., Np = 13 + 33 +···+ (2n − 1)3 [1].

The relation of the golden ratio with the prime numbers
Item 13 - 453 - [12] F. Close, Antimatter, New York: Oxford University Press, 2009. ... Black Holes & Time Warps, New York: W.W. Norton & Company, 1994.

A Simple Construction of the Golden Ratio
Feb 5, 2007 - is parallel to PQ. Then MN lies between the bases PQ and RS (see [1, p.57]). It is easy to show that MN bisects the area of the trapezoid.

Proof Without Words: A Sine Identity for Triangles Roger B. Nelsen ...
Proof Without Words: A Sine Identity for Triangles. Roger B. Nelsen ([email protected]), Lewis & Clark College, Portland OR. If x + y + z = π, then 4(sin x)(sin ...

Proof Without Words: Sums of Every Third Triangular Number Roger B ...
Let Tk denote the kth triangular number, Tk = 1 + 2 +···+ k. We show that. T3 + T6 +···+ T3n = 3(n + 1)Tn. Proof. I. T3k = 3(k2 + Tk). k. 2. T k. 3k k. 2 k. 2. T k. T k. II. n.

RATIO AND PROPORTION Ratio Ratio of two ... -
the product of the extremes = the product of the means. i.e. ad = bc. 2. Compounded ratio of the ratios (a : b), (c : d), (e : f) is (ace : bdf). 3. Duplicate ratio of (a : b) ...

An Invitation to Proofs Without Words
EUROPEAN JOURNAL OF PURE AND APPLIED MATHEMATICS. Vol. 3, No. 1, 2010, 118-127. ISSN 1307-5543 –www.ejpam.com. An Invitation to Proofs Without Words. Claudi Alsina1 and Roger B. Nelsen2∗. 1 Universitat Politecnica de Catalunya, Secció de Matemà

Download [Epub] Golden Ratio Coloring Book by Artist Rafael Araujo Full Pages
Golden Ratio Coloring Book by Artist Rafael Araujo Download at => https://pdfkulonline13e1.blogspot.com/0646951904 Golden Ratio Coloring Book by Artist Rafael Araujo pdf download, Golden Ratio Coloring Book by Artist Rafael Araujo audiobook downl

108 pedigree.pdf
Rains Miss Longevity E764. ASR/GLS Pacesetter U862. ASR Longevity Y184. ASR Miss Primrose M231. G T Shear Force. SMR Blackcap 8521. NER Blackcap 2104. Hooks Pacesetter. GLS S82. ASR Showcase K053. ASR Miss Fanfare G720. N Bar Prime Time D806. G T Sis

108.pdf
did not allow to distinguish among either cattle groups or breeds. Two Correspondence Analysis Dimensions. computed on qualitative traits (explaining 26.2 and ...