Konten dengan label tugas kuliah http://www.halimi.web.id diupload 2 Januari 2017

Mata Kuliah Rancangan Percobaan (Experimental Design) Judul Konten : RAL Annova Para praktikan mata kuliah budidaya pakan alami ingin mengetahui pengaruh pemberian bubuk Spirulina platensis terhadap pertumbuhan Moina sp. dengan perlakuan sebagai berikut: A : Manure (Sebagai Kontrol), B : 1 gram/hari, C : 2 gram/hari, dan D : 3 gram/hari. Tabel hasil kelimpahan Moina sp. Perlakuan Ulangan Jumlah Rerata A B C D I 80 5000 7000 3000 15080 3770 II 10 11500 210 1000 12720 3180 III 40 40 2000 18500 20580 5145 Jumlah 130 16540 9210 22500 48380 Rerata 43,333 5513,333 3070 7500 1. Anova dengan data lengkap FK = (483802)/3 x 4 = 2340624400/12 = 195052033,3 JKT = (802 + 50002 + 70002 + 30002 + 102 + 115002 + 2102 + 10002 + 402 + 402 + 20002 + 185002) - 195052033,3 = (6400 + 25000000 + 49000000 + 9000000 + 100 + 132250000 + 44100 + 1000000 + 1600 + 1600 + 4000000 + 342250000) - 195052033,3 = 562553800 - 195052033,3 = 367501766,7 JKP = ((1302 + 165402 + 92102 + 225002)/3) - 195052033,3 = ((16900 + 273571600 + 84824100 + 506250000)/3) - 195052033,3 = (864662600/3) - 195052033,3 = 288220866,7 - 195052033,3 = 93168833,33 JKG = 367501766,7 - 93168833,33 = 274332933,33 DBp = t – 1 = 4 -1 = 3 DBg = (rt-1) – (t-1) = (3x4 – 1) – (4-1) = (12-1) – 3 = 11 – 3 = 8 KTP = 93168833,33 / 3 = 31056277,78 KTG = 274332933,33 / 8 = 34291616,67 Tabel anova SK Perlakuan Galat Total

DB 3 8 11

JK KT 93168833,33 31056277,78 274332933,33 34291616,67 367501766,7

Fhit Ftab 5% 0,905652191 4,066

Ftab 1% 7,591

Konten dengan label tugas kuliah http://www.halimi.web.id diupload 2 Januari 2017

Konten dengan label tugas kuliah http://www.halimi.web.id diupload 2 Januari 2017

Kesimpulan: Fhit(0,9056) < Ftab(0,05;3;8) Maka terima H0 dan tolak H1 Perlakuan tidak berpengaruh signifikan terhadap hasil Tidak diperlukan uji lanjutan 2. Anova dengan dihilangkan nilai ekstrim Tabel kelimpahan (dihilangkan nlai ekstrim) Perlakuan Ulangan Jumlah Rerata A B C D I 80 5000 7000 3000 15080 3770 II 10 11500 xx 1000 12510 4170 III 40 xx 2000 18500 20540 6846,667 Jumlah 130 16500 9000 22500 48130 Rerata 43,333 8250 4500 7500 FK = (481302)/10 = 2316496900/10 = 231649690 JKT = (802 + 50002 + 70002 + 30002 + 102 + 115002 + 10002 + 402 + 20002 + 185002) - 231649690 = (6400 + 25000000 + 49000000 + 9000000 + 100 + 132250000 + 1000000 + 1600 + 4000000 + 342250000) - 231649690 = 562508100 – 231649690 = 330858410 JKP = ((1302)/3) + ((165002)/2) + ((90002)/2) + ((225002)/3) - 231649690 = ((16900/3) + (272250000/2) + (81000000/2) + (506250000/3)) - 231649690 = (5633,34 + 136125000 + 40500000 + 168750000) - 231649690 = 345380633,3- 231649690 = 113730943 JKG = 330858410 - 113730943 = 217127466,7 DBp = t – 1 = 4 -1 = 3 DBg = (10 – 1) – (4-1) = (10 - 1) – 3 = 9 – 3 = 6 KTP = 113730943 / 3 = 37910314,45 KTG = 217127466,7 / 6 = 36187911,11 Tabel anova SK Perlakuan Galat Total

DB 3 6 9

JK 113730943 217127466,7 367501766,7

KT 37910314,45 36187911,11

Fhit Ftab 5% 1,047596097 4,757

Ftab 1% 9,780

Konten dengan label tugas kuliah http://www.halimi.web.id diupload 2 Januari 2017

Konten dengan label tugas kuliah http://www.halimi.web.id diupload 2 Januari 2017

Kesimpulan: Fhit(1,0476) < Ftab(0,05;3;8) Maka terima H0 dan tolak H1 Perlakuan tidak berpengaruh signifikan terhadap hasil Tidak diperlukan uji lanjutan

Konten dengan label tugas kuliah http://www.halimi.web.id diupload 2 Januari 2017

Tugas pa el Anova moina sp.pdf

DBg = (rt-1) – (t-1) = (3x4 – 1) – (4-1) = (12-1) – 3 = 11 – 3 = 8. KTP = 93168833,33 / 3 = 31056277,78. KTG = 274332933,33 / 8 = 34291616,67. Tabel anova. SK DB JK KT Fhit Ftab 5% Ftab 1%. Perlakuan 3 93168833,33 31056277,78 0,905652191 4,066 7,591. Galat 8 274332933,33 34291616,67. Total 11 367501766,7.

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