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SSC MOCK TEST 3 (SOLUTION)
II 1. (8) 2. (D)
1l .21
216
L
s "1
£i.12~
£~~ +].
4.
(C)
:
tIl MOUSE
:
1-21_2
1-2
5. (Al 264 + 2
tJ
1+ 3 + 22+9+0-11
Son 21.(0)
22.
6. (Al
Physical Model 5
Implementation
the
w w
A 8
997
9+9+7
L I
= =
lx2=>2 2x2=>4
=
12 x 2 =>24
A
,
=
..
1x2=>2
place value
0=4x2=>8 I
..
place value
Y
=
25 x 2 =>50
I Il. place value
(5)2
So, LADY= 24 + 2 + 8 + 50 = 84 LEA
27. (C) 14. (8) place value
15. (A) bc
cde
de
efg fg ghl Similarly.
I
16
('3+ I)
51
11('3+3) tI
158 ('3+5)
tl
D
E R
~~~~~~ 12 5 1 4
5
18
+8
+8
+8
+8 +8 +8
20 139" "'i2 13 26
16. (8) 17. (C) 5
brother/sister
place value
A
(4)'
= 25
of Simran's
Similarly,
w
=> 6+8+2=16
son
I Il. place value
11 (D) 12. (D) (A) 563 - 547 = 16 (8)71-55=16 (C) 523 - 517 = 6 (D) 248 - 231 = 17 (1)2 13. (D) 10 => 1 + 0 = 1 13 1+ 3 = 4 (2)2 (3)2 234 2 +3 +4 =9 682
.is: .l;
~~n~iWij~¥~r:~b:re",,:c::(;)~'!-l::S~ion
are related
to lock of vitamins
('3+7)
K:th'!V
Maruti is the son of Sirnaran and Sunil is
.s
1 7. (AJ b a alb b b b/ a a b b / b 8. (D) abc a b b cab c a abc a c b 9. (CJ 10. (D) Except option (D) all diseases
Sister
sc
Scheme Refinement 6
SitA"J.an
-c
Conceptual Modelling Logical Modelling 2 4
1
Son
Cous;"
(A) Prl;/n ,BrOther
1 + 4 + 7 - 12
735+5147
~Sister-in-law
24+ 16-8-32 40 - 8 - 32 32 - 32 (correct)
6 and
Similarly,
Wife
1
'+'t1
1-21-21_2"
132 290
870 + 3
20. (A) Man
LIGHT : JJEIR
+1 J
Lokita
>
l'
+1
+11 I
'"~ KPSTC
9x9=tl 9x6=~ 19. (C) Pritl > Rahul > Yamuna = Oivya > Manju
1728 (12)3
9 x 5 = 45
14 .in
:
lJ'>
20
F
gl
3. (AJ
18. (8) 9 x 2 =
II
481
f
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of Maru ti.
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 28. (0) According to question the new form of COMMUNICATIONSwill beOCMMIrnUCI TAOISN ,.10'" letter from right I 29. (C) 8 x 20 + 5 + 9 - 3 ~ 38 => 8 x 4 + 9 - 3 ~ 38 32 + 9 - 3 ~ 38 41 - 3 ~ 38 38 - 38 (correct) 30. (B) 33 • 11 + 3 - 6 - 115
121-6-115 115 - 115 (correct) 31. (A) 15+24+3-6-17 15+8-6-17 23 - 6 - 17 17 17 (correct) 32. (0) (14 + 2) x 12 84 (18+2)x981 Similarly, [x + 2) x 11 88 or (88 + 11) x 2 or 8 x 2; 16 33. (0) 3 x 4 x 5 = 60 60 - 2 58 5 x 6 x 2 = 60 60 - 2 58 8 x 4 x 2 = 64 64-2 62 Similarly, 7 x 6 x 3 = 126 126 - 2 124
38.(0)
or
~ Conclusions:
39. 42. 45. 48. 50.
I. x II. Ill. x (0) 40. (D) 41. (0) (0) 43. (C) 44. (0) (A) 46. (0) 47. (0) (A) 49. (8) (C) The numerical groups of BEST will be B - 00, 12, 24,31,43 E - 03,10,22,34,41 S - 58, 65,77,89,96 T - 59, 66, 78, 85, 97
5
=6
3 x 27 = 81 = Similarly,
../8l = 9
20
1
gl
20 1
-c
Work done by (C + A) in 1 day
15
WG'I'kUloneby 2(A + B + C) in 1 day
sc
9 = 36
12
Work done by (B + C) in 1 day =-
=-+-+12 20
.s
x
I
51. (C) Work done by (A + B) in 1 day =-
w w
34. (C) 4
r.:G::::\
14 .in
=> 11)(11-6-115
37. (0)
5+3+4 60
15 12 60
-=-
1 5 1
Work done by (A + B + C) in 1 day =10
~=10 or,2xx=10x 10 or, 2x = 100 .'. x = 100 + 2 = 50 35(0)
w
Hence A, B & C together complete the work in 10 days. 52. (B) Work done by (A + B) in 1 day
1 = -
3
Work done by (A + B) in 2 days = ~ Remaining work = 1- ~ = 1 3
I
36. (A) Horn~__
8_k_m~FiE-
"'"
A 3 krn
lkm
OF - OA- FA (Here, FA- 8C+OE - 2+1-3km) - 8 km - 3 km - 5 km
3
1
Now'3work in completedby onlyA in 2 days .'. 1 work in completed by only A in = 2 x 3 = 6 days Work done by B alone in 1 day =
2- 1
1
:--=-
6 6 8 alone can do the same work in 6 days.
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For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 57. (0) TSA of a sphere
1
53. (B) Let B's 1 hr. work = -
=
8 TT
=8TT
x
A's 1 hr. work
=
1
r
x
r =
80% of -
80 1 =_.-
=2 unit
Volume of the sphere
100 x 4
=
aJ2TT blICunit. = -3-CU
=-
5x
ATQ.
58. (C) Volume of the water in conical flask
x
2
=
= 15
3 Volume of the water in cylindrical
15· 4
=""5.'2 = 6
=
.'. B can do the work in 6 hI'S. number
ATQ.
and 3 8
between
1 3 3 -+4 8
= -2
H
9 16
8
sc
1 9
-c
gl
59. (A)CP of 12 pairs of socks
2
w w
.s
Co-prime numbers have no common factor other than 1. Their LCM = 117
144
= Rs. 12 .'. No. of pairs ofsocks available for Rs. 48
MP = Rs. 12000 SP = Rs. 10500 Let x% discount is given on the MP of the table.
w
TT·
80 . 180 100
60. (B)
A, : Area of the circle (whose diameter
=
=
= 4 pairs
= .fix
the side of the square)
80% of 180
144 =Rs.1'2
CP of 1 pair of socks
Let ABCO is a square of side x unit. Side x unit. Its diagonal
=
= Rs.
55. (0) Product of two co-prime numbers = 117
56. (0)
flask
TT. (mr)2H
20
54. (C) A rational
2.TTr2h
14 .in
4 5x
Q
c: 3
4
'3TT' (",2)
x
'2
is
Then,
12000(100-x) 100
= 10500
2
sq. unit
A2 : Area of the circle (whose diameter
.,fix
is
2
~
100 - x
~
x
61. (C)
MP
= Rs.
= 87.5
= =
100 - 87.5 12.5%
480
the diagonal of the square) =TT -2- sq. SP (after 10% discount) unit
= = Rs. 432
CP
SP· 100 100+%gain
432· 100 = R 400 108 s.
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For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 When no discount is given, Profit = 480 - 400 = Rs. 80 0/ 10
.
gaIn
=
80· 100 400
No. of ball left in the box = (100 + 50 + 50) - (25 + 25) = 150 No. of black balls = 50
= 200/70
62. (B) Let the price of a school bag = Rs. 7x & the price of a pair of shoes = Rs. 5x ATQ, 7x - 5x = 200 X = 100 Price of a pair of shoes = 5x Rs. 500 63. (A) Let P gets Rs. x. Share of Q = Rs. (x + 30) Share of R = Rs. (x + 30) + 60 Rs. (x + 90) Now, P + Q + R = X + (x + 30) + (x + 90) 300 3x + 120 x Rs. 60 P : Q : R = 60 : 90 : 150 = 2: 3: 5 64. (B) Let xl' x2' .... , Xgbe nine numbers.
=
0;(,
of black balls
332.% 3 68. (A) Suppose each car takes t sec time to reach the crossing. 40 = -t-
V,
14 .in
20
They do not collide if v, 69. (A) Let the distance = x m & the speed = y mls
gl
50
-c
x, + x2 + ...... + X9 = 450 x"X2+X3+X4+XS =5x54=270 x7 + Xg+ X9= 52 x 3 = 156 X6= (x, + x2 + .... + Xg) - [(Xl+ x2 + ... + xs) + x7 + Xg+ xgl = 450 - [270 + 156) = 450 - 426 = 24 65. (B) Average of 1st 9 integral multiple of 3.
x
w w
.s
2t
NewSP % loss
(250-235)· 250
67. (B) Blue balls withdrawn
Red balls withdrawn
4
Ratio of the two speeds = y : ~ = 4 : 1 70. (D)
sr, = S12
Q
5000· 12· 2 100 5000· 12· 2 4000· 3 10% 3x + 1 =0 X2 + 1 = 3x
71. (D)
X2 -
100
x2 + 1 --=3 x 1
15· 100 = 60/ 250
X+x
10
= 25% of 100 = 25 . 100 100 25 50% of 50 = 25
= =
is
L
2. ~ Y
x
300· 100 = Rs. 250 120 = Rs. 235
5.
x
=.£..= _2_=
3· 9· 10 9.2 =15
66. (C) CP of the article =
=1=4:
Time 't'
w
=
:v2
x = -secons Y spee d w h en ha lfd istance ll in double time.
sc
I---'--~*""ef't!¬
3+ 6+ 9 +12+ 15+18 +21+24 +27 9 3. 9· 10 3(1+2+3+ ...+9J _ 2 9 9
50
& V2 = -t-
40 4 = _t_= _ 50 5
= =
=
50· 100 150
=
=
Then,
=
2
1
=3 1
Now , x +x+-+2" x x 2
J
I
X
X
= x +-2 + x +-
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For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 x+-
032 4x -
3
-
1 2
x
-2+
x+-
x + 1 = 8x - 48 x =7
1
x
Fraction =
2 +3 = 10 4y -
3
72. (B) --+--+-x y
4z -
3
z
7- 4
3
7
7
78. (A) x2 + y2 + Z2 = 2x + 2y + 2z It is possible only when x2 = 2x y2 = 2y Z2 = 2z
=0
~ x = 2, 0 Y = 2,0 When x y = z = 0
=0
z = 2,0
0
~ 4+4+4-
=0
=3
When x = y ~
12
°
I
= z °2 I
J
=1
14 .in
I+X+l+y+l+y
=4
79.ICIC~
J72 2 + J3.
73. (A) 2./50 + J18 5
3· 2 -
J6
6· 2
20
2JS.
A
2· sJ2 + 3./2- 6J2
B
LC + LCAD = 90° (Q LADC = 90° )
gl
(lO+3-6)J2
7J2
~
LCAD + LBAD = 90° (Q
LA= 90°, given)
LC + LCAD = LCAD + LBAD 31 4z 3 Iyl-zz
sc
-c
° 7 x 1.414 = 9.898 74. (C) a2 + b?+ 4c2 = 2(a + b - 2c) - 3 ~ a2 + b2+ 4c2 - 2a - 2b + 4c + 3 = 0 (a2-2a + 1)+ f:>2-2b+ 1)+ (LJc2 + 4c+ 1)= 0 (a - 1)2+ (b - 1)2+ (2c + 1)2= 0
z
.s
A
w w
lt is posstble only when a= 1, b= 1,Co
w
=(1)2+(1)2+ =1+1+=2-
1
-
2
2
1 4
ABC is a triangle and G is its centroid. Mark an another point E on AG s.t. AE=EG AE ° EG (by assumption) ar = ar ( EBG) ---------(i) [A median of a triangle divides it into 2 triangles of equal area] also G is the mid pt of ED ~ ar = art BGD) -------(ii) [same reason] from (i) & (ii)
1
4
= 289K + 18 ° 17 x 17K + 17 + 1 = 17(17K+ 1)+ 1 °17xM+1 When x is divided by 17, Remainder ° 1 :. y = 1
75. (C) x
76. (B) For x = 0, y = 0, here ax + by + C = 0 passes through origin 77. (A)Let the denominator = x
the number ° x - 4 New numerator ° x - 4 - 2 ° x - 6 New denominator = x + 1 ATQ, x + 1 = 8(x - 6)
1
art BGD) = -art ABD)--------(A) 3
Similarly we can write art CGD) =
1
3ar( ACD) --------(B)
from (A)& (B)
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For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 art BOC) =
1
"3ar(
(say) ABC) XO
+
XO
+ 1100
1 = -·48 3
XO
= =
1800
35°
c16sq.cm
Chords AC & BD intersect at P. .. AP.PC = BP.PD I when any two chords of a circle intersect each other at a point inside it, the rectangle so formed by the segments of one chord must be equal to the rectangle formed by the segments of the other chords]
14 .in
84. (A)
Q
20
~
82. (C)
-c
gl
~
I!Q
~eight
8S'f)
A
&/!'P
of the tower = 60 m. EB
I
.s
sc
Let ON = x em In
40· 12
... (i)
PN2
w w
In
= PB2 - BN2 = 122 - (7 + X)2
...
(ii)
w
72 - x2 = 122 - (7 + X)2 49 - x2 = 144 - (49 + 14x + x2) 49-x2 = 144-49-14x-x2 14x = 144- 98
x
=
LAEB + LBEC = 1800
(Linear pair)
Also, (Angles in the same segment of a cirle are equal)
23
=Tcm
NB =NO+OB 23+ 49 _ 72 7
83. (C)
p
7
=
lO3..cm 7
In
(Angle sum property of a triangle)
86. (A)Equilateral. Q
OP = OR
In
OQR, OQ=OR
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For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 87. (A)
= sin9[J2+1-1)
90. (B)
tana
=
sino coso
I
sin 0 coso' De=MB MB = 24 m AM =AB-BM = 36 - 24 = 12 m
mx--
cos~ coso
=n
cos~ coso
n =-
=m
Q sina
sin
.B
14 .in
.j3
m n
= -
=2
20
m
1 88. (A) -----=.--
=
8../3 m
-c
.j3. .j3. 2 .j3 1
1 cosB
sc
sine
coseca+cote
gl
AD
1
sinB
sinB
m2
-
»a
(1-cos2
w w
sine 1 1- cos G sine
= sin
m'-
.s
sinB
cos 13 sinl3 = n =n
sin600
4·
sinl3 _ cosf - n
~
fn
=
= J2sinB
= n' cos 2a 0) = n2 cos2o
m2 -1 --=
. ') B - (1- cosB) SIO-
112
-1
cos 2 0
w
(1- cos B)(sinB)
91.
(1- cos2 B)- (1- cos B) (1- cos B)(sinB)
2 3
~ (1- cose)[(1 + cos e) -11 (1- cos B)(sinB)
2 -3
cote
2 3
89. (C) cosB+sine sine
= Now, sinB.
2 3
= -
cosB-sinB
r.::--:- - SII1 B = V;{. -I
Ii-I I
sin B r.::--:,,2 -1
-I
92. (A)
tane=-
3 4 4
cote =3
. .fi + 1 = smB ---I 2-]
~ cosec
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=
For More Video / Audio Tutorials & Study Material visit www.ssc-cgl2014.in And for regular updates on our website like us on facebook - www.facebook.com/cgl.ssc2014 Marks obtained in Social Science
= =n= ~ J1+ 196
1
55
= 360' 810 = 123.75 Marks obtained in Maths 90 = 360.810= 202.5
1
93. (A) (1 + tan2 9) + (1+ cot2 9) 1
1
sec29
cos ec29
Marks obtained in Chemistry 70 = 360.810= 157.5
--+----,;= cos29+sin29
Total marks in (English, Physics and Social Science) = 450 Total marks in (Maths & Chemistry) = 360 % of marks in (English, Physics, Social
= 1
250 . 100 1600 = 15.6% 95. (A)No. of science students in 2001-02 = 400 No. of science students in 2003-04 = 600 % increase in science students
14 .in
94. (8) No. of students in law faculty in 2003-04 = 250 Total students= 250 + 250 + 600 + 500 = 1600 % of students in law faculty
Science) = 450. 100 810
20
=
= 500% 9
-c
gl
% of marks in (Maths & Chemistry)
= 360. 100 810
= 400 % 9
sc
600-400.100 Difference = 500 _ 400 % 400 9 9 = 50% 100 1 96. (C) No.ofstudents in sciencefaculty in 200102 -% = 11-% 9 9 = 400 98. (D)Difference of marks between Physics & Total students= 150 + 200 + 400 + 600 Chemistry = 191.25 157.5 = 1350 = 33.75 % of students in science faculty Difference of marks between Social = 400.100 Science & Chemistry 1350 = 157.5 - 123.75 = 33.75 = 29.6% 99. (C)Marks obtained in (Maths & Chemistry) 97. (D) Marks obtained in English = 360 60 810= 135 = _. Marks obtained in (Physics & Social 360 Science) = 315 Marks obtained in Physics Difference = 45 85 100. (D) Marks obtained in English = 135 = 360.810 = 191.25
w
w w
.s
=
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SSC MOCK TEST 3 (ANSWER KEY) 126.8 127.C 128.8 129.8 130.B 131. C 132.8 133. B 134. C 135. 8 136.8 137. D 138. D 139.C 140.C 141. C 142.C 143.0 144.C 145.C 146.C 147.C 148.C 149.C 150.8
151. C 152.C 153.A 154.8 155.A 156.A 157.8 158.0 159.D 160. 8 161. C 162.D 163.C 164.C 165.C 166.C 167.A 168.C 169.C 170.C 171. D 172.C 173.0 174.C 175.8
14 .in
101. C 102.8 103.B 104.A 105.8 106.0 107. C 108. C 109. C 110. D Ill. A 112. C 113.A 114. C 115. C 116. A 117.8 118. C 119.8 120. C 121. 8 122. D 123.0 124.0 125.8
20
76. B 77. A 78. A 79. C 80. 8 81. A 82. C 83. C 84. A 85. C 86. A 87. A 88. A 89. C 90. 8 91. 8 92. A 93. A 94. 8 95. A 96. C 97. D 98. 0 99. C 100.0
gl
C 8 8 C 0 0 0 C A 8 C 8 A 8 8 C 8 A A D D 8 A C C
-c
51. 52. 53. 54. 55. 56. 57. 58. 59. 60. 61. 62. 63. 64. 65. 66. 67. 68. 69. 70. 71. 72. 73. 74. 75.
sc
C C 0 C 8 A 0 0 C D A D 0 D 0 0 D C 0 A D D A 8 C
.s
26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. 41. 42. 43. 44. 45. 46. 47. 48. 49. 50.
w w
151 152 153 154 155
8 0 A C A A A 0 C D D D D 8 A 8 C 8 C A D A 0 A B
(C); 'On' in place of 'in' (C); 'between' in place of 'among' (A); Add 'it' before 'being' (8); 'Will' in place of 'would' (A);Put 'not only' before 'anxious'
w
1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25.
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176.C 177.8 178.8 179.A 180.C 181. 0 182.8 183.8 184.D 185.8 186. D 187.D 188.A 189.8 190.A 191. 8 192. D 193. D 194.A 195.8 196.C 197.D 198.8 199.C 200.0
