SERIES ALPHABETIC SERIES
Example - 1 :
missing as shown by (?j Choose the correct answer
What will be the next term in ; CEH, DGJ,
1) FKO
2) FLO
3)GKO
4) FOK
1.
A, E, I,
r,
3) 0 2.
of the next term. So, the missing term is FKO.
-.-;~)o
L
__ .3---»
K 0
Hence the answer is (I).
1) L
2) M
3} K
4) N
B, D, H, N,?
u
1) V
2}
3) R
4) S
Y, U, R, P,? 1) M
2) N
3) 0
4) R
Choose the term which will continue the folfowing series:
cq
2.
4.
ue
Example - 2 :
3.
io
F
st
~
4)S
B, C, E, H,?
np
term are respectively moved one, two and three steps forward to obtain the corresponding Ipttefs
2) M
ap
Clearly, the first, second and third letters of each
E
U
1) R
Solution : (1)
5.
C4F, E61, G9L, 1130? 1) K17R
2} K18R
Solution:
B, D, G, I, L, ? 1) M
2) N
3) 0
4) P
4) K18S
tn
3) L18R
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ElL?
out of the given alternatives.
er
1.
s. co m
, TYPE 1
6.
(2)
M
2) N
3) L
4) K
I}
Clearly, the first letters of the terms are alternate.
ww w.
U,T,R,Q, 0, ?
The sequence followed by the numbers is +2., +3, +4, +5 ...... The last letter of each term is
7.
H, M,?, T,?
three steps forward of the last letter of the
1) Q, V
2) Q, U
preceeding term. Thus, the next term would be
3} R, U
4) R, V
K18R.
8.
Z, Y, X, T, S, R, N, M, L, ?
Directions (1-35): In each of the following question,
1) H, E, F
2) H, G, F
various terms of a letter series and given with one term
3) F, E, D
4) D. C, B
c e" b j, t I, o??
19. FKN, JOR, OIL, O??
1) n, q
2) m, q
1) 5, W
2) T, W
3) q, m
4) q, n
3) W, T
4) W, Y
10. DGI, KNP, PSU, N ? ? 1) Q, T
2) Q, 5
1) NP
3) R, T
4) M, N
3) Nf
2) MQ 4) WY
21. alf, ene, i?d, mr?
1) C, E
2) D,E
1) p, c
3) E,C
4) M, N
3) a,
C
2) c. p 4), q,
2) 5, T
1) n
2) m
3) T, R
4) S, U
3) q
4) p
23 . acd, dca, mpq, qpm, fgh, ???
3) 0, M
4) P, S
14. WRT, OJL, SN?, L?I 2) Q, H
3) R,H
4)R,G
cq
ue
1) P, .G
st
2) 0, R
io
DIL, OTW
1) R,5
15, HF, KC, NK, QH, SU. ?? 1) VO 3)VM
np
1) R, T
13. . FKN. J??,
1) ghf
3) hgf
2) hfg . 4) fhj
24. AB, DEF, IJKL, PQR?T, ?? 1) 5, X, Y
2) 5, Y, Z
3) T, Y, Z
4) X, Y, Z
25. AC, EG, HJ,??
2;VR
1) M. N
2) K, L
4) WR
3) J,L
4) J, I
16. OGI, KNp, PSU, ???
tn
C
22. cr, gw, ka, oe, si, w?
ap
12. GEC, MKI, TRP, N? ?
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,11. JMK, VYW, PSQ, B? ?
s. co m
20. Win, OJL, S??
er
9,
26. BAT, DCV, FEX, ? 2) NQT
1) HGI
2) HGZ
3)NQS
4) NRS
3) HIJ
4) HGY
ww w.
1) MQS
27. MN, LO, KP, ?
17. JMK, VYW. ?S? BEC 1} MN
2)PQ
1) RS
2) JQ
3) PR
4) ST
3) IJ
4) QR
18. GEe, MKI, TRP, ???
28. C, G, L, R, ?
1} VTQ
2) MTR
1) U
2) S
3) VTR
4) MQS .
3) Y
4} Z
29. QR, PSJ OT, 1) NT
..
??,
MV 2) NU
1) EU
2) EV
3~ EF
4) FV
4) SU
3) NW
33. AD, EI, IN, PS ?
1) X
2} W
3) Y
4)V
4) WW
3) WX 34. BDF, CFI. DHL. ?
,...,."
2) EJO
1) ElM
31. JAZ, LEX, NIV, POT
4) EMI
2) PQR-
3) RSR
4) ACM
er
3) CJM
1} TOC
35. RGS, SRG, GSR, ? i) GRG
32. BY, ex, OW,?
2) SRS 4) SRG
np
ap
3) RGS
3) The series consist of vowels A, E, I, 0, U
1) The series is of the form B ~ C
+2
E
E
+3
H
H
+4
L
ps
3.
C
2) The series is obtained as below: B ~
D
D ~
G
G
+2
L
~ L
6.
.2
N
2) The leiters are alternately moved one and two steps backward to obtain the successive terms.
1) The letters are obtained as below :
B
+2
D
+4'
H
last 1, 2, 3 and 4 letters are missing between two consecutive letters.
ww w.
D
4.
cq
2.
ue
written in the order as above.
5.
st
1.
io
ANSWERS
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2) XX
s. co m
1) WY
30. C, H, M, R, ?
H
+6
N
N
+8
V
7.
8.
1) Letters are in reverse order in which term the
2) Beginning
from Z in the
alphabets
3
consecutive letters are written and then 3
3) The letters are obtained as below :
consecutive letters are 'deleted and so on.
Y
-4
U
U
--3
R
R
-2
P
shown ceb / jli / oqn.
°
In each group, first letter is moved one step
P ~
9.
4) The series may be divided into groups as
backward
to obtain the third letter while the
16. 3) The arrangement of alphabets are as fr ..
third letter is moved. Three steps forward to
D ~
G
~->
obtain the second letter.
K -~> p ~
N
----_-:?_._)-
P
S
·2
U
10. 2) Here the letters are obtained as follows : .2
K
+3
N
--~
P
P
·3
S
~
U
N
~3
Q
~
s
.'
M
-2
K
V
+3
Y
-2
W
B
.3
S
~
Q
E
~
C
·2
E
-2
M
-2
K
-2
T
-2
R
~
P
N
-2
T
~
R
ue
cq
K
.3
N
J
+5
0
+3
R
D
+5
0
+5
ps
+5
y
P ~
S
z
E
2
.3
K
W
~ -.-~
Q C
·K
'T ~
R
V ~
T
__
2_~
I
--~-> P 1\ ~
19. 2) Here the first letter the first series il!cn~c:,:.'d by 5 to obtain second letter is increas- by :~ to obtain the third letter. T _._'."._.:> W 0 ~
20. 1) The first letter of the first series decreased L;,;
L
5 to obtain the second letter of the first series and then the second letter increases by ~ to obtain the third letter.
W
S -~
14. 1) Here the arrangement is as follows: W
-5
R
~
T
0
--5
J
~
L
S
5
N
.2
L
--5
G
.2
ww w.
~
2 --~
st
C
F
~
v
M ~
13. 2) Here th", letters are arranged as follows:
T
M
io
G
s
18. 3) The arrangement of letters are as follows : E __ 2_> C G ~
12. 3) The letters are obtained as follows :
+3
~
np
+3
--~
J
B
J
.~
Q
17, 2) The letters are arranged as follows .
11. 3) The letters are arranged as follows :
p ~
__ +3_7
s. co m
N
~
er
G
Therefore the order must be
ap
.3
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0
P
15. 2) The first letter of each term is moved three steps forward and the second letter is moved three steps backward to obtain the corresponding letters of the next letter.
N
-~->
P
21. I} The first letters of each series is increased by 4 and the second letter of all series is increased by 2 and third letter of each series is decreased by one. .. _.- .4-- -->
a -.~
e
A
-_+~
n
+2
p
~-}
e
1
d
_~l
f
.__ l_~
----)-
III
__ )-
22. 2) The _lettersin each term are moved four si~i;~ forward to obtain. The corresponding letter of the next term.
~... 3} The series tan be splitted as follows :
28.
---'----7
,4
G
G
+S
L
The reciprocal of first series is the second.
L
.6
R
Similarly
mpq
~
qpm
R
-7 ---7
Y
Similarly
fgh
~
hgf
So, the answer .isY
s. co m
acd , dca
24. i) The series consists of letters 2, 3, 4, 5, etc. and one letter is between first two series, 2
29. 2) Q ~
p
letters between second and third and so on.
p ~
0
s, y, z is the correct one.
0 ~
N
N ~
M
25. 3) The series goes on increasing as follows: ·1 H --~ .3
C J
E
30. 2) C ~
~
J G
.• 2
L
~
starting
A from
the second
position to first position only. Therefore the
st
first two ietters of the next word is HG. The third letter in each word starting from first
V
,-2
X
X
.2
Z
cq
V
ue
word exceeds by 2. T ..-.~·,2
So, the answer is HGZ 27. 2) The second letters
H
,5
M
M
+5
R
R ~
W
J ~
L
+2
N ~ A
P
2
14
E
.4
.4
0
,4
Z ~
X
··2
V ~
T
--)
32. 2) B ~
C
~
D
Y ~
X
~
W ~
31. 3)
io
26. 2) The first two letters in each words are alphabets
each sequence is a
I
33. 3) A
tn 0 ~
P
ww w.
0
Q P ~ Similarly the first letters
In each sequence is a decreasing series M ~
L
L ~
K
K ~
T
So, the answer is JQ.
+4 +7
continuing series. N ~
H
ap
.--~*
np
A
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3} C
er
;.
D
-2
.5
E
R S 1 E
~
V
J
+-6
P
N
.5
S
W ,5
+5 +5
Therefore the required term is X. 34. 2) B ~ D
C +2
F
F ~
D
~
E
.2
H
~
J
,3
L
~
0
~
35. 3) The last letter becomes the first letter is each subsequent series.