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𝑨 βŠ‚ 𝑩 vdpy; , 𝑨 ∩ 𝑩 , 𝑨\𝑩 Mfpatw;iw ntd;glj;jpy; tiuf.

(Oct-2014)

ST UD Y

2.

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π‘¨βŠ‚π‘©

π‘¨βˆ©π‘© =𝑨

𝑨\𝑩 = βˆ…

𝑷 = 𝒂, 𝒃, 𝒄 , 𝑸 = π’ˆ, 𝒉, 𝒙, π’š , 𝑹 = {𝒂, 𝒆, 𝒇, 𝒔} vdpy,; (i) 𝑷 \𝑹 (ii) 𝑸 ∩ 𝑹 (iii) 𝑹 \ (𝑷 ∩ 𝑸) (Jun-15) (i) 𝑃 \𝑅 = {a, b, c}\{a, e, f, s}={b, c} (ii) 𝑄 ∩ 𝑅 = {g, h, x, y}∩{a, e, f, s} = { } (iii) 𝑅 \ (𝑃 ∩ 𝑄) β‡’ (𝑃 ∩ 𝑄) = {a, b, c} ∩ g, h, x, y = { } 𝑅 \ (𝑃 ∩ 𝑄) = π‘Ž, 𝑒, 𝑓 , 𝑠 \{ }= {π‘Ž, 𝑒, 𝑓 , 𝑠}

4.

𝑨 = {πŸ’, πŸ”, πŸ•, πŸ–, πŸ—}, 𝑩 = {𝟐, πŸ’, πŸ”}, π‘ͺ = {𝟏, 𝟐, πŸ‘, πŸ’, πŸ“, πŸ”}, vdpy; , (i) 𝑨 βˆͺ (𝑩 ∩ π‘ͺ) (Apr-14) (ii) 𝑨 ∩ (𝑩 βˆͺ π‘ͺ) (Jun-12, Oct-12) (iii) 𝑨\(π‘ͺ\𝑩) fhz;f. (i) 𝑨 βˆͺ (𝑩 ∩ π‘ͺ) β‡’ (𝐡 ∩ 𝐢) 𝐴 βˆͺ (𝐡 ∩ 𝐢) (ii) 𝑨 ∩ (𝑩 βˆͺ π‘ͺ) β‡’ (𝐡 βˆͺ 𝐢) 𝐴 ∩ (𝐡 βˆͺ 𝐢)

6.

𝟐, πŸ’, πŸ” ∩ 1, 𝟐, 3, πŸ’, 5, πŸ” = {2, 4, 6} 4, 6, 7, 8, 9 βˆͺ 2, 4, 6 = {2, 4, 6, 7, 8, 9}

= =

2, 4, 6 βˆͺ 1, 2, 3, 4, 5, 6 = {1, 2, 3, 4, 5, 6} πŸ’, πŸ”, 7, 8, 9 ∩ 1, 2, 3, πŸ’, 5, πŸ” = {4, 6}

= =

A\ (C\B)

5.

= =

DO O

(iii) 𝑨\ (π‘ͺ\𝑩) β‡’ (𝐢\𝐡)

ZY

3.

1, 2, 3, 4, 5, 6 \ 2, 4, 6 = {1, 3, 5} 4, 6, 7, 8, 9 \{1, 3, 5}= {4, 6, 7, 8, 9}

A kw;Wk; B vd;gd C-d; cl;fzq;fs;. NkYk; mit ntl;lhf; fzq;fs; vdpy; ntd;glk; tiuf.

𝑨 ∩ (𝑩\π‘ͺ) ntd;glk; tiuf.

(B\C) https://doozystudy.blogspot.in/

A ∩(B\C) https://doozystudy.blogspot.in/

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(𝑩 βˆͺ π‘ͺ) \𝑨 ntd;glk; tiuf.

(BβˆͺC) 8.

𝑨 βˆͺ (𝑩 ∩ π‘ͺ) ntd;glk; tiuf.

(B∩C) π‘ͺ ∩ (𝑩\𝑨) ntd;glk; tiuf.

10.

π‘ͺ ∩ (𝑩 βˆͺ 𝑨) ntd;glk; tiuf.

11.

DO O

(B\A)

ZY

9.

(BβˆͺA)

(BβˆͺC) \A

ST UD Y

7.

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(Apr-2015)

Aβˆͺ(B∩C)

C ∩(B\A)

C ∩(BβˆͺA)

𝑨 = 𝟏, 𝟐, πŸ‘, πŸ’ , 𝑩 = βˆ’πŸ, 𝟐, πŸ‘, πŸ’, πŸ“, πŸ”, πŸ•, πŸ—, 𝟏𝟎, 𝟏𝟏, 𝟏𝟐 vd;f. 𝑹 = 𝟏, πŸ‘ , 𝟐, πŸ” , πŸ‘, 𝟏𝟎 , πŸ’, πŸ— βŠ† 𝑨 Γ— 𝑩 xU cwT vdpy; xU rhh;G vdf; fhl;Lf. mjd; kjpg;gfk;> Jizkjpg;gfk;> tPr;rfk; fhz;f. (Jun-2012, Oct-2013) A apy; cs;s xt;nthU cWg;gpw;Fk; xU epoy; cU B apy; cs;sJ. / ,J xU rhh;G MFk;. kjpg;gfk; = {1, 2, 3, 4} Jizkjpg;gfk; = {βˆ’1, 2, 3, 4, 5, 6, 7, 9, 10, 11, 12} tPr;rfk; = {3, 6, 9, 10}

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𝒇 = {(𝟏𝟐, 𝟐), (πŸπŸ‘, πŸ‘), (πŸπŸ“, πŸ‘), (πŸπŸ’, 𝟐), (πŸπŸ•, πŸπŸ•)} vd;w fhz;f. 2 d; Kd; cUf;fs; = 12, 14 3 d; Kd; cUf;fs; = 13, 15

13.

𝑹 = {𝒂, βˆ’πŸ), (βˆ’πŸ“, 𝒃), (πŸ–, 𝒄), (𝒅, βˆ’πŸ)} vd;gJ rkdpr; rhh;igf; Fwpf;fpwJ vdpy; , a, b, c , d kjpg;Gfis fhz;f. (Apr-2013) π‘Ž = βˆ’2, 𝑏 = βˆ’5, 𝑐 = 8, 𝑑 = βˆ’1

14.

𝑨 = {βˆ’πŸ, βˆ’πŸ, 𝟏, 𝟐} kw;Wk; 𝒇 = { 𝒙,

𝟏 𝒙

𝑨 - apypUe;J 𝑨 -f;F xU rhh;ghFkh? tPr;rfk; = { tPr;rfj;jpy;

βˆ’1 1 , βˆ’1, 1, }, 𝑓 = 2 2 βˆ’1 1 cs;s , Mfpa 2 2

βˆ’2,

1 βˆ’2

rhh;gpy;

2

kw;Wk;

3-d;

Kd;

cUf;fisf;

ST UD Y

12.

: 𝒙 ∈ 𝑨} vdpy,; f-d; tPr;rfk; fhz;f. NkYk; f vd;gJ , βˆ’1,

1 βˆ’1

, 1,

1 1

, 2,

1 2

cWg;Gfs; Ay; ,y;yhjjhy; A apypUe;J Af;F rhh;G MfhJ.

𝑨 = {𝟏, 𝟐, πŸ‘, πŸ’, πŸ“}, 𝑩 = β„• kw;Wk; f : A β†’ B MdJ f(x) = x2 vd tiuaWf;fg;gl;Ls;sJ. f d; tPr;rfk; fhz;f. NkYk; rhh;gpd; tifia fhz;f . (Apr-2015, Jun-2015) f (x) = x2 f (1) = 12 = 1 f (2) = 22 = 2 f (3) = 32 = 9 f (4) = 42 = 16 f ( 5) = 52 = 25 (i) f - d; tPr;rfk; = {1, 4, 9, 16, 25} (ii) ,J xd;Wf;F xd;whd rhh;G

16.

rhh;G 𝒇 = { βˆ’πŸ, 𝟐 , βˆ’πŸ‘, 𝟏 , βˆ’πŸ“, πŸ” , βˆ’πŸ’, πŸ‘ } I (i) ml;ltiz (ii) mk;Gf;Fwpg;glk; Mfpatw;wpd; %yk; Fwpf;fTk;. (i) ml;ltiz (ii) mk;Gf;Fwpg;glk; x βˆ’1 βˆ’3 βˆ’5 βˆ’4 f(x) 2 1 6 3

18.

DO O

17.

ZY

15.

𝒙, 𝒙 β‰₯ 𝟎 vDk; NghJ> (Jun-2013) βˆ’π’™, 𝒙 < 𝟎 vDk; NghJ {(𝒙, π’š)| π’š = 𝒙 , 𝒙 ∈ ℝ } vd;w cwT> rhh;ig tiuaWf;fpwjh? mjd; tPr;rfk; fhz;f. (i) x- d; xt;nthU kjpg;gpw;Fk; 𝑦 = π‘₯ vd;w xU jdpj;j (xNunahU) kjpg;G cs;sJ. vdNt ,J rhh;ghFk;. (ii) ,jd; tPr;rfk; G+r;rpak; kw;Wk; kpif nka;naz;fs; MFk;. 𝒙 =

𝑭 = {(𝟏, πŸ‘), (𝟐, πŸ“) (πŸ’, πŸ•) (πŸ“, πŸ—), (πŸ‘, 𝟏)} vDk; rhh;gpw;F kjpg;gfk;> tPr;rfk; fhz;f. (i) kjpg;gfk; = {1, 2, 3, 4, 5} (ii) tPr;rfk; = {3, 5, 7, 9, 1}

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19.

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𝑨 = {𝟏𝟎, πŸπŸ“, 𝟐𝟎, πŸπŸ“, πŸ‘πŸŽ, πŸ‘πŸ“, πŸ’πŸŽ, πŸ’πŸ“, πŸ“πŸŽ}, 𝑩 = {𝟏, πŸ“, 𝟏𝟎, πŸπŸ“, 𝟐𝟎, πŸ‘πŸŽ} kw;Wk; π‘ͺ = {πŸ•, πŸ–, πŸπŸ“, 𝟐𝟎, πŸ‘πŸ“, πŸ’πŸ“, πŸ’πŸ–} vdpy; , A\ (B∩C) fhz;f. (𝐡 ∩ 𝐢) = {1, 5, 10, πŸπŸ“, 𝟐𝟎, 30} ∩ {7, 8, πŸπŸ“, 𝟐𝟎, 35, 45, 48} = {15, 20} 𝐴\ 𝐡 ∩ 𝐢 = 10, 15, 20, 25, 30, 35, 40, 45, 50 \ 15, 20 = {10, 25, 30, 35, 40, 45, 50}

(Apr- 2012)

𝑨 = πŸ“, 𝟏𝟎, πŸπŸ“, 𝟐𝟎 , 𝑩 = {πŸ”, 𝟏𝟎, 𝟏𝟐, πŸπŸ–, πŸπŸ’} kw;Wk; π‘ͺ = {πŸ•, 𝟏𝟎, 𝟏𝟐, πŸπŸ’, 𝟐𝟏, πŸπŸ–} Mfpa fzq;fSf;F A\(B\C) = (A\B) \C vd;gJ nka;ahFkh vd Muha;f. (Jun-2013) LHS 𝐴\(𝐡\𝐢) β‡’ (𝐡\𝐢) = 6, 10, 12, 18, 24 \ 7, 10, 12, 14, 21,28 = {6, 18, 24} 𝐴\(𝐡\𝐢) = 5, 10, 15, 20 \ 6, 18, 24 = {5, 10, 15, 20 …….. (1) RHS (𝐴\𝐡) \𝐢 β‡’ (𝐴\𝐡) = 5, 10, 15, 20 \ 6, 10, 12, 18, 24 = {5, 15, 20} (𝐴\𝐡) \𝐢 = 5, 15, 20 \ 7, 10, 12, 14, 21,28 = {5, 15, 20} ……………. (2) LHS β‰  RHS (1) β‰  (2) vdNt A\(B\C) β‰  (A\B)\C vd;gJ nka;ay;y.

21.

𝑿 = {𝟏, 𝟐, πŸ‘, πŸ’, πŸ“}, 𝒀 = {𝟏, πŸ‘, πŸ“, πŸ•, πŸ—} vd;f. X - ypUe;J Y- f;fhd cwT {(1, 1), (1, 3) (3, 5) (3, 7), (5, 7)} vd tiuaWg;gpd; mJ rhh;G MFkh vd Muha;f. ,y;iy vdpy;> fhuzk; $W. (Apr-2012) (i) rhh;G my;y (ii) Vnddpy; X-y; cs;s 1,3 Mfpa cWg;Gfs; Y-y; cs;s ,uz;L cWg;GfNshL njhlh;GgLj;jg;gl;Ls;sd. (1, 1), (1, 3) kw;Wk; (3, 5), (3, 7)

22.

𝑨 = {𝒍, π’Ž, 𝒏, 𝒐, 𝟐, πŸ‘, πŸ’, πŸ•} kw;Wk; 𝑩 = {𝟐, πŸ“, πŸ‘, βˆ’πŸ, π’Ž, 𝒏, 𝒐, 𝒑} Mfpatw;wpw;F fzq;fspd; ntl;L> ghpkhw;Wg; gz;G cilaJ vd;gij rhpghh;f;fTk;. (Apr-2013) 𝐴 ∩ 𝐡 = {𝑙, π‘š, 𝑛, π‘œ, 2, 3, 4, 7} ∩ {2, 5, 3, βˆ’2, π‘š, 𝑛, π‘œ, 𝑝} = {π‘š, 𝑛, π‘œ, 2, 3} ……… 1 𝐡 ∩ 𝐴 = {2, 5, 3, βˆ’2, π‘š, 𝑛, π‘œ, 𝑝} ∩ {𝑙, π‘š, 𝑛, π‘œ, 2, 3, 4, 7} = {π‘š, 𝑛, π‘œ, 2, 3} ……… 2 (1) & (2), Mfpatw;wpypUe;J A∩B = B∩A vd;w fzq;fspd; ntl;L> ghpkhw;Wg; gz;G cilaJ vd rhpghh;;f;fg;gl;lJ.

23.

𝑼 = {πŸ’, πŸ–, 𝟏𝟐, πŸπŸ”, 𝟐𝟎, πŸπŸ’, πŸπŸ–} , 𝑨 = {πŸ–, πŸπŸ”, πŸπŸ’} kw;Wk; 𝑩 = {πŸ’, πŸπŸ”, 𝟐𝟎, πŸπŸ–} vdpy; (𝑨 βˆͺ 𝑩)’ kw;Wk; (𝑨 ∩ 𝑩)’ Mfpatw;iwf; fhz;f. (Jun-2014) 𝐴 βˆͺ 𝐡 = 8, 16, 24 βˆͺ 4, 16, 20, 28 = {4, 8, 16, 20, 24, 28} 𝐴 βˆͺ 𝐡 ’ = π‘ˆ\ 𝐴 βˆͺ 𝐡 = {4, 8, 12, 16, 20, 24, 28}\{4, 8, 16, 20, 24, 28} = {12} 𝐴 ∩ 𝐡 = 8, πŸπŸ”, 24 ∩ 4, πŸπŸ”, 20, 28 = {16} 𝐴 ∩ 𝐡 ’ = π‘ˆ\ 𝐴 ∩ 𝐡 = 4, 8, 12, 16, 20, 24, 28 \ 16 = {4, 8, 12, 20, 24, 28}

25.

ZY

DO O

24.

ST UD Y

20.

{𝟏, πŸ’, πŸ—, πŸπŸ”} ypUe;J 𝑩 = {βˆ’πŸ, 𝟐, βˆ’πŸ‘, βˆ’πŸ’, πŸ“, πŸ”}f;F 𝟏, βˆ’πŸ , πŸ’, 𝟐 , πŸ—, βˆ’πŸ‘ , (πŸπŸ”, βˆ’πŸ’)} vd;gJ xU rhh;ghFkh? 𝒇 vd;gJ vdpy; mjd; tPr;rfj;ijf; fhz;f. (Oct-12) apy; cs;s vy;yh cWg;gpw;Fk; xNu xU epoy; cU Bapy; cs;sJ. / ,J rhh;G MFk;. (ii) tPr;rfk; = {βˆ’1, 2, βˆ’3, βˆ’4} 𝑨 = 𝒇={ rhh;G (i) A

𝑨 = {πŸ“, πŸ”, πŸ•, πŸ–}, 𝑩 = {βˆ’πŸπŸ, πŸ’, πŸ•, βˆ’πŸπŸŽ, βˆ’πŸ•, βˆ’πŸ—, βˆ’πŸπŸ, βˆ’πŸπŸ‘} vd;f. 𝒇 = {(𝒙, π’š): π’š = πŸ‘ βˆ’ πŸπ’™, 𝒙 ∈ 𝑨, π’š ∈ 𝑩 } vd

tiuaWf;fg;gl;Ls;sJ. 𝒇-d; tPr;rfk; fhz;f. (Oct-2014) (ii) f d; cWg;Gfis vOJf (Apr-2016) 𝑦 = 3 βˆ’ 2π‘₯

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π‘₯ = 5 vdpy;> 𝑦 π‘₯ = 6 vdpy;> 𝑦 π‘₯ = 7 vdpy;> 𝑦 π‘₯ = 8 vdpy;> 𝑦 (i) f -d; tPr;rfk; (ii) 𝑓 = { 5, βˆ’7 ,

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= 3 βˆ’ 2 5 = 3 βˆ’ 10 = = 3 βˆ’ 2(6) = 3 βˆ’ 12 = = 3 βˆ’ 2 (7) = 3 βˆ’ 14 = = 3 βˆ’ 2 (8) = 3 βˆ’ 16 = = {βˆ’7, βˆ’ 9, βˆ’11, βˆ’13} 6, βˆ’9 , 7, βˆ’11 , (8, βˆ’13)}

βˆ’7 βˆ’9 βˆ’11 βˆ’13

𝑿 = {𝟏, 𝟐, πŸ‘, πŸ’} vd;f. 𝒇 = {(𝟐, πŸ‘), (𝟏, πŸ’), (𝟐, 𝟏), (πŸ‘, 𝟐), (πŸ’, πŸ’)} vd;w cwT X- ypUe;J X- f;F xU rhh;ghFkh vd Muha;f. cd; tpilf;Nfw;w tpsf;fk; jUf. (Apr-2014) rhh;G my;y. Vnddpy; 𝑋-y; cs;s 2 vd;w cWg;G π‘Œ-y; cs;s ,uz;L cWg;GfNshL njhlh;G gLj;jg;gl;Ls;sJ. (2, 3), (2, 1)

27.

A, B vd;gd ,U fzq;fs; kw;Wk; U vd;gJ midj;Jf;fzk; vd;f. NkYk; 𝒏 𝑼 = πŸ•πŸŽπŸŽ, 𝒏 (𝑨) = 𝟐𝟎𝟎, 𝒏 (𝑩) = πŸ‘πŸŽπŸŽ kw;Wk; 𝒏 (𝑨 ∩ 𝑩) = 𝟏𝟎𝟎 vdpy;> 𝒏 (𝑨’ ∩ 𝑩 ’) If; fhz;f. 𝑛 (𝐴 βˆͺ 𝐡) = 𝑛(𝐴) + 𝑛(𝐡) – 𝑛(𝐴 ∩ 𝐡) = 200 + 300 – 100 = 400 𝑛(𝐴’ ∩ 𝐡’) = 𝑛(𝐴 βˆͺ 𝐡)’ β‡’ 𝑛(π‘ˆ) – 𝑛(𝐴 βˆͺ 𝐡)= 700 βˆ’ 400 β‡’ 𝑛(𝐴’ ∩ 𝐡’) = 300

28.

𝒏 (𝑨) = πŸπŸ–πŸ“, 𝒏 (𝑩) = πŸπŸ—πŸ“, 𝒏 (𝑼) = πŸ“πŸŽπŸŽ kw;Wk; 𝒏 (𝑨 βˆͺ 𝑩) = πŸ’πŸπŸŽ vdpy;> 𝒏 (𝑨’ βˆͺ 𝑩’) If; fhz;f. 𝑛(𝐴 ∩ 𝐡) = 𝑛(𝐴) + 𝑛(𝐡) – 𝑛(𝐴 βˆͺ 𝐡)= 285 + 195 βˆ’ 410 = 480 βˆ’ 410 = 70 𝑛(π΄β€™π‘ˆπ΅β€™) = 𝑛 𝐴 ∩ 𝐡 ’ β‡’ 𝑛 π‘ˆ – 𝑛 𝐴 ∩ 𝐡 = 500 – 70 β‡’ 𝑛(𝐴’ βˆͺ 𝐡’) = 430

29.

A, B kw;Wk; C VNjDk; %d;W fzq;fs; vd;f. NkYk;> 𝒏 𝑨 = πŸπŸ•, 𝒏 𝑩 = πŸπŸ•, 𝒏 π‘ͺ = πŸπŸ•, 𝒏 𝑨 ∩ 𝑩 = πŸ•, 𝒏(𝑩 ∩ π‘ͺ) = πŸ”, 𝒏(𝑨 ∩ π‘ͺ) = πŸ“ kw;Wk; 𝒏 𝑨 ∩ 𝑩 ∩ π‘ͺ = 𝟐 vdpy;> 𝒏(𝑨 βˆͺ 𝑩 βˆͺ π‘ͺ) – If; fhz;f. 𝑛 (𝐴 βˆͺ 𝐡 βˆͺ 𝐢) = 𝑛(𝐴) + 𝑛(𝐡) + 𝑛(𝐢) – 𝑛(𝐴 ∩ 𝐡) βˆ’ 𝑛(𝐡 ∩ 𝐢) – 𝑛(𝐴 ∩ 𝐢) + 𝑛(𝐴 ∩ 𝐡 ∩ 𝐢)

ZY

ST UD Y

26.

= 𝑛 (𝐴 βˆͺ 𝐡 βˆͺ 𝐢) =

fPNo nfhLf;fg;gl;Ls;s ml;ltiz MdJ> 𝑨 = {πŸ“, πŸ”, πŸ–, 𝟏𝟎} apypUe;J 𝑩 = {πŸπŸ—, πŸπŸ“, πŸ—, 𝟏𝟏} f;F 𝒇(𝒙) = πŸπ’™ βˆ’ 𝟏 vd;wthW mike;j xU rhh;G vdpy;> 𝒂 kw;Wk; 𝒃 Mfpadtw;wpd; kjpg;Gfisf; fhz;f. x 5 6 8 10 f(x) a 11 b 19

DO O

30.

17 + 17 + 17 – 7 – 6 – 5 + 2 = 53 βˆ’ 18 35

𝑓(π‘₯) = 2 π‘₯ βˆ’ 1

31.

𝑓(5) = 2(5) βˆ’ 1 = 10 βˆ’ 1 = 9 𝑓(8) = 2(8) βˆ’ 1 = 16 βˆ’ 1 = 15 / π‘Ž = 9 , 𝑏 = 15 (𝑨 βˆͺ 𝑩)’ f;F ntd;glk; tiuf.

https://doozystudy.blogspot.in/

(Oct-2013)

https://doozystudy.blogspot.in/

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rhh;G 𝒇: (βˆ’πŸ‘, πŸ•) β†’ 𝑹 fPo;f;fz;lthW tiuaWf;fg;gl;Ls;sJ. πŸ’π’™πŸ βˆ’ 𝟏 ; βˆ’πŸ‘ ≀ 𝒙 < 2 π‘₯ = {βˆ’2, βˆ’1,0,1} 𝑓 𝒙 = πŸ‘π’™ βˆ’ 𝟐 ; 𝟐 ≀ 𝒙 ≀ πŸ’ vdpy; πŸπ’™ βˆ’ πŸ‘ ; πŸ’<π‘₯ <7 𝑓 5 = 2 5 βˆ’ 3 = 10 βˆ’ 3 = 7 𝑓 6 = 2 6 βˆ’ 3 = 12 βˆ’ 3 = 9 𝑓 5 + 𝑓 6 = 7 + 9 = 16

33.

(Jun -2014) 𝒇 πŸ“ + 𝒇 πŸ” d; kjpg;igf; fhz;f.

[4 < π‘₯ < 7 vdpy,; 𝑓 π‘₯ = 2π‘₯ βˆ’ 3]

ST UD Y

32.

https://doozystudy.blogspot.in/

𝑨 = 𝒂, 𝒙, π’š, 𝒓, 𝒔 , 𝑩 = {𝟏, πŸ‘, πŸ“, πŸ•, βˆ’πŸπŸŽ} vd nfhLf;fg;gl;Ls;s fzq;fSf;F> fzq;fspd; Nrh;g;G nrayhdJ> ghpkhw;W gz;G cilaJ vd;gij rhpghh;f;fTk;. (Apr-2016) 𝐴 βˆͺ 𝐡 = 𝐡 βˆͺ 𝐴 vd;gij rhpghh;g;Nghk;; 𝐴 βˆͺ 𝐡 = π‘Ž, π‘₯, 𝑦, π‘Ÿ, 𝑠 βˆͺ 1, 3, 5, 7, βˆ’10 = {π‘Ž, π‘₯, 𝑦, π‘Ÿ, 𝑠, 1,3,5,7, βˆ’10}………… 1 𝐡 βˆͺ 𝐴 = 1, 3, 5, 7, βˆ’10 βˆͺ π‘Ž, π‘₯, 𝑦, π‘Ÿ, 𝑠 = {π‘Ž, π‘₯, 𝑦, π‘Ÿ, 𝑠, 1,3,5,7, βˆ’10}…………. 2 (1) kw;Wk; (2) ypUe;J 𝐴 βˆͺ 𝐡 = 𝐡 βˆͺ 𝐴 vdNt> fzq;fspd; Nrh;g;G nrayhdJ> ghpkhw;W gz;G cilaJ

2. nka;naz;fspd; njhlh;thpirfSk; njhlh;fSk; 1.

𝟐, πŸ‘ 𝟐, πŸ“ 𝟐, …… vd;w $l;Lj; njhlh; thpirapd; 12 MtJ cWg;igf; fhz;f. (Apr-2016) π‘Ž = 2,

𝑑= 3 2 βˆ’

2 = 2 2,

𝑑𝑛 = π‘Ž + (𝑛 βˆ’ 1)𝑑 𝑑12 = 23 2 2.

2 + 22 2 = 23 2

ZY

𝑑12 = 2 + (12 βˆ’ 1) Γ— 2 2 =

𝑛 = 12

4, 9, 14, ..…… vd;w $l;Lj; njhlh; thpirapd; 17 MtJ cWg;igf; fhz;f. π‘Ž = 4, 𝑑 = 9 – 4 = 5, 𝑛 = 17 𝑑𝑛 = π‘Ž + (𝑛 βˆ’ 1)𝑑

(Apr-2014)

3.

DO O

𝑑17 = 4 + (17 βˆ’ 1) Γ— 5 = 4 + 16 Γ— 5 = 4 + 80 = 84 𝑑17 = 84

13 My; tFgLk;
𝑛 =

91βˆ’13 13

π‘™βˆ’π‘Ž

+1 =

𝑑 78 13

(Apr-2012)

+1

+1 = 6+1 =7

𝑛 = 7

4.

5+11+17+…….. +95 vd;w $l;Lj; njhlhpd; $Ljy; fhz;f. π‘Ž = 5, 𝑑 = 11 βˆ’ 5 = 6, 𝑙 = 95 𝑛 =

π‘™βˆ’π‘Ž 𝑑

(Apr-2013, Jun-2014)

+1

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𝑛 = 𝑆𝑛 = 𝑆16

+1 = +𝑙 =

90 6 16 x 2

+ 1 = 15 + 1 = 16 [5 + 95]

= 8 Γ— 100 = 800

πŸπŸ‘ + πŸπŸ‘ + πŸ‘πŸ‘ + …….. +πŸπŸŽπŸ‘ $Ljy; fhz;f. 13 + 23 + 33 + …….. +𝑛3 =

𝑛(𝑛+1) 2 2 20(20+1) 2 2

13 + 23 + 33 + …….. +203 = 6.

(Oct-2014)

ST UD Y

5.

95βˆ’5 6 𝑛 π‘Ž 2

https://doozystudy.blogspot.in/

=

20x21 2 2

= [210]2 = 44100.

𝟏 + 𝟐 + πŸ‘ +……. +𝒏 = 𝟏𝟐𝟎 vdpy,; πŸπŸ‘ + πŸπŸ‘ + πŸ‘πŸ‘ +……. π’πŸ‘ kjpg;G fhz;f. βˆ‘π‘› = 120 khw;WKiw βˆ‘π‘›3 = βˆ‘π‘›

2

= 1202 = 14400

𝑛 (𝑛+1)

1 + 2 + 3 + ……… +𝑛 =

2

13 + 23 + 33 +……….. + 𝑛3 =

=

7.

πŸπŸ‘ + πŸπŸ‘ + πŸ‘πŸ‘ +…… +π’πŸ‘ = πŸ‘πŸ”πŸπŸŽπŸŽ vdpy; , 𝟏 + 𝟐 + πŸ‘ +…….+𝒏 kjpg;G fhz;f. βˆ‘π‘›3 = (βˆ‘π‘›)2 = 36100 = 1902 khw;WKiw 13 + 23 + 33 + ……. +𝑛3 =

βˆ‘π‘› = 190 1 + 2 + 3 + ……. +𝑛 = 190

βˆ‘π‘ƒ3 = (βˆ‘π‘ƒ)2 = 1712 = 29241

𝑃(𝑃+1) 2

13 + 23 + 33 + …… +𝑃3 =

πŸπŸ‘ + πŸπŸ‘ + πŸ‘πŸ‘ + … + π’ŒπŸ‘ = πŸ–πŸπŸ–πŸ, vdpy; , 1+𝟐 + πŸ‘ + … . . +π’Œ βˆ‘π‘˜ 3 = (βˆ‘π‘˜)2 = 8281 = 912 khw;WKiw βˆ‘π‘˜ = 91

1 + 2 + 3 + ……… + π‘˜ = 91

10.

1 + 2 + 3 + ….. + 𝑃 =

DO O

9.

𝑛 𝑛+1 2 2 1202 =

14400

(Jun-2013)

𝑛(𝑛 +1) 2 = 36100 2 𝑛 (𝑛+1) = 190 2

= 1902

𝟏 + 𝟐 + πŸ‘ + ……. + 𝑷 = πŸπŸ•πŸ, vdpy,; πŸπŸ‘ + πŸπŸ‘ + πŸ‘πŸ‘ +…….+π‘·πŸ‘ kjpg;G fhz;f. βˆ‘π‘ƒ = 171 khw;WKiw

ZY

8.

1 + 2 + 3 + ….. +𝑛 =

= 120

= 171 𝑃(𝑃+1) 2 2

kjpg;G fhz;f. π‘˜(π‘˜+1) 2 = 2 π‘˜(π‘˜+1) = 91 2

13 + 23 + 33 + ……. + π‘˜ 3 = 1 + 2 + 3 +….. + π‘˜ =

= 1712 = 29241

8281 = 912

xU $l;Lj; njhlh; thpirapy;> Ie;jhk; cWg;gpd; 5 klq;Fk;> Vohk; cWg;gpd; 7 klq;Fk; rkkhf ,Ug;gpd; 12 tJ cWg;G 0 vd epUgpf;f. (Oct-2012) 𝑑𝑛 = π‘Ž + (𝑛 βˆ’ 1) 𝑑 7𝑑7 = 5𝑑5 7(π‘Ž + 6𝑑) = 5(π‘Ž + 4𝑑) 7π‘Ž + 42𝑑 = 5π‘Ž + 20𝑑

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7π‘Ž βˆ’ 5π‘Ž + 42𝑑 – 20𝑑 = 0 2π‘Ž + 22𝑑 = 0 π‘Ž + 11𝑑 = 0 𝑑12 = 0 xU $l;Lj; njhlhpy; Sn = πŸπŸπŸ•πŸ“ kw;Wk; Kjy; cWg;G 𝒂 = πŸ‘, nghJ tpj;jpahrk; 𝒅 = πŸ’ vdpy; , 𝒏-d; kjpg;gpidf; fhz;f. (Jun-2012) 𝑆𝑛 = 𝑆𝑛 =

𝑛 2

𝑛 2

[2π‘Ž + 𝑛 βˆ’ 1 𝑑]

2 3 + π‘›βˆ’1 4

= 1275

𝑛 6 + 4𝑛 βˆ’ 4 = 1275 Γ— 2 6𝑛 + 4𝑛2 – 4𝑛 = 2550 4𝑛2 + 2𝑛 – 2550 = 0 (2My; tFf;f) 2𝑛2 + 𝑛 βˆ’ 1275 = 0 (2𝑛 + 51) (𝑛 βˆ’ 25) = 0 𝑛 = 25

2𝑛2 + 𝑛 βˆ’ 1275 = 0

xU $l;Lj; njhlh;thpirapd; Kjy; cWg;G 6 kw;Wk; nghJtpj;jpahrk; mj;njhlh;thpiriaAk; mjd; nghJ cWg;igAk; fhz;f. $l;Lj; njhlHthpirapd; nghJ tbtk; π‘Ž, π‘Ž + 𝑑, π‘Ž + 2𝑑, π‘Ž + 3𝑑, ………. ,q;F π‘Ž = 6, 𝑑 = 5 vdNt $l;Lj;njhlh;thpir = 6, (6 + 5), 6 + 2(5), 6 + 3(5), ……. = 6, 11, 16, 21, ………. $l;Lj;njhlh;thpirapd; nghJtbtk; 𝑑𝑛 = π‘Ž + (𝑛 βˆ’ 1)𝑑

DO O

13.

ZY

%d;W vz;fspd; tpfpjk; 2:5:7 vd;f. Kjyhk; vz;> ,uz;lhk; vz;zpypUe;J 7-If; fopj;Jg; ngwg;gLk; vz; kw;Wk; %d;whk; vz; Mfpad xU $l;Lj; njhlh;thpiria Vw;gLj;jpdhy;> mt;ntz;fisf; fhz;f. nfhLf;fg;gl;l %d;W vz;fspd; tpfpjk; 2:5:7 me;j vz;fs; KiwNa 2π‘₯, 5π‘₯ kw;Wk; 7π‘₯ vd;f. (π‘₯ β‰  0) fzf;fpd;gb 2π‘₯, 5π‘₯ βˆ’ 7, 7π‘₯ vd;gd xU $l;Lj;njhlh;thpir MFk;. vdNt nghJ tpj;jpahrk; 𝑑 = (5π‘₯ βˆ’ 7) – 2π‘₯ = 7π‘₯ – (5π‘₯ βˆ’ 7) Fwpg;G:[𝑑 = 𝑑2 βˆ’ 𝑑1 ] 3π‘₯ βˆ’ 7 = 2π‘₯ + 7 π‘₯ = 7 + 7 = 14 vdNt me;j vz;fs; 2π‘₯, 5π‘₯, 7π‘₯ = ( 2 Γ— 14), 5 Γ— 14 , 7 Γ— 14 = 28, 70, 98

12.

14.

ST UD Y

11.

5

vdpy;>

= 6 + (𝑛 βˆ’ 1)(5) = 6 + 5𝑛 βˆ’ 5 = 5𝑛 + 1 𝑑𝑛 = 5𝑛 + 1

gpd;tUk; $l;Lj; njhlh;thpirapd; Kjy; cWg;G kw;Wk; nghJ tpj;jpahrj;ijf; fhz;f. 𝟏 πŸ“ πŸ• πŸ‘ πŸπŸ• , , , ,………, . 𝟐 πŸ” πŸ” 𝟐 πŸ”

Kjy; cWg;G

nghJ tpj;jpahrk;

https://doozystudy.blogspot.in/

π‘Ž

(Apr-2015)

1 = 2 5

1

5βˆ’3

6

2

6

𝑑= βˆ’ =

2

1

6

3

= =

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

xU fbfhuk; xU kzpf;F xU Kiw> 2 kzpf;F ,U Kiw> 3 kzpf;F %d;W Kiw vd;wthW> njhlh;e;J rhpahf xt;nthU kzpf;Fk; xyp vOg;Gk; vdpy;> xU ehspy; mf;fbfhuk; vj;jid Kiw xyp vOg;Gk;? xU fbfhuk; xt;nthU kzpf;Fk; vOg;Gk; xyp xU $l;Lj; njhlh; mf;$l;Lj;njhlh; 1 + 2 + 3 + ……. +12 𝑛 2

𝑆𝑛 = [π‘Ž + 𝑙]

vdNt

𝑆12 =

12 2

[1 + 12] = 6 Γ— 13 = 78

ST UD Y

15.

https://doozystudy.blogspot.in/

xU ehspy; fbfhuk; vOg;Gk; xyp mstpd; vz;zpf;if = 2 Γ— 78 = 156

xUth;> Kjy; khjk; &.640. 2 Mk; khjk; &.720. 3 Mk; khjk; &.800-I Nrkpf;fpwhh;. mth; jd;Dila Nrkpg;ig ,Nj njhlh;thpirapy; njhlh;e;jhy;> 25 MtJ khjk; mth; Nrkpf;Fk; njhifiaf; fhz;f. Nrkpf;fg;gLk; njhif xU $l;Lj; njhlh; thpir MFk;. 640, 720, 800, ………. 𝑑𝑛 = π‘Ž + (𝑛 βˆ’ 1)𝑑 ,f;$l;Lj;njhlh; thpirapd; Kjy; cWg;G π‘Ž = 640, nghJ tpj;jpahrk; 𝑑 = 720 βˆ’ 640 = 80 25 MtJ khjk; Nrkpf;fg;gLk; njhif 𝑑25 = 640 + (25 βˆ’ 1) Γ— 80 = 640 + ( 24 Γ— 80 ) = 640 + 1920 = 2560 25 MtJ khjk; Nrkpf;fg;gLk; njhif & 2560

17.

1, 2, 4, 8, ……… vd;w ngUf;Fj;njhlh;thpirapy; 1024 vd;gJ vj;jidahtJ cWg;ghFk;? 1, 2, 4, 8, ……… vd;w ngUf;Fj;njhlhpy; 𝑑 2 π‘Ž =1 π‘Ÿ= 2= =2

ZY

16.

𝑑1

1

18.

19.

DO O

𝑑𝑛 = 1024 𝑛 βˆ’1 π‘Žπ‘Ÿ = 1024 1 Γ— 2𝑛 βˆ’1 = 210 2𝑛 βˆ’1 = 210 𝑛 βˆ’ 1 = 10 𝑛 = 10 + 1 = 11 / 1, 2, 4, 8, ..………. vd;w ngUf;Fj; njhlh; thpirapy; 1024 vd;gJ 11 cWg;ghFk;. 125, 120, 115, 110, …….. vd;w $l;Lj;njhlh; thpirapd; nghJ tpj;jpahrj;ijAk; 15 MtJ cWg;igAk; fhz;f. 125, 120, 115, 110, …… vd;w $l;Lj;njhlh; thpirapd; Kjy; cWg;G π‘Ž = 125 nghJ tpj;jpahrk; 𝑑 = 120 – 125 = βˆ’ 5 𝑑𝑛 = π‘Ž + (𝑛 βˆ’ 1) 𝑑 15 MtJ cWg;G 𝑑15 = 125 + (15 βˆ’ 1) (βˆ’5) = 125 + 14 (βˆ’5) = 125 – 70 = 55 𝟏𝟐 βˆ’ 𝟐𝟐 + πŸ‘πŸ βˆ’ πŸ’πŸ +… vd;w njhlhpd; Kjy; 10 cWg;Gfspd; $l;lw;gyidf; fhz;f. (Jun-15)

12 βˆ’ 22 + 32 βˆ’ 42 +… Kjy; 10 cWg;Gfs; = (1 βˆ’ 4) + (9 βˆ’ 16) + … 5 cWg;Gfs;

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= (βˆ’3) + (βˆ’7) + … 5 cWg;Gfs; = (βˆ’3) + (βˆ’7) + … 5 cWg;Gfs; π‘Ž = βˆ’3, 𝑑 = (βˆ’7) – (βˆ’3) = βˆ’7 + 3 = βˆ’4 𝑆𝑛 =

=

5 [2 βˆ’3 2 5 βˆ’6 2

+ 𝑛 βˆ’ 1 𝑑]

+ 5 βˆ’ 1 βˆ’4 ] + βˆ’16

=

5 2

ST UD Y

𝑆5 =

𝑛 [2π‘Ž 2

βˆ’22 = 5 Γ— βˆ’11 = βˆ’55

πŸπŸ” βˆ’ πŸ’πŸ– + πŸπŸ’πŸ’ βˆ’ πŸ’πŸ‘πŸ … vd;w ngUf;Fj;njhlhpy; cs;s Kjy; 25 cWg;Gfspd; $Ljiyf; fhz;f.

20.

βˆ’48 = βˆ’3 β‰  1 16 𝑛 π‘Ž(1βˆ’π‘Ÿ ) ,π‘Ÿ β‰  1 1βˆ’ π‘Ÿ 16[1βˆ’(βˆ’3)25 ] 16[1+325 ] = 1βˆ’(βˆ’3) 4 25 4 (1 + 3 )

,q;F π‘Ž = 16, π‘Ÿ = vdNt>

𝑆𝑛 = 𝑆25 = =

𝒏 (𝒏 + πŸ‘), 𝒏 ∈ β„• kw;Wk; 𝒏 ,ul;ilg;gil vz; vDk; NghJ 21.

an = πŸπ’ ,𝒏 π’πŸ + 𝟏

∈ β„• kw;Wk; 𝒏 xw;iwg;gil vz; vDk; NghJ vd tiuaWf;fg;gl;l njhlh;thpirapd; 18-tJ kw;Wk; 25tJ cWg;Gfisf; fhz;f. 𝑛 ,ul;ilg;gil vz; vDk; NghJ vdNt 18-tJ cWg;G

π‘Žπ‘› = 𝑛 (𝑛 + 3) π‘Ž18 = 18 (18 + 3) = 18 Γ— 21 = 378

𝑛 xw;iwg;gil vz; vDk;NghJ

ZY

π‘Žπ‘› =

vdNt 25-tJ cWg;G

23.

=

50 625 + 1

=

50 626

=

25 313

njhlh; thpirapYs;s rhh;Gf;F xU vLj;Jf;fhl;L jUf. (Oct-2013) rhh;G 𝑓: 𝑅 β†’ 𝑅 MdJ 𝑓 π‘₯ = 2π‘₯ + 1, βˆ€π‘₯ ∈ 𝑅 vd mikAkhdhy;> mJ xU njhlh;thpirahfhJ. Vnddpy;> ,r;rhh;gpd; tPr;rfj;jpd; cWg;Gfisj; njhlh; thpirapy; mikf;f ,ayhJ. NkYk;> ,r;rhh;gpd; kjpg;gfk; MdJ ,ay; vz;fspd; fzk; N MfNth my;yJ ,ay; vz;fspd; cl;fzk; {1,2,….n} MfNth mikag; ngwtpy;iy.

DO O

22.

π‘Ž25 =

2𝑛 𝑛 2 +1 2 Γ— 25 25 2 + 1

𝒏 tJ cWg;G 𝒂𝒏 =

𝒏(π’βˆ’πŸ) πŸ‘

vdf; nfhLf;fg;gl;l njhlh;thpirapd; Kjy; %d;W cWg;Gfisf;

fhz;f.

π‘Žπ‘› =

3 1(1βˆ’2) βˆ’1 π‘Ž1 = = , 3 3 𝑛 π‘›βˆ’2 π‘Žπ‘› = nfhLf;fg;gl;l 3

24.

(Oct-2015)

𝑛(π‘›βˆ’2)

π‘Ž2 =

2(2βˆ’2) 3

=

0 3

= 0,

π‘Ž3 =

njhlh;thpirapd; Kjy; %d;W cWg;Gfs;

3(3βˆ’2) 3

=

3 3

=1

βˆ’1 , 0, 1. 3

50 kw;Wk; 200 ,tw;wp;w;fpilNaahd 10 My; tFgLk; midj;J KO vz;fspd; $Ljiyf; fhz;f. 50 kw;Wk; 200 ,tw;wp;fpilNaahd 10 My; tFgLk; midj;J KO vz;fspd; $Ljy; 60 + 70 + ……. + 190

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π‘Ž = 60, 𝑑 = 10, 𝑙 = 190 𝑛= = =

π‘™βˆ’π‘Ž + 1 𝑑 190βˆ’60 + 10 130 +1 10

1

𝑛 = 14 𝑆𝑛 = =

ST UD Y

= 13 + 1 𝑛 [π‘Ž + 𝑙] 2 14 [60 + 190] 2

= 7 Γ— 250 𝑆14 = 1750

50 kw;Wk; 200 ,tw;wp;w;fpilNaahd 10 My; tFgLk; midj;J KO vz;fspd; $Ljy; 60 + 70 + ……. +190 = 1750

3. ,aw;fzpjk; 1.

jPh;f;f: πŸ‘π’™ + πŸ“π’š = πŸπŸ“, πŸ•π’™ + πŸ”π’š = πŸ‘πŸŽ π‘₯ 𝑦 5 -25 3 6 -30 7

= 5

jPh;T {0,5}

ePf;fy; Kiwapy; jPh;f;f. πŸ‘π’™ + π’š = πŸ–, πŸ“π’™ + π’š = 𝟏𝟎 3π‘₯ + 𝑦 = 8 ……….. 1 5π‘₯ + 𝑦 = 10 …….... 2

DO O

2.

5 6

ZY

π‘₯ 𝑦 1 = = βˆ’150+150 βˆ’175+90 18βˆ’35 π‘₯ 𝑦 1 = = 0 βˆ’85 βˆ’17 0 βˆ’85 π‘₯ = = 0 kw;Wk; 𝑦 = 17 βˆ’17

1

(Jun-2012)

βˆ’

βˆ’

(2) – (1) βˆ’2π‘₯

(βˆ’)

=βˆ’2

π‘₯ = 1

π‘₯ = 1 vd (1)-y; gpujpapl> 3(1) + 𝑦 = 8 3 + 𝑦 = 8 𝑦 = 8 βˆ’ 3 = 5 𝑦 = 5

3.

𝒙 =

𝟏 πŸ’

jPh;T {1, 5}

kw;Wk; 𝒙 = βˆ’πŸ vd;w G+r;rpaq;fisf; nfhz;l ,Ugb gy;YWg;Gf;Nfhitiaf; fhz;f.

,Ugb gy;YWg;Gf;Nfhit =

https://doozystudy.blogspot.in/

π‘₯2

(Jun-2013) – (𝛼 + 𝛽) π‘₯ + 𝛼𝛽

https://doozystudy.blogspot.in/

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,q;F 𝛼 =

1 4

https://doozystudy.blogspot.in/

, 𝛽 = βˆ’1

vdNt> ,Ugb gy;YWg;Gf;Nfhit = π‘₯ 2 βˆ’ = π‘₯2 – ,Ugb gy;YWg;Gf;Nfhit

3 4

π‘₯ βˆ’

π‘₯ βˆ’

1 4

1 4

Γ— βˆ’1)

1 4

πŸ‘, 𝟐 Mfpatw;iw KiwNa G+r;rpaq;fspd; $LjyhfTk; kw;Wk; mtw;wpd; nfhz;l gy;YWg;Gf; Nfhitiaf; fhz;f. ,Ugb gy;YWg;Gf; Nfhitapd; G+r;rpaq;fspd; $Ljy; = 𝛼 + 𝛽 = 3 mtw;wpd; ngUf;fw;gyd; = 𝛼𝛽 = 2 vdNt> gy;YWg;Gf;Nfhit = 𝑝 π‘₯ = π‘₯ 2 – 𝛼 + 𝛽 π‘₯ + 𝛼𝛽 gy;YWg;Gf;Nfhit= π‘₯ 2 βˆ’

5.

= π‘₯2 +

βˆ’1 π‘₯+ (

ngUf;fw;gydhfTk;

ST UD Y

4.

1 4 1βˆ’4 4

3π‘₯ + 2

xU ,Ugb gy;YWg;Gf;Nfhitapd; G+r;rpaq;fspd; $Ljy; -4 kw;Wk; mjd; ngUf;fw;gyd; 3 vdpy;> mf;Nfhitiaf; fhz;f. ,Ugb gy;YWg;Gf; Nfhitapd; G+r;rpaq;fspd; $Ljy; = 𝛼 + 𝛽 = βˆ’4 mtw;wpd; ngUf;fw;gyd; = 𝛼𝛽 = 3 vdNt> gy;YWg;Gf;Nfhit = 𝑝 (π‘₯) = π‘₯ 2 – (𝛼 + 𝛽) π‘₯ + 𝛼𝛽 = π‘₯ 2 βˆ’ (βˆ’4) π‘₯ + 3 gy;YWg;Gf;Nfhit

= π‘₯2 + 4 π‘₯ + 3

kP.ngh.t. fhz;f. πŸπŸ“π’ƒπ’„πŸ’ π’…πŸ‘ , πŸ‘πŸ“π’ƒπŸ π’„πŸ‘ , πŸ’πŸ“π’„πŸ‘ 𝒅. 25𝑏𝑐 4 𝑑 3 = 5 Γ— 5 Γ— 𝑏𝑐 4 𝑑 3 35𝑏 2 𝑐 3 = 7 Γ— 5 Γ— 𝑏 2 𝑐 3 45𝑐 3 𝑑 = 9 Γ— 5 Γ— 𝑐 3 𝑑 kP.ngh.t = 5𝑐 3

7.

π’ŽπŸ βˆ’ πŸ‘π’Ž βˆ’ πŸπŸ–, π’ŽπŸ + πŸ“π’Ž + πŸ” Mfpa Nfhitfspd; kP.ngh.t. fhz;f. (Apr-2014) π‘š2 βˆ’ 3π‘š βˆ’ 18 = (π‘š βˆ’ 6) (π‘š + 3) π‘š2 + 5π‘š + 6 = (π‘š + 2) (π‘š + 3) kP.ngh.t = (π‘š + 3)

DO O

8.

ZY

6.

kP.ngh.k. fhz;f. πŸ‘ 𝒂 βˆ’ 𝟏 , 𝟐 𝒂 βˆ’ 𝟏 𝟐 , (π’‚πŸ – 𝟏). (Jun-2015) 3 π‘Ž βˆ’ 1 = 3(π‘Ž βˆ’ 1) 2(π‘Ž βˆ’ 1)2 = 2(π‘Ž βˆ’ 1) (π‘Ž βˆ’ 1) π‘Ž2 βˆ’ 1 = (π‘Ž βˆ’ 1) (π‘Ž + 1) kP.ngh.k. = 3 Γ— 2 (π‘Ž βˆ’ 1) (π‘Ž βˆ’ 1) (π‘Ž + 1) = 6(π‘Ž βˆ’ 1)2 (π‘Ž + 1) kP.ngh.k. = 6(π‘Ž βˆ’ 1)2 (π‘Ž + 1)

9.

kP.ngh.k. fhz;f. π’™πŸ π’š + π’™π’šπŸ , π’™πŸ + π’™π’š π‘₯ 2 𝑦 + π‘₯𝑦 2 = π‘₯𝑦 (π‘₯ + 𝑦) 2 π‘₯ + π‘₯𝑦 = π‘₯ (π‘₯ + 𝑦) kP.ngh.k. = (π‘₯ + 𝑦)

https://doozystudy.blogspot.in/

(Oct-2013)

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π’™πŸ βˆ’πŸ’ π’‚πŸ‘ βˆ’π’‚ 𝐱 πŸ‘ 𝟐 𝟐 𝒂 βˆ’πŸ 𝒙 +πŸπ’™ π‘₯ 2 βˆ’4 π‘Ž 3 βˆ’π‘Ž π‘₯ 2 βˆ’22 Γ— = π‘Ž 2 βˆ’1 π‘₯ 3 +2π‘₯ 2 π‘Ž 2 βˆ’1

RUf;Ff.

π‘₯+2 (π‘₯βˆ’2) π‘Ž 2 βˆ’1

= π‘₯ 2 βˆ’4 π‘Ž 2 βˆ’1

Γ—

πŸ“π’™+𝟐𝟎 πŸ•π’™+πŸπŸ– 5π‘₯+20 5(π‘₯+4) = 7π‘₯+28 7 π‘₯+4

π‘Ž 3 βˆ’π‘Ž π‘₯ 3 +2π‘₯ 2

π‘Ž(π‘Ž 2 βˆ’1) π‘₯ 2 (π‘₯+2)

Γ—

=

π‘Ž(π‘₯βˆ’2) π‘₯2

=

RUf;Ff.

RUf;Ff.

12.

π‘₯ 3 βˆ’27 π‘₯ 2 βˆ’9

=

β‡’

13.

π‘₯ 2 βˆ’4

=

Γ—

=

Γ·

π‘₯ π‘₯+1 π‘₯2 π‘₯ 2 βˆ’1

π‘₯ 2 βˆ’22

π‘₯βˆ’9 π‘₯+9 π‘₯βˆ’2 π‘₯+2

π‘₯ 2 +6π‘₯+8 π‘₯ 2 βˆ’5π‘₯βˆ’36

Γ·

π‘₯2

π‘₯ π‘₯+1

π’™πŸ‘ βˆ’πŸ π’™πŸ +𝟐

Γ·

π‘₯2 π‘₯ 2 βˆ’1

π‘₯+2 (π‘₯+4)

Γ—

=

π‘₯βˆ’4 (π‘₯+9)

Γ—

π‘₯ 2 βˆ’1 π‘₯ π‘₯2 = Γ· π‘₯+1 π‘₯+1 (π‘₯βˆ’1)

=

π‘₯+2 (π‘₯+4) π‘₯+4 (π‘₯βˆ’9)

π‘₯+9 π‘₯βˆ’2

DO O

π‘₯ π‘₯+1

Γ—

5 7

(π‘₯ 2 +3π‘₯+9) (π‘₯+3)

π‘₯ 2 βˆ’5π‘₯βˆ’36

π‘₯ 2 βˆ’81 π‘₯ 2 βˆ’4

=

π‘₯βˆ’3 (π‘₯ 2 +3π‘₯+9) π‘₯+3 π‘₯βˆ’3

=

RUf;Ff.

5π‘₯+20 7π‘₯+28

β‡’

π’™πŸ βˆ’πŸ–πŸ π’™πŸ +πŸ”π’™+πŸ– 𝐱 𝟐 π’™πŸ βˆ’πŸ’ 𝒙 βˆ’πŸ“π’™βˆ’πŸ‘πŸ” π‘₯ 2 +6π‘₯+8 π‘₯ 2 βˆ’92

RUf;Ff. π‘₯ 2 βˆ’81

(Apr-2015)

π’™πŸ‘ βˆ’πŸπŸ• π’™πŸ βˆ’πŸ— π‘₯ 3 βˆ’33 = π‘₯ 2 βˆ’32

π‘₯ 3 βˆ’27 π‘₯ 2 βˆ’9

π‘Ž(π‘₯βˆ’2) π‘₯2

ZY

11.

15.

π‘Ž(π‘Ž 2 βˆ’1) π‘₯ 2 (π‘₯+2)

Γ—

ST UD Y

10.

14.

https://doozystudy.blogspot.in/

=

π‘₯ π‘₯+1

Γ—

π‘₯+1 (π‘₯βˆ’1) π‘₯2

=

π‘₯βˆ’1 π‘₯

cld; ve;j tpfpjKWf; Nfhitiaf; $l;bdhy;

Njitahd tpfpjKWf; Nfhit 𝑝 π‘₯

π‘₯βˆ’1 π‘₯

πŸπ’™πŸ‘ βˆ’π’™πŸ +πŸ‘ π’™πŸ +𝟐

fpilf;Fk;?

𝑝(π‘₯) vd;f.

2π‘₯ 3 βˆ’π‘₯ 2 +3 π‘₯ 3 βˆ’1 = βˆ’ 2 π‘₯ 2 +2 π‘₯ +2 2π‘₯ 2 βˆ’π‘₯ 2 +3βˆ’π‘₯ 3 +1 = π‘₯ 2 +2

=

π‘₯ 3 βˆ’π‘₯ 2 +4 π‘₯ 2 +2

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

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https://doozystudy.blogspot.in/

njhFKiw tFj;jiyg; gad;gLj;jp>
1 3

[3π‘₯ 2 + 6π‘₯ βˆ’ 6] = π‘₯ 2 + 2π‘₯ βˆ’ 2 , kPjp = 2

th;f;f%yk; fhz;f. (𝒙 + 𝟏𝟏)𝟐 – πŸ’πŸ’π’™

17.

(π‘₯ + 11)2 βˆ’ 44π‘₯ =

π‘₯ 2 + 22π‘₯ + 121 βˆ’ 44π‘₯ = π‘₯ 2 βˆ’ 22π‘₯ + 121 =

th;f;f%yk; fhz;f. π’™πŸ’ +

18.

1

π‘₯4 +

π‘₯4

+ 2 = =

𝟏 π’™πŸ’

+ 𝟐.

π‘₯2 + π‘₯2 +

1

2

π‘₯2

1 π‘₯2

th;f;f%yk; fhz;f. πŸπŸπŸπ’™πŸ– π’šπŸ” Γ· πŸ–πŸ π’™πŸ’ π’šπŸ–

19.

121π‘₯ 8 𝑦 6 Γ· 81 π‘₯ 4 𝑦 8 = jPh;f;f: πŸ‘π’™ βˆ’ jPh;T:

20.

3π‘₯ βˆ’

8 π‘₯

πŸ– 𝒙

=2

(Oct-2014)

121π‘₯ 8 𝑦 6 81π‘₯ 4 𝑦 8

(Oct-2013)

=𝟐 ⟹

ST UD Y

16.

3π‘₯ 2 βˆ’8 = π‘₯ 2 3π‘₯ βˆ’ 8

2

112 π‘₯ 4 92 𝑦 2

=

=

11π‘₯ 2 9𝑦

=

11 9

(π‘₯ βˆ’ 11)2 = (π‘₯ βˆ’ 11

π‘₯2 𝑦

ZY

⟹ = 2π‘₯ 2 ⟹ 3π‘₯ βˆ’ 2π‘₯ βˆ’ 8 = 0 ⟹ (π‘₯ βˆ’ 2) (3π‘₯ + 4) = 0 ⟹ π‘₯ = 2 my;yJ π‘₯ = βˆ’

4 3

jPh;T =

4 3

βˆ’ ,2

22.

DO O

,U njhlh;e;j kpif ,ul;ilg; gil vz;fspd; ngUf;fypd; kjpg;G 24 vdpy; mt;ntz;fisf; fhz;f. (Oct-2012) ,U njhlh;e;j kpif ,ul;ilg; gil vz;fs; π‘₯ kw;Wk; π‘₯ + 2 vd;f. fzf;fpd;gb π‘₯ (π‘₯ + 2) = 24 π‘₯ 2 + 2π‘₯ βˆ’ 24 = 0 (π‘₯ + 6) (π‘₯ βˆ’ 4) = 0 π‘₯ = βˆ’ 6 my;yJ 4 π‘₯ kw;Wk; π‘₯ + 2 vd;gJ kpif vz;fs;. vdNt mt;tpU vz;fs; 4 kw;Wk; 6 MFk;.

21.

𝟏 πŸπŸ” = 𝒙 πŸ“ 1 26 π‘₯ 2 +1 = ⟹ π‘₯ 5 π‘₯ ⟹ 5π‘₯ 2

jPh;f;f: 𝒙 + π‘₯ +

=

(Apr-2013, Jun-2013)

26 5

+ 5 = 26π‘₯ ⟹ 5π‘₯ – 26π‘₯ + 5 = 0 2

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⟹ (π‘₯ βˆ’ 5) (5π‘₯ βˆ’ 1) = 0 ⟹ π‘₯ = 5 my;yJ π‘₯ = jPh;T = 5,

1 5

1 5

π’™πŸ βˆ’ πŸπŸπ’™ βˆ’ 𝟏𝟎 = 𝟎 vd;w rkd;ghl;bd; %yq;fspd; jd;ikia Muha;f. π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 tbtk; π‘Ž = 1, 𝑏 = βˆ’11, 𝑐 = βˆ’10 𝑏 2 βˆ’ 4π‘Žπ‘ = (βˆ’11)2 – 4 Γ— 1 (βˆ’10) = 121 + 40 = 161 > 0 / %yq;fs; nka;;> rkky;y.

24.

πŸπ’™πŸ + πŸ“π’™ + πŸ“ = 𝟎 vd;w rkd;ghl;bd; %yq;fspd; jd;ikia Muha;f. π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 tbtk; π‘Ž = 2, 𝑏 = βˆ’5, 𝑐 = 5 𝑏 2 βˆ’ 4π‘Žπ‘ = (βˆ’5)2 – 4 Γ— 2 Γ— 5 = 25 βˆ’ 40 = βˆ’15 < 0 / %yq;fs; fw;gid π’™πŸ βˆ’ πŸ–π’™ + 𝟏𝟐 = 𝟎 vd;w rkd;ghl;bd; %yq;fspd; jd;ikia Muha;f. π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 tbtk; π‘Ž = 1, 𝑏 = βˆ’8, 𝑐 = 12 2 2 𝑏 βˆ’ 4π‘Žπ‘ = (βˆ’8) – 4 Γ— 1 Γ— 12 = 64 βˆ’ 48 = 16 > 0 / %yq;fs; nka;> rkky;y.

25.

ST UD Y

23.

πŸπ’™πŸ βˆ’ πŸ‘π’™ + πŸ’ = 𝟎 vd;w rkd;ghl;bd; %yq;fspd; jd;ikia Muha;f. π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 tbtk; π‘Ž = 2, 𝑏 = βˆ’3 , 𝑐 = 4 𝑏 2 βˆ’ 4π‘Žπ‘ = (βˆ’3)2 – 4 Γ— 2 Γ— 4 = 9 βˆ’ 32 = βˆ’23 < 0 / %yq;fs; fw;gid

27.

πŸ’π’™πŸ βˆ’ πŸπŸ–π’™ + πŸ’πŸ— = 𝟎 vd;w rkd;ghl;bd; %yq;fspd; jd;ikia Muha;f. π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 tbtk; π‘Ž = 4, 𝑏 = βˆ’28, 𝑐 = 49 𝑏 2 βˆ’ 4π‘Žπ‘ = (βˆ’28)2 – 4 Γ— 4 Γ— 49 = 784 βˆ’ 784 = 0 / %yq;fs; nka;;> rkk;

DO O

28.

ZY

26.

(𝒙 βˆ’ πŸπ’‚) (𝒙 βˆ’ πŸπ’ƒ) = πŸ’π’‚π’ƒ vd;w ,Ugbr; rkd;ghl;bd; %yq;fspd; jd;ikiaf; fhz;f.

(Jun-14) 2

2

(π‘₯ βˆ’ 2π‘Ž) (π‘₯ βˆ’ 2𝑏) = 4π‘Žπ‘ ⟹ π‘₯ – π‘₯ (2π‘Ž + 2𝑏) + 4π‘Žπ‘ = 4π‘Žπ‘ ⟹ π‘₯ βˆ’ 2π‘₯ (π‘Ž + 𝑏) = 0 π‘Žπ‘₯ 2 + 𝑏π‘₯ + 𝑐 = 0 tbtk;

𝑏 2 βˆ’ 4π‘Žπ‘

= [βˆ’2(π‘Ž + 𝑏)]2 – 4 Γ— 1 Γ— 0 = 4(π‘Ž + 𝑏)2 > 0 / %yq;fs; nka;;> rkky;;y.

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π‘Ž = 1, 𝑏 = βˆ’2 π‘Ž + 𝑏 , 𝑐 = 0

https://doozystudy.blogspot.in/

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nfhLf;fg;gl;Ls;s rkd;ghl;bd; %yq;fs; nka;naz;fs; kw;Wk; rkkhdit vdpy; π’Œ d; kjpg;igf; fhz;f. πŸπŸπ’™πŸ + πŸ’π’Œπ’™ + πŸ‘ = 𝟎. (Jun-2015) 12π‘₯ 2 + 4π‘˜π‘₯ + 3 = 0 vd;w rkd;ghl;bd; %yq;fs; nka; kw;Wk; rkk;. vdNt βˆ†= 𝑏 2 βˆ’ 4π‘Žπ‘ = 0 ⟹ (4π‘˜)2 βˆ’ 4 Γ— 12 Γ— 3 = 0 16π‘˜ 2 βˆ’ 144 = 0 16π‘˜ 2 = 144 π‘˜2 = 9 k =Β±3

30.

πŸ• + πŸ‘, πŸ• βˆ’ πŸ‘ vd;gij %yq;fshff; nfhz;l ,Ugbr; rkd;ghl;ilf; fhz;f. (Apr-14, Oct-14) %yq;fspd; $Ljy; = 7 + 3 + 7 βˆ’ 3 = 14 %yq;fspd; ngUf;fw;gyd; = (7 + 3 ) Γ— (7 βˆ’ 3 ) = 72 – ( 3)2 = 49 βˆ’ 3 = 46 rkd;ghL: π‘₯ 2 - (%yq;fspd; $Ljy;) π‘₯ + %yq;fspd; ngUf;fw;gyd; = 0

ST UD Y

29.

π‘₯ 2 – 14π‘₯ + 46 = 0 31.

πŸ‘ + πŸ• , πŸ‘ βˆ’ πŸ• vd;gij %yq;fshff; nfhz;l ,Ugbr; rkd;ghl;ilf; fhz;f. %yq;fspd; $Ljy; =3+ 7+3– 7=6 %yq;fspd; ngUf;fw;gyd; = (3+ 7 )Γ— (3 – 7 ) = 32 – ( 7)2 = 9 – 7 = 2 rkd;ghL: π‘₯ 2 - (%yq;fspd; $Ljy;) π‘₯ + %yq;fspd; ngUf;fw;gyd; = 0 π‘₯ 2 βˆ’ 6π‘₯ + 2 = 0

3, 4 vd;gij %yq;fshff; nfhz;l ,Ugbr;rkd;ghl;ilf; fhz;f. (Jun-2012, Oct-2012) Njitahd rkd;ghL π‘₯ 2 - (%yq;fspd; $Ljy;) π‘₯ + %yq;fspd; ngUf;fw;gyd; = 0 π‘₯ 2 βˆ’ (3 + 4) π‘₯ + (3 Γ— 4) = 0 π‘₯ 2 βˆ’ 7π‘₯ + 12 = 0

33.

π’‚π’™πŸ βˆ’ πŸ“π’™ + 𝒄 = 𝟎 vd;w ,Ugbr; rkd;ghl;bd; %yq;fspd; $Ljy; 10kw;Wk; ngUf;fw;gyd; 10 vdpy; , 𝒂 kw;Wk; 𝒄 Mfpatw;wpd; kjpg;Gfisf; fhz;f. (Apr-2013)

ZY

32.

π‘Žπ‘₯ 2 βˆ’ 5π‘₯ + 𝑐 = 0 vd;w ,Ugbr; rkd;ghl;bd; %yq;fspd; $Ljy; = 5 1 π‘Ž= = 10 2

(βˆ’π‘) π‘Ž

=

DO O

1 2 π‘Žπ‘₯ 2 βˆ’ 5π‘₯ + 𝑐 = 0 vd;w ,Ugbr; rkd;ghl;bd; %yq;fspd; ngUf;fw;gyd; = 𝑐 = 10π‘Ž = 10 Γ—

34.

1 2

5 π‘Ž

= 10

π‘Ž=

= 5

𝐢 π‘Ž

= 10

𝑐 = 5

𝜢, 𝜷 vd;gd πŸ‘π’™πŸ βˆ’ πŸ”π’™ + πŸ’ = 𝟎, vd;Dk; rkd;ghl;bd; %yq;fs; vdpy; 𝜢𝟐 + 𝜷𝟐 d; kjpg;G fhz;f.

(Apr-2012, Apr-2016)

3π‘₯ 2 βˆ’ 6π‘₯ + 4 = 0 vd;Dk; rkd;ghl;bd; %yq;fs; 𝛼, 𝛽 βˆ’π‘ 6 𝛼+𝛽 = = = 2 𝛼 2 + 𝛽 2 = |(𝛼 + 𝛽)2 βˆ’ 2𝛼𝛽| 𝛼𝛽 =

𝑐 π‘Ž

=

π‘Ž 4 3

3

= 4βˆ’

8 3

=

𝛼 2 + 𝛽2 =

https://doozystudy.blogspot.in/

4 3 12βˆ’8 3

= (2)2 βˆ’ 2 Γ—

=

4 3

4 3

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

πŸ‘π’™πŸ βˆ’ πŸ“π’™ + 𝟐 = 𝟎 vd;w rkd;ghl;bd; %yq;fs; 𝜢 , 𝜷 vdpy; 3π‘₯ 2 βˆ’ 5π‘₯ + 2 = 0, vd;w rkd;ghl;by; (βˆ’π‘) βˆ’(βˆ’5) vdNt 𝛼 + 𝛽 = = π‘Ž 3 𝑐 2 𝛼𝛽 = = π‘Ž 3 𝛼 𝛽 𝛼 2 +𝛽 2 (𝛼+𝛽 )2 βˆ’2𝛼𝛽 + = = 𝛽 𝛼 𝛼𝛽 𝛼𝛽

= 36.

jPh;.

37 .

RUf;Ff.

5 2 2 βˆ’2 3 3 2 3

=

=

𝜢 𝜷 + -d; 𝜷 𝜢

π‘Ž = 3, 𝑏 = βˆ’5, 𝑐 = 2

25 9

4

βˆ’ 3 2 3

=

25βˆ’12 9

+

8 2βˆ’π‘₯

=

πŸ– πŸβˆ’π’™

3 2

=

13 6

π‘₯3 π‘₯βˆ’2

βˆ’

23 π‘₯βˆ’2

(Oct-2015)

(Apr-2016)

π‘₯ 3 βˆ’23 π‘₯βˆ’2

(π‘₯βˆ’2)(π‘₯ 2 +2π‘₯+4) π‘₯βˆ’2

ZY

π‘₯3 π‘₯βˆ’2

+

(Apr-15)

5 3

πŸ‘π’™ βˆ’ πŸ“π’š = βˆ’πŸπŸ”, πŸπ’™ + πŸ“π’š = πŸ‘πŸ 3π‘₯ βˆ’ 5𝑦 = βˆ’16 …………………….. 1 2π‘₯ + 5𝑦 = 31 ……………………… 2 (1) + (2) 5π‘₯ = 15 π‘₯=3 π‘₯ = 3 vd (1) y; gpujpapl ⟹ 3π‘₯ βˆ’ 5𝑦 = βˆ’16 3 3 βˆ’ 5𝑦 = βˆ’16 βˆ’5𝑦 = βˆ’16 βˆ’ 9 βˆ’5𝑦 = βˆ’25 𝑦 =5 / jPh;T = {3, 5} π’™πŸ‘ π’™βˆ’πŸ

kjpg;G fhz;f.

ST UD Y

35.

=

=

= π‘₯ 2 + 2π‘₯ + 4

4. mzpfs;

2.

𝟐 πŸ‘ πŸ’ βˆ’πŸ“ vdpy; (𝑨𝑻 )𝑻 = 𝑨 vd;gij rhpghh;. βˆ’πŸ“ πŸ” 1 2 3 𝐴 = 2 4 βˆ’5 3 βˆ’5 6 1 2 3 𝑇 𝐴 = 2 4 βˆ’5 3 βˆ’5 6 1 2 3 (𝐴𝑇 )𝑇 = 2 4 βˆ’5 = 𝐴 vd;gJ rhpghh;f;fg;gl;lJ. 3 βˆ’5 6

DO O

1.

𝟏 𝐀 = 𝟐 πŸ‘

𝑨 =

πŸ– 𝟏

𝐴 =

πŸ“ βˆ’πŸ‘

8 1

𝟐 vdpy; 𝑨𝑻 , (𝑨𝑻 )𝑻 Mfpatw;iwf; fhz;f. πŸ’ 5 2 βˆ’3 4

https://doozystudy.blogspot.in/

(Jun-12, Apr-13, Jun-14, Apr-15)

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

𝐴𝑇 = (𝐴𝑇 )𝑇

6.

7.

𝟏 βˆ’πŸ πŸ‘ 𝟐 𝑨 = πŸ“ βˆ’πŸ’ πŸ• πŸ’ vdpy; (i) mzpapd; thpiriaf; fhz;f. πŸ” 𝟎 πŸ— πŸ– cWg;Gfisf; fhz;f. (iii) cWg;G 7 mike;Js;s epiu> epuiyf; fhz;f. i) mzpapd; thpir 3 Γ— 4 ii) π‘Ž24 = 4, π‘Ž32 = 0 iii) cWg;G 7 mike;Js;s epiy π‘Ž23

(ii) π’‚πŸπŸ’ kw;Wk; πšπŸ‘πŸ Mfpa

𝟏 πŸ’ πŸ– 𝑨 = [π’‚π’Šπ’‹ ] = πŸ” 𝟐 πŸ“ vdpy; (i) mzpapd; thpiriaf; fhz;f. (ii) π’‚πŸπŸ‘ kw;Wk; πšπŸ’πŸ Mfpa πŸ‘ πŸ• 𝟎 πŸ— βˆ’πŸ βˆ’πŸ cWg;Gfisf; fhz;f. (iii) 2 vd;w cWg;G mike;Js;s epiy Mfpatw;iwf; fhz;f. i) mzpapd; thpir 4 Γ— 3 ii) π‘Ž13 = 8, π‘Ž42 = βˆ’2. iii) 2 vd;w cWg;gpd; epiy π‘Ž22 πŸ’ βˆ’πŸ πŸ– 𝟐 , 𝐁 = vdpy;> πŸ”π‘¨ βˆ’ πŸ‘π‘© vd;w mzpiaf; fhz;f. πŸ“ βˆ’πŸ— βˆ’πŸ βˆ’πŸ‘ 4 βˆ’2 8 2 24 βˆ’12 βˆ’24 βˆ’6 6𝐴 – 3𝐡 = 6 βˆ’3 = + 5 βˆ’9 βˆ’1 βˆ’3 30 βˆ’54 3 9 0 βˆ’18 = 33 βˆ’45 A=

𝑨 = 𝐢

8.

𝟐 πŸ’ πŸ“

ST UD Y

5.

πŸ‘ 𝟏 vdpy;> A apd; epiu epuy; khw;W mzpiaf; fhz;f. 𝟎 2 4 5 A apd; epiu epuy; khw;W mzp = 𝐴𝑇 = 3 1 0

𝑨 =

ZY

4.

2 4

πŸ‘ 𝟐 , 𝑩 = πŸ“ 𝟏 = 2𝐴 + 𝐡 3 2 = 2 + 5 1 14 3 = 14 5

πŸ– πŸ’

βˆ’πŸ vdpy;> π‘ͺ = πŸπ‘¨ + 𝑩 vd;w mzpiaf; fhz;f. πŸ‘

DO O

3.

8 1 5 βˆ’3 2 4 8 5 = 1 βˆ’3

https://doozystudy.blogspot.in/

𝑨 =

𝟐 βˆ’πŸ—

8 βˆ’1 6 = 4 3 10

4 8 + 2 4

(Apr-2012)

(Jun-2014)

βˆ’1 3

πŸ‘ 𝟏 πŸ“ βˆ’ vdpy;> A d; $l;ly; Neh;khW mzpiaf; fhz;f. πŸ“ πŸ• βˆ’πŸ

2 𝐴 = βˆ’9

3 2 3 1 5 βˆ’1 βˆ’ = + 5 βˆ’9 5 7 βˆ’1 βˆ’7 βˆ’1 2 A d; $l;ly; Neh;khW mzp = 16 βˆ’6

https://doozystudy.blogspot.in/

(Oct-2012, 2013, Apr- 2015, Jun-2015)

βˆ’5 = 1

1 βˆ’16

βˆ’2 6

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

πŸ– πŸ‘ πŸ“ πŸ— A-d; thpir B-d; thpir A-d; thpir

𝑨 =

10.

𝑨=

11.

12.

𝟐 𝟏 βˆ’πŸ ,𝐁 = vdpy;> 𝑨 + 𝑩 ,Uf;Fkhdhy; mjidf; fhz;f. 𝟏 πŸ‘ 𝟎 = 2 Γ— 3 = 2 Γ— 2 β‰  B-d; thpir. vdNt A+B fhz ,ayhJ.

πŸ‘ βˆ’πŸ πŸ’ πŸ” βˆ’πŸ πŸ‘ 𝑩 = 𝟐 πŸ– 𝟐 𝟎 πŸ’ 𝟐 3 βˆ’1 4 5 6 βˆ’2 3 𝐴+𝐡 = + 2 8 2 1 0 4 2 πŸ“ 𝟏

πŸ• vdpy;> 𝑨 + 𝑩 –If; fhz;f. πŸ‘ 7 8 5 2 10 = 3 3 8 6 5

ST UD Y

9.

https://doozystudy.blogspot.in/

πŸ‘ πŸ“ 𝒛 𝒙 πŸ“ πŸ’ = vdpy;> 𝒙, π’š kw;Wk; 𝒛 Mfpatw;wpd; kjpg;Gfisf; fhz;f. πŸ“ π’š 𝟏 πŸ“ πŸ— 𝟏 π‘₯ = 3, 𝑦 = 9, 𝑧 = 4 30 cWg;Gfs; nfhz;l mzpf;F vt;tif thpirfs; ,Uf;f ,aYk;?

(Jun-2013)

30 cWg;Gfs; nfhz;l mzpapd; thpir 1 Γ— 30, 2 Γ— 15, 3 Γ— 10, 5 Γ— 6, 6 Γ— 5, 10 Γ— 3, 15 Γ— 2, kw;Wk; 30 Γ— 1 vd ,Uf;f ,aYk;. 8 cWg;Gfs; nfhz;l mzpf;F vt;tif thpirfs; ,Uf;f ,aYk;? 8 cWg;Gfs; nfhz;l mzpapd; thpir 1 Γ— 8, 2 Γ— 4, 4 Γ— 2 kw;Wk; 8 Γ— 1 vd ,Uf;f ,aYk;

14.

𝑨 = π’‚π’Šπ’‹ = π’Šπ’‹ vd;w 𝟐 Γ— 𝟐 thpirf; nfhz;l mzpia mikf;f. π‘Ž11 π‘Ž12 𝐴 = π‘Ž = 𝑖𝑗 21 π‘Ž22 π‘Ž11 = 1 Γ— 1 = 1, π‘Ž12 = 1 Γ— 2 = 2 , π‘Ž21 = 2 Γ— 1 = 2, π‘Ž22 = 2 Γ— 2 = 4 1 2 ∴𝐴 = 2 4

15.

𝑨 = [π’‚π’Šπ’‹ ] = πŸπ’Š – 𝒋 vd;w 𝟐 Γ— 𝟐 thpir nfhz;l mzpia mikf;f. π‘Ž11 π‘Ž12 𝐴 = π‘Ž = 2𝑖 – 𝑗 21 π‘Ž22 π‘Ž11 = 2 Γ— 1 – 1 = 2 βˆ’ 1 = 1, π‘Ž12 = 2 Γ— 1 – 2 = 2 βˆ’ 2 = 0 π‘Ž21 = 2 Γ— 2 – 1 = 4 βˆ’ 1 = 3, π‘Ž22 = 2 Γ— 2 – 2 = 4 βˆ’ 2 = 2 1 0 ∴𝐴 = 3 2

DO O

16.

ZY

13.

π’Šβˆ’π’‹

𝑨 = [π’‚π’Šπ’‹ ] = vd;w 𝟐 Γ— 𝟐 thpir nfhz;l mzpia mikf;f. π’Š+𝒋 π‘Ž11 π‘Ž12 π‘–βˆ’π‘— 𝐴 = π‘Ž = 𝑖+𝑗 21 π‘Ž22 π‘Ž11 =

π‘Ž21 = 𝐴 =

1βˆ’1 1+1 2βˆ’1 2+1

0 2

=

=

0

βˆ’1 3

1 3

0

1 3

= 0,

,

https://doozystudy.blogspot.in/

1βˆ’2 1+2 2βˆ’2 π‘Ž22 = 2+2

π‘Ž12 =

= =

βˆ’1 3 0 4

= 0

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

18.

πŸ“ ngUf;Ff. πŸ’ 5 (2 βˆ’ 1) = 10 βˆ’ 4 = 6 4 (𝟐 βˆ’ 𝟏)

𝑨 = [π’‚π’Šπ’‹ ] = πŸπ’Š βˆ’ πŸ‘π’‹ vd;w cWg;Gfs; nfhz;l 𝟐 Γ— πŸ‘ thpir cs;s mzp 𝑨 = [π’‚π’Šπ’‹ ] apidf; fhz;f. 𝐴

=

π‘Ž11 = π‘Ž12 = π‘Ž13 =

π‘Ž11 π‘Ž12 π‘Ž13 π‘Ž21 π‘Ž22 π‘Ž23 2 1 βˆ’ 3(1) = 2 1 βˆ’ 3(2) = 2(1) βˆ’ 3(3) =

(Apr-2014) = 2𝑖 βˆ’ 3𝑗 2 βˆ’ 3 = βˆ’1 = 1 2 βˆ’ 6 = βˆ’4 = 4 2 βˆ’ 9 = βˆ’7 = 7 ∴𝐴

𝒂

=

π‘Ž21 = 2 2 βˆ’ 3(1) = 4 βˆ’ 3 = 1 = 1 π‘Ž22 = 2 2 βˆ’ 3(2) = 4 βˆ’ 6 = βˆ’2 = 2 π‘Ž23 = 2 2 βˆ’ 3(3) = 4 βˆ’ 9 = βˆ’5 = 5

1 4 1 2

7 5

𝟐 𝟏𝟎 βˆ’πŸ +𝒃 = vdpy;> 𝒂, 𝒃 kjpg;Gfisf; fhz;f. πŸ‘ 𝟏 πŸ“ 2 10 βˆ’1 π‘Ž +𝑏 = 3 1 5 2π‘Ž 10 βˆ’π‘ + = 3π‘Ž 5 𝑏 2π‘Ž βˆ’ 𝑏 10 = 3π‘Ž + 𝑏 5 2π‘Ž – 𝑏 = 10………………………………… 1 3π‘Ž + 𝑏 = 5……………..…………………… 2 5π‘Ž = 15 π‘Ž = 15/5 π‘Ž = 3 π‘Ž = 3 vd (2) y; gpujpapl (3 Γ— 3) + 𝑏 = 5 9 + 𝑏 = 5 𝑏 = 5 – 9 = βˆ’4 𝑏 = βˆ’4

20.

DO O

ZY

19.

ST UD Y

17.

https://doozystudy.blogspot.in/

πŸ– 𝑨 = βˆ’πŸ 𝟎 𝐴𝐡

βˆ’πŸ• πŸ— βˆ’πŸ‘ 𝟐 vdpy; 𝑨𝑩 kw;Wk; 𝑩𝑨 Mfpa mzpfisf; fhz;f. πŸ’ 𝑩 = πŸ” βˆ’πŸ βˆ’πŸ“ πŸ‘ 8 βˆ’7 9 βˆ’3 2 = βˆ’2 4 6 βˆ’1 βˆ’5 0 3 72 βˆ’ 42 βˆ’24 + 7 16 + 35 = βˆ’18 + 24 6βˆ’4 βˆ’4 βˆ’ 20 0 + 18 0βˆ’3 0 βˆ’ 15 30 βˆ’17 51 = 6 2 βˆ’24 18 βˆ’3 βˆ’15

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

8 βˆ’7 βˆ’2 4 0 3 72 + 6 + 0 βˆ’63 βˆ’ 12 + 6 = 48 + 2 + 0 βˆ’42 βˆ’ 4 βˆ’ 15 78 βˆ’69 = 50 βˆ’61

24.

βˆ’3 2 βˆ’1 βˆ’5

𝟐 ,𝑩 = 𝟎 3 2 𝐴𝐡 = 4 0 9+6 = 12 + 0 3 0 𝐡𝐴 = 3 2 / 𝐴𝐡 β‰  𝐡𝐴

𝑨 =

πŸ‘ πŸ’

πŸ‘ 𝟎 vdpy; 𝑨𝑩, 𝑩𝑨 fhz;f. mit rkkhf ,Uf;Fkh? πŸ‘ 𝟐 3 0 3 2 0+4 15 4 = 0+0 12 0 3 2 9+0 6+0 9 6 = = 9+8 6+0 4 0 17 6

πŸ‘ βˆ’πŸ πŸ“ 𝟐 ,𝑩 = vd;w mzpfs; xd;Wf;nfhd;W ngUf;fy; Neh;khW mzp vd epWTf. βˆ’πŸ• πŸ“ πŸ• πŸ‘ 𝐴, 𝐡 vd;w mzpfs; xd;Wf;nfhd;W ngUf;fy; Neh;khW mzpfs; vdpy; gpd;tUk; tpjpia epiwT nra;a Ntz;Lk; 𝐴𝐡 = 𝐡𝐴 = 𝐼 3 βˆ’2 1 0 5 2 𝐴𝐡 = = =𝐼 0 1 7 3 βˆ’7 5 3 βˆ’2 5 2 1 0 𝐡𝐴 = = =𝐼 βˆ’7 5 0 1 7 3 nfhLf;fg;gl;l mzpfs; xd;Wf;nfhd;W ngUf;fy; Neh;khW mzp MFk;. 𝑨 =

πŸ‘ πŸ“ 𝟐 βˆ’πŸ“ , Mfpa mzpfs; ngUf;fiyg; nghUj;J xd;Wf;nfhd;W ngUf;fy; Neh;khW 𝟏 𝟐 βˆ’πŸ πŸ‘ mzp vd epWTf. 𝐴, 𝐡 vd;w mzpfs; xd;Wf;nfhd;W ngUf;fy; Neh;khW mzpfs; vdpy; gpd;tUk; tpjpia epiwT nra;a Ntz;Lk; 𝐴𝐡 = 𝐡𝐴 = 𝐼> 3 5 2 βˆ’5 𝐴= ,𝐡 = 1 2 βˆ’1 3 1 0 3 5 2 βˆ’5 𝐴𝐡 = = =I 0 1 1 2 βˆ’1 3 1 0 2 βˆ’5 3 5 𝐡𝐴 = = =I 0 1 βˆ’1 3 1 2 nfhLf;fg;gl;l mzpfs; xd;Wf;nfhd;W ngUf;fy; Neh;khW mzp MFk;.

ZY

23.

9 6

DO O

22.

=

ST UD Y

𝐡𝐴

21.

https://doozystudy.blogspot.in/

𝑨=

mzp.

𝟏 πŸ—

πŸ‘ vdpy; βˆ’πŸ”

𝑨𝑰 = 𝑰𝑨 = 𝑨, vd;gij rhpghh;f;f. ,q;F 𝑰 vd;gJ thpir 2 nfhz;l myF

(Apr-2014)

1 3 1 0 1 3 𝐴𝐼 = = =𝐴 9 βˆ’6 0 1 9 βˆ’6 1 0 1 3 1 3 𝐼𝐴 = = =𝐴 0 1 9 βˆ’6 9 βˆ’6 𝐴𝐼 = 𝐼𝐴 = 𝐴 vd;gJ rhpghh;f;fg;gl;lJ.

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

https://doozystudy.blogspot.in/

28.

29.

30.

31.

𝟐 πŸ’

πŸ— βˆ’πŸ

βˆ’πŸ‘ 𝟎

2 4

9 βˆ’3 βˆ’1 0

πŸ” βˆ’πŸ‘

πŸ’ 𝟐 βˆ’πŸ” πŸ• ngUf;Ff. βˆ’πŸ 𝟏 4 2 8 βˆ’ 54 + 6 4 + 63 βˆ’ 3 βˆ’40 = βˆ’6 7 = 16 + 6 + 0 8 βˆ’ 7 + 0 22 βˆ’2 1

(𝟐 βˆ’ πŸ•) ngUf;Ff. 6 12 (2 βˆ’ 7) = βˆ’3 βˆ’6

(Oct-2014,Apr-2016)

ST UD Y

27.

πŸ’ 𝟏 vd;w mzpfspd; ngUf;fiyf; fhz;f. (Apr-2012, Jun-2012) 𝟐 πŸ• 3 Γ— 4 + (βˆ’2 Γ— 2) 3 Γ— 1 + (βˆ’2 Γ— 7) 4 1 = 5 Γ— 4 + 1 Γ— 2 5 Γ— 1 + (1 Γ— 7) 2 7 12 + (βˆ’4) 3 + (βˆ’14) 8 βˆ’11 = = 20 + 2 5 + (7) 22 12

64 1

(Oct-2013)

βˆ’42 21

πŸπ’™ + π’š πŸ“ = vdpy; 𝒙 kw;Wk; π’š Mfpatw;wpd; jPh;T fhz;f. 𝒙 βˆ’ πŸ‘π’š πŸπŸ‘ 2π‘₯ + 𝑦 5 = π‘₯ βˆ’ 3𝑦 13 2π‘₯ + 𝑦 = 5…………………… 1 π‘₯ βˆ’ 3𝑦 = 13…………………. 2 (2) + (1) ⟹ (2) ⟹ π‘₯ βˆ’ 3𝑦 = 13 (1) Γ— 3 ⟹ 6π‘₯ + 3𝑦 = 15 7π‘₯ = 28 π‘₯ = 4 π‘₯ = 4 vd rkd;ghL 1y; gpujpapl ⟹ 2 Γ— 4 + 𝑦 = 5 𝑦 = 5 βˆ’ 8 = βˆ’3 jPh;T = {4, βˆ’3}

(Oct-2014)

ZY

26.

πŸ‘ βˆ’πŸ πŸ“ 𝟏 3 βˆ’2 5 1

π‘¨πŸ Γ— πŸ“ kw;Wk; π‘©πŸ“Γ—πŸ’ vd;w mzpfspd; ngUf;fy; tiuaWf;fg;gl;Ls;sjh? Mk; vdpy;> ngUf;fp tUk; mzpapd; thpiria vOJf. (Jun-2015) 𝐴 -d; epuy;fspd; vz;zpf;ifAk; 𝐡 -d; epiufspd; vz;zpf;ifAk; rkkhf ,Ug;gjhy; ngUf;fw;gyd; mzp 𝐴𝐡 tiuaWf;fg;gLfpwJ. 𝐴𝐡-d; thpir 2 Γ— 4 MFk;.

DO O

25.

https://doozystudy.blogspot.in/

π‘¨πŸ Γ— πŸ‘ kw;Wk; π‘©πŸ’ Γ— πŸ‘ vd;w mzpfspd; ngUf;fy; tiuaWf;fg;gl;Ls;sjh? Mk; vdpy; > ngUf;fp tUk; mzpapd; thpiria vOJf. 𝐴 -d; epuy;fspd; vz;zpf;ifAk; 𝐡 -d; epiufspd; vz;zpf;ifAk; rkkhf ,y;iy. vdNt> ,t;tpU mzpfspd; ngUf;fw;gyd; tiuaWf;fg;gltpy;iy. A kw;Wk; B vd;w mzpfSf;F AB fpilf;fg; ngWfpwJ. Mdhy; BA fpilf;fg; ngwtpy;iy vdpy;> A kw;Wk; B-d; thpirfisg; gw;wp $Wf. (Apr-2013) A kw;Wk; B vd;w mzpfSf;F AB fpilf;fg; ngWfpwJ. Mdhy; BA fpilf;fg; ngwtpy;iy. vdNt> B-apd; epuy;fspd; vz;zpf;ifAk; A-apd; epiufspd; vz;zpf;ifAk; rkky;y. mjhtJ> A-d; thpir π‘š Γ— 𝑛 MfTk;> Bd; thpir 𝑛 Γ— 𝑝 MfTk; ,Uf;f Ntz;Lk;.

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𝑨 = (𝟏 𝟐 βˆ’ 𝟏) ,

33.

jPh;T fhz;f.

𝟐 𝒙 πŸ– = πŸ“ π’š πŸπŸ‘ 3 2 π‘₯ 8 = 4 5 𝑦 13 3π‘₯ + 2𝑦 8 = 4π‘₯ + 5𝑦 13 3π‘₯ + 2𝑦 = 8 ⟹ 3π‘₯ + 2𝑦 βˆ’ 8 = 0 πŸ‘ πŸ’

4π‘₯ + 5𝑦 = 13 ⟹ 4π‘₯ + 5𝑦 βˆ’ 13 = 0 FWf;Fg; ngUf;fy; Kiw π‘₯ 𝑦 1 2 -8 3 2 5 -13 4 5 π‘₯ βˆ’26+40

=

𝑦 βˆ’32+39

⟹

π‘₯ 14

=

1 7

⟹

π‘₯ 14

𝑦 7

= =

⟹π‘₯=

1 7

14 7

&

𝑦 7

=

1 15βˆ’8

(Oct-2015)

ZY

⟹

(Jun-2013)

ST UD Y

𝟐 B= 𝟏 vdpy;> (𝐀𝐁)𝐓 - iaf; fhz;f. πŸ’ 2 𝐴 = (1 2 βˆ’ 1) , 𝐡 = 1 4 2 𝐴𝐡 = (1 2 βˆ’ 1) Γ— 1 = (2 + 2 βˆ’ 4) = (0) 4 (𝐴𝐡)𝑇 = (0)

32.

=

1 7

& 𝑦=

7 7

34.

DO O

⟹π‘₯ =2&𝑦 =1

𝒙+π’š πŸ• π’š + 𝒛 = πŸ— vdpy; 𝒙, π’š kw;Wk; 𝒛 d; kjpg;Gfis fhz;f. π’›βˆ’πŸ“ 𝟎

π‘₯+𝑦 7 𝑦+𝑧 = 9 π‘§βˆ’5 0 π‘₯ + 𝑦 = 7…………… 1 𝑦 + 𝑧 = 9…………… 2 𝑧 βˆ’ 5 = 0…………….. 3 π‘₯ = 3, 𝑦 = 4, 𝑧 = 5

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(Apr-2016)

𝑧 = 5 vd (2)y; gpujpapl 𝑦+5=9 ⇒𝑦 =9βˆ’5 =4 𝑦 = 4 vd (1) y; gpujpapl π‘₯+4= 7β‡’π‘₯ =7βˆ’4 =3

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5. Maj;njhiy tbtpay;

eLg;Gs;sp = = 2.

π‘₯ 1 + π‘₯ 2 𝑦1 + 𝑦2 , 2 2 3βˆ’1 0+4 , = 2 2

= =

π‘₯ 1 + π‘₯ 2 𝑦1 + 𝑦2 , 2 2 1βˆ’5 βˆ’1+3

,

2 βˆ’4 2 2

,

2

2

= (βˆ’2, 1)

(0, 0), (0, 4) Mfpa Gs;spfis ,izf;Fk; Nfhl;Lj;Jz;bd; eLg;Gs;spiaf; fhz;f. π‘₯1 , 𝑦1 π‘₯2 , 𝑦2 (0, 0), (0, 4) eLg;Gs;sp = = =

4.

= (1,2)

(1, -1), (-5, 3) Mfpa Gs;spfis ,izf;Fk; Nfhl;Lj;Jz;bd; eLg;Gs;spiaf; fhz;f. π‘₯1 , 𝑦1 π‘₯2 , 𝑦2 (1, -1), (-5, 3) eLg;Gs;sp =

3.

2 4 , 2 2

ST UD Y

(3, 0), (-1, 4) Mfpa Gs;spfis ,izf;Fk; Nfhl;Lj;Jz;bd; eLg;Gs;spiaf; fhz;f. π‘₯1 , 𝑦1 π‘₯2 , 𝑦2 (3, 0), (-1, 4)

π‘₯ 1 + π‘₯ 2 𝑦1 + 𝑦2 , 2 2 0+0 0+4 , 2 2 0 4 , = (0,2) 2 2

ZY

1.

xU tl;lj;jpd; ikak; ( βˆ’ 6, 4). mt;tl;lj;jpd; xU tpl;lj;jpd; xU Kid Mjpg;Gs;sp vdpy; > kWKidiaf; fhz;f. (Jun-2012, 2014, Apr-2015) π‘₯2 , 𝑦2 π‘₯1 , 𝑦1 (0, 0) = (βˆ’6, 4) = (βˆ’6, 4)

DO O

π‘₯ 1 + π‘₯ 2 𝑦1 + 𝑦2 , 2 2 π‘₯ 1 + 0 𝑦1 + 0 , 2 2

π‘₯1 2 𝑦1 2

= βˆ’6 ⟹ π‘₯1 = βˆ’12 = 4 ⟹ 𝑦1 = 8

kWKid = (βˆ’12, 8)

5.

(1, 3), (2, 7), (12, βˆ’16) Mfpa Gs;spfis Kidfshff; nfhz;l Kf;Nfhzj;jpd; eLf;Nfhl;L ikak; fhz;f. π‘₯1 , 𝑦1 π‘₯2 , 𝑦2 π‘₯3 , 𝑦3 (1, 3), (2, 7), (12, -16) eLf;Nfhl;L ikak; G

= =

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π‘₯ 1 + π‘₯ 2 +π‘₯ 3 𝑦1 + 𝑦2 +𝑦3 , 3 3 1+2+12 3+7βˆ’16 15 βˆ’6 , = , 3 3 3 3

= (5, βˆ’2)

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(3, βˆ’5), (βˆ’7, 4), (10, βˆ’-2) Mfpa Gs;spfis Kidfshff; nfhz;l Kf;Nfhzj;jpd; eLf;Nfhl;L ikak; fhz;f. π‘₯1 , 𝑦1 π‘₯2 , 𝑦2 π‘₯3 , 𝑦3 (3, βˆ’5), (βˆ’7, 4), (10, βˆ’2) eLf;Nfhl;L ikak;

= =

7.

π‘₯ 1 + π‘₯ 2 +π‘₯ 3 𝑦1 + 𝑦2 +𝑦3 , 3 3 3βˆ’7+10 βˆ’5+4βˆ’2

,

3

3

= = =

,

3

= (2, βˆ’1)

Gs;sp (1, 3)-I eLf;Nfhl;L ikakhff; nfhz;l Kf;Nfhzj;jpd; ,U Kidfs; (βˆ’7, 6) kw;Wk; (8, 5) vdpy;> Kf;Nfhzj;jpd; %d;whtJ Kidiaf; fhz;f. (Apr-2012, Apr-2016) π‘₯1 , 𝑦1 π‘₯2 , 𝑦2 π‘₯3 , 𝑦3 (βˆ’7, 6), (8, 5) , (π‘₯3 , 𝑦3 ), π‘₯ 1 + π‘₯ 2 +π‘₯ 3 𝑦1 + 𝑦2 +𝑦3 , = (1, 3) 3 3 βˆ’7+8+π‘₯ 3 6+5+𝑦3 , = (1, 3) 3 3 π‘₯ 3 +1 𝑦3 +11 , = (1,3) 3 3 𝑦3 +11 = 3 3

ZY

eLf;Nfhl;L ikak; =

π‘₯ 3 +1 3

DO O

= 1 π‘₯3 + 1 = 3 π‘₯3 = 3 βˆ’ 1 π‘₯3 = 2 %d;whtJ Kid = (2, -2)

𝑦3 + 11 = 9 𝑦3 = 9 βˆ’ 11

𝑦3 = βˆ’2

(0, 0), (3, 0), (0, 2) Mfpa Gs;spfis Kidfshf nfhz;l Kf;Nfhzj;jpd; gug;gsT fhz;f. 𝐴 = 𝐴 = 𝐴=

10.

3

π‘₯ 1 + π‘₯ 2 +π‘₯ 3 𝑦1 + 𝑦2 +𝑦3 , 3 3 4+3+5 βˆ’6βˆ’2+2 , 3 3 12 βˆ’6 , 3 3

= (4, βˆ’2)

9.

6 βˆ’3

A (4, βˆ’6), B (3, βˆ’2), (5, 2) Mfpa Gs;spfis Kidfshff; nfhz;l Kf;Nfhzj;jpd; eLf;Nfhl;L ikak; fhz;f. (Oct-2012) π‘₯1 , 𝑦1 π‘₯2 , 𝑦2 π‘₯3 , 𝑦3 (4, βˆ’6), (3, βˆ’2), (5, 2) eLf;Nfhl;L ikak;

8.

=

ST UD Y

6.

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1 2 1 2 1 2

{ π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 + π‘₯1 𝑦3 } 0+6+0 βˆ’ 0+0+0

=

1 2

{6 βˆ’ 0}

0

3

0

0

0

0

2

0

Γ— 6 = 3 r.m.

(5, 2), (3, βˆ’5), (βˆ’5, βˆ’1) Mfpa Gs;spfis Kidfshf nfhz;l Kf;Nfhzj;jpd; gug;gsT fhz;f. 𝐴 =

𝐴 = 𝐴 =

1 { 2 1 2 1 2

π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 + π‘₯1 𝑦3 }

5

3

βˆ’5

5

βˆ’25 βˆ’ 3 βˆ’ 10 βˆ’ 6 + 25 βˆ’ 5

2

βˆ’5

βˆ’1

2

{βˆ’38 βˆ’ 26}

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𝐴=

1 2

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Γ— βˆ’64 = βˆ’32 (gug;G vg;nghOJk; kpif vz;zhf ,Uf;f Ntz;Lk;)

𝐴 = 32 r.m. (βˆ’4, βˆ’5), (4, 5),( βˆ’1, βˆ’6) Mfpa Gs;spfis Kidfshf nfhz;l Kf;Nfhzj;jpd; gug;gsT fhz;f. 𝐴 = 𝐴 = 𝐴 = 𝐴=

1 { 2 1

π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 + π‘₯1 𝑦3 }

βˆ’4

4

βˆ’1

βˆ’20 βˆ’ 24 + 5 βˆ’ [βˆ’20 βˆ’ 5 + 24 }

βˆ’5

5

βˆ’6

2 1 {βˆ’39 + 1} 2 1 Γ— βˆ’38 = 2

βˆ’19

𝐴 = 19 r.m. 12.

βˆ’5

(1, 2) (βˆ’3, 4), (βˆ’5, βˆ’6) Mfpa Gs;spfis Kidfshf nfhz;l Kf;Nfhzj;jpd; gug;gsT fhz;f. 𝐴 = 𝐴 = 𝐴 = 𝐴=

13.

βˆ’4

ST UD Y

11.

1 { π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 2 1 4 + 18 βˆ’ 10 βˆ’ [βˆ’6 βˆ’ 20 βˆ’ 6 } 2 1 {12 + 32} 2 1 Γ— 44 = 22 r. m. 2

+ π‘₯1 𝑦3 }

1

βˆ’3

βˆ’5

1

2

4

βˆ’6

2

A(2, 3), B(4, 0) C(6, βˆ’3) Mfpa Gs;spfs; xNu Neh;f;Nfhl;by; mike;Js;sdth vd Muha;f. 1 { π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 2 1 𝐴 = 0 βˆ’ 12 + 18 βˆ’ [12 2 1 𝐴 = {6 βˆ’ 6} 2 1 𝐴= Γ— 0 = 0 2

βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 + π‘₯1 𝑦3 }

2

4

6

2

+0βˆ’6 }

3

0

βˆ’3

3

ZY

𝐴 =

/ nfhLf;fg;gl;l Gs;spfs; xNu Neh;f;Nfhl;by; mike;Js;sd. 14.

A(4, 3), B(1, 2), C(βˆ’2, 1) Mfpa Gs;spfs; xNu Neh;f;Nfhl;by; mike;Js;sdth vd Muha;f. 1

{ π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 2 1 𝐴 = 8 + 1 βˆ’ 6 βˆ’ [3 βˆ’ 4 + 4 } 2 1 𝐴 = {3 βˆ’ 3} 2 1 𝐴= Γ— 0 = 0 2

+ π‘₯3 𝑦2 + π‘₯1 𝑦3 }

DO O

𝐴 =

4

1

βˆ’2

4

3

2

1

3

/ nfhLf;fg;gl;l Gs;spfs; xNu Neh;f;Nfhl;by; mike;Js;sd.

15.

A (βˆ’2, βˆ’2), B(βˆ’6, βˆ’2), C(βˆ’2,2) Mfpa Gs;spfs; xNu Neh;f;Nfhl;by; mike;Js;sdth vd Muha;f. 𝐴 =

𝐴 = 𝐴 = 𝐴=

1 { π‘₯1 𝑦2 + π‘₯2 𝑦3 2 1 4 βˆ’ 12 + 4 2 1 {βˆ’4 βˆ’ 12} 2 1 Γ— {βˆ’16} 2

+ π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 + π‘₯1 𝑦3 }

βˆ’2

βˆ’6

βˆ’2

βˆ’2

βˆ’ [12 + 4 βˆ’ 4 }

βˆ’2

βˆ’2

2

βˆ’2

𝐴 = 8 ⟹ 𝐴 β‰  0 / nfhLf;fg;gl;l Gs;spfs; xNu Neh;f;Nfhl;by; mikahJ.

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16.

A

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βˆ’πŸ‘ , πŸ‘ , B (6, -2), C(-3, 4) Mfpa Gs;spfs; xNu Neh;f;Nfhl;by; mike;Js;sdth 𝟐 1 βˆ’3 𝐴 = { π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 + π‘₯1 𝑦3 } 6 -3 2 2 1 𝐴 = 3 + 24 βˆ’ 9 βˆ’ [18 + 6 βˆ’ 6 } 3 -2 4 2 1 𝐴 = {18 βˆ’ 18} 2 1

𝐴=

2

vd Muha;f. βˆ’3 2

3

Γ— 0 = 0

17.

ST UD Y

/ nfhLf;fg;gl;l Gs;spfs; xNu Neh;f;Nfhl;by; mike;Js;sd.

𝒂, 𝟏 , 𝟏, 𝟐 kw;Wk; (𝟎, 𝒃 + 𝟏) Mfpa Gs;spfs; xNu Neh;f;Nfhl;by; mike;jhy; a 1 0 a

1 2 b+1 = 0 1

2π‘Ž + 𝑏 + 1 + 0 βˆ’ 1 + 0 + π‘Žπ‘ + π‘Ž 2π‘Ž + 𝑏 + 1 βˆ’ 1 βˆ’ π‘Žπ‘ βˆ’ π‘Ž π‘Ž + 𝑏 – π‘Žπ‘ π‘Ž + 𝑏 π‘Ž+𝑏 π‘Žπ‘

,UGwKk; "π‘Žπ‘" My; tFf;f

+ 1 π‘Ž

18.

=

𝑏 π‘Žπ‘

(Apr-2013)

π‘Žπ‘ π‘Žπ‘

= 1 1 𝑏

+ = 1 vd epWtg;gl;lJ.

A (6,7), B (βˆ’4,1) C (a, βˆ’9) Mfpatw;iw Kidfshff; nfhz;l βˆ†π€ππ‚ d; gug;G 68 r. myFfs; vdpy; 𝒂-d; kjpg;igf; fhz;f. (Jun-2013, 2015) A = 68 1 2

{ π‘₯1 𝑦2 + π‘₯2 𝑦3 + π‘₯3 𝑦1 βˆ’ π‘₯2 𝑦1 + π‘₯3 𝑦2 + π‘₯1 𝑦3 = 68

DO O

𝐴 =

6 + 36 + 7π‘Ž βˆ’ [βˆ’28 + π‘Ž βˆ’ 54 } = 68 Γ— 2 42 + 7π‘Ž βˆ’ [βˆ’82 + π‘Ž } = 136 42 + 7π‘Ž + 82 – π‘Ž = 1 124 + 6π‘Ž = 136 6π‘Ž = 12 π‘Ž = 12/6 π‘Ž= 2

19.

𝟏 𝒃

+ = 𝟏 vd epWTf.

0 0 0 π‘Žπ‘

ZY

π‘Ž π‘Žπ‘

= = = =

𝟏 𝒂

6

βˆ’4

a

7

1

βˆ’9

6 7

( βˆ’ 5, βˆ’ 2) vd;w Gs;sp topr; nry;tJk;> Ma mr;RfSf;F ,izahdJkhd Neh;f;NfhLfspd; rkd;ghLfisf; fhz;f. (Jun-2013) π‘₯ mr;Rf;F ,izahd Nfhl;bd; rkd;ghL 𝑦 mr;Rf;F ,izahd Nfhl;bd; rkd;ghL 𝑦 = π‘˜ π‘₯ = π‘˜

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𝑦 = βˆ’2 𝑦 + 2 = 0 20.

π‘₯ = βˆ’5 π‘₯ + 5 = 0

𝒙 + πŸπ’š + 𝟏 = 𝟎 , πŸ‘π’™ + πŸ”π’š + 𝟐 = 𝟎 Mfpa Neh;f;NfhLfs; ,iz vd epWTf. π‘₯ + 2𝑦 + 1 = 0 d; rha;T π‘š1 =

=

βˆ’1 2

21.

βˆ’1 2

ST UD Y

βˆ’3

3π‘₯ + 6𝑦 + 2 = 0 d; rha;T π‘š2 = = = 6 π‘š1 = π‘š2 rha;Tfs; rkk;. vdNt Neh;f;NfhLfs; ,iz.

πŸ‘π’™ + πŸπ’š βˆ’ 𝟏𝟐 = 𝟎 , πŸ”π’™ + πŸ’π’š + πŸ– = 𝟎 Mfpa Neh;f;NfhLfs; ,iz vd epWTf. 3π‘₯ + 2𝑦 βˆ’ 12 = 0 d; rha;T π‘š1 = 6π‘₯ + 4𝑦 + 8 = 0 d; rha;T π‘š2 =

βˆ’3 2

=

=

βˆ’6 4

=

βˆ’3 2

π‘š1 = π‘š2 rha;Tfs; rkk;. vdNt Neh;f;NfhLfs; ,iz. 22.

𝒙 + πŸπ’š + 𝟏 = 𝟎 , πŸπ’™ βˆ’ π’š + πŸ“ = 𝟎 Mfpa Neh;f;NfhLfs; nrq;Fj;J vd epWTf. π‘₯ + 2𝑦 + 1 = 0 d; rha;T π‘š1 = 2π‘₯ βˆ’ 𝑦 + 5 = 0 d; rha;T π‘š2 =

23.

βˆ’1 2

βˆ’2 βˆ’1

= 2

Γ— 2 = βˆ’1. vdNt Neh;f;NfhLfs; nrq;Fj;jhdit.

πŸ‘π’™ βˆ’ πŸ“π’š + πŸ• = 𝟎 , πŸπŸ“π’™ + πŸ—π’š + πŸ’ = 𝟎 Mfpa Neh;f;NfhLfs; nrq;Fj;J vd epWTf. (Apr-2013) 3π‘₯ βˆ’ 5𝑦 + 7 = 0 d; rha;T π‘š1 =

=

15π‘₯ + 9𝑦 + 4 = 0 d; rha;T π‘š2 =

=

3 5

DO O

π‘š1 Γ— π‘š2 = 24.

=

ZY

π‘š1 Γ— π‘š2 =

βˆ’1 2

=

Γ—

βˆ’5 3

βˆ’3 βˆ’5 βˆ’15 9

= =

3 5 βˆ’5 3

= βˆ’1. vdNt Neh;f;NfhLfs; nrq;Fj;jhdit.

πŸ“π’™ βˆ’ πŸπ’š βˆ’ πŸ— = 𝟎 , π’‚π’š + πŸπ’™ βˆ’ 𝟏𝟏 = 𝟎 Mfpa Neh;f;NfhLfs; xd;Wf;nfhd;W nrq;Fj;J vdpy; 𝒂-d; kjpg;igf; fhz;f. (Apr-2016) 5π‘₯ βˆ’ 2𝑦 βˆ’ 9 = 0 vd;w Neh;f;Nfhl;bd; rha;T π‘š1 =

=

βˆ’5 βˆ’2

2π‘₯ + π‘Žπ‘¦ βˆ’ 11 = 0 vd;w Neh;f;Nfhl;bd; rha;T π‘š2 =

=

βˆ’2 π‘Ž

Neh;f;NfhLfs; xd;Wf;nfhd;W nrq;Fj;J> vdNt

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=

5 2

π‘š1 Γ— π‘š2 = βˆ’1 5 2

Γ—

βˆ’2 π‘Ž

= βˆ’1

βˆ’π‘Ž = βˆ’5 π‘Ž=5

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25.

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rha;Tf;Nfhzk; πŸ’πŸ“πŸŽ kw;Wk; π’š-ntl;Lj;Jz;L

𝟐 πŸ“

Mfpatw;iwf; nfhz;l Neh;f;Nfhl;bd; rkd;ghl;ilf;

$Wf.

(Oct-2013) rha;T π‘š = π‘‘π‘Žπ‘› πœƒ =

π‘‘π‘Žπ‘›450

𝑦 –ntl;Lj;Jz;L 𝑐 =

2 5

= 1

Njitahd Neh;f;Nfhl;bd; rkd;ghL 𝑦 = π‘šπ‘₯ + 𝑐 2 5 5𝑦 = 5π‘₯ + 2 5π‘₯ βˆ’ 5𝑦 + 2 = 0

ST UD Y

𝑦 = 1π‘₯ +

πŸ‘π’™ βˆ’ π’š + πŸ• = 𝟎 vd;w Neh;f;Nfhl;bw;F ,izahdJk; (𝟏, βˆ’πŸ) vd;w Gs;sp topr; nry;tJkhd Neh;f;Nfhl;bd; rkd;ghl;ilf; fhz;f. (Jun-2015) 3π‘₯ βˆ’ 𝑦 + 7 = 0 vd;w Neh;f;Nfhl;bw;F ,izahd Neh;f;Nfhl;bd; rkd;ghL 3π‘₯ – 𝑦 + π‘˜ = 0 3 π‘₯ βˆ’ 𝑦 + π‘˜ = 0 vd;gJ (1, -2) vd;w Gs;sp topr; nry;fpwJ. vdNt> Neh;f;Nfhl;bd; rkd;ghl;by; π‘₯ = 1, 𝑦 = 2 vdg; gpujpapl 3(1) βˆ’ (βˆ’2) + π‘˜ = 0 ⟹ 3 + 2 + π‘˜ = 0 5+π‘˜ = 0 ⟹ π‘˜ = βˆ’5 Njitahd Neh;f;Nfhl;bd; rkd;ghL 3 π‘₯ – 𝑦 – 5 = 0 MFk;. 27. πŸ’ 𝒙 βˆ’ πŸπ’š + 𝟏 = 𝟎 vd;w Neh;f;Nfhl;bd; rha;T kw;Wk; π’š-ntl;Lj;Jz;L Mfpatw;iwf; fhz;f. 26.

(Apr-15)

nfhLf;fg;gl;l Neh;f;Nfhl;bd; rkd;ghL 4 π‘₯ βˆ’ 2𝑦 + 1 = 0.

𝑦 ntl;Lj;Jz;L rha;T = 2, 28.

=

=

βˆ’4 βˆ’2

= 2

ZY

rha;T

=

=

𝑦 ntl;Lj;Jz;L =

βˆ’1 βˆ’2

=

1 2

khw;WKiw

𝑦 = π‘šπ‘₯ + 𝑐 β‡’ βˆ’2𝑦 = βˆ’4π‘₯ βˆ’ 1

𝑦=

βˆ’4 π‘₯ βˆ’2

+

βˆ’1 βˆ’2

β‡’π‘š=

βˆ’4 βˆ’2

= 2, 𝑐 =

βˆ’1 βˆ’2

=

1 2

1 2

πŸπ’™ – π’š + πŸπŸ” = 𝟎 vd;w Neh;f;Nfhl;bd; rkd;ghl;bypUe;J 𝒙, π’š -ntl;Lj;Jz;Lfisf; fhz;f.

DO O

nfhLf;fg;gl;l Neh;f;Nfhl;bd; rkd;ghL 2π‘₯ – 𝑦 + 16 = 0 π‘₯ -ntl;L =

=

𝑦 -ntl;L =

=

βˆ’16 2 βˆ’16 βˆ’1

= βˆ’8 = 16

π‘₯–ntl;Lj; Jz;L = -8, 𝑦 -ntl;Lj;Jz;L = 16

29.

(βˆ’πŸ, πŸ“) kw;Wk; (πŸ‘, πŸ”) Mfpa Gs;spfs; topr; nrY;Yk; Neh;f;Nfhl;bd; rkd;ghl;ilf; fhz;f. ,U Gs;spfs; topr; nry;Yk; Nfhl;bd; rkd;ghL π‘¦βˆ’π‘¦1 π‘₯βˆ’π‘₯ 1 = (π‘₯1 = βˆ’2, 𝑦1 = 5, π‘₯2 = 3, 𝑦2 = 6) 𝑦2 βˆ’π‘¦1

π‘₯ 2 βˆ’π‘₯ 1

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nfhLf;fg;gl;l ,U Gs;spfs; (-2, 5) kw;Wk; (3, 6) π‘¦βˆ’5 6βˆ’5

=

π‘₯+2 3+2

π‘¦βˆ’5 1

=

π‘₯+2 5

5(𝑦 βˆ’ 5) = π‘₯ + 2 π‘₯ βˆ’ 5𝑦 + 27

ST UD Y

5𝑦 – 25 = π‘₯ + 2 = 0

Njitahd Neh;f;Nfhl;bd; rkd;ghL π‘₯ βˆ’ 5𝑦 + 27 = 0 30.

rha;T βˆ’3 kw;Wk; π’š - ntl;Lj;Jz;L 4 nfhz;lJkhd Neh;f;Nfhl;bd; rkd;ghl;ilf; fhz;f. nfhLf;fg;gl;lit rha;T π‘š = βˆ’3 kw;Wk; 𝑦 - ntl;Lj;Jz;L 𝑐 = 4 Njitahd Neh;f;Nfhl;bd; rkd;ghL 𝑦 = π‘šπ‘₯ + 𝑐 𝑦 = βˆ’ 3π‘₯ + 4 3π‘₯ – 𝑦 + 4 = 0 Njitahd Neh;f;Nfhl;bd; rkd;ghL 3π‘₯ βˆ’ 𝑦 + 4 = 0

31.

(7, 3), (6, 1), (8, 2) kw;Wk; (P, 4) vd;gd Xh; ,izfuj;jpd; thpirg;gb mike;j cr;rpfs; vdpy; P-d; kjpg;igf; fhz;f. (Jun-2012) ,izfuk; ABCD d; cr;rpfs; A(7,3), B(6,1), C(8,2) kw;Wk; D(P,4) vd;f. Xh; ,izfuj;jpd; %iytpl;lq;fs; xd;iwnahd;W ,Urkf;$wpLk; mjhtJ %iytpl;lk; AC-d; eLg;Gs;sp = %iytpl;lk; BD-d; eLg;Gs;sp 7+8 3+2 6+𝑃 1+4 / , = , 2

=

2 7+8 2

2

eLg;Gs;sp fhZk; tha;g;ghL β‡’

6+ P = 15 P = 15 - 6 = 9 P=9

π‘₯ 1 +π‘₯ 2 𝑦1 +𝑦2 , 2 2

rha;Tf;Nfhzk; πŸ‘πŸŽπŸŽ nfhz;l kw;Wk; (4,2), (3,1) Mfpa Gs;spfis ,izf;Fk; Neh;f;Nfhl;Lj; Jz;bd; eLg;Gs;sp topr; nry;Yk; Neh;f;Nfhl;bd; rkd;ghl;ilf; fhz;f. (Oct-2012) rha;Tf;Nfhzk; πœƒ = 300

DO O

32.

2

ZY

6+P 2

rha;T π‘š = π‘‘π‘Žπ‘› πœƒ = π‘‘π‘Žπ‘›300 =

1 3

(4, 2), (3, 1) Mfpa Gs;spfis ,izf;Fk; Neh;f;Nfhl;Lj; Jz;bd; eLg;Gs;sp π‘₯ 1 +π‘₯ 2 𝑦1 +𝑦2 , 2 2

=

4+3 2+1 , 2 2

=

7 3 , 2 2

Njitahd Neh;f;Nfhl;bd; rkd;ghl;bd; rkd;ghL 𝑦 βˆ’ 𝑦1 = π‘š( π‘₯ βˆ’ π‘₯1 ) Fwpg;G: π‘š = (π‘₯1 , 𝑦1 ) =

1 3

7 3 , 2 2

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𝑦 βˆ’

3 2

2π‘¦βˆ’3 2

=

= 1 3

1 3 2π‘₯βˆ’7 2

π‘₯βˆ’

7 2

3(2𝑦 βˆ’ 3) = 2 π‘₯ βˆ’ 7 2 3𝑦 βˆ’ 3 3 βˆ’ 2π‘₯ + 7 = 0 2π‘₯ βˆ’ 2 3 𝑦 + (3 3 βˆ’ 7) = 0

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33.

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πŸπ’‚ + 𝟐, πŸ‘ , πŸ’, πŸπ’ƒ + 𝟏 Mfpa Gs;spfis ,izf;Fk; Nfhl;Lj;Jz;bd; eLg;Gs;spapd; Maj;njhiyTfs; (πŸπ’‚, πŸπ’ƒ) vdpy;> 𝒂, 𝒃 Mfpatw;wpd; kjpg;Gfisf; fhz;f. (Apr-2014) 2π‘Ž + 2, 3 , 4, 2𝑏 + 1 Mfpa Gs;spfis ,izf;Fk; Nfhl;Lj;Jz;bd; eLg;Gs;sp = (2π‘Ž, 2𝑏) = (2π‘Ž, 2𝑏) = (2π‘Ž, 2𝑏) 2𝑏+4 2

= 2𝑏

ST UD Y

π‘₯ 1 +π‘₯ 2 𝑦1 +𝑦2 , 2 2 2π‘Ž+2+4 3+2𝑏 +1 , 2 2 2π‘Ž+6 = 2π‘Ž 2

2π‘Ž + 6 = 4π‘Ž

2𝑏 + 4 = 4𝑏

2π‘Ž = 6

π‘Ž =3

2𝑏 = 4

𝑏=2

π‘Ž = 3, 𝑏 = 2

34. (3, βˆ’4) vd;w Gs;sp topr; nry;Yk; kw;Wk; Ma mr;RfSf;F ,izahf mike;j Neh;f;NfhLfspd; rkd;ghLfisf; fhz;f. (Apr-2014) (3, βˆ’4) vd;w Gs;sp topr; nry;Yk; kw;Wk; π‘₯ mr;Rf;F ,izahd Nfhl;bd; rkd;ghL 𝑦=𝑐, vdNt> 𝑦 = βˆ’4 (3, βˆ’ 4) vd;w Gs;sp topr; nry;Yk; kw;Wk; 𝑦 mr;Rf;F ,izahd Nfhl;bd; rkd;ghL π‘₯ = 𝑐, vdNt> π‘₯ = 3 35.

(βˆ’2, 3) vd;w Gs;sp topr; nry;tJk;> rha;T

3

πŸ‘

cilaJkhd Neh;f;Nfhl;bd; rkd;ghl;ilf; fhz;f.

(Jun- 2014)

ZY

(π‘₯1 , 𝑦1 ) = (βˆ’2,3) 1 rha;T π‘š =

𝟏

Njitahd Nfhl;bd; rkd;ghL 𝑦 βˆ’ 𝑦1 = π‘š π‘₯ βˆ’ π‘₯1 π‘¦βˆ’3 =

1 3

π‘₯+2

3𝑦 βˆ’ 9 = π‘₯ + 2 π‘₯ βˆ’ 3𝑦 + 11 = 0

(βˆ’ 3, 5) kw;Wk; (4, βˆ’ 9) Mfpa Gs;spfis ,izf;Fk; Nfhl;Lj;Jz;bid cl;Gwkhf 1:6 vd;w tpfpjj;jpy; gphpf;Fk; Gs;spapd; mr;Rj; njhiyTfisf; fhz;f. (Oct-2014)

DO O

36.

cl;Gwkhf gphpf;Fk; Gs;sp 𝑃

cl;Gwkhf gphpf;Fk; Gs;sp 𝑃

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= = = =

𝑙π‘₯ 2 +π‘šπ‘₯ 1 𝑙𝑦 2 +π‘šπ‘¦ 1

,

𝑙+π‘š 𝑙+π‘š 1 4 + 6(βˆ’3) 1 βˆ’9 +6(5) , 1+6 1+6 4βˆ’18 βˆ’9+30

,

7 7 βˆ’14 21 , 7 7

= (βˆ’2,3)

π‘₯1 = βˆ’3, π‘₯2 = 4, 𝑦1 = 5, 𝑦2 = βˆ’9 𝑙 = 1, π‘š = 6

= (βˆ’2,3)

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(2, 1) kw;Wk; (5, βˆ’8) vd;w Gs;spfis ,izf;Fk; Nfhl;Lj; Jz;il P,Q vd;w Gs;spfs; %d;W rkghfq;fshfg; gphpf;fpd;wd. Gs;sp P MdJ πŸπ’™ βˆ’ π’š + π’Œ = 𝟎 vd;w Nfhl;bd; Nky; cs;sJ vdpy;> π’Œ-d; kjpg;G fhz;f. (Oct-2014) P,Q vd;w Gs;spfs; AB I Kr;rkf; $wpLk; Gs;spfs; MFk;. mjhtJ P vd;gJ AB I 1:2 vd;w tpfpjj;jpy; gphpf;Fk; Gs;sp MFk;. vdNt>

𝑙π‘₯ 2 +π‘šπ‘₯ 1 𝑙𝑦 2 +π‘šπ‘¦ 1 , 𝑙+π‘š 𝑙+π‘š 1 5 +2(2) 1 βˆ’8 + 2(1) , 1+2 1+2 5+4 βˆ’8+2 , 3 3 9 βˆ’6 , 3 3

𝑃= = = =

ST UD Y

37.

https://doozystudy.blogspot.in/

𝑃 = (3, βˆ’2)

38.

π‘₯1 = 2, π‘₯2 = 5, 𝑦1 = 1, 𝑦2 = βˆ’8 𝑙 = 1, π‘š = 2

𝑃 MdJ 2π‘₯ βˆ’ 𝑦 + π‘˜ = 0 vd;w Nfhl;bd; Nky; cs;sJ. vdNt 2 3 + 2 + π‘˜ = 0 8+π‘˜ =0 π‘˜ = βˆ’8 rJuk; ABCD-apd; gf;fk; AB MdJ 𝒙 -mr;Rf;F ,izahf cs;sJ. vdpy;> %iytpl;lk; 𝑨π‘ͺ -apd; rha;T fhz;f. (Oct-2015) rJuk; ABCD –apd; gf;fk; AB MdJ π‘₯-mr;Rf;F ,izahf cs;sJ. %iytpl;lk; AC MdJ ∠𝐷𝐴𝐡 –I ,Urkf; $wpLk;. vdNt> ∠𝐡𝐴𝐢 = 450 mjhtJ πœƒ = 450 MfNt %iytpl;lk; AC-d; rha;T

m = tanΞΈ

ZY

= tan 450 =1

6. tbtpay;

βˆ†π‘¨π‘©π‘ͺ –y; βˆ π‘¨ – d; ntspg;Gw ,Urkntl;b MdJ BC-d; ePl;rpapid E-y; re;jpf;fpwJ. AB = 10 nr.kP> AC = 6 nr.kP kw;Wk; BC = 12 nr.kP vdpy;> CE-If; fhz;f. βˆ†ABC y; ∠𝐴 – d; ntspg;Gw ,Urkntl;b AE vd;f. NkYk; AE MdJ BC-d; ePl;rpia E-y; re;jpf;fpwJ. CE = π‘₯ vd;f. Nfhz ,Urkntl;bj; Njw;wg;gb>

DO O

1.

12+π‘₯ π‘₯

=

𝐡𝐸 𝐢𝐸 10 6

=

𝐴𝐡 𝐴𝐢

⟹

12+π‘₯ π‘₯

=

5 3

3(12 + π‘₯) = 5π‘₯ ⟹ 36 + 3π‘₯ = 5π‘₯ 36 = 5 π‘₯ βˆ’ 3π‘₯ 2 π‘₯ = 36 ⟹ π‘₯ = 18 / EC = 18 nr.kP

2.

glj;jpy; CD-d; msT fhz;f. EA Γ— EB = EC Γ— ED 8 Γ— 5 = (x + 4) Γ— 4

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(Apr-2015)

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8Γ—5 4

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=π‘₯+4

x + 4 = 10 x = 10 - 4 = 6 CD = 6 nr.kP 𝑨𝑫 𝑫𝑩

βˆ†ABC y; DE βˆ₯ BC and 𝐴𝐷 𝐷𝐡

=

𝐴𝐸 𝐸𝐢

2 3

=

3.7 𝐸𝐢

𝐸𝐢 =

3.7Γ—3 2

=

=

𝟐 πŸ‘

, AE = 3.7 nr.kP. vdpy;> EC-If; fhz;f. (Jun- 2012, Jun-2014)

ST UD Y

3.

11.2 2

= 5.55 nr.kP. 4.

D,E vd;w Gs;spfs; βˆ†ABCy; AB, AC fspy; DE βˆ₯ BC vd;wthW cs;sd. AD = 6 nr.kP> DB = 9 nr.kP kw;Wk; AE = 8 nr.kP> vdpy;> AC- If; fhz;f. Njy;]; Njw;wg;gb

𝐴𝐷 𝐷𝐡

=

𝐴𝐸 𝐸𝐢

6 9

=

8 𝐸𝐢

EC =

8Γ—9

= 12 nr.kP

6

AC = AE+EC=12 + 8 = 20 nr.kP

D,E vd;w Gs;spfs; βˆ†ABCy; AB, AC fspy; DE βˆ₯ BC vd;wthW cs;sd. AD = 8 nr.kP> AB = 12 nr.kP> kw;Wk; AE = 12 nr.kP> vdpy;> CE- If; fhz;f. Njy;]; Njw;wg;gb

𝐴𝐷 𝐷𝐡 8 4

= =

=

𝐴𝐸 𝐸𝐢 12

𝐸𝐢

12 Γ— 4 8

=

DO O

EC

ZY

5.

48 8

=6

CE = 6 nr.kP

6.

βˆ†ABC y; ∠A vd;w Nfhzj;jpd; cl;Gw ,Urkntl;b AD MdJ> gf;fk; BC I D-y; re;jpf;fpwJ. BD = 2.5 nr.kP> AB = 5 nr.kP. kw;Wk; AC = 4.2 nr.kP. vdpy; DC-If; fhz;f.

(Apr-2012, Oct-2012, 2013, June-2015)

Nfhz ,Urkntl;bj; Njw;wg;gb>

𝐡𝐷 𝐷𝐢 2.5 𝐷𝐢

=

𝐴𝐡 𝐴𝐢

=

5 4.2

DC =

2.5 Γ— 4.2 10.5 = 5 5

= 2.1

DC = 2.1 nr.kP

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7.

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βˆ†π‘·π‘Έπ‘Ή –d; gf;fq;fs; PQ kw;Wk; PR-fspd; kPJ mike;j Gs;spfs; S kw;Wk; T vd;f. NkYk; ST βˆ₯ QR, 𝑷𝑺 𝑺𝑸

PR = 5.6 nr.kP. kw;Wk;

=

πŸ‘ πŸ“

vdpy;> PT-If; fhz;f.

βˆ†PQR -y; PT = x vd;f. / TR = PR βˆ’ PT = 5.6 βˆ’ x 𝑃𝑆 𝑆𝑄

𝑃𝑇 𝑇𝑅

=

⟹ 𝑃𝑇 = 𝑇𝑅

x = (5.6 βˆ’ x)

𝑃𝑆 𝑆𝑄

3 5

5x = 16.8 – 3x 5x + 3x = 16.8 β‡’ 8π‘₯ = 16.8 x=

16.8 8

= 2.1

/ PT = 2.1 nr.kP 8.

𝑨𝑫 vd;gJ βˆ†π‘¨π‘©π‘ͺ -y; ∠A –d; cl;Gw Nfhz ,Urkntl;b. mJ BC-I D-y; re;jpf;fpwJ. BD = 2 nr.kP> AB = 5 nr.kP kw;Wk; DC = 3 nr.kP vdpy; AC-If; fhz;f. Nfhz ,Urkntl;bj; Njw;wg;gb> 2 3

=

5 𝐴𝐢

AC =

5Γ—3 2

=

𝐡𝐷 𝐷𝐢

15 = 7.5 2

AC = 7.5 nr.kP

=

𝐴𝐡 𝐴𝐢

AD vd;gJ βˆ†ABC –y; ∠A – d; cl;Gw Nfhz ,Urkntl;b. mJ BC I D-y; re;jpf;fpwJ. AB = 5.6 nr.kP> AC = 6 nr.kP kw;Wk; DC = 3 nr.kP. vdpy; BC-If; fhz;f.

ZY

9.

ST UD Y

NkYk; ST βˆ₯ QR Njy;]; Njw;wj;jpd;gb

Nfhz ,Urkntl;bj; Njw;wg;gb> 𝐡𝐷

=

5.6

5 5.6 Γ— 3 BD = = 2.8 6

=

𝐴𝐡 𝐴𝐢

DO O

3

𝐡𝐷 𝐷𝐢

BD = 2.8 nr.kP BC = 2.8 + 3 = 5.8 nr.kP

10.

glj;jpy; 𝒙-d; kjpg;igf; fhz;f. PA Γ— PB = PC Γ— PD 4Γ—x=8Γ—3 8Γ—3

x= = 4 x=6

11.

24 4

xU tl;lj;jpy; AB, CD vd;Dk; ,U ehz;fs; xd;iwnahd;W cl;Gwkhf P-apy; ntl;bf; nfhs;fpd;wd. CP = 4 nr.kP.> AP = 8 nr.kP.> PB = 2 nr.kP.> vdpy;> PD-If; fhz;f. (Apr-2014) PA Γ— PB = PC Γ— PD 8Γ—2=4Γ—x

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8Γ—2 = 4 16 =x 4

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x PD= 4 nr.kP

x=4

xU tl;lj;jpy; AB, CD vd;Dk; ,U ehz;fs; xd;iwnahd;W cl;Gwkhf nfhs;fpd;wd. AP= 12 nr.kP> AB = 15 nr.kP> CP = PD vdpy;> CD-If; fhz;f. PA Γ— PB = PC Γ— PD 12 Γ— 3 = x Γ— x 36 = x2 x=6 CD = 6+6 = 12 nr.kP

13.

glj;jpy; x –d; kjpg;igf; fhz;f. PA Γ— PB = PC Γ— PD 9 Γ— 4 = (π‘₯+2) Γ— 2 9Γ—4 = π‘₯+2 2 36 = x+2 2

π‘₯+2 = 18 π‘₯ = 18 βˆ’2= 16 π‘₯ = 16

AB kw;Wk; CD vd;w ,U ehz;fs; tl;lj;jpw;F ntspNa P vDk; Gs;spapy; ntl;bf; nfhs;fpd;wd. AB = 4 nr.kP> BP= 5 nr.kP kw;Wk; PD = 3 nr.kP vdpy;> CD-If; fhz;f. PA Γ— PB = PC Γ— PD 9 Γ— 5 = (π‘₯+3) Γ— 3 9Γ—5 3 45 3

= x+3

= x+3

DO O

π‘₯+3 = 15 π‘₯ = 15 – 3 = 12 CD = 12 nr.kP

15.

ntl;bf;

ZY

14.

P-apy;

ST UD Y

12.

AB kw;Wk; CD vd;w ,U ehz;fs; tl;lj;jpw;F ntspNa P vDk; Gs;spapy; ntl;bf; nfhs;fpd;wd. BP = 3 nr.kP> CP = 6 nr.kP kw;Wk; CD = 2 nr.kP> vdpy;> AB-If; fhz;f. PA Γ— PB = PC Γ— PD (π‘₯+ 3) Γ— 3 = 6 Γ— 4 6Γ—4 3

=

π‘₯+3 π‘₯ AB

=8 = 8 βˆ’ 3= 5 = 5 nr.kP

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=

24 3

π‘₯+3

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16.

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glj;jpy; TP xU njhLNfhL A,B vd;gd tl;lj;jpd; kPJs;s Gs;spfspy; ∠BTP = πŸ•πŸπŸŽ kw;Wk; ∠ATB = πŸ’πŸ‘ 𝟎 vdpy; ∠ABT If; fhz;f. (Apr-2013,Apr-2016)

17.

18.

ST UD Y

∠BAT = ∠BTP = 720 [njhLNfhL – ehz; Njw;wk; ] βˆ†ABT y; ∠ATB + ∠BAT + ∠ABT = 1800 430 + 720 + ∠ABT = 1800 ∠ABT = 1800 – 1150 = 650

xU tl;lj;jpd; Gs;sp A-y; tiuag;gLk; njhLNfhL PQ vd;f. AB vd;gJ tl;lj;jpd; ehz; vd;f. NkYk;> ∠BAC = πŸ“πŸ’πŸŽ kw;Wk; ∠BAQ = πŸ”πŸπŸŽ vd;W mikAkhW tl;lj;jpd; Nky; cs;s Gs;sp C vdpy;> ∠ABC - If; fhz;f. A-y; PQ xU njhLNfhL kw;Wk; AB xU ehz;. vdNt ∠BAQ = ∠ACB = 620 (njhLNfhL – ehz;Njw;wk;) NkYk;> ∠BAC + ∠ACB + ∠ABC = 1800 (xU Kf;Nfhzj;jpd; %d;W Nfhzq;fspd; $Ljy; 1800 ) ∠ABC = 1800 – (∠BAC + ∠ACB) = 1800 – (540 +620 ) = 640 ∠ABC = 640 gpjhfu]; Njw;wj;ij vOJf. (my;yJ) ngsjad; Njw;wj;ij vOJf. xU nrq;Nfhz Kf;Nfhzj;jpy; fh;zj;jpd; th;f;fk; kw;w ,U gf;fq;fspd; th;f;fq;fspd; $LjYf;Fr; rkk;. 𝑩π‘ͺ𝟐 = 𝑨𝑩 𝟐 + 𝑨π‘ͺ𝟐 gpjhfu]; Njw;wj;jpd; kWjiyia vOJf. xU Kf;Nfhzj;jpy;> xU gf;fj;jpd; th;f;fk;> kw;w ,U gf;fq;fspd; th;f;fq;fspd; $LjYf;Fr; rkk; vdpy;> Kjy; gf;fj;jpw;F vjpNu cs;s Nfhzk; nrq;Nfhzk; MFk;. 𝑩π‘ͺ𝟐 = 𝑨𝑩 𝟐 + 𝑨π‘ͺ𝟐

20.

njhLNfhL ehz;Njw;wj;ij vOJf. tl;lj;jpy; njhLNfhl;bd; njhL Gs;sp topNa xU ehz; tiuag;gl;lhy;> me;j ehz; njhLNfhl;Lld; Vw;gLj;Jk; Nfhzq;fs; KiwNa xt;nthd;Wk; jdpj;jdpahf khw;W tl;lj;Jz;Lfspy; mike;j Nfhzq;fSf;Fr; rkk;. βˆ π‘©π‘¨π‘» = βˆ π‘©π‘·π‘¨ , βˆ π‘©π‘¨π‘Ί = βˆ π‘¨π‘Έπ‘©

22.

DO O

21.

ZY

19.

njhLNfhL ehz; Njw;wj;jpd; kWjiyia vOJf. xU tl;lj;jpy; xU ehzpd; xU Kidg;Gs;sp topNa tiuag;gl;l Neh;f;NfhL me;ehZld; cz;lhf;Fk; NfhzkhdJ kW tl;lj; Jz;bYs;s Nfhzj;jpw;Fr; rkkhdhy;> me;Neh;f;NfhL tl;lj;jpw;F xU njhLNfhlhFk;. MP vd;gJ βˆ†MNO-y; ∠M-d; ntspg;Gw ,U rkntl;b> NkYk; NO-d; ePl;rpapid P -apy; re;jpf;fpwJ. MN=10 nr.kP> MO = 6 nr.kP NO = 12 nr.kP vdpy; OP If; fhz;f. (Jun-2013) MP vd;gJ βˆ†MNO-y; ∠M –d; ntspg;Gw ,U rkntl;b. βˆ†MNO –y; Nfhz ,Urkntl;b Njw;wj;jpd;gb

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𝑁𝑃 𝑂𝑃

=

𝑀𝑁 𝑀𝑂

12+𝑂𝑃 𝑂𝑃

=

𝑀𝑁 𝑀𝑂

12+𝑂𝑃 𝑂𝑃

=

10 6

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10 𝑂𝑃 βˆ’ 6 𝑂𝑃 = 72 4 𝑂𝑃 = 72 𝑂𝑃 =

72 4

= 18 nr.kP

ST UD Y

72 + 6 𝑂𝑃 = 10 𝑂𝑃

7. Kf;Nfhztpay; 1.

Rthpy; rha;j;J itf;fg;gl;l xU VzpahdJ jiuAld; πŸ”πŸŽ 𝟎 Nfhzj;ij Vw;gLj;JfpwJ. Vzpapd; mb Rtw;wpypUe;J 3.5 kP J}uj;jpy; cs;sJ. vdpy;> Vzpapd; ePsj;ijf; fhz;f.

(Oct-2012, Apr-2013, Jun-2014, Jun-2015)

nrq;Nfhzk; βˆ†ABC –y; 𝐡𝐢 𝐴𝐢 3.5 𝐴𝐢

cos 600 = 1 2

=

𝐴𝐢 = 3.5 Γ— 2 = 7 Vzpapd; ePsk; = 7kP

30 kP ePsKs;s xU fk;gj;jpd; epoypd; ePsk; 𝟏𝟎 πŸ‘ kP vdpy; #hpadpd; Vw;wf;Nfhzj;jpd; (jiu kl;lj;jpypUe;J Vw;wf;Nfhzk;) mstpidf; fhz;f. (Apr-2012, Apr-2014) nrq;Nfhz βˆ†ABC –y; 𝐴𝐡 π‘‘π‘Žπ‘›πœƒ = =

=

10 3 3Γ— 3 3

3

3

DO O

=

𝐡𝐢 30

ZY

2.

=

tan

3

600

= 3 / πœƒ = 600 #hpadpd; Vw;wf;Nfhzk; = 600

3.

xU Rik Ch;jpapypUe;J Rikia ,wf;f VJthf πŸ‘πŸŽπŸŽ Vw;wf; Nfhzj;jpy; xU rha;T jsk; cs;sJ. rha;T jsj;;jpd; cr;rp jiuapypUe;J 0.9 kP cauj;jpy; cs;sJ vdpy; rha;T jsj;jpd; ePsk; ahJ? (Oct-2014, Apr-2015) nrq;Nfhz βˆ†ABC –y; sin 300 = 1 2

=

𝐴𝐡 𝐴𝐢 0.9 𝐴𝐢

𝐴𝐢 = 0.9 Γ— 2 = 1.8 rha;T js ePsk; = 1.8 kP

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4.

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cauk; 150 nr.kP. cs;s xU rpWkp xU tpsf;Ff; fk;gj;jpd; Kd; epd;wthW πŸπŸ“πŸŽ πŸ‘ nr.kP. ePsKs;s epoiy Vw;gLj;Jfpwhs; vdpy; tpsf;Ff; fk;gj;jpd; cr;rpapd; Vw;wf;Nfhzk; fhz;f.

(Jun-12) 𝐴𝐡 𝐡𝐢 150 150 3 1 3 1 3 300

π‘‘π‘Žπ‘› πœƒ = = = tan 300 =

/πœƒ = Vw;wf;Nfhzk; = πŸ‘πŸŽπŸŽ 5.

πŸβˆ’π’”π’Šπ’πœ½ 𝟏+π’”π’Šπ’πœ½ 1βˆ’π‘ π‘–π‘›πœƒ 1+π‘ π‘–π‘›πœƒ

= π’”π’†π’„πœ½ βˆ’ π’•π’‚π’πœ½ vd epWTf. =

1βˆ’π‘ π‘–π‘›πœƒ 1+π‘ π‘–π‘›πœƒ

x

1βˆ’π‘ π‘–π‘›πœƒ 1βˆ’π‘ π‘–π‘›πœƒ

ST UD Y

nrq;Nfhz βˆ†ABC –y;

(Oct-2012, Jun-2014)

(1βˆ’π‘ π‘–π‘›πœƒ )2 1βˆ’π‘ π‘–π‘› 2 πœƒ

=

1

(1βˆ’π‘ π‘–π‘›πœƒ )2 = π‘π‘œ 𝑠 2 πœƒ 1 π‘ π‘–π‘›πœƒ βˆ’ = π‘π‘œπ‘ πœƒ π‘π‘œπ‘  πœƒ

= =

=

1βˆ’π‘ π‘–π‘› πœƒ π‘π‘œπ‘ πœƒ

π‘ π‘’π‘πœƒ βˆ’ π‘‘π‘Žπ‘›πœƒ vd epWtg;gl;lJ.

π’”π’†π’„πŸ 𝜽 + π’„π’π’”π’†π’„πŸ 𝜽 = 𝐭𝐚𝐧 𝜽 + 𝐜𝐨𝐭 𝜽 vd epWTf. 𝑠𝑒𝑐 2 πœƒ

+ π‘π‘œπ‘ π‘’π‘ 2 πœƒ

=

1

+ π‘‘π‘Žπ‘› 2 πœƒ

π‘‘π‘Žπ‘›2 πœƒ

+1+

(Apr-2014, 2015)

π‘π‘œπ‘‘ 2 πœƒ

+ π‘π‘œπ‘‘ 2 πœƒ + 2

ZY

6.

1βˆ’π‘ π‘–π‘› πœƒ 2 2 π‘π‘œπ‘ πœƒ

=

= π‘‘π‘Žπ‘›2 πœƒ + π‘π‘œπ‘‘ 2 πœƒ + 2π‘‘π‘Žπ‘›πœƒ. π‘π‘œπ‘‘πœƒ = = π‘‘π‘Žπ‘› πœƒ + π‘π‘œπ‘‘ πœƒ vd epWtg;gl;lJ.

π’”π’Šπ’πœ½ π’„π’π’”π’†π’„πœ½ π‘ π‘–π‘›πœƒ π‘π‘œπ‘ π‘’π‘πœƒ

+

π’„π’π’”πœ½ = 𝟏 vd;gij epWTf. π’”π’†π’„πœ½ π‘π‘œπ‘ πœƒ π‘ π‘–π‘›πœƒ π‘π‘œπ‘ πœƒ + = 1 + 1 π‘ π‘’π‘πœƒ

DO O

7.

(π‘‘π‘Žπ‘›πœƒ + π‘π‘œπ‘‘πœƒ)2

π‘ π‘–π‘›πœƒ

(Jun- 2012, Oct-2014)

π‘π‘œπ‘ πœƒ

= π‘ π‘–π‘›πœƒ Γ— π‘ π‘–π‘›πœƒ + ( π‘π‘œπ‘ πœƒ Γ— π‘π‘œπ‘ πœƒ) = 𝑠𝑖𝑛2 πœƒ + π‘π‘œπ‘ 2 πœƒ

= 1

8.

π’„π’π’”πœ½ = 𝟏 π’”π’†π’„πœ½βˆ’π’•π’‚π’πœ½ π‘π‘œπ‘ πœƒ π‘ π‘’π‘πœƒ βˆ’π‘‘π‘Žπ‘›πœƒ

vd epWtg;gl;lJ.

+ 𝐬𝐒𝐧𝜽 vd;w Kw;nwhUikia epWTf. = =

π‘π‘œπ‘ πœƒ π‘ π‘’π‘πœƒ +π‘‘π‘Žπ‘›πœƒ Γ— π‘ π‘’π‘πœƒ βˆ’π‘‘π‘Žπ‘›πœƒ π‘ π‘’π‘πœƒ +π‘‘π‘Žπ‘›πœƒ π‘π‘œπ‘ πœƒ (π‘ π‘’π‘πœƒ +π‘‘π‘Žπ‘›πœƒ ) = π‘π‘œπ‘ πœƒ 𝑠𝑒𝑐 2 πœƒβˆ’π‘‘π‘Žπ‘› 2 πœƒ

(Jun-2013) 𝑠𝑒𝑐 2 πœƒ – π‘‘π‘Žπ‘›2 πœƒ = 1

Γ—

1 π‘π‘œπ‘ πœƒ

+ π‘π‘œπ‘ πœƒ Γ—

π‘ π‘–π‘›πœƒ π‘π‘œπ‘ πœƒ

= 1+ sinπœƒ vd epWtg;gl;lJ.

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9.

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𝟏 πŸβˆ’π’”π’Šπ’πŸ 𝜽 βˆ’ = 𝟏 vd epWTf. 𝟐 π’”π’Šπ’ 𝜽 πŸβˆ’π’„π’π’”πŸ 𝜽 2 2 1 1βˆ’π‘ π‘–π‘› πœƒ 2 πœƒ βˆ’ π‘π‘œπ‘  πœƒ βˆ’ = π‘π‘œπ‘ π‘’π‘ 𝑠𝑖𝑛 2 πœƒ 1βˆ’π‘π‘œπ‘  2 πœƒ 𝑠𝑖𝑛 2 πœƒ

(Apr-2013) π‘π‘œπ‘ π‘’π‘ 2 πœƒ – π‘π‘œπ‘‘ 2 πœƒ = 1.

= cosec2 πœƒ βˆ’ cot2 πœƒ = 1 vd epWtg;gl;lJ.

11.

(π’”π’Šπ’πŸ” 𝜽 + π’„π’π’”πŸ” 𝜽) = 𝟏 βˆ’ πŸ‘π’”π’Šπ’πŸ 𝜽 π’„π’π’”πŸ 𝜽 vd epWTf. 𝑠𝑖𝑛6 πœƒ + π‘π‘œπ‘  6 πœƒ = (𝑠𝑖𝑛2 πœƒ)3 + (π‘π‘œπ‘  2 πœƒ)3 (π‘Ž = 𝑠𝑖𝑛2 πœƒ, 𝑏 = π‘π‘œπ‘  2 πœƒ ) = (𝑠𝑖𝑛2 πœƒ + π‘π‘œπ‘  2 πœƒ)3 – 3 𝑠𝑖𝑛2 πœƒ π‘π‘œπ‘  2 πœƒ (𝑠𝑖𝑛2 πœƒ + π‘π‘œπ‘  2 πœƒ) = 1 βˆ’ 3𝑠𝑖𝑛2 πœƒ π‘π‘œπ‘  2 πœƒ vd epWtg;gl;lJ. 𝟏+π’”π’†π’„πœ½ π’”π’†π’„πœ½

=

1+π‘ π‘’π‘πœƒ π‘ π‘’π‘πœƒ

π’”π’Šπ’πŸ 𝜽 πŸβˆ’π’„π’π’”πœ½ 1 1+π‘π‘œπ‘ πœƒ

=

vd epWTf.

1 π‘π‘œπ‘ πœƒ

=

π‘π‘œπ‘ πœƒ +1 π‘π‘œπ‘ πœƒ

= (1 + π‘π‘œπ‘  πœƒ) Γ— = =

+ = (π‘Ž + 𝑏)3 – 3π‘Žπ‘(π‘Ž + 𝑏) 𝑠𝑖𝑛2 πœƒ + π‘π‘œπ‘ 2 πœƒ = 1

π‘π‘œπ‘ πœƒ

Γ—

1

(1βˆ’π‘π‘œπ‘ πœƒ ) (1βˆ’π‘π‘œπ‘ πœƒ ) (1βˆ’π‘π‘œπ‘ πœƒ ) (1βˆ’π‘π‘œπ‘ πœƒ )

1βˆ’π‘π‘œπ‘  2 πœƒ 1βˆ’π‘π‘œπ‘ πœƒ 𝑠𝑖𝑛 2 πœƒ 1βˆ’π‘π‘œπ‘ πœƒ

200 kP ePsKs;s E}ypdhy; xU fhw;whb fl;lg;gl;L gwe;Jf; nfhz;bUf;fpwJ. me;j E}y; jiukl;lj;Jld; πŸ‘πŸŽπŸŽ Nfhzj;ij Vw;gLj;jpdhy;> fhw;whb jiukl;lj;jpypUe;J vt;tsT cauj;jpy; gwf;fpwJ. vdf; fhz;f. (,q;F E}y; xU Neh;f;Nfhl;by; cs;sjhff; fUJf). glj;jpy; C vd;gJ fhw;whb vd;f. jiukl;lj;jpypUe;J fhw;whbf;F cs;s J}uk; BC = h vd;f. E}ypd; ePsk; AC = 200 kP

ZY

12.

𝑏3

(Oct-2013, Apr-2016)

= 1 + π‘π‘œπ‘  πœƒ = (1 + π‘π‘œπ‘  πœƒ) Γ—

(Apr-2012) π‘Ž3

ST UD Y

10.

nrq;Nfhz βˆ†ABC y; sin 300 = 1 2

DO O

=

β„Ž=

𝐡𝐢 𝐴𝐢 β„Ž 200 200 2

= 100

jiukl;lj;jpypUe;J fhw;whbf;F cs;s J}uk; BC = h = 100 kP

13.

πŸβˆ’π’„π’π’”πœ½ 𝟏+π’„π’π’”πœ½

= π’„π’π’”π’†π’„πœ½ βˆ’ π’„π’π’•πœ½ vd epWTf. 1βˆ’π‘π‘œπ‘ πœƒ 1+π‘π‘œπ‘ πœƒ

=

1βˆ’π‘π‘œπ‘ πœƒ 1+π‘π‘œπ‘ πœƒ

=

(1βˆ’π‘π‘œπ‘ πœƒ )2 𝑠𝑖𝑛 2 πœƒ

Γ—

1βˆ’π‘π‘œπ‘ πœƒ 1βˆ’π‘π‘œπ‘ πœƒ

=

(1βˆ’π‘π‘œπ‘ πœƒ )2 1βˆ’π‘π‘œ 𝑠 2 πœƒ

1 βˆ’ π‘π‘œπ‘  2 πœƒ = 𝑠𝑖𝑛2 πœƒ

1

=

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1βˆ’π‘π‘œπ‘  πœƒ 2 2 π‘ π‘–π‘›πœƒ

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= = 14.

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1βˆ’π‘π‘œπ‘  πœƒ π‘ π‘–π‘›πœƒ 1 π‘π‘œπ‘ πœƒ – π‘ π‘–π‘›πœƒ π‘ π‘–π‘›πœƒ

= π‘π‘œπ‘ π‘’π‘πœƒ βˆ’ π‘π‘œπ‘‘πœƒ xU βˆ†π‘¨π‘©π‘ͺ –apy; nrq;Nfhzk; β€˜C’-apy; mikag;ngw;why; 𝐜𝐨𝐬(𝑨 + 𝑩)kw;Wk; 𝐬𝐒𝐧 (𝑨 + 𝑩) d; kjpg;Gfisf; fhz;f (Apr-2016)

ST UD Y

xU Kf;Nfhzj;jpd; midj;J Nfhzq;fspd; $Ljy; 1800 C = 900 , vdNt> 𝐴 + 𝐡 = 900 cos(𝐴 + 𝐡) = cos 900 = 0 sin (𝐴 + 𝐡) = sin 900 = 1 15.

5 mb cauKs;s xU rpWtd; xU J}zpypUe;J 100 mb J}uj;jpy; epd;W mjd; cr;rpia πŸ’πŸ“πŸŽ Vw;wf; Nfhzj;jpy; ghh;j;jhy; J}zpd; cauk; vd;d? (Jun-2013) glj;jpy; AB =rpWtd; = 5 mb BC = rpWtDf;Fk; J}zpw;Fk; ,ilNaahd J}uk; = 100 mb J}zpd; cauk; = CE = CD + DE = 5 + DE nrq;Nfhz βˆ†ADE-y; π‘‘π‘Žπ‘›450 =

𝐷𝐸 𝐴𝐷

=

𝐷𝐸 100

(CD = AB = 5 mb) π‘‘π‘Žπ‘›450 = 1

=1

/ 𝐷𝐸 = 100

/ J}zpd; cauk; 𝐢𝐸 = 5 + 100 = 105 mb

𝜽 xU FWq;Nfhzk; kw;Wk; π’”π’Šπ’πœ½ = π’„π’π’”πœ½ vdpy; π’•π’‚π’πŸ 𝜽 βˆ’ πŸπ’„π’π’”πŸ 𝜽 = 𝟎 vd ep&gpf;f. (Oct-2013) πœƒ xU FWq;Nfhzk; kw;Wk; π‘ π‘–π‘›πœƒ = cos πœƒ vdpy; πœƒ = 45Β° LHS π‘‘π‘Žπ‘›2 πœƒ βˆ’ 2π‘π‘œπ‘  2 πœƒ = π‘‘π‘Žπ‘›2 45Β° βˆ’ 2π‘π‘œπ‘  2 45Β°

ZY

16.

= 12 βˆ’ 2

1

2

2 1

1.

2.

DO O

=1βˆ’ 2Γ— 2 = 1 βˆ’ 1= 0 RHS = 0 vd ep&gpf;fg;gl;lJ.

8. mstpay;

xU jpz;k Neh;tl;l cUisapd; Muk; 7 nr.kP. kw;Wk; cauk; 20 nr.kP vdpy; mjd; tisgug;G> nkhj;j Gwg;gug;G Mfpatw;iwf; fhz;f. jpz;k Neh;tl;l cUis: r = 7 nr.kP. h = 20 nr.kP. tisgug;G = 2πœ‹π‘Ÿβ„Ž r.m nkhj;j Gwg;gug;G = 2πœ‹π‘Ÿ(β„Ž + π‘Ÿ) r.m 22 22 = 2 Γ— Γ— 7 Γ— 20 = 2 Γ— Γ— 7 (20 + 7) 7 7 = 880 r.nr.kP = 1188 r.nr.kP xU jpz;k Neh;tl;l cUisapd; Muk; 14 nr.kP. kw;Wk; cauk; 8 nr.kP. vdpy; mjd; tisgug;G> nkhj;j Gwg;gug;G Mfpatw;iwf; fhz;f. (Apr-2014) jpz;k Neh;tl;l cUis: r =14 nr.kP h = 8 nr.kP

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tisgug;G = 2πœ‹π‘Ÿβ„Ž r.m 22 = 2 Γ— Γ— 14 Γ— 8 7

nkhj;j Gwg;gug;G = 2πœ‹π‘Ÿ(β„Ž + π‘Ÿ) r.m 22 = 2 Γ— Γ— 14 (8 + 14) 7

= 704 r.nr.kP

= 1936 r.nr.kP

,U Neh;tl;l cUisfspd; Muq;fspd; tpfpjk; 3 : 2 vd;f. NkYk; cauq;fspd; tpfpjk; 5 : 3 vdpy; tisgug;Gfspd; tpfpjk; fhz;f. (June-2015) Neh;tl;l cUis: π‘Ÿ1 ∢ π‘Ÿ2 = 3 ∢ 2, β„Ž1 ∢ β„Ž2 = 5 ∢ 3 tisgug;Gfspd; tpfpjk; = 2πœ‹π‘Ÿ1 β„Ž1 : 2πœ‹π‘Ÿ2 β„Ž2 = 3 Γ— 5 : (2 Γ— 3) = 5 : 2

4.

xU jpz;k cUisapd; Muk; 14 nr.kP. mjd; cauk; 30 nr.kP. vdpy; cUisapd; fd msitf; fhz;f. (Oct-2012) jpz;k cUis: r =14 nr.kP h=30 nr.kP fd msT = πœ‹π‘Ÿ 2 β„Ž f.m =

22 7

Γ— 14 Γ— 14 Γ— 30

=18480 f.nr.kP.

ST UD Y

3.

,U Neh;tl;l cUisfspd; Muq;fspd; tpfpjk; 2 : 3 vd;f. NkYk; cauq;fspd; tpfpjk; 5 : 3 vdpy; fdmsTfspd;; tpfpjk; fhz;f. Neh;tl;l cUis: π‘Ÿ1 ∢ π‘Ÿ2 = 2 ∢ 3, β„Ž1 ∢ β„Ž2 = 5 ∢ 3 2 fdmsTfspd;; tpfpjk; = πœ‹π‘Ÿ1 β„Ž1 : πœ‹π‘Ÿ22 β„Ž2 = 2 Γ— 2 Γ— 5 : (3 Γ— 3 Γ— 3) = 20 : 27

6.

xU jpz;k Neh;tl;lf; $k;gpd; Muk; kw;Wk; rhAauk; KiwNa 35 nr.kP. kw;Wk; 37 nr.kP. vdpy; mjd; tisgug;G kw;Wk; nkhj;jg; gug;Gf; fhz;f. jpz;k Neh;tl;lf; $k;G: r = 35 nr.kP 𝑙 = 37 nr.kP tisgug;G = πœ‹π‘Ÿ 𝑙 r.m 22 7

Γ— 35 Γ— 37

DO O

=

ZY

5.

= 4070 r.nr.kP nkhj;jGwg;gug;G = πœ‹π‘Ÿ (𝑙 + π‘Ÿ) r.m = =

7.

22 7 22 7

Γ— 35 (37 + 35)

Γ— 35 Γ— 72

= 7920 r.nr.kP xU jpz;k Neh;tl;lf; $k;gpd; mbr;Rw;wsT 236 nr.kP. mjd; rhAauk; 12 nr.kP. vdpy; mjd; tisgug;Gf; fhz;f. (Apr-2013, Jun-2013) jpz;k Neh;tl;lf; $k;G: l =12 nr.kP 2πœ‹π‘Ÿ = 236 πœ‹r =

236 2

= 118

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tisgug;G = πœ‹ π‘Ÿπ‘™ r.m = 118 Γ— 12 = 1416 r.nr.kP xU jpz;k Neh;tl;lf; $k;gpd; Muk; kw;Wk; cauk; KiwNa 7 nr.kP. kw;Wk; 24 nr.kP. vdpy; mjd; tisgug;G kw;Wk; nkhj;jg; gug;Gf; fhz;f. (Jun-12) jpz;k Neh;tl;lf; $k;G: r =7 nr.kP h= 24 nr.kP 𝑙

π‘Ÿ2 + β„Ž2

=

= 72 + 242 = 49 + 576 = = 25 nr.kP tisgug;G

625

= πœ‹π‘Ÿπ‘™ r.m =

22 7

Γ— 7 Γ— 25

=550 r.nr.kP nkhj;j Gwg;gug;G = πœ‹π‘Ÿ(𝑙 + π‘Ÿ) r.m = 9.

22 7

ST UD Y

8.

Γ— 7 Γ— (25 + 7) =704 r.nr.kP

kuj;jpyhd xU jpz;kf; $k;gpd; mbr;Rw;wsT 44 nr.kP. mjd; cauk; 12 nr.kP. vdpy; mjd; fd msT fhz;f. (Oct-2013) jpz;kf; $k;G: h =12 nr.kP 2πœ‹r = 44 nr.kP 2 Γ—

22 7

Γ— π‘Ÿ = 44 π‘Ÿ = 44 Γ—

1 2

Γ—

7 22

fd msT

= 616 f.nr.kP

Γ— 7 Γ— 12

xU jpz;kf; $k;gpd; Muk; kw;Wk; rhAauk; KiwNa 20 nr.kP. kw;Wk; 29 nr.kP. vdpy; mjd; fd msitf; fhz;f. (Apr-2012). jpz;kf; $k;G: r = 20 nr.kP l = 29 nr.kP

DO O

10.

ZY

r = 7 nr.kP 1 = πœ‹π‘Ÿ 2 β„Ž f.m 3 1 22 = Γ— Γ— 7 3 7

h = 𝑙2 βˆ’ π‘Ÿ 2 = 292 βˆ’ 202 = 841 βˆ’ 400 = 441 = 21 h = 21 nr.kP

fd msT =

=

1 πœ‹π‘Ÿ 2 β„Ž f.m 3 1 22 Γ— Γ— 20 3 7

Γ— 20 Γ— 21

= 8800 f.nr.kP

11.

Xh; miuf;Nfhsj;jpd; fd msT 1152 𝝅 f.nr.kP. vdpy; mjd; tisg;gug;igf; fhz;f. miuf;Nfhsj;jpd; fd msT = 1152 πœ‹ f.nr.kP. 2 3

πœ‹r 3 = 1152 πœ‹

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π‘Ÿ 3 = 1152 Γ—

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3 2

π‘Ÿ 3 = 1728 r = 12 nr.kP tisgug;G = 2πœ‹π‘Ÿ 2 r.m = 2 Γ— πœ‹ Γ— 12 Γ— 12 = 288 πœ‹ r.nr.kP

2 Γ—

22 7

Γ— 12 Γ— (β„Ž + 7) = 660 (β„Ž + 7) = 660 Γ—

1 2

Γ—

7 22

β„Ž + 7 = 15 β„Ž = 15 βˆ’ 7 = 8 nr.kP h = 8 nr.kP tisg;gug;G = 2πœ‹π‘Ÿβ„Ž r.m 22 7

= 2 Γ—

ST UD Y

xU jpz;k Neh; tl;l cUisapd; nkhj;jg; Gwg;gug;G 660 r.nr.kP. mjd; mbg;gf;fj;jpd; tpl;lk; 14 nr.kP. vdpy;> mt;TUisapd; cauk;> tisg;gug;igf; fhz;f. (Oct-2012) jpz;k Neh; tl;l cUis: tpl;lk; = 14 nr.kP Muk; = 7 nr.kP nkhj;jg;gug;G = 660 r.nr.kP 2πœ‹π‘Ÿ (β„Ž + π‘Ÿ) = 660

12.

Γ— 7Γ— 8

= 352 r.nr.kP

Γ—

1 7

fd msTfspd; tpfpjk;

ZY

7 nr.kP. Muk; nfhz;l Nfhs tbt gY}dpy; fhw;W nrYj;jg;gLk; NghJ Muk; 14 nr.kP. Mf mjpfhpj;jhy;> mt;tpU epiyfspy; gY}dpd; fd msTfspd; tpfpjj;ijf; fhz;f. Nfhsk; : π‘Ÿ1 = 7 nr.kP π‘Ÿ2 = 14 nr.kP

13.

4 3

πœ‹r13 :

4 3

πœ‹r23

= 7 Γ— 7 Γ— 7 : 14 Γ— 14 Γ— 14 = 1: 8

DO O

14. 14nr.kP. gf;f msT nfhz;l xU fd rJuj;jpy; ,Ue;J ntl;br; vLf;fg;gLk; kpfg;nghpa $k;gpd; fd msT fhz;f. $k;gpd; tpl;lk; = 14 nr.kP Muk; (r) = 7 nr.kP cauk; (h) = 14 nr.kP fd msT

=

=

1

3 1 3

πœ‹π‘Ÿ 2 β„Ž f.m

Γ—

22 7

Γ— 7 Γ— 7 Γ— 14

= 718.67 f.nr.kP

15.

8.4 nr.kP tpl;lk; nfhz;l xU Nfhs tbt jpz;k cNyhf vwpf;Fz;bd; fd msitf; fhz;f.

(Apr-2013, Jun-2015)

Nfhsj;jpd; tpl;lk; = 8.4 nr.kP Muk; (r)

= 4.2 nr.kP =

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42 10

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4 πœ‹π‘Ÿ 3 f.m 3 4 22 42 = Γ— Γ— 3 7 10 38808 = 125

fd msT =

πœ‹π‘Ÿ 2 = 1386 miuf;Nfhsj;jpd; nkhj;jg;gug;G = 3πœ‹π‘Ÿ 2 = 3 Γ— 1386 = 4158 r.nr.kP. ,U jpz;k miuf;Nfhsq;fspd; Muq;fs; 3:5 vd;w tpfpjj;jpy; cs;sd. mtw;wpd; tisgug;Gfspd; tpfpjk; kw;Wk; nkhj;jg; gug;Gfspd; tpfpjk; fhz;f. jpz;k miuf;Nfhsk;: π‘Ÿ1 : π‘Ÿ2 = 3 ∢ 5 2 tisgug;Gfspd; tpfpjk; = 2πœ‹π‘Ÿ1 ∢ 2πœ‹π‘Ÿ22 = 3 Γ— 3 : ( 5 Γ— 5) = 9 ∢ 25 nkhj;jg; gug;Gfspd; tpfpjk; = 3πœ‹π‘Ÿ12 : 3πœ‹π‘Ÿ22 = 3 Γ— 3 : (5 Γ— 5 ) = 9 ∢ 25 98.56 r.nr.kP. Gwg;gug;G nfhz;l xU jpz;kf; Nfhsj;jpd; Muj;ijf; fhz;f. (Oct-2013) jpz;kf; Nfhsk;: Gwg;gug;G = 98.56 r.nr.kP. 4πœ‹π‘Ÿ 2 = 98.56 4 Γ—

22 7

Γ— π‘Ÿ 2 = 98.56

π‘Ÿ 2 = 98.56 Γ—

1 4

Γ—

7 22

π‘Ÿ 2 = 7.84 Muk; r = 2.8 nr.kP 19.

2772 2

ZY

18.

42 10

fd msT = 310.464 f.nr.kP xU jpz;k miuf;Nfhsj;jpd; tisgug;G 2772 r.nr.kP. vdpy; mjd; nkhj;jg; gug;igf; fhz;f. miuf;Nfhsj;jpd; tisgug;G = 2πœ‹π‘Ÿ 2 = 2772 r.nr.kP. πœ‹π‘Ÿ 2 =

17.

Γ—

ST UD Y

16.

42 10

Γ—

xU jpz;k miuf;Nfhsj;jpd; nkhj;jg;gug;G πŸ”πŸ•πŸ“π… r.nr.kP. vdpy; mjd; tisg;gug;igf; fhz;f. miuf;Nfhsj;jpd; nkhj;jg;gug;G

DO O

= 675πœ‹ 675πœ‹ πœ‹r 2 = = 225πœ‹ 3 tisg;gug;G = 2πœ‹π‘Ÿ 2 = 225πœ‹ Γ— 2 = 450πœ‹ r.nr.kP

20.

=

(Jun-2014)

3πœ‹π‘Ÿ 2

xU cs;sl P w;w cUisapd; cs; kw;Wk; ntsp Muq;fs; KiwNa 12 nr.kP. kw;Wk; 18 nr.kP. NkYk; mjd; cauk; 14 nr.kP. vdpy; mjd; tisgug;G kw;Wk; nkhj;jg;gug;G fhz;f. (Apr-2012) cs;sl P w;w cUis: r = 12 nr.kP R= 18 nr.kP h=14 nr.kP tisgug;G = 2πœ‹β„Ž (𝑅 + π‘Ÿ) r.m nkhj;jg;gug;G = 2πœ‹(𝑅 + π‘Ÿ) (𝑅 βˆ’ π‘Ÿ + β„Ž) r.m = 2Γ—

22 7

Γ— (18 + 2)(18 βˆ’ 12 + 14)

= 2 Γ— 22 Γ— 2 Γ— 30

= 2Γ—

22 7

Γ— 30 Γ— 20

= 2640 r.nr.kP

= 3771.43 r.nr.kP

= 2Γ—

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22 7

Γ— 14 Γ— (18 + 12)

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21.

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14 kP. MoKs;s xU fpzw;wpd; Muk; 5 kP. xU rJu kPl;lUf;F &.2 tPjk; mf;fpzw;wpd; cl;Gwr; Rtw;wpw;F rpnkz;l; G+r MFk; nrytpidf; fhz;f. (Oct-2014) cUis : r = 5 kP h=14 kP fpzw;wpd; cl;Gwg; gug;G (cUisapd; tisgug;G)

= 2πœ‹π‘Ÿβ„Ž = 2 Γ—

22 7

Γ— 5 Γ— 14

= 2 Γ— 22 Γ— 5 Γ— 2 = 440 r.kP = &.2 = &. 440 Γ— 2 = &.880

ST UD Y

xU rJu kPl;lUf;F rpnkz;l; G+r MFk; nryT 440 rJu kPl;lUf;F rpnkz;l; G+r MFk; nryT

22. KiwNa 3 nr.kP. kw;Wk; 4 nr.kP. Muq;fshff; nfhz;l ,U Nfhsq;fspd; fd msTfspd; tpfpjj;jpidf; fhz;f. (Jun-2012) Nfhsk; : R = 4 nr.kP r = 3 nr.kP ,U Nfhsq;fspd; fd msTfspd; tpfpjk; =

4 πœ‹π‘… 3 3 𝑅3 : π‘Ÿ3

∢

4 3

πœ‹π‘Ÿ 3

= = 43 : 33 = 64: 27

62.37 f.nr.kP. fd msT nfhz;l xU jpz;k Neh;tl;l cUisapd; cauk; 4.5 nr.kP. vdpy; mt;TUisapd; Muj;ijf; fhz;f. (Jun-2013) cUisapd; cauk; h = 4.5 nr.kP fd msT V = 62.37 f.nr.kP. Muk; r =? fd msT 𝑉 = πœ‹π‘Ÿ 2 β„Ž = 62.37 f.nr.kP 22 7

π‘Ÿ2 =

Γ— r 2 Γ— 4.5 = 62.37 62.37 Γ— 7 22 Γ— 4.5

π‘Ÿ= Muk; r

4.41 = 2.1 nr.kP = 2.1 nr.kP

miuf;Nfhs tbt fpz;zj;jpd; jbkd; 0.25 nr.kP kw;Wk; mjd; cl;Gw Muk; 5 nr.kP vdpy; mf;fpz;zj;jpd; ntspg;Gw tisgug;igf; fhz;f. (Apr-2015) miuf;Nfhsk;: cl;Gw Muk; r = 5 nr.kP jbkd; w = 0.25 nr.kP ∴ ntspg;Gw Muk; R = 5+ 0.25 = 5.25 nr.kP

DO O

24.

ntspg;Gw

25.

= 4.41

ZY

23.

tisgug;G = 2πœ‹π‘… 2 = 2 Γ—

22 7

Γ— 5.25 Γ— 5.25

= 173.25 r.nr.kP

xU cs;sl P w;w Nfhsj;jpd; ntsp kw;Wk; cs; Muq;fs; KiwNa 12 nr.kP. kw;Wk; 10 nr.kP. vdpy; mf;Nfhsj;jpd; fd msitf; fhz;f. cs;sl P w;w Nfhsk;: ntspg;Gw Muk; R = 12 nr.kP cl;Gw Muk;

r = 10 nr.kP

cs;sl P w;w Nfhsj;jpd; fd msT

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𝑉 =

4 3

πœ‹ (𝑅 3 βˆ’ π‘Ÿ 3 ) =

4 3

Γ—

22 7

(123 βˆ’ 103 )

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88 21

=

88 21

1728 βˆ’ 1000 Γ— 728

= 3050

xU jpz;k Neh;tl;lf; $k;gpd; fd msT 4928 f.nr.kP. kw;Wk; mjd; cauk; 24 nr.kP vdpy; mf;$k;gpd; Muj;ijf; fhz;f. $k;gpd; fd msT = 4928 nr.kP kw;Wk; cauk; h = 24 nr.kP 1 3

Γ—

22 7

π‘Ÿ2 = π‘Ÿ = 27.

Γ—

1 πœ‹r 2 h = 3 r 2 Γ— 24 =

4928 Γ— 3Γ— 7 22Γ— 24

4928 4928

= 196

196 =14 nr.kP

xU Neh; tl;lf; $k;gpd; fd msT πŸπŸπŸ” 𝝅 cauj;ijf; fhz;f. $k;gpd; Muk; r = 9 nr.kP $k;gpd; fd msT = 216 πœ‹ f.nr.kP $k;gpd; fd msT = 1 3

1 3

Γ— πœ‹ Γ— 92Γ— β„Ž

πœ‹π‘Ÿ 2 β„Ž = 216 πœ‹ = 216 πœ‹

β„Ž=

216 Γ— 3 9Γ—9

= 8 nr.kP

7 kP cs;tpl;lKs;s xU Nfhsj;jpDs; xU rh;f;f]; tPuh; Nkhl;lhh; irf;fpspy; rhfrk; nra;fpwhh;. me;j rhfr tPuh; rhfrk; nra;af; fpilj;jpLk; cs;sl P w;wf; Nfhsj;jpd; cl;Gwg;gug;igf; fhz;f. cs;sl P w;w Nfhsj;jpd; cs; tpl;lk; 2r = 7kP Nkhl;lhh; irf;fps; tPuh;> rhfrk; nra;af; fpilj;jpLk; gug;G = Nfhsj;jpd; cl;Gw tisg;gug;G = 4 πœ‹π‘Ÿ 2 = πœ‹(2π‘Ÿ)2 =

1 3

30.

22 7

Γ— 72 =

22 7

Γ— 7 Γ— 7 = 154 nr.kP2

xU $k;G> xU miuf;Nfhsk; kw;Wk; xU cUis Mfpad rk mbg;gug;gpidf; nfhz;Ls;sd. $k;gpd; cauk;> cUisapd; cauj;jpw;F rkkhfTk;> NkYk; ,t;Tauk;> mtw;wpd; Muj;jpw;F rkkhfTk; ,Ue;jhy; ,k;%d;wpd; fd msTfSf;fpilNa cs;s tpfpjj;ijf; fhz;f. $k;G> miuf;Nfhsk;> cUis Mfpatw;wpd; nghJthd Muk; r vd;f. $k;G> cUis Mfpatw;wpd; nghJthd cauk; h vd;f. fzf;fpd;gb r = h $k;G> miuf;Nfhsk;> cUis Mfpatw;wpd; fd msTfspd; tpfpjk;

DO O

29.

f.nr.kP kw;Wk; mf;$k;gpd; Muk; 9 nr.kP vdpy;> mjd;

ZY

28.

f.nr.kP

ST UD Y

26.

2 3

πœ‹r 2 h:

2 3

πœ‹r 3 : πœ‹r 2 h =

1 3

∢

2 3

∢1

[r = h]

=1:2:3 4.2 kP tpl;lKs;s miuf;Nfhs tbtj; njhl;bapy; epug;gg;gLk; ePhpd; fd msitf; fhz;f.

(Apr-2014)

miuf;Nfhs tbtj; njhl;bapd; tpl;lk; d= 4.2 kP

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Muk; r = 2.1 m 2 3 2 3

miuf;Nfhs tbtj; njhl;bapd; fd msT = πœ‹π‘Ÿ 3 =

x

22 7

x 2.1 x 2.1 x 2.1

miuf;Nfhs tbtj; njhl;bapd; fd msT = 19.404 kP 3 = 19404 ypl;lh;

= 1000 ypl;lh;]

14 nr.kP. gf;f msT nfhz;l xU fdr; rJuj;jpypUe;J> kpfg;nghpa (kPg;ngU fd msTs;s) Nfhsk; ntl;b vLf;fg;gLfpwJ. vdpy;> mf;Nfhsj;jpd; fd msT fhz;f. (Jun- 2014) fdr;rJuj;jpd; gf;f msT = Nfhsj;jpd; tpl;lk; d= 14 nr.kP Nfhsj;jpd; Muk; r=7 nr.kP Nfhsj;jpd; fd msT

32.

3

=

4 πœ‹π‘Ÿ 3 3 4 22

ST UD Y

31.

[1kP

= Γ—

Γ— 7Γ— 7Γ— 7

=

1437 nr.kP

3 7 4312 = 3

1 3

21 nr.kP MuKs;s xU tl;lj;jpypUe;J 𝟏𝟐𝟎𝟎 ikaf;Nfhzk; nfhz;l xU tl;lf; Nfhzg;gFjpia ntl;bnaLj;J> mjd; Muq;fis xd;wpizj;J xU $k;ghf;fpdhy;> fpilf;Fk; $k;gpd; tisgug;igf; fhz;f. (Oct-2014) tl;lf; Nfhzg;gFjpapd; Muk; R = 21 nr.kP ikaf;Nfhzk; πœƒ = 1200 tpy;ypd; ePsk;

𝑙=

πœƒ 360 0

Γ— 2πœ‹π‘…

ZY

xU tl;lf; Nfhzg;gFjpapd; Muq;fis xd;wpizj;J xU $k;ghf;fpdhy;> $k;gpd; mbr;Rw;wsT = tl;lf; Nfhzg;gFjpapd; tpy;ypd; ePsk; 2πœ‹π‘Ÿ =

120 0 360 0

Γ— 2πœ‹ Γ— 21 7

DO O

3 π‘Ÿ = 7 nr.kP $k;gpd; rhAauk; 𝑙 = tl;lf; Nfhzg;gFjpapd; Muk; $k;gpd; tisgug;G

= 21 nr.kP = πœ‹π‘Ÿπ‘™ =

22 7

Γ— 7 Γ— 21 = 462 nr.kP2

khw;W Kiw: $k;gpd; tisgug;G = tl;lf; Nfhzg;gFjpapd; gug;G πœƒ = Γ— πœ‹π‘… 2 360 0 7 =

120 0 360 0

Γ—

22 7

Γ— 21 Γ— 21 = 462 nr.kP2

3

33.

24 nr.kP cauKila xU $k;gpd; mbg;gug;G 550 nr.kP2 vdpy; mjd; fd msT ahJ? (Oct-15) $k;gpd; cauk; h = 24 nr.kP 2 mjd; mbg;gug;G πœ‹π‘Ÿ = 550 nr.kP2

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$k;gpd; fd msT

https://doozystudy.blogspot.in/

= = =

1 3 1 3 1 3

πœ‹π‘Ÿ 2 β„Ž Γ— πœ‹π‘Ÿ 2 Γ— β„Ž Γ— 550 Γ— 24

= 4400 nr.kP3 xU cUis tbt ,Uk;Gf; Fohapd; ntspg;Gw tpl;lk; 25 nr.kP mjd; ePsk; 20 nr.kP. kw;Wk; jbkd; 1 nr.kP. vdpy; mf;Fohapd; nkhj;jg;Gwg;gug;igf; fhz;f. (Oct-2015) cUis tbt ,Uk;Gf; Fohapd; ntspg;Gw tpl;lk; D = 25 nr.kP / ntspg;Gw Muk; R

= 12.5 nr.kP

mjd; jbkd;

= 1 nr.kP

w

/ cl;Gw Muk;

r =Rβˆ’w = 12.5 – 1 r = 11.5 nr.kP

ST UD Y

34.

cUis tbtf; Fohapd; ePsk; (cauk;) h Fohapd; nkhj;jg;Gwg;gug;G

= 20 nr.kP

= 2πœ‹ 𝑅 + π‘Ÿ (𝑅 βˆ’ π‘Ÿ + β„Ž) r.m

= 2πœ‹ 12.5 + 11.5 (12.5 βˆ’ 11.5 + 20) 22 x 7

24 x 21

ZY

=2x

= 3168 nr.kP2

35.

xU jpz;k Neh;tl;l cUisapd; tisgug;G kw;Wk; mbr;Rw;wsT KiwNa 4400 r.nr.kP. kw;Wk; 110 nr.kP vdpy; mt;TUisapd; cauj;ijAk;> tpl;lj;ijAk; fhz;f. (Apr-2016) cUisapd; tisgug;G = 4400r.nr.kP.

DO O

xU jpz;k Neh;tl;l cUisapd; 2Γ—

22 7

mbr;Rw;wsT 2πœ‹π‘Ÿ = 110 nr.kP

Γ— π‘Ÿ = 110

tpl;lk; 2π‘Ÿ =

110Γ—7 =35cm 22

tisgug;G 2πœ‹π‘Ÿβ„Ž = 110 Γ— β„Ž = 4400 vdNt> cUisapd; cauk; β„Ž =

36.

4400 110

= 40 nr.kP

πŸπŸ–πŸŽΒ° ikaf; NfhzKk; 21 nr.kP. MuKk; nfhz;l tl;lNfhz tbtpyhd ,Uk;Gj; jfl;bd; Muq;fis ,izj;J xU $k;G cUthf;fg;gLfpwJ vdp;y; mf;$k;gpd; Muj;ijf; fhz;f.

(Apr-2016)

180Β° ikaf; NfhzKk; 21 nr.kP. MuKk; nfhz;l tl;lNfhz tbtpyhd ,Uk;Gj; jfl;bd; Muq;fis ,izj;J xU $k;G cUthf;fg;gLfpwJ. R ;$k;gpd; Muk; vd;f.

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$k;gpd; mbr;Rw;wsT = tl;ltpy;ypd; ePsk; 2πœ‹π‘… = 𝑅=

πœƒ 360

180 360

Γ— 2πœ‹π‘Ÿ

Γ— 21 = 10.5 nr.kP.

43, 24, 38, 56, 22, 39, 45 Mfpa Gs;sp tptuq;fspd; tPr;R kw;Wk; tPr;Rf; nfO fhz;f. (Apr-2012, 2015) L = 56, S = 22 tPr;R = Lβˆ’S = 56 βˆ’22 = 34 tPr;Rf; nfO

2.

=

34 78

=

56βˆ’22 56+22 17 39

= 0.435

πΏβˆ’π‘† 𝐿+𝑆

=

50.5βˆ’42.4 50.5+42.4

=

8.1 92.9

=

81 929

= 0.0871

gpd;tUk; kjpg;GfSf;F tPr;R kw;Wk; tPr;Rf; nfO fhz;f. 59, 46, 30, 23, 27, 40, 52,35, 29.(Oct-2014) L = 59, S = 23 tPr;R = L βˆ’ S = 59 βˆ’ 23 = 36 πΏβˆ’π‘† 𝐿+𝑆 36 82

= =

59βˆ’23 59+23

18 41

= 0.4390

DO O

=

gpd;tUk; kjpg;GfSf;F tPr;R kw;Wk; tPr;Rf; nfO fhz;f. 41.2, 33.7, 29.1, 34.5, 25.7, 24.8, 56.5, 12.5. L= 56.5, S=12.5 tPr;R =L βˆ’ S = 56.5 βˆ’ 12.5 = 44 tPr;Rf; nfO =

5.

=

=

tPr;Rf; nfO =

4.

πΏβˆ’π‘† 𝐿+𝑆

xU tFg;gpYs;s 13 khzth;fspd; vil (fp.fp) gpd;tUkhW: 42.5, 47.5, 48.6, 50.5, 49, 46.2, 49.8, 45.8, 43.2, 48, 44.7, 46.9, 42.4. ,tw;wpd; tPr;R> tPr;Rf;nfO fhz;f. L= 50.5, S= 42.4 tPr;R = L βˆ’ S = 50.5 βˆ’ 42.4 = 8.1 tPr;Rf; nfO

3.

=

ZY

1.

ST UD Y

11. Gs;spapay;

πΏβˆ’π‘† 𝐿+𝑆

=

56.5βˆ’12.5 56.5+12.5

=

44 69

= 0.6376

xU Gs;sp tptuj;jpd; kPr;rpW kjpg;G 12. mjd; tPr;R 59 vdpy; mg;Gs;sp tptuj;jpd; kPg;ngU kjpg;igf; fhz;f. tPr;R = 59, S = 12 tPr;R = L βˆ’ S

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59 59+12 71 L

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= L βˆ’ 12 =L =L = 71

50 msTfspy; kpfg;nghpa kjpg;G 3.84 fp.fp. mjd; tPr;R 0.46 fp.fp. vdpy;> mitfspd; kPr;rpW kjpg;igf; fhz;f. (Apr-2013) L = 3.84, tPr;R = 0.46 tPr;R = L βˆ’ S 0.46 = 3.84 –S S = 3.84 – 0.46 S = 3.38 fp.fp.

7.

xU Gs;sp tptuj; njhFg;gpd; kPg;ngU kjpg;G 7.44 kw;Wk; tPr;R 2.26 vdpy;> mj;njhFg;gpd; kPr;rpW kjpg;igf; fhz;f. (Oct-2012) L = 7.44, tPr;R = 2.26 tPr;R = L βˆ’ S 2.26 = 7.44 –S S = 7.44 – 2.26 S = 5.18 fz;lwpe;j Gs;sp tptuj; njhFg;gpYs;s 20 kjpg;Gfspd; jpl;ltpyf;fk; πŸ“ vd;f. Gs;sp tptuj;jpd; xt;nthU kjpg;igAk; 2 My; ngUf;fpdhy; fpilf;Fk; Gjpa Gs;sp tptuq;fspd; jpl;ltpyf;fk; kw;Wk; tpyf;f th;f;fruhrhp fhz;f. jpl;ltpyf;fk; = 5

8.

ST UD Y

6.

Gjpa jpl;ltpyf;fk; tpyf;f th;f;fruhrhp

Kjy; 13 ,ay; vz;fspd; jpl;l tpyf;fj;ijf; fzf;fpLf. 𝑛 = 13 =

13 2 βˆ’1 12

=

169βˆ’1 12

=

168 12

=

(Oct-2013, Jun-2015) 14 = 3.7

Kjy; 10 ,ay; vz;fspd; jpl;l tpyf;fj;ijf; fzf;fpLf. 𝑛 = 10 jpl;ltpyf;fk; =

11.

𝑛 2 βˆ’1 12

DO O

jpl;ltpyf;fk; = 10.

ZY

9.

= 2 Γ— 5= 2 5 = (2 5)2 = 4 Γ— 5 = 20

𝑛 2 βˆ’1 12

=

10 2 βˆ’1 12

=

100βˆ’1 12

=

99 12

(Apr-2014, Jun-2014)

= 2.87

xU Gs;sp tptuj;jpd; khWghl;Lf; nfO 57 kw;Wk; jpl;ltpyf;fk; 6.84 vdpy; mjd;; $l;;Lruhrhp fhz;f. (Jun-2012, Jun-2013, Apr-2016) C.V. = 57, 𝜎 = 6.84

𝐢. 𝑉. = 57 = π‘₯ =

𝜎 π‘₯

Γ— 100

6.84 π‘₯ 6.84 57

Γ— 100 Γ— 100

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π‘₯ =

6.84 57

https://doozystudy.blogspot.in/

= 12

π‘₯ = 12

π‘₯

3.2 = 𝜎=

𝜎 Γ— 100 163.8 3.2 x 163.8 = 15.24 100

𝜎 = 5.24

ST UD Y

12. xU FOtpy; 100 Ngh; cs;sdh;. mth;fspd; cauq;fspd; $l;Lruhrhp 163.8 nr.kP. kw;Wk; khWghl;Lf; nfO 3.2 vdpy; jpl;ltpyf;fk; fhz;f. π‘₯ = 163.8 C.V. = 3.2, 𝜎= ? 𝜎 C. V. = Γ— 100

13. xU Gs;sp tptuj;jpy; 30 kjpg;Gfspd; $l;Lruhrhp kw;Wk; jpl;ltpyf;fk; KiwNa 18 kw;Wk; 3 MFk;. mtw;wpd; $l;Lj;njhifiaAk;> NkYk; mtw;wpd; th;f;fq;fspd; $l;Lj;njhifiaAk; fhz;f. 𝑛 = 30, π‘₯ = 18, 𝜎 = 3 βˆ‘π‘₯ = n Γ— π‘₯ = 30 Γ— 18 = 540 βˆ‘π‘₯ 2 𝑛 βˆ’ 182

𝜎2 = βˆ‘π‘₯ 2 𝑛 βˆ‘π‘₯ 2 30

βˆ’

βˆ‘π‘₯ 2 𝑛

= 32

= 9

βˆ‘π‘₯ = 540 βˆ‘π‘₯ 2 = 9990

βˆ’ 324 = 9

βˆ‘π‘₯ 2 – 9720 = 270 βˆ‘π‘₯ 2 = 270 + 9720 = 9990

𝒏 = 𝟏𝟎, 𝒙 = 𝟏𝟐 kw;Wk; βˆ‘ π’™πŸ = πŸπŸ“πŸ‘πŸŽ vdpy;> khWghl;Lf; nfOitf; fzf;fpLf. 𝑛 = 10, π‘₯ = 12, βˆ‘π‘₯ 2 = 1530 jpl;ltpyf;fk;

ZY

14.

βˆ‘π‘₯ 2 𝑛

𝜎 =

khWghl;Lf; nfO C.V.

= =

=

βˆ‘π‘₯ 2 𝑛

=

153 βˆ’ 144 =

𝜎 Γ— 100 π‘₯ 3 Γ— 100 12 1 Γ— 100 = 4

DO O

=

βˆ’

1530 10

βˆ’ 122

9 = 3

25

C.V. = 25

15.

xU Gs;sp tptuj; njhFg;gpYs;s 100 kjpg;Gfspd; ruhrhp kw;Wk; jpl;ltpyf;fk; KiwNa 48 kw;Wk; 10 MFk;. midj;J kjpg;Gfspd; $l;Lj;njhif kw;Wk; mitfspd; th;f;fq;fspd; $l;Lj;njhif Mfpatw;iwf; fhz;f. 100 kjpg;Gfspd; ruhrhp π‘₯ = 48 100 kjpg;Gfspd; $l;Lj;njhif βˆ‘ π‘₯ = 48 Γ— 100 = 4800 jpl;ltpyf;fk; 𝜎 = 10 vdNt> tpyf;f th;f;fruhrhp 𝜎 2 =

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βˆ‘π‘₯ 2 𝑛

βˆ’

βˆ‘π‘₯ 2 𝑛

= 102 = 100

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βˆ‘π‘₯ 2 𝑛 βˆ‘π‘₯ 2 𝑛

βˆ’

4800 2 100

= 100 ⟹

βˆ’ 2304 = 100 ⟹

βˆ‘π‘₯ 2 𝑛

βˆ‘π‘₯ 2 𝑛

βˆ’ (48)2 = 100

= 100 + 2304 = 2404

100 kjpg;Gfspd; th;f;fq;fspd; $l;Lj;njhif βˆ‘π‘₯ 2 = 100 Γ— 2404 = 2,40, 400

ST UD Y

12. epfo;jfT 1.

xU Fwpg;gpl;l ehspy; kio ngWtjw;fhd epfo;jfT 0.76 mf;Fwpg;gpl;l ehspy; kio tuhky; ,Uf;f epfo;jfT ahJ? P(A) = 0.76 P A’ = 1βˆ’ P (A) = 1βˆ’ 0.76 P A’ = 0.24

2.

Kjy; 20 ,ay; vz;fspypUe;J xU KO vz; rktha;g;G Kiwapy; Njh;e;njLf;fg;gLfpwJ. me;j vz; gfh vz;zhf ,Uf;f epfo;jfT fhz;f. (Apr-2012) S = {1, 2, 3,……..20 n(S) = 20 gfh vz;zhf ,Uf;Fk; epfo;r;rp A = {2, 3, 5, 7, 11, 13, 17, 19} n(A) = 8

P(A)

8 20

=

2 5

35 nghUl;fs; mlq;fpa njhFg;G xd;wpy; 7 nghUl;fs; FiwghLilad. mjpypUe;J xU nghUs; rk tha;g;G Kiwapy; Njh;e;njLf;f> mJ Fiwghlw;w nghUshf ,Uf;f epfo;jfT ahJ? n(S) n(A)

= 35 = 28 ( 35 βˆ’7= 28)

P(A)

=

P(A)

4.

=

𝑛 (𝐴) 𝑛 (𝑆) 4 = 5

=

28 35

=

4 5

(Jun-12, Apr-13)

DO O

3.

𝑛 (𝐴) 𝑛 (𝑆) 2 = 5

=

ZY

P(A)

rktha;g;G Kiwapy; Njh;e;njLf;fg;gLk; nel;lhz;by; 53 nts;spf;fpoikfs; ,Uf;f epfo;jfT ahJ? S = {(QhapW> jpq;fs;)> (jpq;fs;> nrt;tha;)> (nrt;tha;> Gjd;)> (Gjd;> tpahod;)> (tpahod;> nts;sp)> (nts;sp> rdp)> (rdp>QhapW)}

n(S) = 7 A ={(tpahod;> nts;sp)> (nts;sp> rdp)} n(A) = 2 P(A) P(A)

𝑛 (𝐴) 𝑛 (𝑆) 2 = 7

=

=

2 7

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5.

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rktha;g;G Kiwapy; Njh;e;njLf;fg;gLk; nel;lhz;by; 52 nts;spf;fpoikfs; ,Uf;f epfo;jfT ahJ? S = {(QhapW> jpq;fs;)> (jpq;fs;> nrt;tha;)> (nrt;tha;> Gjd;)> (Gjd;> tpahod;)> (tpahod;> nts;sp)> (nts;sp> rdp)> (rdp>QhapW)}

n(S) = 7 A = {(QhapW> jpq;fs;)> (jpq;fs;> nrt;tha;)> (nrt;tha;> Gjd;)> (Gjd;> tpahod;)> (rdp>QhapW)} n(A) = 5

P(A) 6.

𝑛 (𝐴) 𝑛 (𝑆) 5 = 7

=

=

5 7

ST UD Y

P(A)

rktha;g;G Kiwapy; Njh;e;njLf;fg;gLk; rhjhuz Mz;by; 53 nts;spf;fpoikfs; ,Uf;f epfo;jfT ahJ? S = {QhapW> jpq;fs;> nrt;tha;> Gjd;> tpahod;> nts;sp> rdp} n(S)

=7

A= { nts;sp } =1

P(A)

=

𝑛 (𝐴) 𝑛 (𝑆)

P(A)

=

1 7

=

1 7

xU rPuhd gfil ,uz;L Kiw cUl;lg;gLfpwJ. Kf vz;fspd; $Ljy; 9 fpilf;f epfo;jfT ahJ? (Oct-2012, 2014) 𝑆 = { 1,1 , 1,2 , 1,3 , 1,4 , 1,5 , 1,6 ,

ZY

7.

n(A)

2,1 , 2,2 , 2,3 , 2,4 , 2,5 , 2,6 , 3,1 , 3,2 , 3,3 , 3,4 , 3,5 , 3,6 , 4,1 , 4,2 , 4,3 , 4,4 , 4,5 , 4,6 ,

8.

DO O

5,1 , 5,2 , 5,3 , 5,4 , 5,5 , 5,6 , 6,1 , 6,2 , 6,3 , 6,4 , 6,5 , (6,6)}

n(S)

= 36

A

= {(3, 6), (4, 5), (5, 4), (6, 3)}

n(A)

=4

P(A)

=

P(A)

1 = 9

𝑛 (𝐴) 𝑛 (𝑆)

=

4

36

=

1 9

12 ey;y Kl;ilfSld; 3 mOfpa Kl;ilfs; fye;Js;sd. rktha;g;G Kiwapy; Njh;e;njLf;f g;gLk; xU Kl;il mOfpajhf ,Uf;f epfo;jfT ahJ? n(S) = 15 n(A) = 3

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P(A)

=

𝑛 (𝐴) 𝑛 (𝑆)

= P(A) 9.

=

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3 15

=

1 5

1 5

,U ehzaq;fis xNu rkaj;jpy; Rz;Lk; NghJ> mjpfgl;rk; xU jiy fpilf;f epfo;jfT fhz;f. = {HH, HT, TH, TT} =4 = {TT, HT, TH} =3

P(A)

=

P(A)

=

=

3 4

4

mh;n[z;bdh> gq;fshNj\;> rPdh> mq;Nfhyh> U\;ah> my;[Phpah Mfpa ehLfspd; ngah;fisf; nfhz;l gl;baypypUe;J xU Rw;Wyhg; gazp rktha;g;G Kiwapy; xU ehl;bd; ngaiuj; Njh;e;njLf;fpwhh;. β€˜m’ vd;w vOj;jpy; Muk;gkhFk; ehl;bd; ngaiuj; Njh;e;njLf;f epfo;jfT vd;d? n(S) = 6 n(A) = 3 P(A) P(A)

11.

𝑛 (𝐴) 𝑛 (𝑆) 3

=

𝑛 (𝐴)

𝑛 (𝑆) 1 = 2

=

3 6

=

1 2

ed;F fiyj;J itf;fg;gl;l 52 rPl;Lfisf; nfhz;l rPl;Lf; fl;bypUe;J rk tha;g;Gr; Nrhjid Kiwapy; xU rPl;L vLf;fg;gLfpwJ. me;j rPl;L gpd;tUtdthf ,Uf;f epfo; jfTfisf; fhz;f. m) fUg;G ,uhrh M) ];NgL fhh;L. (Oct-2013) n(S) = 52 fUg;G ,uhrh n(A) = 2 𝑛 (𝐴) 2 1 P(A) = = =

ZY

10.

S n(S) A n(A)

𝑛 (𝑆)

n(S) n(B) P(B)

= 52 = 13 𝑛 (𝐴) = =

DO O

];NgL fhh;L

12.

ST UD Y

(Jun-2015)

𝑛 (𝑆)

52

13 52

26

=

1 4

ed;F fiyj;J itf;fg;gl;l 52 rPl;Lfisf; nfhz;l rPl;Lf; fl;bypUe;J rk tha;g;Gr; Nrhjid Kiwapy; xU rPl;L vLf;fg;gLfpwJ. me;j rPl;L gpd;tUtdthf ,Uf;f epfo;jfTfisf; fhz;f. m) ,uhrh M) lakz;l; 10. n(S) = 52 ,uhrh n(A) = 4 𝑛 (𝐴) 4 1 P(A) = = = 𝑛 (𝑆)

lakz;l; 10

n(S) n(B) P(B)

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= 52 =1 𝑛 (𝐡) = = 𝑛 (𝑆)

52

13

1 52

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%d;W gfilfs; xNu Neuj;jpy; cUl;lg;gLk;NghJ %d;W gfilfspYk; xNu vz; fpilg;gjw;fhd epfo;jfT ahJ? (Apr-2014) S = 1, 1, 1 , 1, 1, 2 , …….. 6, 6, 6 n(S) = 216 A = {(1, 1, 1), (2, 2, 2), (3, 3, 3), (4, 4, 4), (5, 5, 5), (6, 6, 6)} n(A) = 6 𝑛 (𝐴) 6 1 P(A) = = = 𝑛 (𝑆)

14.

216

36

%d;W ehzaq;fs; xNu Neuj;jpy; Rz;lg;gLfpd;wd. gpd;tUk; epfo;r;rpfSf;F epfo;jfT fhz;f. (i) Fiwe;jJ xU jiy fpilg;gJ (ii) ,U G+f;fs; kl;Lk; fpilg;gJ (iii) Fiwe;jJ ,U jiyfs; fpilg;gJ S = {HHH, HHT, HTH, HTT, THH, THT, TTH, TTT} n(S) = 8 (i) Fiwe;jJ xU jiy fpilg;gJ A = {HHH, HHT, HTH, HTT, THH, THT, TTH} n(A) = 7 𝑛 (𝐴) 7 P(A) = = 𝑛 (𝑆)

ST UD Y

13.

https://doozystudy.blogspot.in/

8

(ii) ,U G+f;fs; kl;Lk; fpilg;gJ B = {HTT, TTH, THT} n(B) = 3 𝑛 (𝐡) 3 P(B) = = 𝑛 (𝑆)

8

(iii) Fiwe;jJ ,U jiyfs; fpilg;gJ C = {HHH, HTH, HHT, THH} n(C) = 4

P(A)

, P(C) =

P(A)

(ii) khztp Njh;e;njLf;fg;gl epfo;jfT

16.

1 2

xU tFg;gpy; cs;s 35 khzth;fspy; 20 Ngh; Mz;fs; kw;Wk; 15 Ngh; ngz;fs;. rktha;g;G Kiwapy; xU khzth; Njh;e;njLf;fg;gLfpwhh; vdpy;> gpd;tUk; epfo;r;rpfspd; epfo;jfTfisf; fhz;f. (i) Njh;e;njLf;fg;gLgth; khztdhf ,Uj;jy;> (ii) Njh;e;njLf;fg;gLgth; khztpahf ,Uj;jy;. tFg;gpy; cs;s khzth;fspd; vz;zpf;if n(S) = 35 (i) khztd; Njh;e;njLf;fg;gl epfo;jfT n(A) = 7

DO O

15.

𝑛 (𝐢) 4 1 = = 𝑛 (𝑆) 8 2 7 3 = , P(B) = 8 8

=

ZY

P(C)

P(B)

=

𝑛 (𝐴) 𝑛 (𝑆)

n(B)

=

20 35

=

4 7

= 15

𝑛 (𝐡) 15 = = 𝑛 (𝑆) 35

=

3 7

xU igapy; 5 rptg;G kw;Wk; rpy ePy epwg;ge;Jfs; cs;sd. mg;igapypUe;J xU ePy epwg; ge;ij vLg;gjw;fhd epfo;jfT> xU rptg;G epwg; ge;ij vLg;gjw;fhd epfo;jftpd; %d;W klq;F vdpy;> mg;igapYs;s ePy epwg; ge;Jfspd; vz;zpf;ifiaf; fhz;f. igapy; 5 rptg;G epwg;ge;Jfs;> π‘₯ ePy epwg; ge;JfSk; cs;sd. vdNt> n(S) = 5 + π‘₯ B vd;gJ xU ePy epwg;ge;ij vLf;Fk; epfo;r;rp kw;Wk; R vd;gJ xU rptg;G epwg;ge;ij vLf;Fk; epfo;r;rp vd;f. fzf;fpd;gb P(B) = 3P(R)

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𝑛 (𝐡) 𝑛 𝑅 =3 𝑛 (𝑆) 𝑛 (𝑆) π‘₯ 5 =3 5+π‘₯ 5+π‘₯

β‡’ π‘₯ = 3 Γ— 5 = 15 ePy epwg; ge;Jfspd; vz;zpf;if π‘₯ = 15 xU rktha;g;Gr; Nrhjidapy; xU epfo;r;rp A vd;f. me;;epfo;r;rpapd; epug;G epfo;r;rp 𝑨 vd;f. P(A) : P(𝑨 ) = 7:12, vdpy;> P(A)- If; fhz;f.

ST UD Y

17.

𝑃(𝐴) 7 = P(𝐴 ) 12

P(A) : P(𝐴 ) = 7:12 vdNt

12 Γ— P(A) = 7Γ— P(𝐴 ) 12P(A) = 7[1βˆ’P(A) ] = 7 βˆ’ 7P(A) 19P(A) = 7 P (A) = 18.

7 19

A kw;Wk; B vd;gd xd;iwnahd;W tpyf;Fk; epfo;r;rpfs;. NkYk; P(A) =

πŸ‘ πŸ“

kw;Wk; P(B) =

𝟏 , πŸ“

vdpy;

P(AβˆͺB)-If; fhz;f. A kw;Wk; B vd;gd xd;iwnahd;W tpyf;Fk; epfo;r;rpfs; vdNt> P(AβˆͺB) = P(A) + P(B) 3 1 πŸ’ P(AβˆͺB) = + = [P(A ∩ B) = 0] 5

19.

A kw;Wk; B vd;w ,uz;L epfo;r;rpfspy; P(A)

𝟏 = πŸ’

5

, P(B) =

fhz;f. P(AβˆͺB) = P(A) + P(B) – P(A∩B) 1 2 1 5+8 βˆ’ 10 P(A∩B) = P(A) +P(B) – P (AβˆͺB) = + βˆ’ = =

21.

20

vdpy; , P(A∩B)-If;

πŸ‘ 𝟐𝟎

26

26

26

13

1 Kjy; 100 tiuapyhd KO vz;fspypUe;J rk tha;g;G Kiwapy; Njh;e;njLf;fg; gLk; xU vz; xU KO th;f;fkhf ,Uf;f epfo;jfT fhz;f. $Wntsp S = 1, 2, 3,…..100 n(S) = 100 KO th;f;f vz;fs; A = {1, 4, 9, 16, 25, 36, 49, 64, 81, 100} n(A) = 10 𝑛 (𝐴) 10 1 P(A) = = = 𝑛 (𝑆)

22.

2

𝟏 𝟐

xU igapy; 10 nts;is> 6 rptg;G kw;Wk; 10 fUg;G epwg;ge;Jfs; cs;sd. rktha;g;G Kiwapy; xU ge;jpid vLf;Fk;NghJ mJ nts;is my;yJ rptg;G epwg; ge;jhf ,Ug;gjw;fhd epfo;jftpidf; fhz;f. nts;isg; ge;Jfspd; vz;zpf;if n(W) = 10, rptg;Gg; ge;Jfspd; vz;zpf;if n(R) = 6, fUg;Gg; ge;Jfspd; vz;zpf;if n(B) =10 /$Wntsp n(S) = 10+6+10=26 nts;is my;yJ rptg;G epwg;ge;J vLf;f epfo;jfT 10 6 16 8 P(WβˆͺR) = P(W) + P(R) = + = = [P(W∩R)= 0]

DO O

20.

5

kw;Wk; P(AβˆͺB) =

ZY

4

πŸ“

𝟐 πŸ“

100

10

1 Kjy; 100 tiuapyhd KO vz;fspypUe;J rk tha;g;G Kiwapy; Njh;e;njLf;fg; gLk; xU vz; xU KO fdkhf ,y;yhky; ,Uf;f epfo;jfT fhz;f. $Wntsp S = 1, 2, 3, …….100

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n (S) = 100 KO fd vz;fs; A = {1, 8, 27, 64} n(A) = 4 𝑛 (𝐴) 4 1 epfo;jfT P(A) = = = 𝑛 (𝑆)

100

25

25

25

25

ST UD Y

xU KO fdkhf ,y;yhky; ,Uf;f epfo;jfT P A’ = 1βˆ’P(A) 1 25βˆ’1 24 = 1βˆ’ = = 23. 20 rPl;Lfspy; 1 Kjy; 20 tiuAs;s KO vz;fs; Fwpf;fg;gl;Ls;sd. rktha;g;G Kiwapy; xU rPl;L vLf;fg;gLfpd;wJ. mt;thW vLf;fg;gl;l rPl;bYs;s vz; (1) 4-d; klq;fhf ,Uf;f epfo;jfT fhz;f. (2) 6-d; klq;fhf ,y;yhky; ,Uf;f epfo;jfT fhz;f. (Jun-2014, Apr-2016) $Wntsp S = 1, 2, 3, …….20 n(S)= 20 (1) 4 -d; klq;Ffs; A = {4, 8, 12, 16, 20} n(A) = 5 𝑛 (𝐴) 5 1 4-d; klq;fhf ,Uf;f epfo;jfT P(A) = = = 𝑛 (𝑆)

(2)

6 –d; klq;Ffs; B={6,12,18} 𝑛(𝐡) 𝑛 𝐡 = 3, 𝑃 𝐡 = = 𝑛 (𝑆)

3 20

6-d; klq;fhf ,y;yhky; ,Uf;f epfo;jfT

3 20

=

17 20

100

10

DO O

,U gfilfs; xU Nru cUl;lg;gLfpd;wd. Kf vz;fisf; nfhz;L mikf;fg;gLk;
26.

𝑃 𝐡 = 1βˆ’π‘ƒ 𝐡 =1βˆ’

xU igapy; cs;s 1 Kjy; 100 tiuAs;s vz;fshy; Fwpf;fg;gl;l rPl;LfspypUe;J xU rPl;L vLf;fg;gLfpwJ. mt;thW vLf;fg;gLk; rPl;bd; vz; 10 My; tFgLk; vz;zhf ,Ug;gjw;fhd epfo;jftpidf; fhz;f. $Wntsp S = 1, 2, 3, …….100 n(S) = 100 10 My; tFgLk; vz;fs; A = 10, 20, 30,….100 n(A) = 10 𝑛 (𝐴) 10 1 epfo;jfT P(A) = = = 𝑛 (𝑆)

25.

4

ZY

24.

20

36

3

ed;F fiyj;J mLf;fp itf;fg;gl;l 52 rPl;Lfisf; nfhz;l rPl;Lf;fl;bypUe;J rk tha;g;G Kiwapy; xU rPl;L vLf;fg;gLfpwJ. me;j rPl;L ];NglhfNth (spade) my;yJ ,uhrhthfNth (king) ,Ug;gjw;fhd epfo;jftpidf; fhz;f. (Jun-2013) nkhj;j rPl;Lfspd; vz;zpf;if 𝑛 𝑆 = 52 ];NgL rPl;Lfspd; vz;zpf;if 𝑛 𝐴 = 13 𝑛 (𝐴) 13 epfo;jfT 𝑃 𝐴 = = 𝑛 (𝑆)

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52

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,uhrh rPl;Lfspd; vz;zpf;if 𝑛 𝐡 = 13 𝑛 (𝐡) epfo;jfT 𝑃 𝐡 = = 𝑛 (𝑆)

];NgL rPl;lhfTk; ,uhrh rPl;lhfTk; ,Uf;Fk; rPl;Lfspd; vz;zpf;if epfo;jfT

4 52

𝑛 𝐴∩𝐡 = 1 𝑛 (𝐴∩𝐡) 𝑃 𝐴∩𝐡 = = 𝑛 (𝑆)

1 52

ST UD Y

/ rPl;L ];NglhfNth my;yJ ,uhrhfNth ,Ug;gjw;fhd epfo;jfT 𝑃 𝐴 βˆͺ 𝐡 = 𝑃 𝐴 + 𝑃 𝐡 βˆ’ 𝑃(𝐴 ∩ 𝐡) 13 4 1 17βˆ’1 16 = + βˆ’ = = = 52

52

52

52

4 13

2 nr.kP. MuKs;s tl;lj;jpd; cs;Ns cs;s Gs;spfspy; rktha;g;G Kiwapy; xU Gs;spiaj; Njh;T nra;a mJ tl;lj;ij (ghpjp) tpl ikaj;Jf;F mUfpy; ,Uf;f epfo;jfT vd;d? (Oct-15) 2nr.kP. MuKs;s tl;lj;jpd; cs;Ns cs;s Gs;spfs; vd;gJ mt;tl;lj;jpd; gug;gsthFk;. vdNt> $Wntsp 𝑛 𝑆 = πœ‹π‘Ÿ 2 = πœ‹ Γ— 22 = 4πœ‹ Njh;e;njLf;fg;gLk; Gs;sp tl;lj;ij (ghpjp) tpl ikaj;Jf;F mUfpy; ,Uf;f Ntz;Lnkdpy; 1 nr.kP MuKs;s tl;lj;jpd; gFjpf;Fs; mikAk; Gs;spfshFk;. vdNt epfo;r;rpfspd; vz;zpf;if 𝑛 𝐴 = πœ‹π‘Ÿ 2 = πœ‹ π‘₯ 12 = πœ‹ 𝑛(𝐴) 𝑛(𝑆)

=

πœ‹ 4πœ‹

=

1 4

ZY

epfo;jfT 𝑃 𝐴 =

DO O

27.

52

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Doozy Study_ SSLC MATHS 2 MARKS QUESTION AND ANSWERS ...

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