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Dr. G.S. Giridhar

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In data interpretation questions, be careful about units given in the directions. For example, in directions if it is given that the data is in ten thousands then don’t forget to add four zeros to the data. i.e., 7 means it becomes 70000.

What is his overall profit percent?

Quantitative Aptitude Directions ( Q.1-5): Study the following table and answer the questions that follow. Following table shows the number of Boys and Girls studying in different schools. SCHOOL A B C D E F G H

BOYS 340 860 1320 430 1250 860 740 320

GIRLS 280 740 1260 240 1125 750 650 460

1. In how many schools the number of boys less than the average? 1) 5 2) 2 3) 4 4) 1 5) 6 2. What is the ratio of the number of boys in school F and the number of girls in school B? 1) 33 : 35 2) 12 : 17 3) 11 : 5 4) 43 : 37 5) None of these 3. The number of girls in school E is approximately what percent of the total number of students of that school? 1) 39% 2) 47% 3) 53% 4) 40% 5) 65% 4. In how many schools the number of girls more than 20% of the total number of girls of all the schools? 1) 2 2) 3 3) 6 4) 1 5) 4 5. In which of the following schools, the number of girls is same as the number of boys of schools D and H together? 1) B 2) G 3) E 4) C 5) F Directions (Q.6-7): Four of the five parts numbered 1, 2, 3, 4 and 5 are exactly same. Which of the parts is not equal to the other

Explanations 1. Average boys = 340 + 860 + 1320 + 430 + 1250 + 860 + 740 + 320

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8 6120 = ⎯⎯ = 765 8 ∴ A, D, G & H less than the average 2. Required Ratio = 860 : 740 = 43 : 37 1125 3. ⎯⎯ × 100 = 47.37% 2375 4. Total number of girls = 280 + 740 + 1260 + 240 + 1125 + 750 + 650 + 460 = 5505 20% of 5505 = 1101 ∴ Two schools more than the required figure 6. Substitute a and b values as '1' each. All will have same answer except (2) 7. All will have answer as 99 except (1) 8. Convert all his profit in centimetres By using 90 cm he gains 10 cm.

four? The number of that part is the answer. 6. 6(a2 + b2) + 13ab = (2a + 2b) (4a + 3b) − 2a2 = (1) (2) ⎯ ⎯ 2 (√ 6a + √ 6b) + ab = (2a + 3b) (2b + 3a) = (3) (4) (6a + b) (a + 6b) − 24ab (5) 7. LCM of 3 & 33 = 43 + 33 + 23 = 60 + 15% of 260 (1) (2) (3) ⎯ = 426 − 42 × 8 + √ 81 = 62 + 82 + 23 − 32 (4) (5) 8. A dishonest cloth merchant claims that he sells goods at 20% profit but he uses only 90 cm for one metre scale. What is his overall profit percent? 1 1 1)13 ⎯ % 2) 30% 3) 33 ⎯ % 9 3 4) 35% 5) None of these 9. What digit should come in place of star (★) in the following number, so that it is exactly divisible by 9? 527683★426 1) 2 2) 5 3) 9 4) 1 5) 0 10. A building worth Rs.2,70,000 is constructed on land worth Rs.80,000. Find after how many years will the value of both be same if land appreciates at 20% p.a. and building depreciates at 20% p.a.? 1) 4 2) 6 3) 7 4) 3 5) None Directions (Q. 11-15): In each of the following number series questions one number is wrong. You have to identify that number. 11. 45 388 172 297 233 261 1) 388 2) 261 3) 45 4) 233 5) 172 12. 14 159 281 382 463 529 1) 463 2) 14 3) 382 4) 159 5) 529 13. 38 61 90 123 158 199 1) 158 2) 123 3) 90 4) 61 5) 199 14. 6 15 51 249 1487 10401 1) 1487 2) 249 3) 10401 4) 15 5) 6 15. 20000 8000 3200 1280 512.2 204.8 1) 20000 2) 512.2 3) 3200 4) 204.8 5) 8000 Directions(Q.16-20): Study the following graph carefully and answer the questions accordingly.

Following graph gives the sale and revenue of a departmental store during 2005 to 2012. Sales in lakh rupees and revenue in ten thousands.

20% profit is 20 cm His total profit =10 + 20 = 30cm 30 1 Profit% = ⎯ × 100 = 33 ⎯ % 90 3 9. 5 + 2 + 7 + 6 + 8 + 3 + 4 + 2 + 6 = 43 43 + 2 = 45, which is divisible by 9 10. Let the required time be x years 20 x 20 x 80000 1 + ⎯ = 270000 1− ⎯ 100 100

13. Difference between the numbers is prime numbers 14. 6 × 3 − 4 = 14; 14 × 4 − 5 = 51 51 × 5 − 6 = 249; 249 × 6 − 7 = 1487 1487 × 7 − 8 = 10401 15. 20000 × 2 ÷ 5 = 8000; 8000 × 2 ÷ 5 = 3200 3200 × 2 ÷ 5 = 1280; 1280 × 2 ÷ 5 = 512 512 × 2 ÷ 5 = 204.8

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4 ⎯ 80000 5 4 x = ⎯⎯⎯ = ⎯⎯ = ⎯ x 6 270000 6 ⎯ 5 8 2 x 2 3 2 x ⎯= ⎯ ⇒ ⎯ = ⎯ ∴x=3 27 3 3 3 11. 45 + 73 = 388; 388 − 63 = 172 3 172 + 5 = 297; 297 − 43 = 233 3 233 + 3 = 260 12. 14 + 122 + 1 = 159; 159 + 112 + 1 = 281 281 + 102 + 1 = 382; 382 + 92 + 1 = 464 464 + 82 + 1 = 529

Revenue

Sales

16. The average annual increase in sales from 2007 to 2010 is ....... 1) Rs.45000 2) Rs.50000 3) Rs.25000 4) Rs.40000 5) None of these 17. From 2005 to 2012, in which year was the revenue increased by more than 100% as compared to the previous year? 1) 2008 2) 2012 3) 2006 4) 2009 5) 2010 18. What is the average sales of the store per year approximately? 1) Rs.8 lakhs 2) Rs.7.5 lakhs 3) Rs.9 lakhs 4) Rs.7 lakhs 5) Rs.9.5 lakhs 19. The revenue of 2009 was approximately what percent of the revenue in the year 2007? 1) 76% 2) 120% 3) 85% 4) 165% 5) 130% 20. What is the respective ratio of the sales of the store in the year 2010 and 2006? 1) 95 : 63 2) 12 : 13 3) 19 : 13 4) 12 : 19 5) None of these

Key 1-3 2-4 3-2 4-1

5-5 6-2 7-1 8-3

9-1 10-4 11-2 12-1

13-2 14-4 15-2 16-3

17-4 18-2 19-4 20-3.

(Writer - Director, RACE Institute, Hyderabad)

(9.5 − 7.5) 16. ⎯⎯⎯⎯ lakh = Rs.25000 8 17. From the graph we can easily make out 9−4 Increment percent in 2009 is ⎯⎯ × 100 4 = 125% 18. Average sales = 4.5 + 6.5 + 7.5 + 7 + 5 + 9.5 + 8.5 + 11 ⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯ 8 59.5 = ⎯⎯ = 7.4375 lakhs 8 9 19. ⎯⎯ × 100 ≈ 164% 5.5 20. Required ratio = 9.5 : 6.5 = 19 : 13.