SIGNED PERMUTATIONS AND THE BRAID GROUP MICHAEL P. ALLOCCA, STEVEN T. DOUGHERTY, AND JENNIFER F. VASQUEZ

Abstract. We make a connection between the braid group and signed permutations. Using this link, we describe a commutative diagram which contains the fundamental sequence for the braid group. Mathematics Subject Classification (2010): 20F36, 20B30 Keywords: Braid group, signed permutation, symmetric group

1. The Braid Group The braid group was first explicitly defined by Emil Artin in 1925 [1]. For a recent detailed description of braids see [10] and for a classical treatment of braids see [3]. In the context of our investigation, we will establish a very close connection between the braid group and Japenese ladders. This connection will enhance our understanding of a well-known short exact sequence related to the braid group. We begin by defining the braid group and then relating its elements to signed permutations. The braid group, Bn , is generated by the elements σ1 , σ2 , ..., σn−1 along with with the following defining relations: (B1): σi σj = σj σi , |i − j| ≥ 2; (B2): σi σi+1 σi = σi+1 σi σi+1 , 1 ≤ i ≤ n − 2. The first relation is commonly called far-commutativity and the second the braid relation. There is also the trivial relation, σi (σi )−1 = e = (σi )−1 σi , where e is n straight strands with no crossings, namely it is the identity. Pictorially, we may represent the braid σi as in Figure 1, the ith strand crossing over the (i + 1)st . 1 2

n

i+1

i

···

···

Figure 1. Generator of the Braid Group, σi Even in a small example like B3 , the group can be complex, it is a nonabelian infinite group and corresponds to the fundamental group of the compliment of the trefoil knot [12]. 1

By enumerating each strand, it is fairly intuitive to associate permutations with braids. This can be accomplished by mapping each generator, σi to the transposition (i, i + 1). The kernel of this homomorphism is of particular interest. Definition 1. The kernel of the homomorphism that maps Bn to Sn given by σi → (i, i + 1) is Pn , the pure braid group. Pictorially, Pn consists of the braids in which each strand starts and ends in the same position. The pure braid group plays a significant role in a short exact sequence, which will be discussed in a later section. 1.1. Signed Permutations and Ladders. In the visual representation of a braid, instead of drawing two strands crossing transversely, one may draw vertical lines and a horizontal segment between them. This corresponds to a permutation in Sn , and is sometimes called a Japanese ladder. This representation is not unique, as exemplified in Figure 2. 1

2

3

4

1

2

3

4

3

4

1

2

3

4

1

2

Figure 2. Two ladders representing the permutation π = (1, 3)(2, 4). Ladders lack the distinction between clockwise and counterclockwise crossings. We may equip ladders with this distinction by adding arrows to each rung. We will refer to these as signed ladders. Furthermore, signed ladders provide a visualization of what is called signed permutations. The braid σi corresponds to the signed ladder in Figure 3 and represents sending i → i + 1, i + 1 → −i and j → j for j 6= i, i + 1. Definition 2. A signed permutation is a map α : {1, 2, . . . , n} → {±1, ±2, . . . , ±n} such that if α(i) = k then α(i0 ) 6= ±k whenever i 6= i0 . For those more familiar with Coxeter groups, signed permutations can be viewed in terms of the Coxeter group of type B. See [4, 5, 9]. They can also be viewed as the group of signed permutation matrices and the hyperoctahedral group. Definition 3. Let π be a signed permutation. Consider the sequence: π −1 (1), π −1 (2), . . . , π −1 (n). 2

1

2

···

1

···

-

−(i + 1)

2

n

i+1

i

n

i

Figure 3. Signed ladder representation of σi 1

2

1

2

1

2

1

-

-

-

,

, 1

2

-2

1

2

, -1

-2

2

-1

Figure 4. Realizable signed Ladders on 2 Elements These numbers, at the bottom of the ladder, are the final state and are denoted by [π −1 (1), π −1 (2), . . . , π −1 (n)]. If there exists a ladder with this final state then this final state is said to be realizable. For each signed permutation there are infinitely many signed ladders that correspond to it; however, not all signed permutations are realizable by signed ladders. We let En0 be the set of all signed permutations and let En be the group of signed permutations that are realizable as signed ladders. Figure 4 shows all the realizable signed permutations for n = 2. There are four non-realizable signed permutations in E20 : (1 → −1, 2 → 2), (1 → 1, 2 → −2) (1 → 2, 2 → 1), and (1 → −2, 2 → −1). In general, the signed permutations σi , σi2 , σi3 , and σi4 , which are (i → i + 1, i + 1 → −i), (i → −i, i + 1 → −(i + 1)), (i → −(i + 1), i + 1 → i) and (i → i, i + 1 → i + 1) respectively, are realizable. The signed permutations (i → −i, i + 1 → i + 1), (i → i, i + 1 → −(i + 1)), (i → i + 1, i + 1 → i) and (i → −(i + 1), i + 1 → −i) are not realizable. We shall now determine the cardinality of the group En0 and show how En relates to it. 3

Theorem 1.1. The cardinality of the group En0 is n! 2n , moreover En is normal in En0 . Proof. There are n! permutations on n letters and there are two choices of sign for each of the n letters. To find the size of En , notice that inserting σi2 into a ladder results in multiplying the signs of the ith and (i + 1)st positions by −1, but does not change the underlying permutation. For each permutation, there are n − 1 places to put σi2 giving n! 2n−1 elements in En . The normality follows from the fact that En is of index 2 in En0 .  It can be shown how to transform one Japanese ladder into an equivalent ladder using two different representations of the permutation (1, 3). Namely, (1, 3) = (1, 2)(2, 3)(1, 2) and (1, 3) = (2, 3)(1, 2)(2, 3). This is even more natural for braids. Consider the ladders given in Figure 5. 1

2

3

1

2

-

-

-

-

3

−2

3

-

1

3

−2

1

Figure 5. Equivalent signed permutations They both represent the realizable signed permutation (1 → 3, 2 → −2, 3 → 1). Moreover, this represents one of the fundamental braid relations. Namely, it is simply a visualization of property B2, that is, σi σi+1 σi = σi+1 σi σi+1 , 1 ≤ i ≤ n − 2. Recall the correspondence between a braid generator and a signed ladder by drawing σi as a rung going from left to right. The inverse braid, σi−1 , would correspond to a ladder with the rung going from right to left. Notice that when viewed as signed ladders, σi−1 = σi3 , as illustrated in Figure 6. The ladders would also correspond to the same underlying permutation. This leads us to say that two braids are signed permutation equivalent if their corresponding signed permutations are equal. Alexander’s Theorem states that there is an onto function from the set of braids to the set of links and knots. However, closing two braids might result in the same link so this map is not one-to-one. A natural question is whether two equivalent signed permutations can give two different knots. The answer is yes. For example, we have seen that as signed permutations, σ −1 = σ 3 ; however, the closure of σ −1 is the unknot and the closure of σ 3 is the trefoil. In a signed ladder, every occurrence of σi−1 can be replaced with σi3 making each rung in the ladder run from left to right. Further we say that a braid is positive if it can be expressed 4

1

2

1

2

-

=



-

−1

2

−1

2

σ1−1

σ13

Figure 6. All realizable signed permutations can be written as positive braids as a product of only positive powers of σi , 1 ≤ i < n. Figure 6 shows that every realizable signed permutation can be written as a positive braid. 1.2. A Short Exact Sequence. The usual short exact sequence used when studying the braid group is: 1 −−−→ Pn −−−→ Bn −−−→ Sn −−−→ 1. The kernel in this sequence represents those braids whose underlying permutation is the identity. From the point of view presented here, instead of mapping Bn to Sn , it makes more sense to consider the mapping of Bn to En . Then the kernel, Kn , consists only of those braids whose underlying signed permutation is the identity. This means that not only is the underlying permutation the identity, but all signs are positive. Our new short exact sequence is: 1 −−−→ Kn −−−→ Bn −−−→ En −−−→ 1. To find the kernel Kn , we get our hands dirty and consider the smallest example, n = 2. According to earlier calculations, |E2 | = 4 (see Figure 4) and B2 = Z so K2 should be 4Z. In fact, K2 = hσ14 i, see Figure 7. This can also be seen as Dirac’s belt trick [8], [11] or Feynman’s plate trick [7]. More specifically, it is a physical representation of the fact that SU (2) double covers SO(3). The knot theorist Louis Kauffman has called it the quaternionic handshake. Let us delve into the group E2 . The element σ12 is the signed permutation (1 → −1, 2 → −2). Exploring this further, we notice that while its underlying permutation is the identity, the signs are not all positive. Therefore, it is not the identity as a signed permutation. Notice that σ14 is the identity. This explains why we want σi4 to be in the kernel but we do not want σi2 to be in the kernel. In terms of Kauffman’s quaternionic handshake, the first rung of σ12 is like multiplying by the quaternion i. Then the next rung is like multiplying by the quaternion j and then by the quaternion k since you are not only going over a rung 5

-

Figure 7. Generator of K2 but being multiplied by −1 since you are going across in the wrong direction. In this sense, everything has returned to its original position but has been multiplied by a −1. In general, the group Kn is a bit more complicated. In Figure 8 we have an element of K3 that is not generated by a combination of (σi )4 nor its conjugates. 1

2

3

-

1

2

3

Figure 8. Element of K3 There are infinitely many distinct elements in Pn and Kn for n > 1. For example, consider for any k. As braids, they are distinct but they represent only one element as signed permutations. Juxtaposing the two earlier short exact sequences, we get the following: 1 −−−→ Kn −−−→ Bn −−−→ En −−−→ 1 

 

 y

y (σ14 )k

1 −−−→ Pn −−−→ Bn −−−→ Sn −−−→ 1 6

Given this beautiful commutative diagram, it is natural to wonder how Kn sits inside Pn . There are n − 1 possible spaces between posts to put σi2 which corresponds to 2n−1 cosets of Kn in Pn . The following is an immediate consequence. Theorem 1.2. Let Pn be pure braid group and let Kn be the set of those braids whose underlying signed permutation is the identity. Then we have [Pn : Kn ] = 2n−1 . 1.3. An Explicit Description of Kn . The pure braid group, Pn , is generated by −1 −1 −1 . . . σj−2 σj−1 ai,j = σj−1 σj−2 . . . σi+1 σi2 σi+1

where 1 ≤ i < j ≤ n [2]. We aim to expose a similar construction of Kn and to fully understand the manner in which it sits inside Pn . In order to do so, we must first consider the signs created by all possible final states of a signed permutation. Theorem 1.3. The only allowable final states for a signed permutation, π, adhere to the property n Y (Sign(π(i)) = (−1)par(π) , i=1

where par(π) is the parity of the underlying permutation π. Proof. Each time a transposition is made, one element is multiplied by −1. This implies that the product of the signs of the elements in the final state must equal (−1)r where r is the number of rungs in the signed ladder corresponding to π.  Since every element in Pn and hence in Kn is the identity permutation, which is even, the product of the signs in the final state is +1. That is, there must be an even number of rungs in the ladder corresponding to each element of Pn . We observe that   k 6= m;  k, σm (k) = k + 1, m = k;   −k, m = k + 1. Hence the the signs of the final state of ai,j may be viewed in sequence as [+, +, . . . , +, −, +, +, . . . , +, +, −, +, . . . , +] where the negative signs are in the ith and the j th positions. Therefore ai,j ∈ / Kn . However, 2 th st multiplying ai,j by σi simply multiplies the signs of the i and (i + 1) positions by −1. So, j−1 Y by multiplying ai,j by σk2 , all the signs in the final state will become positive. k=i 2 2 Theorem 1.4. The group Kn is generated by ri,j = ai,j σi2 σi+1 . . . σj−1 , 1 ≤ i < j ≤ n.

Proof. Recall that Pn is generated by ai,j for 1 ≤ i < j ≤ n. By the preceding argument, Y ri,j ∈ Kn . Thus, hri,j i ≤ Kn . Moreover, the cosets of hri,j i in Pn are σi2 , which A⊆{1,...,n}, i∈A

implies [Pn : hri,j i] = 2n−1 . However, [Pn : Kn ] = 2n−1 by Theorem 1.2. Therefore Kn is generated by {ri,j }.  7

Notice, we have a canonical map Pn → Zn−1 , since every strand in Pn ends where it 2 n−1 begins, and Z2 corresponds to possible changes in sign. Further, we have the following diagram: 1   y 1 −−−→ Kn −−−→



1   y

Pn −−−→ Z2n−1 −−−→ 1     y y

1 −−−→ Kn −−−→ Bn −−−→   y

En   y

Sn   y

Sn   y

1

1

−−−→ 1

Acknowledgement. The authors are grateful to the referee for useful comments and insights into the structure of the paper.

References [1] [2] [3] [4] [5] [6] [7] [8] [9] [10] [11] [12] [13]

E. Artin: Theorie der Z¨ opfe, Hamburger Abhandlungen, 4, 1925. V. G. Bardakov: The Virtual and Universal Braids, Fund. Math., 181 (2004), 1 - 18. J. Birman: Braids, Links, and Mapping Class Groups, Annals of Mathematics Studies, No. 82, 1975. A. Bjorner and F. Brenti: Combinatorics of Coxeter Groups, Graduate Texts in Mathematics, 231, Springer, New York, 2005. A. V. Borovik and A. Borovik: Mirrors and reflections. Springer, New York, 2010. S. T. Dougherty and J. Franko Vasquez: Amidakuji and Games, Journal of Recreational Mathematics, 37 (1) (2008), 46-56. R. P. Feynman and S. Weinberg: Elementary Particles and the Laws of Physics: The 1986 Dirac Memorial Lectures, Cambridge University Press, 1987. V. L. Hansen: The Story of a Shopping Bag, The Mathematical Intelligencer 19, (2) (1997). J. E. Humphreys: Reflection groups and Coxeter groups, Cambridge Studies in Advanced Mathematics, 29, Cambridge University Press, 1990. C. Kassel and V. Turaev: Braid Groups, Graduate Texts in Mathematics, 247, Springer, New York, 2008. L. H. Kauffman: On Knots, Annals of Mathematics Studies, No. 115, Princeton University Press, 1987. V. Manturov: Knot Theory. Chapman & Hall/CRC, Boca Raton, FL, 2004. L. Lange and J. W. Miller: A Random Ladder Game: Permutations, Eigenvalues, and Convergence of Markov Chains, Mathematics Magazine, 23, (5) (1992). 8

Department of Mathematics and Computer Science, Muhlenberg College, Allentown, PA, 18104 USA E-mail address: [email protected] Department of Mathematics, University of Scranton, Scranton, PA 18510, USA E-mail address: [email protected] Department of Mathematics, University of Scranton, Scranton, PA 18510, USA E-mail address: [email protected]

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SIGNED PERMUTATIONS AND THE BRAID GROUP 1. The Braid ...

Even in a small example like B3, the group can be complex, it is a nonabelian infinite group and corresponds to the ... For each signed permutation there are infinitely many signed ladders that correspond to it; however, not all signed ..... [2] V. G. Bardakov: The Virtual and Universal Braids, Fund. Math., 181 (2004), 1 - 18.

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