BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com India Post Payment Bank (IPPB) Scale-I Officers Prelims Exam 2016/17 Practice Mock Paper-1 (SOLUTION KEY) QUANTITATIVE APTITUDE 1) D From the graph it can be seen that, I/E > 1 is in 2 cases. 2) D I/E = 0.7 E = 51.688/0.7 = 73.84 3) B Required answer = 84 * 0.9 – 84 * 0.8 = 8.4 4) B I(A)/E(A) = 1.2 I(B)/E(B) = 0.9 I(B)/I(A) = ¾ (as E(a) = E(B)) Required % = ¾ * 100 = 75% 5) C I/E = 0.8 New ratio, (I*200)/(E*300)=8/10 I/E=(8*3)/(10*2)=1.2 6)

10)

11) A

12) C 7)

13) E 8) 14) A

9) 15) E

16) B ? = 13.33/100 * 240 + 1.33/100 * 380

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BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com = 13.33 * 2.4 + 1.333 * 3.80 = 31.992 + 5.0654 = 37.0574 17) D 13.58 * 23.37 / 7.99 = 14 * 23/8 = 322/8 = 40 18) C 69751/75 = 930.01 19) D 0.33/100000 - 0.222/100 * 150000 0.333 * 1000 - 0.222 * 1500 333 - 333 = 0 20) D 33^3 = 35937 or 35935 approx. 21. b Let age of the daughter before 10 years = x Then, age of Madhan before 10 years = 3x After 10 years, Madhan will be twice as old as his daughter. ⇒ 3x + 20 = 2( x+20) ⇒ x = 20 ⇒ Present age of Madhan = 3x + 10 = 3× 20+ 10 = 70 years. 22. d Since P and Q move in the opposite direction along the circular field, so they will first meet each other when there is a difference of one round between the two. Relative speed of P and Q = 8+2 = 10 rounds per hour. Time taken to complete one round at this speed = 1/10 hr = 6 min. 6 Hrs 45 min + 6 min = 6 hrs 51 min i.e, 6.51 a.m 23. a Part of the tank filled by pipe P in 1 minute = 1 / 40 Part of the tank filled by pipe Q in 1 minute = 1 / 15 Part of the tank filled by pipe R in 1 minute = 1/ 30 Here we have to find the proportion of the solution Y. Pipe Q discharges chemical solution Y. Part of the tank filled by pipe Q in 5 minutes = 5 × 1 / 15 = 1 / 3 Part of the tank filled by pipe P, Q, R together in 1 minute = 1/40 + 1/15 + 1/30 = (3+8+4)/120 = 15 / 120 = 1 / 8. Part of the tank filled by pipe P, Q, R together in 5 minute = 5 × 1/8 = 5/ 8 Required proportion = (1/3) / ( 5/8) = 8 / 15 24. c Rate of downstream=(20 / 5 ) kmph= 4kmph Rate of upstream =( 20/10) kmph= 2kmph Therefore Speed of the stream= (1/2)(4 - 2) kmph= 1 kmph 25. e

Suppose they meet z hours after 6 a.m. Distance covered by X in z hours = 25× z km. Distance covered by Y in (z - 2) hours = 35(z - 2) km. Therefore 25z + 35(z- 2) = 170 60z = 240 x = 4. So, they meet at 10 a.m. 26. a C.I = 8000 * (1+(10/100))2 –8000 = 8000 *110/100 * 110/100 – 8000 = 9680 – 8000 = Rs.1680 Therefore, S.I = C.I / 2 = 1680 / 2=Rs. 840 840 = sum * 4 * 5 / 100 :. Sum = Rs.(840 * 100)/ (4 *5) = Rs.4200 27. b Profit = (S.P of 25 balls) - (C.P of 25 balls) = 1015 (C.P of 25 balls) Given that Profit = (C.P of 10 balls) => 1015 - (C.P of 25 balls) = (C.P of 10 balls) => (C.P of 25 balls) + (C.P of 10 balls) = 1015 => C.P of 35 balls = 1015 => C.P of 1 ball=1015 / 35 = Rs. 29 28. d Since each ring consists of five different letters, the total number of attempts possible with the four rings is =5 * 5 * 5 * 5 = 625. Of these attempts, one of them is a successful attempt. Maximum number of unsuccessful attempts = 625 - 1 = 624. 29. b Suppose, Arul joined after x months. Then, 40000 * 12 = 60000 * (12 – x) => 48 = 72 - 6x => 6x = 24 → x = 4 30. a Kathir’s one day’s work= 1/20 Kathir’s 4 day’s work =4* (1/20) = 1/5 Work left= 1-1/5 = 4 /5 Anand’s one day’s work= 1/30 Anand can do work in = (4/5) *(30/ 1) = 24 days So total days = 24+4 = 28 days 31). (?)2 = 1250 × 450 = 562500 ? = 750 Answer: a) 32). 48.7 + 8.75 = (460 / 100) × ? 57.5 = 4.6 × ? ? = 12.5 Answer: d) 33). 3√148877 = 3√(53)2 = 53 ? = 53 – 30 = 23 Answer: e) 34). [12(3 / 5) – 5(2 / 5)] / 5(3 / 70) = ? = 7(1 / 5) / 5(3 / 70) = (36 / 5) / (353 / 70) = (36 / 5) × (70 / 353) = 501 / 353 = 1(151 / 353)

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BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com Answer: c) 35). 1805 / 19 + 65 = 200 + ? 95 + 65 = 200 + ? 160 = 200 + ? ? = -40 Answer: b)

From above, it is clear that only Conclusion II follows. 52). (a)

REASONING ABILITY Directions (Q. Nos. 36-40) Arrangement according to the question is as follows

36). F is next to the right of E. Answer : a) 37). D is 2nd to the right of B. hence, statement (d) is not true Answer : d) 38). C alone is the neighbour of D. Answer : b) 39). All the given statements are correct Answer : d) 40). E and D are sitting at the ends. Answer : d)

From above, it is clear that only Conclusion I follows. 53). (a)

From above, it is clear that only Conclusion I follows. 54). (b)

Directions (41-45):

So, only conclusion II follows. 55). (d) 41). Answer: a) 42). Answer: b) 43). Answer: d) 44). Answer: b) 45). Answer: c) 46) C 47) A 48) E 49) D 50) D 51). (b)

56) B 57) A 58) A 59) C 60) C Solution(Q 61 – 65):

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BASE INSTITUTE – NAMAKKAL | www.ibpsguide.com Floor Person Subject 7 P Biology 6 K Accounts 5 J History 4 N English 3 M Computer 2 O Commerce 1 L Geography 61). Answer: d) 62). Answer: a) 63). After arranging all the persons in alphabetical order from top to bottom: Floor Original Changed position position 7 P J 6 K K 5 J L 4 N M 3 M N 2 O O 1 L P Here there are only two persons - K and O – Whose positions are unchanged from the original position Answer: c) 64). Answer: c) 65). Answer: e) 66). Required position = (40 + 1 - 14) = 27th Answer: b) 67). Required number = (38 + 9 - 1) = (47 – 1) = 46 Answer: c) 68). According to the Question,

Required distance, AE=DE-AD [AD=BC] = 3-2 = 1 km Hence, Rohan is 1 km far away from starting point Answer: a) 69). According to the questions

A is the second turn. Required distance, XA = √ [(XA)2 + (YA)2] = √ [(80)2 + (50)2] = √ [6400+2500] = √ (8900) m Hence, Rahul was √ 8900 m far apart at second point from starting point Answer: c) 70). According to the questions

Required distance, EQ = AP-(AB+CD+PQ) = 150 – (25+25+35) = 150 -85 = 65 km Hence, both buses aew 65km far away from each other Answer: a) ENGLISH LANGUAGE 71).b 72).d 73).b 74).a 75).d 76).d 77).b 78).e 79).c 80).c 81).d 82).b 83).c 84).c 85).d 86).d 87).a 88).a 89).c 90).e 91).c 92).a 93).e 94).d 95).d 96).a 97).d 98).a 99).d 100).b Explanation (91-100): 91). Past Perfect Tense will be used. The structure is : Subject + had + past participle 92). ‘That boy possesses’ is the correct usage, as the verb must agree with its subject in number and person. 93). No Error 94). Replace ‘have’ with ‘has’. 95). ‘Because of’ is the correct idiomatic form. 96). Replace ‘comes’ with ‘come’. 97). Replace ‘has’ by ‘was’. 98). Replace ‘would’ with ‘did’. 99). Replace ‘at’ with ‘from’. 100). Replace ‘was’ with ‘were’.

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