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SOLUTION KEY REASONING ABILITY Direction (1-5):
1). A; 2). C; 3). A; 4). D; 5). C; 6). Answer: d) Given statements: L = P ≤ W < V ≤ K ≥ Q … (i) B < L …(ii) ; K = M …(iii) Combining (i) and (ii), we get B
P is true. Hence conclusion II is true. 7). Answer: b) Given statements: L=P≤W Q) is not true 8). Answer: b) Given statements: R≤U=B
R≤U=B≤X Thus, R ≤ X or X ≥ R is true. It means either X > R or X = R is true. Hence either conclusion I or II is true. 9). Answer: e) Given statements: C>U≤SD≥Y … (i) Z=O≤P … (ii) Combining (i) and (ii) we get C>U≤S U ≤ S < T = O = Z > D We can‘t compare U and D. Hence I (U > D) is not true 10). Answer: a) Given statements: C>U≤SD≥Y …(i) Z=O≤P …(ii) Combining (i) and (ii) we get C>U≤SD≥Y Thus, Z > Y is true. Hence I is true. Again we can‘t compare C and O. Hence II (C < O) is not true. 11). Answer: a) In the two statements given in I, the common words are ‗But‘, ‗None‘, ‗And‘ and the common code words are ‗Ne‘, ‗Pa‘, ,‘Lo‘. So, ‗Ne‘, ‗Pa‘ and ‗Lo‘ are codes for ‗But‘, ‗None‘ and ‗And‘. Thus, in the first statement, ‗Sic‘ is the code for ‗No‘. 12). Answer: e) From I, we have: M > V > Q. From II, we have: T > Q, T > M, P > T. Combining the above two, we have: P>T>M>V>Q i.e. Q
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www.ibpsguide.com common words are ‗He‘ and ‗is‘ and the common code words are ‗sin‘ and ‗bye‘. So ‗sin‘ and ‗bye‘ are the codes for ‗He‘ and ‗is‘. Thus, in the given statement, ‗co‘ is the code for ‗good‘. 14). Answer: d) From I and II, we find that maximum (243 x 3) i.e. 729 visitors saw the exhibition. But the exact number cannot be determined. 15). Answer: e) From I, we find that number of speakers who attended programme =18-(1/6) of 18 = 15.From II, we find that one-third of 15 i.e. 5 speakers gave 2 speeches each, while each of the remaining 10 speakers delivered only one speech. So, total number of speeches delivered = (5 x 2 + 10 x 1) = 20. Direction (16-20):
16). B; 17). D; 18). D; 19). C; 20). D; Direction (21-25): Words that start with vowel are arranged in decreasing alphabetical order on the left and the words that start with consonant are arranged on the right. Input : horn simple anger best onto danger moon upto erase into Step I : upto horn simple anger onto danger moon erase into best Step II : upto onto horn simple anger moon erase into danger best Step III : upto onto into simple anger moon erase horn danger best Step IV : upto onto into erase anger simple moon horn danger best 21). C; 22). A; 23). A; 24). A; 25). E; 26). Answer: d)
Required distance AF = 30 + 15 = 45 Hence the answer is 45km. 27). Answer: d)
28). Answer: c) Only son of Amar's mother's father - Amar's maternal uncle. So, the girl's maternal uncle is Amar's maternal uncle. Thus, the girl's mother is Amar's aunt. Direction (29-33): 1) First number - the face value of the first letter of the word. 2) Letter - Second letter of the word 3) Last number - the face value of the last letter of the word. For example, ENJOY = 5N25 (E=5, N- Second Letter, Y= 25) 29). D; 30). B; 31). A; 32). B; 33). D; 34). Answer: d)
35). Answer: c)
36). Answer: c)
37). Answer: a)
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38). Answer: b)
48). Answer: a) % £ 8 σ K β Z M S < 2 @ 7 E ⍺ * Σ P 6 1 D $ L 5 # 1 4 49). Answer: d) The second character after the first symbol and the second character before the second symbol have been taken to form the second group. 50). Answer: c) The rest have: The second character in each group is third character to the left of first character of that group as given in the sequence. The third character in each group is immediately right of the first character of that group as given in the sequence. ENGLISH LANGUAGE
Direction (39-43):
39). B; 40). C; 41). E; 42). B; 43). E; 44). Answer: d) 45). Answer: c) T 20 (+1) 21; A 1 (+1) 2 L 12 (+1) 13; K 11 (+1) 12 Similarly, R 18 (+1) 19; A 1 (+1) 2 N 14 (+1) 15; C 3 (+1) 4 H 8 (+1) 9; I 9 (+1) 10 46). Answer: a)
47). Answer: b) Given word, SOVEREIGN After arrangement EEIOVSRNG Required word = 5th from right — 3rd to right = 2nd from right =N
51) C continue (verb), gerund or present participle: continuing Meaning: persist in an activity or process. In the given blank, we need a verb form (present perfect continuous tense) that express the idea of continuity. hence, 'continuing' is correct word choice. 52) D "American society "emphasizes" the importance of education after high school". emphasizes is correct word choice in the given context. denigrate (verb): criticize unfairly; disparage. denigrate is totally irrelevant word. 53) A inflation meaning: a general increase in prices and fall in the purchasing value of money. In this sentence, the comparison is done with inflation. "the cost of undergraduate and advanced degrees continually rises at a greater rate than inflation." inflammatory (adjective) meaning: relating to or causing inflammation of a part of the body. this is totally out of the context word. 54) E pursuing- is correct word choice. pursue-to carry on or continue (a course of action, a train of thought, an inquiry, studies, etc.). 55) B
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www.ibpsguide.com accumulate-gather together or acquire an increasing number or quantity of. accumulate correctly fits in the context of the sentence. "The current system requires the majority of students to accumulate extensive debt with the expectation that" dissipate meaning-(with reference to a feeling or emotion) disappear or cause to disappear. hence, dissipate is totally irrelevant word to fit in this context. 56) C lucrative-producing a great deal of profit. according to the context we need positive word that express profit-making. hence lucrative is correct word choice. 57) E ethical-elating to moral principles or the branch of knowledge dealing with these. ethical is correct word choice and express the idea correctly conveyed in the sentence. 58) A hierarchy-a system in which members of an organization or society are ranked according to relative status or authority. "the hierarchy of differing higher education institutions and cost, and the resulting socioeconomic and racial inequities in college demographics." hierarchy fits in the context of the sentence correctly. 59) D effect is a noun and affect is a verb. in this context, we need a noun form. hence 'effect' is correct word choice. 60) B incur-become subject to (something unwelcome or unpleasant) as a result of one's own behaviour or actions. infer-deduce or conclude (something) from evidence and reasoning rather than from explicit statements. infers is correct choice. 61) D 62) A 63) C 64) E 65) A 66) A 67) D 68) C 69) E 70) C 71). C; ‗on‘ should be replaced by ―in‖ 72). C; use ―ranging‖ in place of ‗ranged‘ 73). E; 74). D; replace ‗them‘ by ―it‖ 75). D; insert ―those‖ after ‗delete‘ 76). D; replace ‗once‘ by ―one‖ 77). C; replace ‗intend‘ by ―intent‖
78). B; replace ‗for‘ by ―of‖ 79). B; replace ‗spread‘ by ―spreading‖ 80). B; replace ‗in‘ by ―for‖ 81). B; 82). D; 83). D; 84). E; 85). E; 86). C; 87). C; 88). A; 89). B; 90). A; 91). E; 92). B; 93). C; 94). A; 95). D; 96). C; 97). B; 98). E; 99). A; 100). D;
101) C 106) C 111) D 116) D 121) D 126) B 131) C 136) A 141) C 146) A
GENERAL AWARENESS 102) A 103) A 104) D 105) B 107) E 108) C 109) E 110) E 112) B 113) B 114) D 115) D 117) B 118) C 119) C 120) A 122) B 123) D 124) D 125) E 127) D 128) C 129) A 130) D 132) A 133) B 134) C 135) B 137) C 138) D 139) D 140) B 142) D 143) C 144) A 145) C 147) D 148) C 149) D 150) C
QUANTITATIVE APTITUDE 151). Answer: c) The given number series is based on the following pattern : 13 × 1 + 1 = 14; 14 × 2 + 2 = 30; 30 × 3 + 3 = 93; 93 × 4 + 4 = 376; 376 × 5 + 5 = 1885 ? = 1885 × 6 + 6 = 11316 Hence, number 11316 will replace the question mark. 152). Answer: b) The given series is based on the following pattern :×1.5,×1.5,…….. 153). Answer: d) The given series is based on the following pattern : ×0.6,×0.6…….. 154). Answer: a) The given series is based on the following pattern : ×0.5,×1,×1.5,×2,×2.5……. 155). Answer: e) 705 + 1 × 23 = 728; 728 + 2 × 23 = 774; 774 + 3 × 23 = 843; 843 + 4 × 23 = 935; 935 + 5 × 23 = 1050; ? = 1050 + 6 × 23 = 1050 + 138 = 1188 156). Answer: b) x² − 6x = 7 x(x-7)+(x-7)=0 → x=7,-1
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www.ibpsguide.com 2y² + 13y + 15 = 0 2y(y+5)+3(y+5)=0 →y = -5, -3/2 i.e x > y 157). Answer: a) 3x² − 7x + 2 = 0 3x(x-2)+(x-2)=0 →x=2,-1/3 2y² − 11x + 15 = 0 2y(y-3)-5(y-3)=0 →y=3,5/2 i.e x
Now, 115 = 3795 x (100/110) = 3450 80 = (3450/115) × 80 = Rs. 2400 CP of shopkeeper = Rs. 2400 Profit = 3450 - 3400 = 1050 Profit % = (1050 / 2400) x100 = 43.75% 163). Answer: b) 12167 = 10580 [1+ (r/100)]1 Or, (12167/10580) = 1+(r/100) Or, (1587/10580) = r/100 r = (1587×100) / 10580 = 15% sum = (10580x100x100) / (115 × 115) = Rs. 8000 Sum = Rs. 8000, Rate = 15% 164). Answer: a) We use only alligation on speed (km/hr) to get ratio of time spent in bus and train. overall speed = (972/10.5) = (1944/21) = 648/7
136/7 : 102/7 136 : 102 Or 4 : 3 Time spent in train = 10.5 (3/7) = 4.5 hours Distance travelled by train = 112 x 4.5 hours = 504 km 165). Answer: b) Apply M1D2 / W2 = M2D2 / W2 Or, (48x55) / (2/3) = (Mx20) / (1/3) M = 66 men Reqd more men = 66 - 48 = 18 men 166). Answer: b) Let the required number of days be x. 49 x (17/2) x 6 = 119 x 7 x x x = 3 days 167). Answer: c) n(S) = 5! = 120 n(E) = 1 Ratio probability = 1/120 168). Answer: a) Let the cost of commodity be Rs.x Then , (2x/3) × 1.05 + (1x/3) × 0.98 = x + 400 Or, (1/3) × (3.08) = x + 400 Or, 0.8 x = 400 × 3 Or, (1200 / 0.08) = (120000 / 8)
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www.ibpsguide.com x = Rs.15000 169). Answer: d) Let the distance between A and B be d km Then. [ d/(45/60)] – [d / (49.5/60)] = 8 Or, 4d/3 – 120d / 99 = 8 Or, (132d – 120d) / 99 = 8 D = (8 × 99) / 12 = 66 km 170). Answer :c) D = Rs. 336.96 T = 3 years R= 12% P = Difference × (100)3 / r2 (300 + r) = (336 .96 × 1000000) / [144(300+12) = 336960000/44928 = Rs. 7500 171). Answer: e) Circumference of outer track 418 2πR = 418 R = (418 × 7) / 44 = 66.5 Circumference of inner track = 396 2πr = 396 r = (396 × 7) / 44 = 63 width of the track = 66.5 – 63 = 3.5m Note: instead of calculating in two parts perform a single calculation like Width = R – r = 7/44 (418 - 396) = (7/44) × 22 = 3.5m 172). Answer: a) Let Raja's salary be Rs. x. Raja gives 30% of his salary to his mother. Raja gives [(x × 30)/100 = Rs. 3x/10] to his mother Remaining salary of Raja = x – (3x /10) = Rs. 7x /10 Investments of Raja in insurance and PPF is 40% of the remaining salary. Insurance + PPF = (7x x 40)/ (10x100) = 7x/25 Remaining salary of Raja = 7x/10 – 7x/25 = (35x —14x)/50 = 21x /50 Raja's investment in insurance scheme = (7x/25) × (4/7) = 4x/25 Now, according to the question, 3x/10 - 4x/7 = 8400 or, (15x-8x) / 50 =8400 or, 7x = 8400 x 50 x = (8400x 50)/7 =1200 x 50 = Rs. 60000 173). Answer: b) Suppose total work = 60 units (LCM of 10 and 15) (A + B)'s one day's work = 60/10 = 6 units And (B + C)'s one day's work = 60/15 = 4 unit
According to the question, C : A = 60 : 100 or, C :A = 3 : 5 C/A = 3/5 Or, A = 5C/3 Again, A +B = 6 units ..(i) B+C = 4 units …(ii) Putting the value of A in equation (i), we get [5C/3 + B = 6 unit ] – [B + C = 4 units] = 5C/3 - C=2units Or, 2C/3 = 2 units C = 3 units Then A = 5C/3 = 5×3 / 5 = 5 units Now, total work is 60 units Then A alone can do the work in, (60 / 5 =) 12 days 174). Answer: b) Total number of balls = 7 + 5 = 12 Now, three halls are picked randomly Then, the number of sample space n(S) = 12C3 =(10 ×11 ×12) / (1×2×3) = 220 The number of events n(E) = 7C2 x5C1 = [(6x7)/2] x 5 = 21 x 5 = 105 P(E) = n(E)/n(S)=105/220 = 21/24 175). Answer: d) Amount received from scheme A = P+ [(Px2x11)/100] =( 100P+22P)/100 = 122P/100 Amount received from scheme B = (P + 600) [1+ (20/100)]2 = (P + 600) (6/5)2 = (P + 600) (36/25) = 36P/25 + (600x36)/25 = 36P/25 + 864 Now, according to the question, 36P/25 + 864 – 122P/100 = 1216 Or, 36P/25 – 122P/100 = 1216-864 Or, (144P-122P)/100 = 352 Or, 22P = 352×100 P = (352×100) / 22 = Rs. 1600 176). Answer: b) ? = 619.002 – 134.99 ÷ 14.998 –(9.01)2 = 620 – 135 ÷ 15 – (9)2 = 620 – 90 = 530 177). Answer: e) ? = 439.97 ÷ 15.02 + 208.08 ÷ 8.01 –16.01 = 450 ÷ 15 + 208 ÷ 8 – 16 = 30 + 26 – 16 =30 + 10 = 40 178). Answer: d) 4? x √226 = 245.998 ’ 8.001 + 929.99
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www.ibpsguide.com or, 4? x √225 = 248 ’ 8 + 930 or, 4? x 15 = 31 + 930 = 961 or 4? = 960/15 = 64 = 43 ?=3 179). Answer: e) ? % of (140.06 x 7.99 — 679.92) = 330.01 = [?x(140x8-680)] / 100 = 330 or, ? x (1120 — 680) = 330 x 100 or, ? x 440 = 33000 ? = 33000 / 440 = 75 180). Answer: e) ? = 40% of 859 + 86.01 ÷ 7.99 = (40 x 860) / 100 + 86 ÷ 8 = 344 + 11 = 355 181). Answer: e) Number = 1040 x7/13 = 560 182). Answer: b) Total boys = 3980 Total Girls = 3390 ∴ Diff = 3980 - 3390 = 590 183). Answer: e) Ratio = 750/720 = 25/24 184). Answer: c) B97 = 800, G98 = 560 ∴ % = 560/800 x 100 = 70% 185). Answer: d) B99 = 70, G95 = 450 ∴ % = more = 720-450/450 x 100 = 60 186). Answer: a) Relative speed of police = 10 - 4 = 6 kmph Time taken by the policeman to cover 100 m = (100/1000 x 1/6)hr = 1/60 hr In 1/60 hr the thief covers a distance of 4x1/60 = 1/15km = 1/15 x 1000 = 66.66m 187). Answer: c) Let the cost of each chair be x and that of each table be y Then 28x = 6y 18x + 3y = 4800 ∴ y = 14/3 = x ∴ 18x + 3 x 14x/3 = 4800 ∴ 18x + 14x = 4800 ∴ x = 4800/32 = 150 ∴ y = 700 Hence cost of 15 chairs and 6 tables = (15 x 150) + (6 x 700) = 6450 188). Answer: b)
No. of men originally = x(D + d)/d = 5(40+10)/10 = 5x50/10 = 25 men 189). Answer: d) We can find the speed originally S = x1x2(t1+t2)/(t2t1-t1t2) = (6x2)(1/2 + 1/2)/(6/2 - 2/2) = 12x1/(3-1) = 12/2 = 6 kmph ∴ Distance = t1×S(S+x1)/x1 = 1/2x6(6 + 6)/6 = 36/6 = 6 km 190). Answer: c) Time = (D+ty)/(x+y) ; D = 200, x = 10, y = 5, y = 5 ∴ T = (200+(5x5))/(10+5) = 225/15 = 15 hrs 191). Answer: d) Because D = 4 lakhs ∴ Total popn = 20 lakhs Let total popn < 18 be x and that above 18 be y ∴ x + y = 500000 ..........(1) 45x/100 + 58y/100 = 264000 ∴ 45x + 58y = 2640000 ................(2) From (1) and (2), x =200000, y = 300000 Males below 18 are 55% of x, ie 55% of 200000 = 1.1 lakh 192). Answer: c) We can find popn of E directly 20 x 16/100 = 3.2 lakh. 193). Answer: a) Let total popn < 18 be x and that above 18 be y Popn of A = 2.5 lakhs ∴ Popn od D = 2 lakhs ∴ x + y = 200000..........(1) X x 50/100 + y x 48/100 = 98000 50x + 48y = 9800000 ......(2) From (1) and (2), x = 100000 and Y = 100000 Popn of male > 18 of D is 50% of 100000 = 50000 194). Answer: d) Data inadequate. 195). Answer: c) Population of A is 25% of x = 1000000 ∴x = 4000000 ∴ Population of C is 18% of 40 lakhs = 7.2 lakhs 196). Answer: d) % of students passed in both subjects is 100 - (30 + 25 - 10) = 55% ∴ 55% of 40 = 22 197). Answer: a) A + B can do the work in 4 days = 4[1/20 + 1/50] = 40 x 7/100 = 7/25
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www.ibpsguide.com Remaining work = 1 - 7/25 = 18/25 ∴ B can do the rest of the work in 18/25 x 20 = 72/5 = 14 2/5 days 198). Answer: c) A + B did 5/9 work. So C did 1 - 5/9 = 4/9 work ∴ (A+B)'s share : C's share = 5/9:4/9=5:4 ∴ C's share = 4500x4/9 = 2000 199). Answer: c) Let their speeds be u and v ∴ u + v = 200/5 = 40 ......(i)
u - v = 10 ......(ii) -1 -1 ∴ u = 25 kmh v = 15 kmh ∴ 5u + 5v = 200 200). Answer: d) Let the distance travelled at 40 kmh-1 = x km ∴ Distance travelled at 30 kmh-1 = 300 - x ∴ 300/8 = 300/x/40 + (300-x)/30 ∴ x/40 + (300-x)/30 = 8 3x + 1200-4x/120 = 8 1200 - x = 960 ∴ x = 240
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