For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014
..
---,
SSC MOCK TEST 2 (SOLUTION) 1. (8) 2. (A)
3.(0)
C
T
D
H
A-E: R-V ::8- F:F-J 1 3 5 18"022 ? 4 6 6""'-' 8'-"""10 .........-..... .._". -..:.; ""t......; .......... 2222 2222
22. (0) OOCTCR 23. (0) ~NCEL 24. (C) B E 25.
(C) MOB
+2
+2
+2
EF~
&1 ..L.!-.3gIg?
7
~~ 5.(0) 13, 10,110~;.Jg~L ~oo
000"'"
j.1JJ +2 +2 +2+2 +2 +2
- -
11. (A)
14 .in
20
gl -c
1820 97
Odd
Otovp
Group
VX
2224
Odd
Qroup
12. (0) T
35
30. (C) In columns
M .1
n
31.(C)
20 17 14 11 8 5 2 25 22 19 16 13 107
w
+3 +3 +3 +3 +3 +3+3+3 +3 +3 +3 +3 +3 13. (0) 14. (0) Yen is the carrency of Japan which is situated in Asian country. Whereas pound (sterling), Outch Mark and Franc are the currencies of Eurpiean countries. 15. (0) Yellow is not present in option '0'. 16. (0) 17. (C) Others are the cube of odd number. 18. (8) 2486 - 85 = 2401 = (49) 2
19 (A)
tD'.~"l
lUm
•
94
J.49 J64
+
+
+
9"""
13
17
,125 J36 J8I
Qroup
Q N K H E B Y V S P
69
ill)
I!:gea
w w
Group
~rr RT
i:
£:
1.2
+2
.s
NP
1416
..=a IG,
sc
repeated ~
Z A M SUM
26. (8) 12 questions, each having 4 parts So total parts are = 12 )( 4 = 48 27. (*) 28. (8) 55 + 66 5 +6 11 )( 3 = 33 and 22 + 99 2+9 11 )( 3 = 33 Similarly, 12)( 3 = 36 44 + 88 4+8 29. (8) In columns 3 2 42 62 + + 52 7' 32 + +
x2+3 x2+3 "2+3 )(2+3x2+3
J:.a
I L E
T·~lLL~tf ff
10~10003
7.(8) 5, 13, 29, 61, 125,253 ......__~ '--"'~
.;;a.
Z
Similarly,
6. (8)61 + 63 = 124 (124.;. 2)-10= 52 Similarly, 94+x=(46+10»(2 94 + x = 56)( 2 94+ x= 112 x = 112 - 94 = 18
9. (C) 10. (A)
Q
'.'\'(.[,(1.. • t f J J J
alLbb/ab_bb/ab_bb
4. (C)
J
~
32. (8)
l' = 1
19-18=1 34 -32 = 2 Similarly, 44 -41 = 3
2' = 4 32 = 9
:6 + 2 J4+ 2)"- 36
~oo+7 J3+ 7t = 100 ~) 33. (C) 5,
5 }2+ 5)" = ~ 11,
24,
51,
106,
217
x2+1 x2+2 x2+3 x2+4 x2+5 34.(8)3917 3526 3174 2857 I +I +1 +
LOa
201m! 20. (A) Roshan > Susheel > Hardik > Niza > Harry 21. (A) POINTER
-391 I
-352 +1
+39 1-4
www.ssc-cgl2014.in
-317 ,.
+35 ..
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014
---,
============================================.== 35. (0)
_3
51. (0)
3 4
3 Ian
x
3
Oistance=4+3+4+5
3 7
=
1
1
5
8
8 5 3 =-_=40 40 Thus time taken by leakage 40 1 = = 13-Hr
3
2x
3 4
2x =10 x =5 52. (B) Number of digits in the square root of 62478078 = 4 53. (C) 10 men = 20 women = 40 children Now, 5 men, 5 women and 5 children = 5x 4 children,5 x 2childrenand 5children. = (20 + 10 + 5) children 40 children can complete a work in 7 months. 1 child can complete a work in 7 x 40 months 35 children can complete a work in
7 40
--
3
w w
.s
sc
38. (A)
1 4
54. (C) After 50 days, work left =
-c
= 13 Hrs, 20 m 37. (0) Both the conclusions do not have relation with the statement.
= 8 months 35 half work is completed in 4 months
20
36. (A) Rate of leakage
.!. work is completed
1 work is completed in 50 days by 200 1work is completed in 1 day by 200
3
- work 4
is
completed
in
x
4
x x
50
days
!=
4 50 x 300 men 100 4 Additional men required = 300 - 200 = 100
w opposite appoaite oppoalte and it baa been
4
100
55. (B) Work completed by A in 1 day =
According to dice
3 4
- work
1 -
in 50 days by 200 men
4
200
Only conclusion - III follows
(A) (0) (B) (C) (A)
4
14 .in
-16km
2x
gl
SIan
2x
_3
7
3 4
4
B
42. 43. 44. 45. 46.
4
-
4ian
39. (B) 40. (C) 41. (0)
3
3
7
4 3
4
4km A
3
IJ
of (5 - 4) of (3- 6) 16 of (1- 21 5 given in option A 8
1 18 1
Work completed by B in 1 day =
15
Work completed by B in 10 days
= -
1
15
Work left =
1
2 3
10
2
-work
1
'3 3' work
1 work is completed by A in 18 days 47. (A) 48. (B)
~ work is completed by A in
49. (C)
= 6days
50. (A)
www.ssc-cgl2014.in
18
1
3
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 56. (8)
100 5 100
SP = 80 x
=
----------
100 5 100
80 95 95 722000 100 100 = 10000 ::; ~ 72.20
t
60. (0) MP = 1600. Two successive discounts = SP = f 1224 ATQ.
Let x unit be the side of the square
Circumradius
1
"2 x
1
100 20 100
(a) SP. = 100 x 1
-x
1
= _2_=_ 1
J2
T2x
-c
8
sc
2' height = 21 cm 1
Vol. of the cone =
3 8
2
w w
1
x
21
-x
88 100
-x-
92 100
Successive discount of option (8) is better.
= -ems
62. (A) A=
outer radius (radius of the circular ground including circular road) r2 inner radius (radius of the circular ground only) ATQ.
3
150 100 C=
"2C
58. (8)r.
2'1
2
r2
125 5 B=100C="4C 3
5
-C--C 2 4
A-B=
= 66 ::;
6C
5C
4
C
::;-
4
% Larger of A as compared to 8
"-'2
66 7
=
100 12 100
607200 = 10000 = t 60.72
w
112
75 100
=100x
64
"3 4""""2
=
100 25 100
100 8 100
21
2
612000 - t61.20 10000
(b) SP2=100x
.s
r =
=
gl
=8
2,
57. (C)
100 15 x 100
80 85 90 100 100 100
= 100 x
J2
Required ratio = 1:
x
100 10 100
20
inradius circumradi us
100 x 100
x
1224 100 100 = 100 - x 1600 90 85 =10Ocx = 15% 61. (8) Let MP = ~ 100
"2 x diagonal
=
100 10 100
1224 = 1600 x
side of the square
14 .in
Inradius=
~ 10% and x%.
21
22"2="2
C
Width of the road = r. - r2 =10.5 ern 59. (8)MP = ~ 80 Two successive discounts of 5% each.
www.ssc-cgl2014.in
= 54
-C 4
100 = 20%
x
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 = 10 m/s Length of the train = speed )( time = 10 x 10 = 100 m Length of the plateform = 55 m Time taken by the train to cross the
63. (A) Let the three numbers be x, 2x & 3x respectively. Then, x + 5 : 2x + 5 : 3x + 5 = 2 : 3 : 4
x
5 2 = 2x 5 3 4x + 10 = 3 x + 15 x=5 Three numbers are 5, 10, 15. 64. (0) Let the initial average age of 10 teachers be x years. Total age of 10 teachers = lOx ATQ,
lOx - Retired teacher
T
25
;;......;.;;......;.;;.;.;;.,;;;;.;; ....1 .... 0..;.;;..;;.;.;;.;;;;......;.......;.;;
155 10 = 15.5 seconds
=-
yrs. 70. (B)A
=x- 3
5
92610
80000
55
21
=
100 21
=
200
01
(100 20 ) 100
w w
SP at 20 10 gain =
n
20
n
n = 3 half years
gl
20
21
n
1
= 1- yrs 2
-c .s
100 .. = "' 200 85
sc
SP 100 CP = 100 % loss 170
=
n
1 100
105
3
20
SP = {170,%loss=15%
=
100
92610 = 80000
= 1800 = 37 5 48 . 66.(0)
= P1
14 .in
45 48
A
20
1900
92, 610, P = ~ 80000 = 10% p.a. = 5% semi annually n
Hence retired teacher's age = 55 yrs. 65. (0) Total sum of 50 numbers = 50 x 38 = 1900 When two numbers namely 45 & 55 discarded, =
=
f
r
x- 30
lOx - Retired teacher + 25 = 10 25 + 30 = Retired teacher
verage
(100 55) 10
platform =
71.(*) Let the cost of 1 cow & 1 goat = t' y respectively. Case I: 3x + 8 y= 47200 Case II: 8x+ 3y= 100200 By cross multiplication,
~ x&
.....(i) ..... (ii)
= ~240 = P1
Rate of Depreciati on 100
w
67. (A) A
50000 = 50000 x
68. (0)
1
10 100
90 100
1
x 801600
= (3 - 2) km/h = 1 km/h = (3 + 2) km/h = 5 km/h
Velocity downstream 10 -
2
90 100
= ~40500 Velocity upstream
Total time =
n
10 - =12 hours
x
5
5 18
141600
377600
= =
9 64
1
55 x 660000
= ~ 12000 = cost of one cow
69. (0) Speed of the train= 36 km/h
= 36 -m/s
y
y
www.ssc-cgl2014.in
1
= )( 77000 = ~ 1400 55
300600
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 72. (C) P - 2q = 4 (p_2q)3=43 p' - (2q)' - 3.p.2q(p - 2q) = 64 [use p - 2q = 4] p' - 8q 3 - 24pq - 64 = 0 73. (C)
x 2x
x2
x2
=14
2
1
x2
7
1
1
?"
---,
=142
- 3
divide both N '& 0 r by x
x
x 2
1
4
x7
3
=5
x
1
-
3
x
1
3.x.- x
x
a
1
x
a
x
1
1
a
x
a
w w
a
ax
X2 +
w 1 .
'4
IS
a perfect square.
n' is a perfect square. r=2 Now, n 2
tn +
-
.!_ is a perfect if tn = n 4
t=1 1 x
x
[The ratio of area of two similar triangles is equal to ratio of the square of their corresponding sides)
1
x
9 2
80. (0)
Chord AB touches circle C 2 It is a tangent for circle C 2 OM, radius through the point of contact is perpendicular to AB. AM = MB [perp. from centre to any chord biseets the chord) In OMB OB2 = OM 2 + MB 2
(./3
1'r
= (./3
1f
+ MB
2
3 + 1+ 2./3 = 3 + 1- 2./3 + MB 2
2
~+2x.-
16
54
= 96 cm
4../3
x2
=
sr( DEF)
a=x
a=x-x2
76. (A)n ' - tn +
=2 4
art DEF)
.s
-+ - =-
77. (C)
x
=53-3)(1.5 = 125 - 15 = 110 + b2 + c2 + 3 = 2(a - b - c) a2 - 2a + 1 + b 2 + 2b + 1 + C 2+ 2c + 1 = 0 (a - 1)2 + (b + 1) 2 + (c + 1) 2 = 0 It is possible only when a=1,b=-1, c=-1 2s-b+c =2)(1-(-1)+(-1) =2+1-1=2
x 1 75. (A) - = -
art ABC) BC2 art DEF) = EF2
-c
2
79. (0)
sc
74. (A)a
= 194
78. (0) y = -3 reprsents equation of a line parallel to x-axis at a distance of 3 unit below origin.
=3
x -
1
14 .in
x
=
20
2
gl
x
1
x
=16
= MB 2
MB
= J4./3 = 2.'1/3
Length of AB = 2>
www.ssc-cgl2014.in
1
V3
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 81. (D)
_A D
B
or
RQS
On adding (i) & (ii), we have
ar(OPQRS)-
C
AB =AC B=
1 = "2ar(rectangle OCOS) ...(ii)
ar[rectangle ABeD]
T
84. (A)
C
!
[Angles of opposite to equal sides of a triangle are equal) Let B= C =x" ABC = 180· 40° + XO + x" = 180·
x" =
180 40 2
= 70'
ABD
14 .in
B = 70' External angle
s
= 180'-70' = 110'
POQ
82(8)~
PSQ
OPS &
180·
OQS = 90' each)
20
POQ = 180 - 20 = 160'
-c
w w
.s
sc
OM AB AM = MB = 15 cm OM =8cm In OMB OB2=OM2+MB2 =82+152 = 64 + 225 OB2= 289 OS = 17 cm Hence radius of the circle = 17cm
gl
ere .!. 2
=
P~Q
.!_ 160 = 180·
2 [Angle made by an arc at the centre is double the angle made by it in the remaining part of the circle) eto PRQ = 180' ( Cl PTOR is a cyclic quadrilateral) 80· + PRQ = 180· PRQ = 1000
w
85. (D)
ABCO is a rectangle & P, 0, R & S are the mid points of its respective sides AB, BC, CO&OA. Now, PQS & rectangle ABOS are on the same base OS and between the same parellels AB & OS. 1
ar( PQS)="2 ar(rectangle ABOS) ...(i) Similarly we can write,
Let OM = x cm ON = 17 - x cm In OMA OA2 = OM 2+ AM 2 = x2 + 52 OC' =ON2+CN2 = (17 -x) 2 + 12 2 OA & OC are radii. x2 + 25 = (17 -x)' + 144 x2+25=289-34 x+x2+144
www.ssc-cgl2014.in
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014
--------------------------------------------.--
34x =289+144-25 = 433- 25
cos 90· = 0 The value of the expression = 0 89. (C) sin 225° + sin 265° = sin 225° + sin 2(90° - 25°) = sin 225° + cos 225° = 1
408 34
radius of the circle
=
----------
88. (B)
x = -=12
= OA
---,
25
~X2
22
7 radi
90. (C)
= 180°
= ~122 25
180 7
1 radi =
= ./144 25 - ./169 = 13 cm
22 630
86. (A)
= - 11
0
= 57° 16' 22"(approx.) (C) sin
=2
+ cosec 1
14 .in
91.
sin
-.-=2 Sin
ADC
C) = 180· -(35° + 35°), AB = AC B = 180· - 70· = 110·
BAD =
CAD =
C
= 35'
92.
2_ A 2
x
(sin
1r = 0
sin
1
9
1
Ian tan 2
sec2
=2
= 2
J5
= (2
J5 )(sec
110° = 55°
....(i) tan
1 sec
tan
.s
1 = 2
1
= (1)e +
(B) sec
1=0
cos ec?
Now, sin9
= 180· - (B
-c
Now,
A)
sc
A
= 2"(
CAD
20
BAD =
2 sin
sin 2
1
gl
ADB
= 2
$
A
w
w w
87. (B)
Let AB be the tower. In right triangle ABC AB tan 30° = -
Be
100
AB =
T3m
=2YS=$2 .... (ii) On adding (i) & (ii), we have
= 2$
2 sec
$
sec
=
cos
=rs
1
On sub (ii) from (i), we have 2 tan
=4
tan
=2
sin cos
--=2 2
sin
www.ssc-cgl2014.in
=
(5
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 Now, sin
2
cos
1
/S/SJ5
47 = 100
93. (B)tanl°tan2°tan3° tan89° = (tanl°.tan89°)(tan2"tan88°)
= =
4 = 100
tan45°
...... )(1
= 1 94. (0) Let the total students be
= 180 100
x= 1000 360 = 3600 100
24000 =~ 4320
11280
960
4320
3 ~5520
14 .in
98. (0) Amount spent on Grocery
3600
=
= 1200 Required ratio
_!i_ 25000 = f 3500 100
9
= 100
25000 = ~ 2250
99. (B)Amount spent on miscellaneous in May month's salary
gl
1000 5 = 1200 = 6"
sc
96. (B) No. of students in commerce
w w
.s
3600
=
-c
= 5: 6
= 650 No. of students in law
20
Amount spent on electricity
No. at" Btudcntl!l in science No. of students in arts
45 = 360
24000 =~ 960
16560 = -3-=
95. (A) No. of students admitted in arts
65 - 360
11280
Amount spent on savings
Average =
=
f
x.
100 360 of x=1000
= 120 360
24000 =
Amount spent on Grocery
tan45°
(tan 1°.cot1°)(tan2°cot2°)
1)(1x1
97. (A) Amount spent on Education
3
3600
2 100
Required ratio =
25000 = ~ 500
f
4320 500 =216:25
100. (A) Amount spent on education in May 50 = 100
25000 =~ 12500
Amount spent on education in April 47 = 100
w
=450 Oiffenence = 650 - 450 = 200 No. of commerce students is 200 more than the no. of law students.
% increase
24000 = ~ 11280
= 12500 11280 11280 = 10.82% (approx.)
www.ssc-cgl2014.in
100
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014
SSC MOCK TEST 2 (ANSWER KEY)
• C C A A
101. C 102. C 103. A 104. A 105. C 106.8 107. C 108. B 109.8 110.0 111. A 112. B 113. C 114.0 115. C 116. C 117.0 118.0 119. B 120. A 121.0 122.0 123. A 124.A 125. A
126. C 127.0 128. C 129.0 130.0 131.8 132.A 133.C 134.A 135. C 136. C 137.A 138.A 139.A 140.B 141.B 142.A 143. C 144.B 145.8 146. C 147.C 148.B 149.C 150. C
151. A 152. B 153. A 154. B 155.C 156.8 157. A 158. C 159.8 160.C 161. A 162.0 163. B 164. B 165. C 166. B 167. B 168.A 169. B 170. C 171. A 172.A 173.A 174. B 175.A
14 .in
A C 0 0 0 0 8 A A 0 A B B C C C 8 8 0 A 8 A 0 B A
20
76. 77. 78. 79. 80. 81. 82. 83. 84. 85. 86. 87. 88. 89. 90. 91. 92. 93. 94. 95. 96. 97. 98. 99. 100.
gl
0 B C C B 8 C B B 0 B A A 0 0 0 A 0 0 B
-c
51. 52. 53. 54. 55. 56. 57. 58. 59. 60. 61. 62. 63. 64. 65. 66. 67. 68. 69. 70. 71. 72. 73. 74. 75.
sc
B * B B C C 8 C 8 0 A 0 A B C * A 0 B C A A B C A
.s
163 (B); 164. (B); 165. (C); 166. (8); 167. (B); 194. (D);
26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. 41. 42. 43. 44. 45. 46. 47. 48. 49. 50.
Change 'raise' into 'raised' 'Both' is at wrong place. Change 'is' into 'are' Add 'as' after 'good' Remove 'not' Read option (D) as stoic.
w w
B A 0 C 0 8 8 0 C A A 0 0 0 0 0 C 8 A A A 0 0 C C
w
1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25.
www.ssc-cgl2014.in
176.0 177. B 178.C 179.B 180. C 181. C 182.C 183. C 184.8 185. A 186.0 187.0 188.B 189.B 190.A 191.0 192. C 193.A 194.0 195.C 196.8 197. A 198.B 199.C 200. C
