University of Bahrain Course: ITIS331 Prepared By: Dr. Jihene Kaabi
Department of Information Systems Second Semester: 2014-2015
Solution is in page 2
Lab 3 Problem 1: Fashion factory produces five types of products (Shirt, Blouse, Dress, Jeans, and Jacket) by using two production processes: Cutting and Stitching. After deducting raw material costs each unit of product yields the following contributions to profit: Shirt
Blouse
Dress
Jeans
Jacket
$550
$600
$350
$400
$200
Each unit requires a certain time on each process. These are given below (in hours). A dash indicates when a process is not needed. Cutting Stitching
Shirt 12 10
Blouse 20 8
Dress 16
Jeans 25 -
Jacket 15 -
In addition the final assembly of each unit of each product uses 20 hours of an employee’s time. The factory has three Cutting machines and two Stitching machines and works a six-day week with two shifts of 8 hours on each day. Eight workers are employed in assembly, each working one shift a day. The problem is to find how much to make of each product so as to maximize the total profit contribution. 1. Develop a linear programming model for the above given problem. 2. Solve the developed model using Excel Solver. 3. Conduct a sensitivity analysis for the different model parameters.
University of Bahrain Course: ITIS331
Department of Information Systems First Semester: 2013-2014
Decision Variables: let Xi be number of Producti, i =1, i<=5 Objective Function: Zmax= 550X1 + 600X2 + 350X3 + 400X4 + 200X5 Constraints: Process 1 : Cutting 12X1 + 20X2 + 0X3 + 25X4 + 15X5 <= 289 (3 machines *6 days * 2 shift *8 hours) Process 2 : stiching 10X1 + 8X2 + 16X3 + 0X4 + 0X5 <= 192 (2 machines *6 days * 2 shift *8 hours) Employees Time 20(X1+ X2 + X3 + X4 + X5) <= 384 (8 workers * 6 days * 1 shift * 8hrs) 20X1+ 20X2 + 20X3 + 20X4 + 20X5 <= 384 Non-Negitivity Constraints: Xi >= 0; i=1, i<=6
Opimal Solution: to achieve the maximum profit (10920) the factory has to produce 12 units of product 1, 7 units of product 2, and zero units of Product 3,4 and5
ai ? Constraint 1 is binding because its parameters are sensitive Constraint 2 is not binding because its parameters are not sensitive. Constraint 3 is binding because its parameters are sensitive.
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