NARAYANA MEDICAL ACADEMY INDIA SR N40+LT N40(PROG-1) Time : 3 Hours

1-10 11-20 21-30 31-40 41-45

1 3 3 2 3

1 4 2 2 3

NEET GRAND TEST-3

1 3 1 2 3

2 2 1 4 2

3 1 3 1 1

46-50 51-60 61-70 71-80 81-90

4 2 2 2

3 2 4 3

2 1 2 4

3 2 3 1

2 2 2 2

91-100 101-110 111-120 121-130 131-135

1 3 2 3 1

3 3 3 4 4

3 4 1 3 2

4 1 1 2 3

4 1 4 4 4

136-140 141-150 151-160 161-170 171-180

3 1 1 4

3 3 2 2

2 2 1 1

1 2 2 3

3 3 3 2

KEY PHYSICS 3 3 1 1 4 3 1 4 CHEMISTRY 3 2 2 3 4 3 1 2 2 2 BOTANY 2 3 2 4 4 1 3 2

ZOOLOGY 2 2 3 3 3 3 3 1 2 2

Date : 23-04-2018 Max.Marks : 720

4 4 3 2

1 4 4 2

4 4 4 3

2 3 3 3 2

4 4 3 4 3

3 1 3 4 4

4 4 4 1

1 2 4 4

1 4 3 2

4 3 2 4 4

1 1 3 4 3

3 1 3 4 3

HINTS PHYSICS 1.

2.

V x  0 1  e at  a 1 D.F of a   T 1  T D.F of V0  D.F of xa   LT 1 

8.

  M 0 LT 1 

9.

   Torque   r  F   is perpendicular to plane containing   r & F then  r.  0   F .  0

Velocity V  5  t 2 Acceleration a  2t If t  2sec  a1  4m / s 2 If t  3sec  a2  6m / s 2

3.

Average acceleration a  5m / s 2 V2  V1  V  2 g 2 s  2 g1s t1  t2  t 

2s 2s  g1 g2

K .Esystem  K .E of all particles + Rolling K.E

of ring

V  g1 g 2  2 g  6 g t  V  4 gt A  i  j 

4.

1 1 2 m  2V0   m 2 2 1  mV02 1    2 K .Esystem  6mV02 

B  i  j Angle between A & B becomes, A.B 1 1 cos    0 2 2 A B 5.

6.

10.

  900 Fmax   1  2  m1  m2  g  0.7 15 10 = 105 N x2 y 20 dy 2 x x   dx 20 10 x  tan    10 x   0.5  x  5m 10

7.

2V0



2

11.

12.

1  2m 2

1 L 2 1  K .E  L  2 f 2 KE1 L1 f1   KE2 L2 f 2 K .E 

2 L f   1 L2 2 f L L2  4 Total Gravitational potential GM GM V   a/2 a 2Gm Gm 3Gm V     a a a T l l YAe F e  1  1 F l T2 l2  l  T1l2  T1l  T2l1  T2l   T2  T1  l  l1T2  l2T1 

Slope 

x 2 25  Maximum height y  20 20 5 y   1.25m 4 work 72 power   0.5  time 60 72  0.1  0.6 watt 12



Natural length l 

l1T2  l2T1 T2  T1



2V0



2

a/2

13.

Work done W 



18.

dmgdx

0 a/ 2

a/2

Initial K.E 1 1 3 K .Ei  mV 2   2mV 2  mV 2 ............. 1 2 2 2

 x2  =  a xgdx    a g     2 0 0 a 2  g  a2   2  4  2

2

2

 mV 1 1    m2V2 

After collision VC 

 mV 



2

  2mV 

2

m1  m2 2



5 V 3

3m  final K. E 1 5V 2 5 1 2  mV 2 K .E f   3mVC   3m  2 2 9 6 Loss of K.E = K .Ei  K .E f

a4 g W 8 14.



19.

3 5 2 mV 2  mV 2  mV 2 2 6 3

P 2V  constant PV  RT  P 

RT V

2

 RT    V  constant  V 

Always lout  lin Candle will fall at the rate of 1 cm /hr

2

T  V T V   1   1  T2  V2 2

1

15.

16.

  2V0  2  P  P0 1       V   Ideal gas equation PV  nRT PV P V T1  1 1  0 0 ............. 1 nR 5nR PV P 2V T2  2 2  0 0 .............  2  nR 2nR Change in temperature PV P V 4P V T2  T1  0 0  0 0  0 0 nR 5nR 5nR For A: - PV 1 1  PV 2 2 V0 P0V0  PA   PA  2 P0 ........... 1 2   For B :- PV 1 1  PV 2 2

2

20.

T1  2

17.

 5  10 1  0  dWCA  dWCA  5J

3R ................ 1 2g

Time period of simple pendulum

T2  2

l ............  2  g

Given T1  T2



 V0    PV 0 0  PB    PB  2 P0 ............  2 2 1  PB  2 1  2 PA dQ = 5 J dU = 0 ( cyclic process) dQ = dW  dQ  dWAB  dWBC  dWCA

T  V   0   0 T2  3T0  T2  3V0 Time period of disc, 3 MR 2 I 2 T1  2  2 mgh mgR

21.

3R l 3R  l  2g g 2 2 U  U0   x dU F   2 x dx

 m 2 x  2 x  w  Time period T 

2 m

2 m  2  2

T 

2m 

22.

Case (i) : -

Motar Cyclist   V0

 V  V0  n11    V  VS Case (ii) : motar cylist   V0

  n1................. 1 

26. Siren

VS2  0

 V  V0  n12    n2 ..................  2   V  But the motor cyclist does not observe any beats n11  n12

23.

24.

 V  V0   V  V0   n1     n2  V  VS  V    1   330  V0   330  V0    176    165  330  22   330  330  V0 330  V0   176  308 2 330  V0 176 8     15V0  330 300  V0 154 7 V0  22m / sec 3V V Given  100  4l 2l V V   100  nopen   200 Hz 4l 2l The intensity of electric field at x due to 3 dipole is on the equatorial line

27.

28. 29.

Resultant intensity E1  E  E 1  Q 2a  Qa E1  2 E  2   E1  3 4 0 x  0 x3 25.

P.d a cross C and B will be same. Then Ceff  C1  C2  8  8  16 F If two cells are wrongly connected then  n  4 E i nr P.D across A or B V  E  ir  n  4 E  r   n  n  4  E E   n nr   4   2   2   E V  2 E 1   n ;   n Let P0 be total power of the combination

PAB : PC  RAB : RC ( series) = 2 : 1 2 PAB  P0 3 1 PC  P0 ............ 1 3 1 1 PA : PB  :  2 :1 ( parallel) 3R 6 R 2 2 2 4P PA  PAB   P0  0 ................  2  3 3 3 9 1 1 2 2 P0 PB  PAB   P0  ................  3  3 3 3 9 From 1 , 2 and 3 4P 2P 1 PA : PB : PC  0 : 0 : p0  4 : 2 : 3 9 9 3 E1  E2 l1 50 E 8 4    1  E1  E2 l2 30 E2 2 1 i 2rB B  0 i  2r 0 2rB A Magnetic moment M = IA  0 But A   r 2  r 

M 

2BA A 0 

A 

30.

Maximum flux pass through the cube  

q 0

q 3l

But  

q  3l

 Flux  

3 l 0

C (curies law) T I C CB   I  H T T I1 B1 T2   I 2 B2 T1 8 0.6 16    I 2 0.2 4 2 I2  A / m 3

31.

x

1 1 1   f V u 1 1 1     V  60cm 10 V 12 Final image is coincides with the object then the object of the convex mirror either centre of curvalure or pole R = 50 cm  f  R / 2  25cm Convex lens :

32.

36.

f 1   g  1 l  f   g  l 



 f    1 l  f    l 

    l  l  l

33.

Flux through inside the loop due to outside i the loop   BA  8 2 0  l 2 4 L But   Mi i Mi  8 2 0  l 2 4 L 2 l M L x tan     30 0  R 1 x    x  10 3 300 Impedence  x 2  R 2

34. 35.

 100  300  20 An acceleration charges can electromagnetic waves

37.

 A  Dm  sin    A  2   cot    sin  A / 2  2

38. produce

 2l  l     l  2  A  Dm  sin   2    sin  A / 2 

 A  A  Dm   cos    sin   2  2  A   A  Dm   Sin  900    sin   2   2   Dm  1800  2 A I1  I2 I max  I min I max  I min

  

2

I1  I 2

   

I1  I 2

2

I1  I 2

I1  I 2

 

2

2



39.

40.

41.

2 I 1 I2  I1  I 2 

1 

I 2 1 I2 2    I1 1  1 I2 d  1mm 10 D 2 D Given  d a d 1  a    0.2mm 5 5 h h   mV 2mK .E h   3 2m  KT 2 h   3mKT Photo electric equation , E  W0  K .E hC Case (i) : - E   W0 ............ 1  hC Case (ii) : - 2 E  1  W0 ............  2   hC  hC  2E  1    E     hC hC E 1    E   hC hC   1  

hC  E   hC

42.

Bohr’s second postulate, mvr 

43.

h 2 r  mv 3 2 r 3  r 3 2 Activity A   N

3h 2



Number of moles n  mN A M

N

 Activity A 

44.

N m  NA M

 mN A M

  0.8  

 0.8  4 1   0.2

I C I B I  4  C  I C  20mA 5



45.

CHEMISTRY 3

46.

Al (OH )3  Al  3OH s



1 P 0.1%  2 2   0.05% 2 P1 2 ;

3s

K sp  27s  432 X 1016 4

48.

-4

47.

S=2x10 [OH-]=35=6x10-4 POH =4-log6 = 3.22 pH=10.77 H 2 ( g )  2H ( g )

4 2 Kp  P 1 2 Kp  2p

49.

Q  mst Q 100 t   4 ms 25 1 44-T1=4 T1=40 PV 3  1.65 n1  1 1   0.11 RT1 0.082  546 PV 0.75  0.55 n2  2 2   0.0184 RT2 0.082  273 n n % of gas escaped = 1 2  100  83.3% n1

50.

NH 2  NH 2 KOH glycol

   -bonds=5  -bonds=19 51.

2 4

52.

57.

SO2  Sp 2 SO3  Sp 2



KMnO4 / H CH 3  CH  CH 2  CH 3COOH  CO2

3

SO  Sp Electron repulsions outweighs the stability gained by achieving noble gas configuration

OH

OH

|

|

KMnO4 / OH 

CH 3  CH  CH 2   CH 3  C H  C H 2

53.

O3 CH 3  CH  CH 2    CH 3CHO  HCHO Zn / H 2 O B2 H 6 CH 3  CH  CH 2   CH 3  CH 2  CH 2  OH NaOH , H 2O2 

H 2O / H CH 3  CH  CH 2   CH 3  CH (OH )  CH 3

is more stable 

54.

58.

Cyclic, planar compounds with 4 n  2 e are aromatic

55.

59.

'  ' order O-dichlorobenzene > m-diclorobenzene>Pdichlorobenzene allylic substitution occurs in presence of Cl2 / 770k (or) SO2Cl2 at 475k

60. CH 3

CH 3

|

H 2O / H g SO4



|

H

CH 3  C|  CH  CH 2  CH 3  C|  C H  CH 3

  H 2 SO4

CH 3

CH 3

CH3 re arrangement

CH3

|

H 2O H 

|

  CH 3  C  CH  CH 3   CH 3  C|  CH  CH 3 | | ()

61.

56.

+

O|| AlCl3 CH 3  CH 2  C  Cl  

62. 63. 64.

65.

CH 3

OH

CH 3

Acidic strength of phenols depends on the stability of phenoxide ion. Hence the order is B>D>A>C>E Rosenmund reduction LiAlH4 doesn’t reduce ‘C=C’

Orlon is the polymer of CH2=CH-CN

66. 67. 68.

69. 70. 71.

72.

Chilarity of RNA and DNA is due to D-sugar component Mohr’s salt : ( NH 4 )2 SO4 .FeSO4 .6 H 2O 1.4  N aVa %N  wt 1.4  2 10  37.33 0.75 use of non toxic reagents to produce environmental friendly products Cis  pt ( NH 3 )2 Cl2  is used as anticancer species

4 0 9 hc 4 hc   9 x 9  x 4 3MnO4  5FeC2O4  24 H  2

3

 3Mn  12H 2O  5Fe  10CO2

74.

Yb(70):(Xe)4f145d06s2

77. 78.

T f  no.of particles

85.

d=

86.

87.

H

2   CrO42   Cr2 O7 OH 

76.

84.

80. 81.

t 

73.

75.

82.

10  0.5  15  0.5  20  0.5 3 Bauxite : Al2O3 .2 H 2O Iron will react with water at electric arc conditions. t99.9  5  t75

79.

1 XeF2  H 2O  Xe  2 HF  O2 2 C , SO2  Cl2  SO2Cl2 10SO2Cl2  P4  4PCl5  10SO2

PCl5  4 H 2O  H 3 PO4  5HCl

88.

3HCl  HNO3  NOCl  2Cl  2 H 2O

89.



Li is very small in size and applies very high polarizing power on CO32 ion leading to the

90.

decomposition of Li2CO3

zw Na 3 zw N 3= da 2  270 2  270   3.33  1024 10 3 24 6  (300 10 ) 6  27 10  2 2 MnO4  5C2O4  16 H   2 Mn 2  10CO2  8 H 2O Fe 2  2e   Fe Fe 3  e   Fe2 Fe 3  3e   Fe

G  G1  G2 nE  n1 E1  n2 E2 3E  2 x1  x2 2x  x E 1 2 3 NCERT XII Page no: 452 (Part-2) z2 I.E  2 n There is no line in balmer series as the e comes to 3rd shell

BOTANY 91. 92. 93. 94. 95. 96. 97. 98. 99. 100. 101. 102. 103.

Textual line NCERT (XI) Page no : 31 Textual line NCERT (XI) Page no : 88 Textual line NCERT (XI) Page no : 68 Textual line NCERT (XI) Page no : 248 Textual line NCERT (XII) Page no : 34 Textual line NCERT (XI) Page no : 13 Textual line NCERT (XII) Page no : 107 Textual line NCERT (XII) Page no : 183 Textual line NCERT (XI) Page no : 187 Phytochrome is a chromo protein that exist in Pr and Pfr forms Textual line NCERT (XI) Page no :168 Textual line NCERT (XII) Page no : 38 Textual line NCERT (XI) Page no :36

104. 105. 106. 107. 108. 109.

110. 111. 112. 113. 114. 115.

Textual line NCERT (XII) Page no :78 Textual line NCERT (XI) Page no : 208 Textual line NCERT (XII) Page no :174 Textual line NCERT (XII) Page no : 99 Textual line NCERT (XII) Page no :106 Primary succession results in formation of communities with no record of earlier vegetation Textual line NCERT (XII) Page no :111 Textual line NCERT (XI) Page no : 73 Textual line NCERT (XI) Page no :229 Textual line NCERT (XI) Page no :154 Textual line NCERT (XII) Page no :117 Textual line NCERT (XII) Page no : 83

116. 117. 118. 119. 120. 121. 122. 123. 124. 125.

Textual Textual Textual Textual Textual Textual Textual Textual Textual Textual

line NCERT (XI) Page no : 176 line NCERT (XI) Page no : 149 line NCERT (XI) Page no : 79 line NCERT (XII) Page no : 34 line NCERT (XI) Page no : 188 line NCERT (XI) Page no :97 line NCERT (XI) Page no : 197 line NCERT (XI) Page no : 217 line NCERT (XII) Page no : 97 line NCERT (XI) Page no : 77

126. 127. 128. 129. 130. 131. 132. 133. 134. 135.

Transgenic papaya is resistant to papaya ring spot virus Textual line NCERT (XII) Page no : 112 Textual line NCERT (XI) Page no : 89 Textual line NCERT (XI) Page no :21 Textual line NCERT (XI) Page no :220 Textual line NCERT (XII) Page no : 23 Textual line NCERT (XII) Page no : 204 Textual line NCERT (XI) Page no : 134 Textual line NCERT (XII) Page no :199 Textual line NCERT (XI) Page no : 38

ZOOLOGY 136. 137.

138. 139. 140.

141. 142.

143. 144. 145. 146.

147. 148. 149. 150. 151. 152.

153.

Argentaffin cells of gastric glands and  cells of pancreas produced somatostatin Barriers- Protection against STDs IUDS- most preferred in India OCPS- prevent ovulation Natural- Higher risk of failure A –Agnatha, B – Gnathostomata, C – Tetrapoda, D - Cyclostomata Measles, mumps, polio – viral diseases Ovum and sperms are not transported simultaneously to the ampullary –isthmic junction Cardiac muscles are striped and involuntary muscles Gir – Gujarath Jimcorbett – Uttarakhand Ranthambore – Rajastan The defect is caused by the substitution of glutamic acid by valine Breakdown of proteins in to amino acids Brain is not involved in any reflex action (NCERT – Examplar) Monocytes are originated in bone narrow and further converted into macrophages when they reached to connective tissue Muscular diaphragm and milk producing glands are present in all mammals Male is xc y , female is x c x

All are correct statements Adrenal medulla - Modified sympathetic ganglion Because of absence of antibodies in plasma – no chance for agglutination Anteater – Numbat A = pulmonary artery, B= left atrium, C= left ventricle, D=aorta, E= right atrium,F= right ventricle,G= superior vena cava

154.

155. 156. 157.

158. 159.

160.

161. 162.

163.

164. 165. 166.

Insulin is hypoglycemic hormone. Over dose of it causes glycogenesis so blood glucose level decreases Continued inbreeding leads to Inbreeding depression Neuro transmitters are released by the axon endings and not by dendrites In protostomes – embryonic blastopore changed to mouth In dueterostomes - embryonic blastopore changed to anus Exocoetus- Bony fish Metagenesis- Cnidarian feature Course of blood circulation in human is - Left atrium – left ventricle - body parts – right atrium- right ventricle Four optic lobes collectively termed as corpora quadrigemina Corpus callosum connects the two halves of Cerebral hemispheres In 10th and 11th segments testes are present – one pair in each segments 1) Tunica dartos – Involuntary muscles – Present in the scrotum 2) Cremaster – Voluntary striated muscles – Found in the inguinal canal and scrotum Both muscles helps to maintain temperature necessary for spermatogenesis The correct sequence of muscle contraction B) Release of acetylcholine D) Release of Ca2+ A) Binding of Ca2+ to Tn-C C) Hydrolysis of ATP F) Formation of cross bridges E) Pulling of thin filaments Neanderthal man-buried their dead Heparin, Oxalates and citrates – anticoagulants (NCERT Exemplar) SAN is located at right atrium

167.

168.

169. 170.

171.

172. 173.

Squamous- Blood vessels Cuboidal- Ovary Columnar- Intestinal glands Ciliated- Bronchioles Pseudo stratified- Trachea Lantana, Eichhornia and African catfish are the species are neither threatened nor indigenous species of India. Multiple concept 1) Cochlea- hearing 2) Semicircular canal- balancing 3) Retina-nervous tunic Agnathans are the chordates – without jaws Prototherians are the mammals – oviparous Crocodiles are the reptiles – with complete devided ventricle Between Humerus and Radio-ulna - Hinge joint Rheumatoid arthritis - autoimmune disease

174. 175. 176. 177. 178.

179. 180.

1st to 7th pair of ribs are vertebro - sternal ribs Neurotransmitter is removed by enzyme called acetyl cholinesterase Gastrin, Pancreozymin and Secretin are the hormones A- Temporal bone, B- Ethmoid bone, CZygomatic bone,D- Sphenoid bone Cockroach has a 13 chambered heart and one aorta Brain of cockroach chiefly sensory and endocrine in function Collaterial gland secretion help in the formation of ootheca Flatworm and Roundworm -Triploblastic helmenths Human insulin is being commercially produced from a transgenic species of Escherichia coli