m%Yak wxlh

ms
m%Yak wxlh

ms
3

(26)

4

(2)

5

(27)

4

(3)

3

(28)

5

(4)

5

(29)

3

(5)

1

(30)

(6)

4

(31)

(7)

5

(32)

(8)

3

(33)

(9)

2

(34)

(10)

2

(11)

2

(12)

5

(13)

3

(14)

3

m

(1)

4

wa

.co

3 2 4 5 4

(36)

5

(37)

2

(38)

4

(39)

1

1

(40)

4

5

(41)

3

5

(42)

2

1

(43)

2

(19)

4

(44)

2

(20)

4

(45)

4

(21)

5

(46)

3

(22)

2

(47)

5

(23)

3

(48)

3

(24)

3

(49)

2

(25)

4

(50)

5

(16) (17)

w.

(18)

vib

(15)

ha

(35)

ww



w'fmd'i' ^W'fm<& Wmldrl iïuka;%Kh - 2016 fN!;sl úoHdj - I m;%h ms
[2 jk mssgqj n,kak

-2fN!;sl úoHdj - II m;%h ms




A fldgi - jHqy.; rpkd

1. (a)

uhsfl%daógr bial=remamq wdudkh

(b)

uQ,dxl fodaIh we;a±hs m¯laId ls¯u

(c)

(a) - ndysr ykq (b) - ndysr ykq (c) - wNHka;r ykq



( )]

m

[a × b − π ( d2 ) ] t 2

wa



.co

ridhksl ;=,dj 2 (e) V = a × b − π d t 2 d =

^,l=Kq 1&

^ish,a,u y˙ kï ,l=Kq 2 $ folla y˙ kï ,l=Kq 1&

(d) bf,lafg%daksla ;=,dj

[

^,l=Kq 1&

m



^,l=Kq 1& ^,l=Kq 1&



^,l=Kq 1&

(f) (i) 0.01 mm

^,l=Kq 1&

3.42 mm 17.12 =

5

(iii)



follg" WmlrKfhka ñkqï .; yelafla oYuia:dk follg neúks'

2. (a) we;a fodr

- A

ìysf∞r -

B

^,l=Kq 1& ^,l=Kq 1&

^,l=Kq 1&

fkdyel' l=àrh ;=< WIaK;ajh 100 C° mj;ajd .; fkdyels ksid oKAv yryd wkjr®: ;;a;ajhla mj;ajd .; fkdyels fõ' yqud, >k;ajh wvq ksid ie,lsh hq;= fõ,djla ;=< oKav r;alr .; yels ùu ^,l=Kq 1&

ww

(b)

3.42 mm

w.



ha

(ii) 3.05 + 3.51 + 3.52 + 3.51 + 3.53 = 17.12



vib





(c)

Out

In

^,l=Kq 1& [3 jk mssgqj n,kak

-3 (d)

Q t



(θ1 − θ2)



;dmh .,d hEfï iS>%;dj

x



WIAK;aj wkql%uh

^,l=Kq 1&

(e)

WIaK;aj udkj, mdGdxl fjkia fkdù mej;Su

^,l=Kq 1&

(f)

oKafâ yrialv úYalïNh T1 yd T2 w;r ≥r okakd ld,hloS tall k,hl .,d hk ;r, m˙udj$ ialkaOh

^,l=Kq 1& ^,l=Kq 1&



^,l=Kq 1&

m

x Q × 1 . t (θ1 − θ2) A

(g) k =

(h) c,h r;aùug ld,h m%udKj;a fkdjk ksid T3 ,T4 WIAK;ajudkj, mdGdxl ie,lsh hq;=

WIaK;aj udkj, mdGdxlj, ie,lsh hq;= ;rï fjkila we;s fkdùu'

wa



.co

fjkila fkdfmkaùu (i) fkdyel' = l



λ = 2l



√ mI

T = 1 2L m



I 1 f = 2 l m





1 2 (b) f 2 = y L = mT

(

2

2

w.

y

=

l

4L m

T

^,l=Kq 1&



= mx

ww



f

2

(



^,l=Kq 1&



vib

f=



^,l=Kq 1&

ha

λ 2

3. (a)

^,l=Kq 1&

^,l=Kq 1&

(c) (i) l †. wvq w.hl mj;ajd ta w;r lvodis wdfrdaylhla r|jd ixLHd;h olajd iriq, lïmkh lr èjks udk fmÜáh u; ;nd fia;= w;r mr;rh l%ufhka jeälr f.k hk úg lvodis wdfrdaylh úisjk fudfydf;ys l †. ,nd .kS' ^,l=Kq 1& (ii) B ys L †. lïmkh lrjd A ys lv∞is wdfrdaylfhka r|jd fia;= w;r mr;rh l=vd w.hl isg l%ufhka jeä lrf.k hk úg lv∞is wdfrdaylh úisjk fudfyd; tkï iqirjk wjia:dj ,nd .kak' tu wjia:dfõ° A lïìfha †. uekf.k tys mriamrh fidhd"

1/l



u.ska .kq ,efí' tu.ska rEmfha ±lafjk wdldrhg Bg wkqrem ixLHd;h ,nd 0

f

.; yel'

^,l=Kq 1&

[4 jk mssgqj n,kak

-4(d) f 2 0 wlaI ,l=Kq ls¯u yd yevh T (e) (i) wkql%uKh = =

m

1 2 m 4L 1 2 = wkql%uKh 4L

^,l=Kq 1&

m



^,l=Kq 1&

(ii) wvqu w.h f ∝ 1 ksid wvqu w.hg wod< †. fidhd .;aúg jeä w.hkg wod< †.j,a l uek.; yel' ^,l=Kq 1&

.co



= 480 f × 1 l 1 = k f l 100 480 = k 23.7 474 = k 100 l 480 = l 474 23.7 480 l = × 23.7 cm 474 (f) f A

^,l=Kq 1&

= 24 cm

vib

l

ha

wa





^,l=Kq 1&

^,l=Kq 1&

- t,jqï fldaIh



B

- iaúph ^talux&



C

- .e,ajfkdaógrfha wdrlaIl Wml%uh



D

- ueo ìx≥ .e,ajfkdaógrh

ww

w.

4. (i) A

(ii) A

- jeä fõ,djla tlu Odrdj iemhSug yels ùu'

D

- by< ixfõ°;djhla ;sîu'

(iii)

^,l=Kq 1&

E (< E0)





P S

(iv)

2 Vcm−1 200 0.01 Vcm−1

10 mVcm−1

^,l=Kq 1&





^,l=Kq 1& [5 jk mssgqj n,kak

-5100

(v) 200 × 4 × 10−1

=

2V

(vi) ke;' †. uekSfï Nd.sl f∞aIh jeähs'

^,l=Kq 1&

(vii) m%;sfrdaOh t,jqï fldaIhg fY%aKs.;j iïnkaO ls¯u

^,l=Kq 1&

(viii) 4 10

: 1996 : 399

3990 Ω



(ix) 200 × 4 = 80 cm 10 (x) F

1



= 1 4

F



=

2



1 800

F1 > F2 ys Nd.sl fodaIhg b;d l=vdhs'

^,l=Kq 1& ^,l=Kq 1&

wa

B fldgi - rpkd

ha

fndAÜgqfõ nr we;sjk Wvql=re f;rmqï n,hg iudk ùu' Wvql=re f;rmqï n,fha l%shd fr®Ldj yd nfr® l%shd fr®Ldj talfr®Çh ùu ^,l=Kq 1& u

vib

5. (a) (b)

^,l=Kq 1&

m



^,l=Kq 1&

.co



0.4 cm



^,l=Kq 1&

mg

w.

600 + 70 × 8 600 + 560 1160 kg 11600 N

ww

(c)

(d) (i) m%;sfrdaë n,h = 1160 × 0.6 N = 6960 N = 696 N (ii) F 696 696

696

696 50

= = = = =

mu (AVP) V 2 2 AV P 2 0.05 × 1000 × V 5 × 1000 × V2

=

50 × V

=

100

V

^,l=Kq 1&

^,l=Kq 1&

^,l=Kq 1& ^,l=Kq 1&

2

2

[6 jk mssgqj n,kak

-6-

3.73 ms

−1

=

V

=

V

(e) (i) P = FV 696 = 696 × 50







=



(ii) P

= FV × 100

^,l=Kq 1&



2596 W

40



696

^,l=Kq 1&



^,l=Kq 1&



=

696 × 50

=

6490 W

m



696 50

× 2.5

.co







=

11600 10000



jdhq nqn, iys; m%foaYfha° .sf,k m˙udj

=

11600 8000



wu;r m˙udj

1

wa

(f) (i) m
ha

V

1 ( 8000

= 11600 ×



vib





= =

^,l=Kq 1&

^,l=Kq 1&



1 10000

)

^,l=Kq 1&

2900

2000 8000 × 10000

11600

0.29 m3

4

^,l=Kq 1&

10

(ii) = 0.29 × 100 × 1 6 60 =

0.029 m3

ww

6. (a)

^,l=Kq 1&

w.



h

β 25 cm

α l

β α

= h l = h D

^,l=Kq 1&



^,l=Kq 1&

uE; ,laIHh jk D ≥r we;súg wefiys oDIaá ú;dkfha wdmd;sk fldaKh α > Bg wE;ska we;s ,laIHhl jia;=j we;s úg wefia wdmd; lrk fldaKh

α > β ∴ úYd,s; m%;sìïnh ,efí'



^,l=Kq 1&

[7 jk mssgqj n,kak

-7(b) mshú weiska n,k úg wefia oDIaá ú;dkfha wdmd; lrk fldaKh fuka wkaùlaIh ;=
Wmfk;

wjfk; l

fe

h

h1 α

f0

m

2f0

wjfk; ^,l=Kq 1& Wmfk; ^,l=Kq 1& ^Bysi iys;" O%ejh yryd hk lsrK iuÛ&

.co

h2

wa



α1 M = α

= me × mo



=





o

−1

)



^,l=Kq 1&

^,l=Kq 1&

( 252.5 + 1 ) ( 2022 − 1) (10 + 1)

(101 −1)

ww

11 × 100

w.

(d)

( Df + 1 ) ( lf e



vib

h h2 / D h h = 2 = 2 × 1 h h/D h1 h



^,l=Kq 1&

ha

h h /D h h M = 2 = 2 = 2 × 1 h h/D h1 h

1100



^,l=Kq 1&

(e) (i) <Û fkdfmkSu ^fyj;a ≥r oDIaál;ajh& ^,l=Kq 1& (ii) 1 − 1 = 1 V U f 1 1 + − 1 =− ^,l=Kq iïuq;sh yd ksjer† wdfoaYhg ,l=Kq 1& 25 2.5 U



1 1 + = 1 25 2.5 U 11 1 + = 25 U 25 U = cm 11 +

^,l=Kq 1& [8 jk mssgqj n,kak

-8kj U

1

=

25 11

175 81 × 11

= 81 × 25 + 175 81 × 11



=

2025 + 175 81 × 11

2200 81 × 11 200 = cm 81

= U

1



= 2.47 cm



1 −1 = 1 f V U 81 = − 1 1 − 200 V 2.5







1 = V

81 − 80 200

1 1 = 200 V V = 200 cm

^ksjer† wdfoaYhg ,l=Kq 1&

ha

81 − 80 200

vib

1 = V













ww

v

w.

(iii) 20.2 + 2.5 cm 22.7 cm 7. (a)

^,l=Kq 1&

wa

81 = − 1 1 − 200 V 2.5



m



+

.co



^,l=Kq 1&

^,l=Kq 1&

t

^,l=Kq 1&

(b) m%d:ñlhg jvd oaú;slfha fmdg .Kk jeä ùu m%d:ñlhg jvd oaú;slfha lïì uy; wvq ùu

^,l=Kq 1&

(c)

v



t

1 g jvd Wi jeä úh hq;=h'

^,l=Kq 1&

[9 jk mssgqj n,kak

-9vp Np

(d) (i)

Np Ns

vs Ns



vp vs



11000 = p Ns 250

=

N

44 = Np Ns 1



44 : 1 = Np : Ns

(ii)

Vrms =



=

vp

Vp

= 250

√2 √2

wa

= 353.5 V (iii) cQ,a ;dmh iq,O s drd ydksh

ha

ukaodhk ydksh

(iv) mdr.uH;dj jeä ls¯u yd i%dj ldka≥j wvq ls¯u I = F × l I

(ii) (iii)



BI (ab) N Cos θ

^,l=Kq 1&

=

V

20

√2

I

IR

= I × 100 =

1 5√2

I



=



=

1.6

5√2

^,l=Kq 1&

BI (ab) N

1 × 0.2 × 5√2 = 1.6 × √ 2 10

= 0.16 ×

20 × 10 ( 100 × 100

(





^,l=Kq 1&

^,l=Kq 1&





^,l=Kq 1&

= BIab N

ww



vib

(e) (i)

^,l=Kq 1&

w.



^,l=Kq 1&

Vrms

= 250 × 1.41



^,l=Kq 1&

m





^,l=Kq 1&

.co



=

× 400

Nm

^,l=Kq 1&

(iv) meΩï ú,s fyj;a kHdfoaYl fh†h hq;=h'

^,l=Kq 1&





√2

= 0.225 Nm

[10 jk mssgqj n,kak

- 10 I



=

6 πqrv



(F)

= MLT−2



6 πqrv

= [q] [r] [v]



= ML−2



= ML−1 T−1 L LT−1 = MLT−2





U

(b) U + F = mg 4 πr3pq + 6πqrv = 4 πdq 3 3

vib

^,l=Kq 1&

w.

(d)

^,l=Kq 1&



v

r

^,l=Kq 1&

wa

6πqrv + 4 πg (d − p)r3 3 v = 2 qr2g(d − p) 9

(c)

^,l=Kq 1&

mg

ha



F

3



^,l=Kq 1&

m

8. (a) F

t

.co

(f)

v = 2g (d − p) r v 9q



2

ww



(i)

= m

y

(ii) m

=

x

2g (d − p) r2 9η

^,l=Kq 1&

2g (d − p) 9m 2g (iii) η = (d − p) 9m

^,l=Kq 1&

= 2 × 10 (1240 − 700) 9 × 800

^wdfoaaYhg ,l=Kq 1&





η



=

60

= 2 × 540 9 × 80

[11 jk mssgqj n,kak

- 11

12 = 1.5 Nm−2 8

=

η (iv) v

= m

× r2 2 = 800 × 10 100

v



^,l=Kq 1&

( )

= 800 × 10 100





= 8 ms−1

(e)

^,l=Kq 1&

η



^,l=Kq 1&

40 × 1.5 × 8



=

60 × 8



=

480 N

(ii)

ha

=

F

V/ms−1

^,l=Kq 1&

^,l=Kq 1&

vib



wa

.co

θ (f) (i) F = η∆V d A F 8 = 1.5 × −1 −4 −3 400 × 10 1× 10

m



^,l=Kq 1&

8

(i)

p,kh jk bf,lafg%dak" bf,lafg%dak iu. .eàu;a mrudKq iu. .eàu;a ksid ydks jk pd,l Yla;sh u.ska ;dmh ckkh fõ' ^,l=Kq 1&

ww

9. (a)

w.

^yevhg ,l=Kq 1& d/ mm 0.1 ^tall iu`. ksjer†j wlaI ,l=Kq ls¯ug ,l=Kq 1&

(ii)

ú≥,s ia;%slalh" iQ;%sld n,anh









^,l=Kq 1&

(b) (A) fY%aKs.;j

R1 I

R2

r E [12 jk mssgqj n,kak

- 12 E = I ( r + R1 + R2 ) I =

(

E (r + R1 + R2)

)



^,l=Kq 1&



(ii) R yryd ;dm Yla;sh Wm†k iS>%;dj } I 2 R 1 1 2

R2 yryd ;dm Yla;sh Wm†k iS>%;dj } I R2

folgu









m

fuys° m%;sfrdaO ;=


ckkh jeä fõ'

iudka;r.;j



R1

.co

(B)

R2 r



I











ww

(

E R1 R2 R1 + R2









Rf = R1 R2 (R1 + R2) I =



E



ha



^iul m%;sfrdaOh fiùug& ^,l=Kq 1&

vib



wa



)

+r





w.

I × R2 R Odrdj I1 = 1 yryd (R1 + R2) R2 yryd Odrdj I2 =

R2 yryd ;dm Yla;sh Wm†k iS>%;dj =















I × R1 (R1 + R2)

R1 yryd ;dm Yla;sh Wm†k iS>%;dj =



^,l=Kq 1&



I 2 R22

(R1 + R2)2 I2 R21 (R1 + R2)2







^,l=Kq 1&





^,l=Kq 1&



× R1 = × R2 =

^,l=Kq 1&

I 2R2R1 (R1 + R2)2 I2R2R1 (R1 + R2)2

× R2

× R1

folgu ^,l=Kq 1&





R1 > R2 neúka R2 yryd ;dm Yla;s W;air®ck iS>%;dj jeäfõ'





^úl,aam l%uh } P } V2/ R wkqj ;r®llr we;akï o ,l=Kq ,nd †h yel'&



















^,l=Kq 1&





[13 jk mssgqj n,kak

- 13 (c) (i)

P = I2 R

( )

2



(ii)



^,l=Kq 1&

R = r fõ'

^,l=Kq 1&

E . R (R + r)

=

( ) ( ) 2





P max

E . R (2r)

1

= 4

E (r)

2

. r

1 2 = 4 r



F

wa

(iii)



=

m

túg P max



vib

ha

R

9. (B) (a)

1

8

3

^,l=Kq 1&

^,l=Kq 1&



7

w.

2



.co



6

ww

4 5

^,l=Kq 1&

Vcal

+VS

−VA

VA

Vn

−VS

^,l=Kq 1&

[14 jk mssgqj n,kak

- 14 -

( ) ( ) (

(b) Vo = 10 V 1 R1 Vo = −

^,l=Kq 1&

10

R2 V2 ∴ Vo = − 10 V1 + 10 V1 R1 R2

^,l=Kq 1&

)

(c) 10 = 5 R1

^,l=Kq 1&

10 = 0.2 R2

(d)

(

V1 = 2 V0 = V

−(10)

V1 = 0

= 0

V2 = 5

V/V t1

1

t2

t3

(e) (i) A

B

C

0

0

1

0 0

0 1

F

0 0

1

ABC

1 0 1 1

A B C

0

ww

1

1

1

1

w.

0

1

^ld, mr;rj,g w.hka iuÛ&

^,l=Kq 3&

vib



)



t

ha

10 11

−1V

^,l=Kq 2&

wa

2

V0 =

.co



= 50 kΩ

m

10 100 R1 = 2 kΩ R2 = = 0.2 2

0 0



^,l=Kq 2&

1 1 1 ABC 1 F2 ABC + ABC + ABC (ii) ^,l=Kq 1& (iii)

^,l=Kq 2&

[15 jk mssgqj n,kak

- 15 10.(A) (a) tall m˙udjl we;s c,jdIam ialkaOh

^,l=Kq 1&

(b) tall m˙udjl we;s c,jdIam ialkaOh tu WIaK;ajfha ix;Dma; c, jdIam ialkaOhg ork wkqmd;h fõ'

^,l=Kq 1&

(c)

^,l=Kq 1&

(d) (i)

idfmalaI wdr®ø;dj

=

ksrfmalaI wdr®ø;dj ldur WIaK;ajfha ix'jd'mS'

.co



m

c,h >kSNjkh lr bj;a lrk ksid wjldYfha we;s c, jdIam idkaøKh wvqh' tneúka ksrfmalaI wdr®ø;dj wvqfõ' idfmalaI wdr®ø;dj jeä jkafka WIaK;ajh wvq lrk úg tu wjldYh ix;Dma; ùug wjYH c, jdIam ialkaOh wvq w.h ksid idfmalaI wdr®ø;dj by< hhs'

ksrfmalaI wdr®ø;dj 80 = 31. 70 100 = 80 × 31. 70 100 2536 = 10

wa

ksrfmalaI wdr®ø;dj

ha

= 25.36 Hgmm

^,l=Kq 1&

^,l=Kq 1&

^,l=Kq 1&

^,l=Kq 1&

(iii) 24 °C ° ;sìh hq;= m%udKh 22.3 Hgmm

^,l=Kq 1&

30 °C 24 °C meñfKk úg"

^,l=Kq 1&



PV = nRT

m RT M = PVM RT

ww

PV =



w.



m

vib

(ii) 25.36 Hgmm jkafka 26 °C ° tu ksid ;=Idr wxlh 26 °C





30 °C m30 = 25.36 × 13600 × 10 × 10 × 60 × 18 8.3 × 303 −3

24 °C m24 = 22.3 × 13600 × 10 × 10 × 60 × 18 8.3 × 297 −3



^,l=Kq 1&

^ksjer† wdfoaYhg& ^,l=Kq 1& ^,l=Kq 1&

[16 jk mssgqj n,kak

- 16 >kSNjkh jk c,jdIam = m − m + m24 30 24 2 ialkaOh (m)

2m30 − m24 = 2 =



=

[



=

13600 × 10 × 10 × 60 × 18 8.3



=

−3

−3

]

]

25.36 22.3 − 303 297

]

.co

[

25.36 22.3 − 303 297

13600 × 10 × 10 × 60 × 18 × (0.162392 − 0.075084) 8.3 −3

13600 × 10 × 10 × 60 × 18 8.3 −3



=



=

1633.52 g



=

1.634 Kg

× 0.092308





^,l=Kq 1&

ha



13600 × 10 × 10 × 60 × 18 8.3

]



(e) wjldYfha c, jdIam wvq lrk ksid m%dYajdi jd;h iuÛ c,h msg jqjo wdYajdi iuÛ th fkd,efí' tu ksid ffi,j, c, idkaøKh wvqfõ' nysiai%dù l%shdj ≥r®j, fõ' tu ksid c,h mdkh l< hq;=h' ^,l=Kq 1&

lef;davh

wefkdavh

ww

w.

10.(B)(a) (i)

vib



−3

wa



[ ][ [

25 − 3 × 2 22.3 − 297 303

13600 × 10 × 10 × 60 × 18 8.3

^,l=Kq 1&

m





μA

V



^,l=Kq 1&

(a) fldaIhg iïnkaO w.% fol udre ls¯u

^,l=Kq 1&

[17 jk mssgqj n,kak

- 17

m%ldY Odrdj

i ^,l=Kq 1&

B

^,l=Kq 1&

C

^,l=Kq 1&

V

^,l=Kq 1&

D

= hf



=



= hC λ

6.6 × 10−34 × 3 × 108 −9 660 × 10 16 −35

= 66 × 3 × 10 660

E

= 3 × 10−19



=

17

× 10

10

ha



3 × 10−19 = 30 16 1.6 × 10−19

15 = = 1.875 ev 8

vib

KE

.co



E E

wa

(b)

úNj wka;rh

m

A

= hf − Q

= 1.875 − 1 = 0.875 ev

= 0.875 × 1.6 × 10 = 1.4 × 10 J VS e

=

VS e

=

−19

^,l=Kq 1&

KEmax

ww



w.

−19

^,l=Kq 1&

0.875 ev

VS e = 0.875 ev

^,l=Kq 1&

[18 jk mssgqj n,kak

- 18 (c)

(i)

to



= 2 × 10−14 Hz



Q = 1.32 × 10 ev h = Δα (ii) Δλ

^,l=Kq 1&

−19



=

(iii)

−19

m

= 0.66 × 10−33



= 6.6 × 10 Js −34

^,l=Kq 1&

^,l=Kq 1&

.co



(iv)



1

2

3

4

wa



^,l=Kq 1&

(1.98 − 0.66) × 10−19 (5 − 3) × 1014

1.32 × 10 = 2 × 1014

^,l=Kq 1&



ha

1.35

ww

w.

vib

2.64

^,l=Kq 1&

Physics - S (Paper I & II) Answer Guide.pdf

Page 2 of 18. [3 jk msgqj n,kak. - 2 -. 1. (a) uhsfl%daógr bial=remamq wdudkh ^,l=Kq1&. (b) uQ,dxl fodaIh we;a±hs m ̄laId ls ̄u ^,l=Kq1&. (c) (a) - ndysr ykq. (b) - ndysr ykq. (c) - wNHka;r ykq ^ish,a,u y ̇ kï ,l=Kq2 $ folla y ̇ kï ,l=Kq1&. (d) bf,lafg%daksla ;=,dj. ridhksl ;=,dj ^,l=Kq1&. (e) [ π. d. 2( ). 2. ] V = a × b − t ^,l=Kq1&. [ π.

470KB Sizes 69 Downloads 356 Views

Recommend Documents

Combined Maths - S (Paper I & II) Answer Guide.pdf
There was a problem loading more pages. Retrying... Whoops! There was a problem previewing this document. Retrying... Download. Connect more apps.

Chemistry - S - (Paper I & II) (1).pdf
Page 1 of 20. [ 2jk msgqj n,kak'. 1. [n = 2, l = 1, ml = 0, ms = +. 1. 2. ] hk lafjdkagï wxl l=,lfhka ksrEmKh jkafka". (1) 1s bf,lafg%dakhls' (2) 2s bf,lafg%dakhls' (3) 2p bf,lafg%dakhls'. (4) 3s bf,lafg%dakhls' (5) 3p bf,lafg%dakhls'. 2. X yd Y hk

NAT June 2012 Paper II Gujarati Answer Key.pdf
There was a problem previewing this document. Retrying... Download. Connect more apps... Try one of the apps below to open or edit this item. Main menu.

answer Part II Paper III KSR.pdf
18 B D D C 68 D C A B. 19 C A C B 69 C A B A. 20 A B B A 70 B D D C. 21 C A A B 71 A C C C. 22 B C D C 72 B D A B. 23 D D C C 73 C A B D. 24 A C B A 74 A B A C. 25 B B A D 75 D D C A. 26 A A B C 76 C C C B. 27 C D C B 77 D A B D. 28 D C C A 78 A B D

KCSE 2006 PHYSICS PAPER 1 Answer all questions ...
helium gas. The mass of the fabric making the balloon is 0.30kg. Determine the maximum tension on the string trying the balloon to the rigid support. 18. (a) Define specific latent heat of fusion of a substance. ( 1 mark). (b) Water of mass 200 g at

CUSAT CAT Previous year question paper Physics 2009 Answer ...
Page 1 of 1. CUSAT CAT Previous year question paper Physics 2009 Answer Key.pdf. CUSAT CAT Previous year question paper Physics 2009 Answer Key.pdf.

IIT JAM 2016 Physics (PH) Question Paper and Answer Key.pdf ...
Page 4 of 18. IIT JAM 2016 Physics (PH) Question Paper and Answer Key.pdf. IIT JAM 2016 Physics (PH) Question Paper and Answer Key.pdf. Open. Extract.

7285 - Subject - Engineering Physics Paper - II - B.E. First Semster ...
Page 1 of 2. TKN/KS/16/7285 1 P.T.O. B.E. First Semester (Fire Engineering) (C.B.S.). Engineering Physics Paper - II. P. Pages : 2 TKN/KS/16/7285. Time : Two Hours Max. Marks : 40. Notes : 1. All questions carry marks as indicated. 2. Solve Question

Maharashtra Board Higher Secondary Physics-II Sample Paper 3.pdf ...
Page 2 of 2. Maharashtra Board Higher Secondary Physics-II Sample Paper 3.pdf. Maharashtra Board Higher Secondary Physics-II Sample Paper 3.pdf. Open.

Note : (i) (ii) Section - 'B' answer all the very short answer (iii) Section ...
refers to e-mail that appears to have originated from one source when it was actually sent from another source. OSEI-044. 1. P.T.O.. Page 2. 3. is the ability of users to deny that they performed specific actions or transactions. 4. XSHM stands for.

TET PAPER - I & II (2018).pdf
contexts—Children With Special Needs (CWSN), Inclusive Education. x Understanding of pedagogic methods — Enquiry based learning, Project based. learning, Survey, Observation and Activity based learning, Cooperative and. collaborative learning. x

12 STD ENGLISH PAPER I & II - SURESH 7373448484
Page 1 of 7. Bohol Profile. Bohol. Basic Facts. Geographic Location Bohol is nestled securely at the heart of the Central. Visayas Region, between southeast of Cebu and southwest. of Leyte. Located centrally in the Philippine Archipelago, specificall

b.com i paper ii financial accounting (admission of 2006 onwords ...
b.com i paper ii financial accounting (admission of 2006 onwords) 1451.pdf. b.com i paper ii financial accounting (admission of 2006 onwords) 1451.pdf. Open.

12 STD ENGLISH PAPER I & II - SURESH 7373448484 (1).pdf ...
12 STD ENGLISH PAPER I & II - SURESH 7373448484 (1).pdf. 12 STD ENGLISH PAPER I & II - SURESH 7373448484 (1).pdf. Open. Extract. Open with. Sign In.

Paper - II
democracy the concept of civil service neutrality is outdated; instead there is a need for a civil service with professional competence and commitment ? SECTION B. 5. Comment on any three of the following in not ... (d) “The machinery of administra

NAT June 2013 Paper II Comparative Study of Religions Answer Key.pdf
Page. 1. /. 1. Loading… Page 1. Main menu. Displaying NAT June 2013 Paper II Comparative Study of Religions Answer Key.pdf. Page 1 of 1.

physics-chemistry-answer-keys.pdf
There was a problem previewing this document. Retrying... Download. Connect more apps... Try one of the apps below to open or edit this item.

physics-i
where 'm' is the order of fringe. m = 0 corresponds to zeroth order fringe,. i.e. path difference between two waves reaching O is zero. λ m. D xd. = is zero. m = 1 corresponds to first order fringe,. i.e. path difference between two waves is λ and

AUG 2 4 2O1 ii :)-s' 1 : I
Aug 24, 2015 - Eula Aileen Perez. Katrina Coritana. Arlene de Panes. Jake Mancenido. Archel Tapia. DOCUMENTATION. Noel Martinez. Jennifer Rivera.

NAT Dec 2013 Paper II Labour Welfare and Industrial Relation Answer ...
48 C. 49 B. 50 C. Qno Answer. Page 1 of 1. Main menu. Displaying NAT Dec 2013 Paper II Labour Welfare and Industrial Relation Answer Key.pdf. Page 1 of 1.Missing:

Biology-paper-with-answer PP.pdf
Martha Chase. (3) Matthew Meselson ... In India, the organisation responsible for assessing. the safety of ... Page 3 of 7. Biology-paper-with-answer PP.pdf.

PART I Module I: Module II
networks,sinusoidal steady state analysis,resonance,basic filter concept,ideal current ... spherical charge distribution,Ampere's and Biot-Savart's law,Inductance ...

paper-1-answer-key.pdf
ANSWER KEYS : ESE–2018. Set-A Set-B Set-C Set-D. 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29. 30. 31. 32. 33. 34. 35. 36. 37. 38. 39. 40. 41. 42. 43. 44. 45. 46. 47. 48. 49. 50. 51. 52.