SERIES ALPHABETIC SERIES

Example - 1 :

missing as shown by (?j Choose the correct answer

What will be the next term in ; CEH, DGJ,

1) FKO

2) FLO

3)GKO

4) FOK

1.

A, E, I,

r,

3) 0 2.

of the next term. So, the missing term is FKO.

-.-;~)o

L

__ .3---»

K 0

Hence the answer is (I).

1) L

2) M

3} K

4) N

B, D, H, N,?

u

1) V

2}

3) R

4) S

Y, U, R, P,? 1) M

2) N

3) 0

4) R

Choose the term which will continue the folfowing series:

cq

2.

4.

ue

Example - 2 :

3.

io

F

st

~

4)S

B, C, E, H,?

np

term are respectively moved one, two and three steps forward to obtain the corresponding Ipttefs

2) M

ap

Clearly, the first, second and third letters of each

E

U

1) R

Solution : (1)

5.

C4F, E61, G9L, 1130? 1) K17R

2} K18R

Solution:

B, D, G, I, L, ? 1) M

2) N

3) 0

4) P

4) K18S

tn

3) L18R

ps

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ElL?

out of the given alternatives.

er

1.

s. co m

, TYPE 1

6.

(2)

M

2) N

3) L

4) K

I}

Clearly, the first letters of the terms are alternate.

ww w.

U,T,R,Q, 0, ?

The sequence followed by the numbers is +2., +3, +4, +5 ...... The last letter of each term is

7.

H, M,?, T,?

three steps forward of the last letter of the

1) Q, V

2) Q, U

preceeding term. Thus, the next term would be

3} R, U

4) R, V

K18R.

8.

Z, Y, X, T, S, R, N, M, L, ?

Directions (1-35): In each of the following question,

1) H, E, F

2) H, G, F

various terms of a letter series and given with one term

3) F, E, D

4) D. C, B

c e" b j, t I, o??

19. FKN, JOR, OIL, O??

1) n, q

2) m, q

1) 5, W

2) T, W

3) q, m

4) q, n

3) W, T

4) W, Y

10. DGI, KNP, PSU, N ? ? 1) Q, T

2) Q, 5

1) NP

3) R, T

4) M, N

3) Nf

2) MQ 4) WY

21. alf, ene, i?d, mr?

1) C, E

2) D,E

1) p, c

3) E,C

4) M, N

3) a,

C

2) c. p 4), q,

2) 5, T

1) n

2) m

3) T, R

4) S, U

3) q

4) p

23 . acd, dca, mpq, qpm, fgh, ???

3) 0, M

4) P, S

14. WRT, OJL, SN?, L?I 2) Q, H

3) R,H

4)R,G

cq

ue

1) P, .G

st

2) 0, R

io

DIL, OTW

1) R,5

15, HF, KC, NK, QH, SU. ?? 1) VO 3)VM

np

1) R, T

13. . FKN. J??,

1) ghf

3) hgf

2) hfg . 4) fhj

24. AB, DEF, IJKL, PQR?T, ?? 1) 5, X, Y

2) 5, Y, Z

3) T, Y, Z

4) X, Y, Z

25. AC, EG, HJ,??

2;VR

1) M. N

2) K, L

4) WR

3) J,L

4) J, I

16. OGI, KNp, PSU, ???

tn

C

22. cr, gw, ka, oe, si, w?

ap

12. GEC, MKI, TRP, N? ?

ps

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,11. JMK, VYW, PSQ, B? ?

s. co m

20. Win, OJL, S??

er

9,

26. BAT, DCV, FEX, ? 2) NQT

1) HGI

2) HGZ

3)NQS

4) NRS

3) HIJ

4) HGY

ww w.

1) MQS

27. MN, LO, KP, ?

17. JMK, VYW. ?S? BEC 1} MN

2)PQ

1) RS

2) JQ

3) PR

4) ST

3) IJ

4) QR

18. GEe, MKI, TRP, ???

28. C, G, L, R, ?

1} VTQ

2) MTR

1) U

2) S

3) VTR

4) MQS .

3) Y

4} Z

29. QR, PSJ OT, 1) NT

..

??,

MV 2) NU

1) EU

2) EV

3~ EF

4) FV

4) SU

3) NW

33. AD, EI, IN, PS ?

1) X

2} W

3) Y

4)V

4) WW

3) WX 34. BDF, CFI. DHL. ?

,...,."

2) EJO

1) ElM

31. JAZ, LEX, NIV, POT

4) EMI

2) PQR-

3) RSR

4) ACM

er

3) CJM

1} TOC

35. RGS, SRG, GSR, ? i) GRG

32. BY, ex, OW,?

2) SRS 4) SRG

np

ap

3) RGS

3) The series consist of vowels A, E, I, 0, U

1) The series is of the form B ~ C

+2

E

E

+3

H

H

+4

L

ps

3.

C

2) The series is obtained as below: B ~

D

D ~

G

G

+2

L

~ L

6.

.2

N

2) The leiters are alternately moved one and two steps backward to obtain the successive terms.

1) The letters are obtained as below :

B

+2

D

+4'

H

last 1, 2, 3 and 4 letters are missing between two consecutive letters.

ww w.

D

4.

cq

2.

ue

written in the order as above.

5.

st

1.

io

ANSWERS

tn

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2) XX

s. co m

1) WY

30. C, H, M, R, ?

H

+6

N

N

+8

V

7.

8.

1) Letters are in reverse order in which term the

2) Beginning

from Z in the

alphabets

3

consecutive letters are written and then 3

3) The letters are obtained as below :

consecutive letters are 'deleted and so on.

Y

-4

U

U

--3

R

R

-2

P

shown ceb / jli / oqn.

°

In each group, first letter is moved one step

P ~

9.

4) The series may be divided into groups as

backward

to obtain the third letter while the

16. 3) The arrangement of alphabets are as fr ..

third letter is moved. Three steps forward to

D ~

G

~->

obtain the second letter.

K -~> p ~

N

----_-:?_._)-

P

S

·2

U

10. 2) Here the letters are obtained as follows : .2

K

+3

N

--~

P

P

·3

S

~

U

N

~3

Q

~

s

.'

M

-2

K

V

+3

Y

-2

W

B

.3

S

~

Q

E

~

C

·2

E

-2

M

-2

K

-2

T

-2

R

~

P

N

-2

T

~

R

ue

cq

K

.3

N

J

+5

0

+3

R

D

+5

0

+5

ps

+5

y

P ~

S

z

E

2

.3

K

W

~ -.-~

Q C

·K

'T ~

R

V ~

T

__

2_~

I

--~-> P 1\ ~

19. 2) Here the first letter the first series il!cn~c:,:.'d by 5 to obtain second letter is increas- by :~ to obtain the third letter. T _._'."._.:> W 0 ~

20. 1) The first letter of the first series decreased L;,;

L

5 to obtain the second letter of the first series and then the second letter increases by ~ to obtain the third letter.

W

S -~

14. 1) Here the arrangement is as follows: W

-5

R

~

T

0

--5

J

~

L

S

5

N

.2

L

--5

G

.2

ww w.

~

2 --~

st

C

F

~

v

M ~

13. 2) Here th", letters are arranged as follows:

T

M

io

G

s

18. 3) The arrangement of letters are as follows : E __ 2_> C G ~

12. 3) The letters are obtained as follows :

+3

~

np

+3

--~

J

B

J

.~

Q

17, 2) The letters are arranged as follows .

11. 3) The letters are arranged as follows :

p ~

__ +3_7

s. co m

N

~

er

G

Therefore the order must be

ap

.3

tn

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0

P

15. 2) The first letter of each term is moved three steps forward and the second letter is moved three steps backward to obtain the corresponding letters of the next letter.

N

-~->

P

21. I} The first letters of each series is increased by 4 and the second letter of all series is increased by 2 and third letter of each series is decreased by one. .. _.- .4-- -->

a -.~

e

A

-_+~

n

+2

p

~-}

e

1

d

_~l

f

.__ l_~

----)-

III

__ )-

22. 2) The _lettersin each term are moved four si~i;~ forward to obtain. The corresponding letter of the next term.

~... 3} The series tan be splitted as follows :

28.

---'----7

,4

G

G

+S

L

The reciprocal of first series is the second.

L

.6

R

Similarly

mpq

~

qpm

R

-7 ---7

Y

Similarly

fgh

~

hgf

So, the answer .isY

s. co m

acd , dca

24. i) The series consists of letters 2, 3, 4, 5, etc. and one letter is between first two series, 2

29. 2) Q ~

p

letters between second and third and so on.

p ~

0

s, y, z is the correct one.

0 ~

N

N ~

M

25. 3) The series goes on increasing as follows: ·1 H --~ .3

C J

E

30. 2) C ~

~

J G

.• 2

L

~

starting

A from

the second

position to first position only. Therefore the

st

first two ietters of the next word is HG. The third letter in each word starting from first

V

,-2

X

X

.2

Z

cq

V

ue

word exceeds by 2. T ..-.~·,2

So, the answer is HGZ 27. 2) The second letters

H

,5

M

M

+5

R

R ~

W

J ~

L

+2

N ~ A

P

2

14

E

.4

.4

0

,4

Z ~

X

··2

V ~

T

--)

32. 2) B ~

C

~

D

Y ~

X

~

W ~

31. 3)

io

26. 2) The first two letters in each words are alphabets

each sequence is a

I

33. 3) A

tn 0 ~

P

ww w.

0

Q P ~ Similarly the first letters

In each sequence is a decreasing series M ~

L

L ~

K

K ~

T

So, the answer is JQ.

+4 +7

continuing series. N ~

H

ap

.--~*

np

A

ps

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3} C

er

;.

D

-2

.5

E

R S 1 E

~

V

J

+-6

P

N

.5

S

W ,5

+5 +5

Therefore the required term is X. 34. 2) B ~ D

C +2

F

F ~

D

~

E

.2

H

~

J

,3

L

~

0

~

35. 3) The last letter becomes the first letter is each subsequent series.

series QA 120.pdf

1) MQS 2) NQT 1) HGI 2) HGZ. 3)NQS 4) NRS 3) HIJ 4) HGY. 17. JMK, VYW. .... series QA 120.pdf. series QA 120.pdf. Open. Extract. Open with. Sign In. Details.

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